Answer:
y = 3x + 1
Step-by-step explanation:
Put the steps in solving this inequality in the correct order…
Answer:
To solve this problem we first subtract 3 from both sides, giving the inequality -cw+3-3<= 15-3. We then simplify the equation to -cw<= 12. Next, we divide both sides by -c and flip the inequality. We flip the inequality because we are dividing by a negative. Now we have the inequality -cw/-c >= 12/-c. Lastly, we simplify to w >= -12/c.
Kate begins solving the equation StartFraction 2 Over 3 EndFraction left-parenthesis 6 x minus 3 right-parenthesis equals StartFraction one-half EndFraction left-parenthesis 6 x minus 4 left-parenthesis.(6x – 3) = StartFraction 2 Over 3 EndFraction left-parenthesis 6 x minus 3 right-parenthesis equals StartFraction one-half EndFraction left-parenthesis 6 x minus 4 left-parenthesis.(6x – 4). Her work is correct and is shown below.
StartFraction 2 Over 3 EndFraction left-parenthesis 6 x minus 3 right-parenthesis equals StartFraction one-half EndFraction left-parenthesis 6 x minus 4 left-parenthesis.(6x – 3) = StartFraction 2 Over 3 EndFraction left-parenthesis 6 x minus 3 right-parenthesis equals StartFraction one-half EndFraction left-parenthesis 6 x minus 4 left-parenthesis.(6x – 4)
4x – 2 = 3x – 2
When she adds 2 to both sides, the equation 4x = 3x results. Which solution will best illustrate what happens to x ?
The answer to the question isit has only one solution x = 0
How to solve for the solutionThe equation that Kate is solving is given as
2/3(6x - 3) = 1/2(6x - 4)
Then we have to factorize the equations
Such that we would have
[tex]\frac{2(6x-3)}{3} =\frac{2(3x-2)}{2}[/tex]
The next step of the equation would have to do with opening the equation
Then we would have 4x - 2 = 3x - 2
then 4x - 3x = 0
Then x = 0
Hence the solution of the equation is that it only has one solution x = 0
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Answer:
B. The equation has one solution: x = 0.
Step-by-step explanation:
Could someone help me with the first two parts of this geometry question? I can do the third and fourth myself.
Answer:
see image
Step-by-step explanation:
see image. We can use the given info and definition of isosceles (congruent sides) and reflexive property (something is congruent to itself) to prove (i) by SSS.
The using "Corresponding Parts of Congruent Triangles are Conguent" (CPCTC) to get more info to prove (ii) by SAS
Devon made a mosaic in art class with different-shaped tiles. She started by putting 2 rows of t triangle tiles at the top of the mosaic and 2 rows of c circle tiles at the bottom. She finished by putting 20 square tiles in between the triangle and circle tiles.
The expressions that represent number of tiles that Devon used on her mosaic:
A. 20 + 2t + 2c
D. 20 + t + t + c + c
What is an expression?An expression refers to a mathematical equation which shows the relationship between two or more numerical quantities or variables.
For the expressions that represent number of tiles that Devon used on her mosaic:
Let the triangle tiles be t.Let the circle tiles be c.Two rows of t triangle tiles = t + t = 2t.Two rows of c circle tiles = c + c = 2t.Mathematically, the expression is given by:
Total tiles = 20 + t + t + c + c
Total tiles = 20 + 2t + 2c.
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Complete Question:
Devon made a mosaic in art class with different-shaped tiles. She started by putting 2 rows of t triangle tiles at the top of the mosaic and 2 rows of c circle tiles at the bottom. She finished by putting 20 square tiles in between the triangle and circle tiles.
Pick all the expressions that represent how many tiles Devon used on her mosaic.
A. 20 + 2t + 2c
B. 20 + 4 ( t + c )
C. 2 ( 20 + t + c )
D. 20 + t + t + c + c
4-5
44
Simplify.
x 43 x 166 4² = 4
응
4-5
44
1
→44x45
=
1
4[?]
