To fulfill all of the orders, they must pay their employees a total of $9600 as 480 * 20 = $9600 .
what is unitary method ?This unit technique is a way of problem-solving that entails calculating the value of a specific unit, multiplying that value, and then calculating the required value. To put it simply, the unit method is used to extract a single model value from a specified multiple. One pen costs 400 rupees, thus 40 pens would cost 400 rupees. There might be a regular procedure for doing this out. merely one nation. anything containing a distinctive component. Mechanics of matrices or operators, abstract algebra, mathematical analysis, and its adjoint and reciprocal are all equivalent.
given
Each employee is paid $12 per hour for the first 40 hours,
therefore $480 must be paid to all of their employees in order to fulfill all orders (20 * 3 = 60 days for 20 automobiles
, or 5 employees working 8 hours per day).
480 * 20 = $9600
To fulfill all of the orders, they must pay their employees a total of $9600.
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Shayla is 3 years older than Todd. If t represents Todd’s age, which expression represents Shayla’s age?
Answer:
t + 3
Step-by-step explanation:
adding 3 years onto t amount of years
If y = square root 81, what is the value of y?
Complete the solution of the equation. Find
the value of y when x equals 4.
-3x + 9y = -57
Answer: -5
Step-by-step explanation:
-3x+9y=-57 x=4
-3(4)+9y=-57
-12+9y=-57
+12
9y=-45
9y
y=-5
Find the recursive rule for the following sequence. -3, 2, 7, 12, 17,
Answer:
+5
Step-by-step explanation:
There is a length of 5 between all numbers, meaning that 5 is added to each number to get the next one.
I hope this helps!
Find the measure of side a.
A = _ m
Instructions: Given the vertex, fill in the vertex form of the quadratic function..
Vertex: (2,-6)
Answer:
[tex]\implies y=(x-2)^2-6[/tex]
Step-by-step explanation:
Vertex form of a quadratic equation:
[tex]y=a(x-h)^2+k[/tex]
where:
(h, k) is the vertexa is some constantGiven vertex: (2, -6)
⇒ h = 2 and k = -6
Substitute the values of h and k into the formula:
[tex]\implies y=a(x-2)^2+(-6)[/tex]
[tex]\implies y=a(x-2)^2-6[/tex]
As we have not been given a value for the constant [tex]a[/tex], assume this is 1.
Therefore, the vertex form of the quadratic function with vertex (2, -6) is:
[tex]y=(x-2)^2-6[/tex]
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Vertex form
y=a(x-h)²+ka=1
Put values
y=(x-2)²-6The weight of toys a toddler owns has a population mean of 15.8kg and a population standard deviation of 4.2kg. What is the probability a toy store owner could select a sample of 49 toddlers and find the sample mean to be
(a) 15.1kg or less? (answer?)
(b) 15.1kg or more? (answer?)
Leave all answers to 4 decimal places.
The weight of toys a toddler owns has a population mean of 15.8kg and a population standard deviation of 4.2kg. then the probability a toy store owner could select a sample of 49 toddlers and find the sample mean to be 15.1kg or less is 0.121 and 15.1kg or more is 0.879.
Given Information:
Population mean, μ = 15.8 kg
Population standard deviation, σ = 4.2 kg
For finding the probability for the sample mean, we first need to find the standard score.
(a) For sample mean to be 15.1kg or less,
z = (x - μ) / (σ/√n)
Here, x = 15.1
⇒ z = (15.1 - 15.8) / (4.2/√49
z =-0.7 / (4.2/7)
z = -1.17
Now, we can use the z-table to find the probability of the sample mean to be 15.1kg or less.
∴ P(x ≤ 15.1) = 0.121
(b) Now, to find the probability of sample mean to be 15.1kg or more, we can simply subtract P(x ≤ 15.1) from 1.
⇒ P(x ≥ 15.1) = 1 - P(x ≤ 15.1)
P(x ≥ 15.1) = 1 - 0.121
P(x ≥ 15.1) = 0.879
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An individual is planning a trip to a baseball game for 15 people. Of the people planning to go to the baseball game, 10 can go on Saturday and 12 can go on Sunday, some of them can go on both days. How many people can only go to the game on Sunday?
The number of people who can go to the game only on Sunday by applying the concept of set theory is equal to 5.
