At the end of the summer, I decide to drain the swimming pool
(which has 1500 gallons of water in it). I noticed that it drains
faster when there is more water in the pool. That was interesting
to me, so I decided to measure the rate at which it drains. I found
that it was draining at a rate of 1% every minute.
How long will it take to empty the pool?

Answers

Answer 1
20% is the answer. 20%

Related Questions

What is the ratio of the length of the rectangle to its width 24 and 20

Answers

6:5 is the ratio
hope this helps!

Shaun climbed Mount Rushmore at a unit rate of
1,250 meters per minute. How long did it take him to
climb 75,000 meters?

Answers

Answer:

60

Step-by-step explanation:

75,000/1,250= 60 mins or an hour

Consider a right triangle ABC where ZC is
the right angle. If sin A = 3/5 and cos A =4/5,
what is cos B?

Answers

Answer:

3/5

Step-by-step explanation:

Triangle A C B is a right triangle. Angle C A B is 90 degrees, angle A B C is (4 x) degrees, and angle A C B is (7 x minus 20) degrees. What is the m∠ACB? 10° 50° 90° 180°

Answers

Answer:

50°

Step-by-step explanation:

The sum of angles in a triangle is 180 degrees

Hence given that in a triangle ACB with angles 90°, 4x°, 7x - 20

As such

90 + 4x + 7x -20 = 180

simplify

11x + 70 = 180

11x = 180 - 70

11x = 110

Divide both sides by 11

x = 110/11

x = 10

m∠ACB is 7x - 20

Substitute the value of x into the expression

= 7(10) - 20

= 70 - 20

= 50

Answer:

The answer is 50 degrees

Step-by-step explanation:

if an angle is three times of its supplement, find the angle​

Answers

Answer:

135° angle

Let the angle be x it's supplement = (180-x)

x = 3 (180-x)

⇒x=540−3x

⇒4x=540⇒x=135°

Step-by-step explanation:

Hope it is helpful....

Harry Potter has a potion that can change voracious vampires into harmless hobbits. But the chemical evaporates over time and when the concentration in the potion is too weak, it turns the vampires into destructive Demogorgons. Oh no! The half-life of the potion means the amount of time it takes for the potion to lose half of its existing power, measured in magical units. This potion has a half-life of 2 months. Which statement about the potion's strength is correct? * a. Of the original 160 magical units, 5 magical units are left after 10 months of mixing the potion. b. Of the original 160 magical units, 16 magical units are left after 10 months of mixing the potion. c. Of the original 160 magical units, less than 1 magical unit is left after 10 months of mixing the potion. d. Of the original 160 magical units, 20 magical units are left after 10 months of mixing the potion e. Of the original 160 magical units, 80 magical units are left after 10 months of mixing the potion.

Answers

Answer:

im going to say c

Step-by-step explanation:

if its has 160 units and goes to half-life after 2 months im assuming it loses 1/2 of the units so in order for it to lose that many it will have to lose 40 units a month so i say its c after 10 months there will be less than 1 unit in the potion

hope this helps im sorry if im wrong have a blessed day :)

I’LL GIVE YOU BRAINLIEST IF YOU ANSWER

Simplify the expression shown

-3√6-3√20-√6

And also please show work and explain how you got the answer!!!


Answers

Answer:

-4√6-6√5

Step-by-step explanation:

-3√6-3√20-√6 = (-3√6-√6)-3√20 = -4√6-3√20

√20 = √4*√5 or 2√5

substitute that in and you get -4√6-3(2√5) which then becomes

-4√6-6√5

Here is my worked out solution to your answer. Hope this helps!

What is the difference of the fractions ? PLZ HELP ONLY HAVE 7 MINS​

Answers

[tex] - 2 \frac{1}{2} - ( - 1 \frac{3}{4} )[/tex]

[tex] - \frac{5}{2} - ( - \frac{7}{4} )[/tex]

[tex] - \frac{10}{4} - ( - \frac{7}{4} )[/tex]

[tex] - \frac{3}{4} [/tex]

How would the average rate of change over years 1 to 5 and years 6 to 10 be affected if the population increased at a rate of 8%?

Answers

Answer:

(A): As year increases the number of pikas reduces.

(B): As year increases the number of pikas increases as opposed to when the rate reduces.

Step-by-step explanation:

See comment for complete question

Given

[tex]a = 144[/tex] --- Initial Population

[tex]r = 8\%[/tex] --- rate

(A) WHEN THE RATE DECREASES

First, we need to write out the function when the population decreases.