Hint: When exponents with the same the
bases are multiplied, add the exponents.
Enter the value that goes in the green box.
Enter
Comparing with the original expression, the value that will go into the green box is 5
Exponents and indicesGiven the indices expression below;
[tex]\frac{4^{-5}}{4^4}[/tex]
Since 4^-5 is equivalent to 1/4^5, hence the given expression will be equivalent to;
[tex]\frac{1}{4^5\times4^4}[/tex]
Comparing with the original expression, the value that will go into the green box is 5
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pls answer both.........
The value of x is 3. The correct option is the third option- 3
The width of the backyard is 9 yards. The correct option is the first option- 9 yards
Perimeter of a RectangleFrom the question, we are to determine the value of x
13.
Perimeter of a rectangle = 2 (l + w)
Where l is the length
and w is the width
From the given information,
Perimeter = 24 cm
In the given diagram,
l = 3x cm
w = 3 cm
Thus,
24 = 2(3x + 3)
24 = 6x + 6
6x = 24 - 6
6x = 18
x = 18/6
x = 3
Hence, the value of x is 3. The correct option is the third option- 3
14.
From the given information,
The width of the yard is 3 less than 4 times the length
That is,
w = 4l - 3 --------- (1)
Also,
Perimeter = 24 yards
∴ 24 = 2(l + w) ---------- (2)
Put equation (1) into (2)
24 = 2(l + w)
24 = 2(l + 4l - 3)
24 = 2(5l - 3)
24 = 10l - 6
10l = 24 + 6
10l = 30
l = 30/10
l = 3 yards
Substitute the value of l into equation (1) to get w
w = 4l - 3
w = 4(3) - 3
w = 12 - 3
w = 9 yards
Hence, the width of the backyard is 9 yards. The correct option is the first option- 9 yards
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The numbers in this chart represent the weights in kilograms of five members of a middle school boys’ baseball team.
Whose record represents an outlier in this data set?
A. Jim’s
B. Tom’s
C. Ben’s
D. John’s
The record that represents an outlier in this data set is John's weight.
What is an outlier?An outlier is a data point that differs significantly from other observations.
In other words, an outlier is a value or point that differs substantially from the rest of the data.
Therefore, the record that represents an outlier in this data set is John's weight. This is because it is on the
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PRE-FINAL REVIEW
LINDA WAS SELLING TICKETS TO THE HOMECOMING GAME
SHE SOLD 15 MORE STUDENT TICKETS THAN FACULTY TICKETS
AND SHE SOLD TWICE AS MANY ALUMI TICKETS AS FACULTY TICKETS.
LET S REPRESENT THE NUMBER OF STUDENT TICKETS
F-FACULTY TICKETS
A-ALUMNI TICKETS
A. WRITE AN EXPRESSION TO REPRESENT THE NUMBER OF STUDENT TICKETS SOLD
BALUMIE TICKETS
SOLD
STUDENT TICKETS COST $5, FACULTY TICKETS COST $2
AND ALUMNI TICKETS COST $10. LINDA MADE $2170.
CWRITE AN EQUATION TO REPRESENT THE TOTAL TICKET SALES.
The equation that can be used to represent total tickets sales is 2170 = 5s + 2f + 10a
Equationlet
Number of students tickets = sNumber of faculty tickets = fNumber of alumni tickets = aExpression for number of students tickets sold;
s = f + 15
Expression for number of faculty tickets sold;
f = 2a
Expression for number of alumni tickets sold;
f = 2a
a = f/2
Cost of students tickets = $5Cost of faculty tickets = $2Cost of Alumni tickets= $10Total revenue = $21702170 = 5s + 2f + 10a
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You have 4 one-dollar bills and 4 five-dollar bills in your piggy bank. You select two bills at random, with replacement. What is the probability you will have selected 2 five-dollar bills? Simplify your answer.
The probability that one would have selected 2 five-dollar bills is; 1/4.