Total number of people for a trip to a baseball game = 15
Number of people planning to go on Saturday = 10
Number of people planning to go Sunday = 12
Let x be the number of people who can go on both Saturday and Sunday.
Then, the number of people who can go only on Saturday is 10 - x.
And the number of people who can go only on Sunday is 12 - x.
Total of 15 people are going to the baseball game.
Using set theory we have,
Number of people going on Saturday only + number of people going on Sunday only + number of people going on both = 15
Substitute the value we have,
⇒(10 - x) + (12 - x) + x = 15
Simplifying the above equation, we get,
⇒22 - x = 15
⇒ x = 7
The number of people who can only go to the game on Sunday is
= 12 - x
= 12 - 7
= 5
Therefore, using set theory number of people can only go to the game on Sunday is equal to 5 .
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None of the pots in the kitchen have a lid.
For each statement below, determine whether it is a negation
All pots in the kitchen have a lid.
Not every pot in the kitchen has a lid.
At least one pot in the kitchen has a lid.
Some pots in the kitchen have a lid.
Yes
No
O
O
The first three statements are not a negation. Only the last statement is a negation.
What is negation?The opposite of the given mathematical statement is the negation of a statement in mathematics. If "P" is a statement, then "P" is the statement's negation. The words negation is used to denote a statement's denial.
It's vital to know the opposite of a given mathematical statement from time to time in mathematics. This practice is known as "negating" a statement. Remember that if a statement is true, then its negation must be false (and if a statement is false, then its negation is true).
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add the different of 9/16 and 5/4
Adding the difference between [tex]$\frac{9}{16}[/tex] and [tex]$\frac{5}{4}[/tex] we get [tex]$1 \frac{13}{16}[/tex].
How to estimate the sum of 9/16 and 5/4?Find the least common denominator or LCM of the two denominators:
LCM of 4 and 16 exist 16.
Subsequently, estimate the equivalent fraction of both fractional numbers with denominator 16.
For the 1st fraction, since 16 × 1 = 16,
9/16 = (9 × 1) / (16 × 1) = 9/16
For the 2nd fraction, since 4 × 4 = 16,
5/4 = (5 × 4) / (4 × 4) = 20/16
Add the two like fractions, then we get
(20/16) + (9/16) = (20 + 9)/16 = 29/16
So, [tex]$\frac{5}{4}+\frac{9}{16} =\frac{29}{16}[/tex]
In mixed form: [tex]$1 \frac{13}{16}[/tex].
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Use the drawing tool(s) to form the correct answer on the provided graph. Graph the solution to this system of inequalities in the coordinate plane. 3y> 2x+122x+y < -5
Thank you in advance!
The solution to the system of inequalities is (-3.375, 1.75)
How to graph the inequalities?The system of inequalities is given as:
3y > 2x+12
2x+y < -5
Next, we plot the graph of the system using a graphing tool
From the graph, both inequalities intersect at
(-3.375, 1.75)
Hence, the solution to the system of inequalities is (-3.375, 1.75)
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Each container must hold exactly 1 litre of water Each container must have a minimum surface area
The containers must be spheres of radius = 6.2cm
How to minimize the surface area for the containers?
We know that the shape that minimizes the area for a fixed volume is the sphere.
Here, we want to get spheres of a volume of 1 liter. Where:
1 L = 1000 cm³
And remember that the volume of a sphere of radius R is:
[tex]V = \frac{4}{3}*3.14*R^3[/tex]
Then we must solve:
[tex]V = \frac{4}{3}*3.14*R^3 = 1000cm^3\\\\R =\sqrt[3]{ (1000cm^3*\frac{3}{4*3.14} )} = 6.2cm[/tex]
The containers must be spheres of radius = 6.2cm
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From atop a 15 m lighthouse, a man spots a dolphin 50 m out to sea. Find the angle of depression from the man to the dolphin, to nearest degree.
Answer:
16.7 degrees
Step-by-step explanation:
NEED HELP!20 points find the area.
Answer:
80 square units
Step-by-step explanation:
These are rectangles and triangles.
The formula to get the area of a rectangle is its length multiplied by its width.
The formula to get the area triangle is its base multiplied by its height, then divided by 2.
Step 1: Rectangle areaThe 3 rectangles all share the width of 6 units, so we can combine the 3 rectangles and consider it as 1 large rectangle.
The lengths of the rectangles are 2, 8, and 2 units.