This is given as:

[tex]f(x) = a(1-r)^x[/tex]

Substitute values for a and r

[tex]f(x) = 144(1-8\%)^x[/tex]

Convert % to decimal

[tex]f(x) = 144(1-0.08)^x[/tex]

[tex]f(x) = 144(0.92)^x[/tex]

Next, we calculate the average rate of change for both intervals using:

[tex]Rate = \frac{f(b) - f(a)}{b-a}[/tex]

For 1 to 5:

[tex]Rate = \frac{f(5) - f(1)}{5-1}[/tex]

[tex]Rate = \frac{f(5) - f(1)}{4}[/tex]

Calculate f(5) and f(1)

[tex]f(x) = 144(0.92)^x[/tex]

[tex]f(1) = 144*0.92^1 =144*0.92=132.48[/tex]

[tex]f(5) = 144*0.92^5 =144*0.66=95.04[/tex]

[tex]Rate = \frac{95.04 - 132.48 }{4}[/tex]

[tex]Rate = \frac{-37.44}{4}[/tex]

[tex]Rate = -9.36[/tex]

For 6 to 10:

[tex]Rate = \frac{f(10) - f(6)}{10-6}[/tex]

[tex]Rate = \frac{f(10) - f(6)}{4}[/tex]

Calculate f(6) and f(10)

[tex]f(x) = 144(0.92)^x[/tex]

[tex]f(6) = 144*0.92^6 =144*0.61=87.84[/tex]

[tex]f(10) = 144*0.92^{10} =144*0.43=61.92[/tex]

[tex]Rate = \frac{61.92-87.84}{4}[/tex]

[tex]Rate = \frac{-25.92}{4}[/tex]

[tex]Rate = -6.48[/tex]

So, we have:

[tex]Rate = -9.36[/tex] for year 1 to 5

This means that the number of pikas reduces by 9.36 yearly

[tex]Rate = -6.48[/tex] for year 6 to 10

This means that the number of pikas reduces by 6.48 yearly

So, we can say that, as year increases the number of pikas reduces.

(B) WHEN THE RATE INCREASES

First, we need to write out the function when the population decreases.

This is given as:

[tex]f(x) = a(1-r)^x[/tex]

Substitute values for a and r

[tex]f(x) = 144(1+8\%)^x[/tex]

Convert % to decimal

[tex]f(x) = 144(1+0.08)^x[/tex]

[tex]f(x) = 144(1.08)^x[/tex]

Next, we calculate the average rate of change for both intervals using:

[tex]Rate = \frac{f(b) - f(a)}{b-a}[/tex]

For 1 to 5:

[tex]Rate = \frac{f(5) - f(1)}{5-1}[/tex]

[tex]Rate = \frac{f(5) - f(1)}{4}[/tex]

Calculate f(5) and f(1)

[tex]f(x) = 144(1.08)^x[/tex]

[tex]f(1) = 144(1.08)^1 = 144*1.08= 155.52[/tex]

[tex]f(5) = 144(1.08)^5 = 144*1.47= 211.68[/tex]

[tex]Rate = \frac{211.68 - 155.52}{4}[/tex]

[tex]Rate = \frac{56.16}{4}[/tex]

[tex]Rate = 14.04[/tex]

For 6 to 10:

[tex]Rate = \frac{f(10) - f(6)}{10-6}[/tex]

[tex]Rate = \frac{f(10) - f(6)}{4}[/tex]

Calculate f(6) and f(10)

[tex]f(x) = 144(1.08)^x[/tex]

[tex]f(6) = 144(1.08)^6 = 228.52[/tex]

[tex]f(10) = 144(1.08)^{10} = 310.89[/tex]

[tex]Rate = \frac{310.89-228.52}{4}[/tex]

[tex]Rate = \frac{82.37}{4}[/tex]

[tex]Rate = 20.59[/tex]

So, we have:

[tex]Rate = 14.04[/tex] for year 1 to 5

This means that the number of pikas increases by 14.04 yearly

[tex]Rate = 20.59[/tex] for year 6 to 10

This means that the number of pikas increases by 20.59 yearly

So, we can say that, as year increases the number of pikas increases as opposed to when the rate reduces.

can someone help solve/understand this?? plzzzz

Answers

Answer:

[tex]y = 4(0.5) {}^{x} [/tex]

Step-by-step explanation:

By looking at your graph, The y intercept is (0,4).