What is the probability you will have selected 2 five-dollar bills?It follows from the task content that the piggy bank contains; 4 one-dollar bills and 4 five-dollar bills to make a total of 8 bills.
Hence, provided the probability events are carried out with replacement, the probability to have selected 2 five-dollar bills is;
= 4/8 × 4/8
= 1/4.
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Answer:
1/4
Step-by-step explanation:
Simplify: ((-3)4)².
The value of the expression ((-3)^4)^2 when simplified is 6561
What are expressions?Expressions are mathematical statements represented by numbers, arithmetic operations and variables
How to simplify the expression?The expression is given as:
((-3)^4)^2
Start by expanding the inner bracket
((-3)^4)^2 = ((-3)*(-3)*(-3)*(-3))^2
Next, we evaluate the product (-3)*(-3)*(-3)*(-3)
This gives
((-3)^4)^2 = (81)^2
Next, expand the exponent
((-3)^4)^2 = (81) * 81
Next, we evaluate the product
This gives
((-3)^4)^2 = 6561
Hence, the value of the expression ((-3)^4)^2 when simplified is 6561
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2. complete the table to summarize each student's conjecture: (2 points: 1 point for each row)
student
conjecture
trey
serena
The statements which summarize each student's conjecture are:
Trey thinks building 4 arch will be a reflection and then a double translation.Serena thinks building 4 arch will be a double reflection. What are the students trying to find out?Trey and Serena are both trying to find the number of stones that were in the original arch or vault. Thus, when they identify the number of stones and its main features, they would be able to determine the type of arch or vault that was built there.
The statements which summarize each student's conjecture are:
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Complete Question:
The Students' Conjectures: During an archeological dig, the students found a voussoir from a semicircular stone arch. A voussoir is a trapezoidal (wedge-shaped) stone used to build an arch or vault.
1. What are the students trying to find out? (1 point)
2. Complete the table to summarize each student's conjecture: (2 points: 1 point for each row)
Answer:
Step-by-step explanation:
Segment AB has point A located at (4, 2). If the distance from A to B is 3 units, which of the following could be used to calculate the coordinates for point B? (5 points) 3 = square root of the quantity of x minus 2 all squared plus y minus 4 all squared 3 = square root of the quantity of x minus 4 all squared plus y minus 2 all squared 3 = square root of the quantity of x plus 2 all squared plus y plus 4 all squared 3 = square root of the quantity of x plus 4 all squared plus y plus 2 all squared
Applying the distance formula, to calculate the coordinates of B, use: 3 =√[(x-4)² + (y-2)²]
What is the Distance Formula?The distance formula, [tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex], is used to find the distance between two points on a coordinate plane.
We are given one point A(4, 2), let:
B (x, y) = (x2, y2)
A(4, 2) = (x1, y1)
d = 3 units
Plug in the values into the distance formula to find how to calculate the coordinates of B:
3 =√[(x-4)² + (y-2)²]
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Which is the equation of a trend line that passes through the points (7, 450) and (14, 401)? y = negative 7 x + 499 y = -1/7x + 451 y = 1/7x +449 y=7x+401
The equation of a trend line that passes through the points (7, 450) and (14, 401) is y = -7x+99.
What is an equation?There are many different ways to define an equation. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions.
More than one variable may be present in a linear equation. An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation.
Points are: (7, 450) and (14, 401)
Slope(m)=(401-450)/(14-7)
= -49/7
= -7
Equation of trend line:
(y-450)= -7(x-7)
y-450= -7x+49
y= -7x+49+450
y= -7x+499
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Please help me with this !!!
Answer:
Step-by-step explanation:
I assume that QP = 18 cm and m∠Q = 72°
Answer:
[tex]\fbox {P = 6.76 cm}[/tex]
Step-by-step explanation:
Finding the missing angle :
22° + ∠R + 72° = 180°∠R = 180° - 94°∠R = 86°Applying the Law of Sines :
[tex]\boxed {\frac{sin P}{P} = \frac{sin R}{PQ}}[/tex]
Substituting the known values :
sin 22° / P = sin 86° / 18P = sin 22° × 18 / sin 86°P = 0.374606593 × 18 / 0.99756405P = 6.76 cmPLEASE HELP AND EXPLAIN!!!