This is an exponential function so it is represented by

[tex]y = ab {}^{x} [/tex]

where a is the vertical stretched and b is the constant rate and x is the nth power.

let plug in 0,4

[tex]4 = ab {}^{0} [/tex]

[tex]b {}^{0} = 1[/tex]

since anything to the 0 power is 1.

[tex]4 = a \times 1[/tex]

[tex]4 = a[/tex]

Know let plug it in to this equation.

[tex]y = 4b {}^{x} [/tex]

Let use 2,1 another point on the graph

[tex]1 = 4b {}^{2} [/tex]

Divide 4 by both sides

[tex]0.25 = {b}^{2} [/tex]

take sqr root of 0.25

[tex]0.5 = b[/tex]

So

the answer is

[tex]y = 4(0.5) {}^{x} [/tex]

HELP ME PLEASEEEE!!!!ORDER THESE BY VALUE FROM LEAST TO GREATEST!!!

Answers

Answer: 5,15,20,25,45

Step-by-step explanation:

1st is 20, 2nd is 25, 3rd is 15, 4th is 45, 5th is 5

I am in need of help

Answers

Answer:

I would say the answer is D because the figure is rotated 180 degrees. Letters C and D are pretty much the same just with some differences, but I would say D. Let me know if it's wrong :)

Step-by-step explanation:

solve the equation for x in simplest form
2 / 3x = 1/6
A x= 1/4
B x= 3/5
C x=1/2
D= x=4/5

Answers

Answer:

A x=1/4

Step-by-step explanation:

2/3x = 1/6

Divide by 2/3

so 1/6 ÷ 2/3

= 1/6 • 3/2

= 3/12

= 1/4

The wrestling team wants to sell pies for a fundraiser. The cafeteria helped out by donating 2 pies. Each pie will be cut into 4 pieces. If the team wants to sell at least 32 pieces, how many pies must the wrestling team bake?
50 pts if they can pout how they solved it and the answer in an inequality form

Answers

Answer:

answer is

Step-by-step explanation:

2+4=6

and 6-32=26 answer

3 = 2 + n/4(that's supposed to be a fraction)someone help solve solve for n​

Answers

Answer:

n = 4

Step-by-step explanation:

3 = 2 + n/4

1 = n/4

4 = n

Answer:

n = 4

Step-by-step explanation:

take the 2 and subtract it from itself then you gotta do it to the other side so it be 3 -2 and you get 1 then you multiply 4 to n/4 and it crosses it out and what you do to one side you do to the other so you multiply 4 by 1 & get 4

-9 = 4n - 1
PLS PLS HELP I can't think my brain isn't there anymore.

Answers

Answer:

-2

Step-by-step explanation:

-9=4n-1

4n=-9+1

4n=-8

n=-8/4

n=-2

Answer:

x= -2

Step-by-step explanation:

you add 1 to both sides

-9+1=4n-1+1

which gives you

-8=4n

and then divide both sides by 4

-2=n

what’s a non example of a slope

Answers

Answer:

a leveled line or a straight line

The length of a rectangle is three more than twice it’s width. the area of the rectangle is 189 in^2

What is the width
What is the length

Answers

Answer:

Let w be the width of the rectangle. The length would be 2w+3. The area of the rectangle would be w(2w+3)=189.

So 2w2+3w-189=0 Solving for w you get w=9 or -10.5. Ignoring negative value Width of the rectangle would be 9mm and length of the rectangle would be 21mm giving you the area 189 square mm.

Hope this helps:)

i dont get this pls help with steps asap!

Answers

Answer:

2.5

Step-by-step explanation:

it's the midpoint of XZ

2.5 is the correct answer

Graph the following Line:
6x+3y=6

Answers

Answer:

Visit geogebra.com

Step-by-step explanation:

none needed <3

use y=mx +b=slope

this will help you get your answer

How many 7/9 cups servings are in 2/9 cups of juice?!?

Answers

Answer:

3

Step-by-step explanation:

I'm going to assume you meant "How many 2/9 cup serving are in 7/9 cup of juice" (since there are no 7/9 cups of serving in 2/9 cups of juice, since 7/9>2/9, and you can't have a serving of something greater than the amount you have).

In this case:

7/9 divided by 2/9=3

Since 7/9 and 2/9 have the same denominater, you can cross them off, since when you divide them, 9 divided by 9=1. 7 divided by 2=3.5, but I'll assume you want full cups.

The sum of five consecutive integers is 0. Find the integers. Show your solution.
Does anyone know the answer? ​

Answers

Answer:

-2, -1, 0, 1, 2.

Solution

Let x be the middle term of this sequence of 5 terms.

Then the sequence is x-2, x-1, x, x+1, x+2.

The sum of the terms is (x-2) + (x-1) + x + (x+1) + (x+2) = 5x.

Thus 5x = 0.

It gives x = 0.

So the sequence is -2, -1, 0, 1, 2.

jjjjjjjjjjjjjjjjjjjhhhhhhhhhhhhhhhhbvvvvvvvvvvvvvvvvvvvvv

Answers

Answer:

Thanks for the point!

Step-by-step explanation:

Have a great day

Which whole numbers does the square root of 104 falls in between?

Answers

Answer:

10 and 11

Step-by-step explanation:

The square root of 104 is 10.1980390272. This falls between the whole numbers 10 and 11.

Lines a and b are horizontal and parallel to each other. Line a contains points L and M and line b contains points O and N. Line c is diagonal and intersects line a at point X and line b and point Z. It also contains points H and G. Line d is diagonal and intersects line a at point X and line b at point Y. It also contains points J and K. Triangle X Y Z is created by the lines. Which represents an exterior angle of triangle XYZ? ∠LXZ ∠JXM ∠JXZ ∠HXJ

Answers

Answer:

The exterior angle of triangle XYZ is;

∠JXM

Step-by-step explanation:

The question is a word problem with the given parameters;

The points on line 'a' = L and M

The points on line 'b' = O and N

The point line 'c' intersect line 'a' = X

The point line 'c' intersect line 'b' = Z

The points on line 'c' = H and G

The point line 'd' intersect line 'a' = X

The point line 'd' intersect line 'b' = Y

The points on line 'd' = J and K

From the drawing of triangle XYZ created with Microsoft Visio, the exterior angle is ∠JXM

Answer:

Step-by-step explanation:

the answer is JXZ

what is the answer to this 10x - 25 + 8

Answers

[tex]10x-25+8[/tex]

Simplify:

[tex]10x+-25+8[/tex]

Combine Like Terms:

[tex](10x)+(-25+8)\\10x+-17(ANSWER)[/tex]

Microsoft Rewards

Earn Gift Cards using Microsoft Rewards by searching daily and completing daily tasks.

What is the value of x? ​

Answers

If you use the Pythagorean Theorem you would get 11.662.

HELP MEEEE I NEED AN ANSWER ​

Answers

I believe b and c don’t have a solution

10.04 × 8.8= ?

can you help me again please​

Answers

Answer:

10.04 × 8.8 =?, ? = 88.352 :)

Answer:

88.352

Step-by-step explanation:

10.04

x. 8.8

=88.352

Solve the linear equation.
2.25 - 11j - 7.75 + 1.5j = 0.5j - 1
A. j = -0.45
B. j = -0.25
C. j = 0.25
D. j = 0.45

Answers

A. The end equation is -10j=4.5 so you would need a negative answer to make the negative ten a positive and matching 4.5

Answer:

Solve the linear equation [tex]2.25 - 11 - 7.75 + 1.5j= 0.5j - 1[/tex]

[tex]j[/tex] = –0.45

[tex]j[/tex]  = –0.25

[tex]j[/tex] = 0.25

[tex]j[/tex] = 0.45

Simplify [tex]2.25 - 11j - 7.75 + 1.5j[/tex] .

Subtract [tex]7.75[/tex] from [tex]2.25[/tex] .

[tex]- 11j - 5.5 + 1.5j = 0.5j -1[/tex]

Add [tex]-11j[/tex] and [tex]1.5j[/tex] .

[tex]- 9.5j - 5.5 = 0.5j - 1[/tex]

Move all terms containing [tex]j[/tex] to the left side of the equation.

Subtract [tex]0.5j[/tex] from both sides of the equation.

[tex]- 9.5j - 5.5 = 0.5j - 1[/tex]

Subtract [tex]0.5j[/tex] from [tex]- 9.5j[/tex].

[tex]- 10j - 5.5 = - 1[/tex]

Move all terms not containing [tex]j[/tex] to the right side of the equation.

Add [tex]5.5[/tex] to both sides of the equation.

[tex]-10j = -1 +5.5[/tex]

Add [tex]-1[/tex] and [tex]5.5[/tex] .