Initially, as x increases, y decreases.
The slope of the graph is equal to 1 for all x between x=0 and x=3.
Starting at x=3, the function value y increases as x increases.
The slope of the graph is equal to 3 for x between x=3 and x=5.
For x between x=0 and x=4, the function value y decreases then increases to 0.
For x between x=4 and x=8, the function value y increases and decreases to 0.
From the graph, initially the it goes down when x increases up-to the x value 3. After that from x value 3 to 5, the graphs goes up. After that from the x value 5 it goes down to zero.
Slope of the line:The slope of the line is the measurement of inclination of that line from the positive x-axis. It can be calculated by the following formula.
[tex]Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
The slope of the graph between x=0 to x=3
[tex]Slope=\frac{-3-0}{3-0}=-1[/tex]
The slope of the graph between x=3 to x=5
[tex]Slope=\frac{3-(-3)}{5-3}=3[/tex]
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Find an equation whose graph is a Parabola with vertex (1, 1) and focus (2, 2).
The matricial equation of the degenerate parabola is [tex]\left[\begin{array}{c}x'\\y'\end{array}\right] = \left[\begin{array}{c}\frac{ \sqrt{2} }{2}\cdot x + \frac{1}{8}\cdot x^{2}+1 \\\-\frac{\sqrt{2}}{2}\cdot x + \frac{1}{8}\cdot x^{2} + 1 \end{array}\right][/tex].
How to determine the equation of a degenerate parabolaA parabola is degenerated when its axis of symmetry is not parallel to any orthogonal axis (i.e. x, y). First, we have to find an "equivalent" parabola whose axis of symmetry is parallel to the y-axis and whose vertex is along that axis.
Direction of the degenerate parabola
[tex]\tan \theta = \frac{2 - 1}{2 - 1}[/tex]
tan θ = 1
θ = 45°
This means that the degenerate parabola must be rotated 45° clockwise (- 45°) around the origin with respect to the "equivalent" parabola.
Distance from the vertex to the focus
[tex]p = \sqrt{(2 - 1)^{2}+(2 - 1)^{2}}[/tex]
[tex]p = \sqrt{2}[/tex]
Vertex of the "equivalent" parabola
[tex](h', k') = (0, \sqrt{2})[/tex]
Equation of the "equivalent" parabola
[tex]y = \frac{1}{4\cdot p}\cdot x^{2} + k'[/tex]
[tex]y = \frac{1}{4\sqrt{2}}\cdot x^{2}+\sqrt{2}[/tex]
Now we apply following rotation formula:
[tex]\left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{cc}\cos (-45^{\circ})&-\sin (-45^{\circ})\\\sin (-45^{\circ})&\cos (-45^{\circ})\end{array}\right] \cdot \left[\begin{array}{c}x\\\frac{1}{4\sqrt{2}}\cdot x^{2}+\sqrt{2}} \end{array}\right][/tex]
[tex]\left[\begin{array}{c}x'\\y'\end{array}\right] = \left[\begin{array}{c}\frac{ \sqrt{2} }{2}\cdot x + \frac{1}{8}\cdot x^{2}+1 \\\-\frac{\sqrt{2}}{2}\cdot x + \frac{1}{8}\cdot x^{2} + 1 \end{array}\right][/tex]
A representation of the degenerate parabola is shown in the figure attached below.
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Which two ratios form a proportion? a) 4 20 and 1 5 b) 4 20 and 2 5 c) 20 4 and 1 5 d) 20 4 and 2 5
A is proportional.
Lets simplify the problem,
← divide numerator/ denominator by 4
= 4/20= 1/5
Thus A form a proportion
≠ 1/5
Thus B is not a proportion
← divide numerator/ denominator by 4
= 2/5 ≠ 1/5
Thus C is not a proportion
5/1 ≠ 1/5
Thus D is not a proportion
A is proportional.
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Which graph represents the function f (x) = StartFraction 1 Over x EndFraction minus 1?
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0, and the horizontal asymptote is at y = 1.
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 0.
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = negative 1, and the horizontal asymptote is at y = 0.
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0, and the horizontal asymptote is at y = negative 1.
Because we have a vertical asymptote at x = 0 and a horizontal asymptote at y = -1, we conclude that the correct option is the last one.
Which graph represents the given function?
Here we have the function:
[tex]f(x) = \frac{1}{x} - 1[/tex]
First notice that we have a vertical asymptote at x = 0, because we can't divide by zero.
Now, notice that when x tends to infinity or negative infinity, the first term becomes zero, then we have a horizontal asymptote at y = -1.
Then the correct option is the last one:
"On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 0, and the horizontal asymptote is at y = negative 1."
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Answer:
Last option
Step-by-step explanation:
The same eight people sit in a certain church pew every week, but not always in the same order. Every week, each person hugs the people immediately to his or her left and right. How many weeks does it take (at a minimum) for every pair of people to hug at least once
It takes 4 weeks at minimum for each pair to hug at least once if they sit in random order.
Analyzing the Given Information
As per the given information,
Number of people = 8
It is given that they sit in random order every week.
W e assume that the order is not repeated.
There are 4 pairs and since a person hugs both the persons on his immediate left and right.
Determining the Number of Weeks
Total number of people to be hugged by each person = 7
Number of people hugged by a person in one week = 2
So, number of weeks taken by each to huge every other person = 7/2
⇒ It will take (3 +1) for every pair to hug.
It takes 4 weeks at a minimum for every pair to hug if we assume that their order is not repeated.
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Determine whether (3, -2) is a solution for the linear system y = 2x - 8 and 2x + 4y = -2
Yes, (3, -2) is a solution for the linear system y = 2x - 8 and 2x + 4y = -2
In mathematics, the theory of linear systems is the foundation and core part of linear algebra, a subject that is used in most parts of modern mathematics. When the number of equations is the same as the number of variables, there is likely to be a solution. Not guaranteed, but likely.
If there is no solution, the equations are called "inconsistent".
One or infinitely many solutions are called "consistent"
In mathematics, a system of linear equations is a set of one or more linear equations involving the same variables
We need to find whether (3, -2) is a solution for the linear system y = 2x - 8 and 2x + 4y = -2 or not
Let y = 2x - 8.......(1)
From equation (1) we get, y - 2x = -8.....(2)
2x + 4y = -2.........(3)
Put (3,-2) in equation (2) , we get
-2 - 2(3) = -2 -6 = -8
LHS = RHS
Put (3,-2) in equation (3) , we get
2(3) + 4(-2) = 6 - 8 = -2
LHS = RHS
Hence,(3, -2) is a solution for the linear system y = 2x - 8 and 2x + 4y = -2
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can someone show me how to do this
The force of a 5.0 kg bowling ball with an acceleration of 3m/s 2 is 15 N.
True or False
Answer:
True
Step-by-step explanation:
We got the formula for that:
F=ma
now if you replace the given data, it's gonna be
F=5 kg×3m/s²====> F=15kg.m/s²
A jar is filled with 50 different colored marbles, 8 of which are red, 20 of which are blue, and 22 of which are green. a player is asked to draw a single marble from the jar and if they draw a red marble they will win $20, if they draw a blue marble they will lose $10, and if they draw a green marble they will lose $5. round your answer to the nearest cent.
The expected value of drawing a marble from the jar is -$0.8.
Given that jar is filled with 50 coloured marbles out of which 8 are red , 20 are blue and 22 are green and we have to find the expected value that a player will get by drawing one marble from the jar if the prize of drawing red marble is $20 and loss of $10 if blue marble is drawn.