[tex]10j=4.5[/tex]

Divide each term in [tex]-10[/tex][tex]j[/tex] [tex]=4.5[/tex] by [tex]-10[/tex] and simplify.

Divide each term in [tex]-10j = 4.5[/tex] by [tex]-10[/tex].

[tex]\frac{-10j}{-10} = \frac{4.5}{-10}[/tex]

Simplify the left side.

Cancel the common factor of [tex]-10[/tex].

[tex]j= \frac{4.5}{-10}[/tex]

Cancel the common factor.

[tex]\frac{-10j }{-10} = \frac{4.5}{-10}[/tex]

Divide [tex]j[/tex] by [tex]1[/tex]

[tex]j=\frac{4.5}{-10}[/tex]

Simplify the right side.

Divide [tex]4.5[/tex] by [tex]-10[/tex].

[tex]j=-4.5[/tex]

The Final Answer is

[tex]j=-4.5[/tex]

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Keisha bought a new pair of skis for $450 She put $120 down and got a student discount for $45. Her mother gave her 1/2 of the balance for her birthday. Which of these expressions could be used to find the amount Keisha still owes on the skis?A: 450 - 120+45/2B: {450-(120-45)/2C: 450-(120-45)/2D: {450-(120-45)} / 2 what volume (ml) of 0.385m potassium permanganate (molar mass = 158 g/mol) contains 0.49 grams of the solute? Each day, a FedEx competitor processes approximately 70,000 shipments. 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For private pilot operations, a second-class medical certificate issued to a 42-year-old pilot on July 15, 2018, will expire at midnight on A - July 31, 2019. B - July 15, 2020, C- July 31, 2020. a chart of a family's history with regard to a particular trait, in which males are designated by squares and females by circles, is a ____. Given the arithmetic sequence a(n)=2n-3,what is the sum of the third and tenth terms? The vertical distance between ATC and AVC is equal to TVC AFC TFC Soccer Team Score ApplicationSuppose a soccer team needs an application to record the number of points scored by its players during a game. Create an application that asks how many players the team has, and then asks for the names of each player. The program should declare an array of strings large enough to hold the number of points scored by each player. The application should have a menu system or buttons that perform the following:1. Display a form that allows the user to enter the player's names.2. Display a form that can be used during a game to record the points scored by each player.3. Display the total points scored by each player and by the teamINPUT VALIDATION: dO NOT ACCEPT NEGATIVE NUMBERS AS POINTS.ObjectivesCreate single arrays.Dynamically resize arrays o Search arrays.Utilize parallel arrays.SituationThe Soccer Team Score Keeping program is an adaptation of the "Question 11: Soccer Team Score Application" program that is on page 571 of the textbook. You will use only menu options only. No buttons to be used. The names entered by the user should be displayed on the form in a list box or combo box in addition to storing it in the array. Include in the menu a menu option "About" which when clicked, displays an About Box that displays the Application name, a brief description of the application and the programmer name.Specifications1. Recurring Specifications that are required for all programs.1. The form must be renamed and the text changed to PhoneLookup by YourFirstName YourLastName. (If Pat Programmer was creating this program, it would be Soccer Score Keeper by Pat Programmer)2. Code must be grouped and commented in compliance with this course's programming standards.3. ALL files, forms, and controls MUST be renamed.4. Option Strict and Option Explicit must be ON5. An AcceptButton and a CancelButton must be assigned appropriately.6. ALL controls on the form must be in logical TabOrder.7. All buttons and labels (before TextBoxes) must have AccessKeys.8. Form's StartPosition property must be CenterScreen.9. The text property of Labels must be changed so that Label1 (or similar name) does not appear at runtime.10. No class level variables unless specifically allowed.11. Data types for variables and constants must be the most efficient.12. Use With. End With if and when appropriate.13. ToolTips2. Create 2 global arrays in the Main Module. They will be two single dimensional arrays to hold the names and scores. These arrays will be parallel. In other words the name array element with an index of 0 will hold the name and the score array element with an index of 0 will hold the score for the first player.3. When retrieving the scores of a player, the SelectedIndex property of the Combo Box can be used to retrieve parallel array items. In this way the number of lines of code can be reduced. Example Since this was not specifically in the text here is an sample where strNames() is the name of the array: intScore= intPlayerScores(cboNames.SelectedIndex)4. For the About menu option, include an About Box that was created using the AboutBox template. The fields on the form must be customized for this program to display the Application name ("Soccer Team Score Keeping" ), a brief description of the application and the programmer name.