Probability that a red marble is drawn from jar=8/50
Probability that a blue marble is drawn from jar=20/50
Probability that a green marble is drawn from jar=22/50
Value that player can expect by drawing a red marble from jar=
=P(X=red)*20-P(X=blue)*10+P(X=green)*0
=8/50*20-20/50*10+0
=16/5-20/5
=-4/5
=-0.8
It is negative ,means that player will not get any money. In fact player will lose $0.8.
Hence the expected value that player can expect is -$0.8.
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Question is incomplete as it should include that calculate the expected value of drawing a marble.
PLEASE HELP ONLY CORRECT ANSWERS ONLY
Answer:
50000
Step-by-step explanation:
Using
[tex]P(percentage) \times CP(cost \: price) = Sales \: Tax[/tex]
Putting the given values
P × 25000 = 1750
[tex]P = \frac{1750}{25000} [/tex]
[tex]P = 0.07 \times 100[/tex]
[tex]P = 7\%[/tex]
Now
For purchase price of a new car.
[tex]P \times CP=Sales \: Tax[/tex]
[tex]7 \times CP = 3500[/tex]
[tex]CP = 50000[/tex]
Hope it helps you, any confusions you may ask!
The soccer team at your school wants to spray paint a design on the middle of the
playing field. The design will include this soccer ball. You have been asked to enlarge the drawing of this ball to use for the painting on the field. Write a brief essay in which you explain how to accurately enlarge or reduce the size of objects
such as the soccer ball. Include the steps that should be taken in order to complete a project like this.
Include scale factor, proportions, dilations, and similarity.
What is the fuction for the graph?
The piecewise defined function is formed by the following three functions: y = 40, for 0 ≤ x < 15, y = 0.0425 · x² - 3.8 · x + 87.438, for 15 ≤ x < 65 and y = 0.4 · x - 6, for x ≥ 65.
What is the piecewise defined function behind the graph?
In this problem we have a piecewise defined function formed by three functions: (i) Linear equation, (ii) Quadratic equation, (iii) Linear equation. The first function is y = 40, for 0 ≤ x < 15.
The second function can be found based on the knowledge of three points:
y = a · x² + b · x + c
(x₁, y₁) = (15, 40)
40 = 225 · a + 15 · b + c
(x₂, y₂) = (45, 2.5)
2.5 = 2025 · a + 45 · b + c
(x₃, y₃) = (65, 20)
20 = 4225 · a + 65 · b + c
And the quadratic equation is y = 0.0425 · x² - 3.8 · x + 87.438, for 15 ≤ x < 65.
And the latter linear equation is:
y = m · x + b
m = (30 - 20)/(90 - 65)
m = 0.4
And the x-intercept is:
b = y - m · x
b = 20 - 0.4 · 65
b = - 6
The linear equation is y = 0.4 · x - 6, for x ≥ 65.
The piecewise defined function is formed by the following three functions: y = 40, for 0 ≤ x < 15, y = 0.0425 · x² - 3.8 · x + 87.438, for 15 ≤ x < 65 and y = 0.4 · x - 6, for x ≥ 65.
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A magazine provided results from a poll of 2000 adults who were asked to identify their favorite pie. Among the 2000 ​respondents, 14​% chose chocolate​ pie, and the margin of error was given as 4 percentage points. Given specific sample​ data, which confidence interval is​ wider: the 90​% confidence interval or the ​80% confidence​ interval? Why is it​ wider?
Between 95% confidence interval and 80% confidence interval, 95% confidence interval is wider than 80% confidence interval.
Given two confidence interval 95% and 80%.
For a given sample data, each confidence interval have different width.
This is because the critical value associated with the confidence level becomes larger as the confidence level is increased which results in an increased interval.
Confidence interval is the range of estimate.
The confidence interval for a population proportion can be found by the following formula:
p±[tex]\sqrt{(pq)/n}[/tex]
The value of z will be wider if the value of p,q are greater.
Hence 95% confidence interval will be wider than 80% confidence interval.
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pls help me out lol
Answer:
Step-by-step explanation:
I'm not entirely sure that this is correct, but it seems so to me from what I've read.
The Coordinate system uses N,S,E,W to denote plus and minus. N (north) and E (east) are plus, and S (south) and W (west) are minus. North is + y and S is - y. E (east is plus x W is minus x)
(4,-7) = 4 east 7 south is what I would use as my answer.
A video game randomly chooses your car color and type. The probability
getting a red car is 0.20, and the probability of getting a convertible is
Event A = You get a red car.
Event B= You get a convertible.
A and B are independent events if
A and B are independent events if the probability of getting a red convertible is 0.08
How to determine the probability?The given parameters are:
P(A) = 0.20
P(B) = 0.40
The events are independent, if
P(A and B) = P(A) * P(B)
So, we have:
P(A and B) = 0.20 * 0.40
Evaluate
P(A and B) = 0.08
Hence, A and B are independent events if the probability of getting a red convertible is 0.08
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Complete question
A video game randomly chooses your car color and type. The probability of getting a red car is 0.20, and the probability of getting a convertible is 0.40.
Event A = You get a red car.
Event B = You get a convertible.
A and B are independent events if _____.
A.The probability of getting a red car or a convertible is 0.60.
B.The probability of getting a red car or a convertible is 0.08.
C.The probability of getting a red convertible is 0
D.The probability of getting a red convertible is 0.08
On a coordinate plane, a curved line with minimum values of (negative 2, 0) and (1.05, negative 41), and a maximum value of (negative 0.5, 5), crosses the x-axis at (negative 2, 0), (0, 0), and (1.5, 0), and crosses the y-axis at (0, 0).
Which statement is true about the end behavior of the graphed function?
As the x-values go to positive infinity, the function’s values go to positive infinity.
As the x-values go to zero, the function’s values go to positive infinity.
As the x-values go to negative infinity, the function’s values are equal to zero.
As the x-values go to negative infinity, the function’s values go to negative infinity.
The statement which is true about the end behaviour of the graphed function is; As the x-values go to positive infinity, the function’s values go to positive infinity.
Which statement is true about the end behaviour of the graphed function?The graph given according to the task content is described to have its first minimum at (-2,0), and then a maximum at; (-0.5, 5) and finally a minimum at; (1.05, -41).
Additionally, since the graph has 3 zeroes as given, it follows that the graph is that of a cubic function which takes the w-form.
Consequently, it can be inferred from the statements above that; As the x-values go to positive infinity, the function’s values go to positive infinity.
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Answer:
A
Step-by-step explanation:
edge 23
Question 13 (2 points)
Is there a value of a such that f(x) = 9x² +4 and g(x) = (3x-a)² are equivalent?
Explain. (show your work).
Answer:
Step-by-step explanation:jneke
There is no such value of 'a' such that f(x) = 9x² + 4 and g(x) = (3x - a)² are equivalent.
What are equivalent polynomials?Two polynomials are said to be equivalent only when the coefficients of all powers of x are equal for both the polynomials.
How to solve the question?In the question, we are asked is there a value of 'a' such that f(x) = 9x² + 4 and g(x) = (3x - a)² are equivalent.
We know that two polynomials are said to be equivalent only when the coefficients of all powers of x are equal for both the polynomials.
Thus to check, we expand g(x), using the formula (p - q)² = p² + q² - 2pq.
g(x) = (3x - a)²,
or, g(x) = (3x)² + (a)² - 2(3x)(a),
or, g(x) = 9x² + a² - 6ax.
For f(x) = 9x² - 4, and g(x) = (3x - a)² to be equivalent,
-6ax should be 0, that is, a should be 0,a² should be 4, that is, a needs to be 2, or -2.As we need two different values of, 'a' at the same time, which ain't possible, thus we can say that there is no such value of 'a' such that f(x) = 9x² + 4 and g(x) = (3x - a)² are equivalent.
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