We can add them together to get a total height of 12 units.
So, the formula to get the area of this rectangle is:
[tex]6\times12= A[/tex]
By solving this, we get:
A = 72 square units
There are 4 triangles remaining.
The base and height of all the triangles are 2 units.
So, by plugging these values into the triangle area formula, as mentioned from the beginning, we get:
[tex](2\times2)\div2=A[/tex]
So, the area of 1 triangle is 2 square units.
But since there are 4 triangles with the same bases and heights, we will multiply the area of 1 triangle by 4.
So, [tex]4 \times 2 = A[/tex]
This means the area of all the triangles together is 8 square units.
Step 3: Total areaBy adding the area of the triangles and rectangles together, we will get the answer.
[tex]72+8 = A[/tex]
So, the total area of this box is 80 square units.
PLEASE HELP WORTH 14 POINTS!
Answer:
180°
cuz when a line (I forgot the name) and radius meet at the circumference they from an angle of 90°
4. G.CO.10 In the figure below, p ll q. What is the value of x? *
O A. 7
B. 68
C. 59
OD. 44
136
121
The measure of the angle x is 77 degrees if two lines are parallel to each other or p ll q option (A) is correct.
What is a perpendicular line?Lines that intersect at a right angle are named perpendicular lines. Lines that are always the same distance apart from each other are known as parallel lines.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have two lines that are parallel to each other or p ll q
The angle made by transversal t is 136 degrees
The measure of the other angle = 180 - 136 = 44 degrees
Draw a line parallel to p and q and passes through the intersection point of line t and v
The angle made by the transversal and the line drawn is the same as 44 degrees.
The measure of the other angle = 121 - 44 = 77 degrees
Thus, the measure of the angle x is 77 degrees if two lines are parallel to each other or p ll q option (A) is correct.
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Jed wants to prove that his test scores are greatly improving. He makes the graph shown here.
Explain why someone may think this graph is misleading.
Someone may think this graph is misleading because it does not start from the origin
How to determine the reason?As a general rule, graphs are to begin from the origin
The origin of a graph is
(x, y) = (0, 0)
From the given graph, the origin is
(x, y) = (0, 60)
This means that someone may think this graph is misleading because it does not start from the origin
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suppose you are conducting a survey about the amount grocery store baggers are tipped for helping customers to their cars .for a similar simulated population with 50 respondents the population mean is $1.73 and the standard deviation is $0.657
about 68% of the sample mean fall with in the intervals $_______ and $________
about 99.7% of the sample mean fall with in the intervals of $-------- and $
Using the Empirical Rule and the Central Limit Theorem, we have that:
About 68% of the sample mean fall with in the intervals $1.64 and $1.82.About 99.7% of the sample mean fall with in the intervals $1.46 and $2.What does the Empirical Rule state?It states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.Approximately 95% of the measures are within 2 standard deviations of the mean.Approximately 99.7% of the measures are within 3 standard deviations of the mean.What does the Central Limit Theorem state?By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
In this problem, the standard deviation of the distribution of sample means is:
[tex]s = \frac{0.657}{\sqrt{50}} = 0.09[/tex]
68% of the means are within 1 standard deviation of the mean, hence the bounds are:
1.73 - 0.09 = $1.64.1.73 + 0.09 = $1.82.99.7% of the means are within 3 standard deviations of the mean, hence the bounds are:
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Answer:
About 68% of the sample means fall within the interval $1.64 and $1.82.
About 99.7% of the sample means fall within the interval $1.45 and $2.01.
Step-by-step explanation:
To verify the given intervals, we need to calculate the standard error of the mean (SE) for a sample size of 50 using the population mean and standard deviation provided.
The standard error of the mean (SE) can be calculated as:
SE = population standard deviation / √(sample size)
Given that the population mean is $1.73 and the population standard deviation is $0.657, and the sample size is 50:
SE = $0.657 / √50 ≈ $0.09299 (rounded to 5 decimal places)
Now, we can calculate the intervals:
For the interval where about 68% of the sample means fall:
Interval = (Mean - 1 * SE, Mean + 1 * SE)
Interval = ($1.73 - $0.09299, $1.73 + $0.09299)
Interval ≈ ($1.63701, $1.82299)
So, about 68% of the sample means fall within the interval $1.64 and $1.82, which matches the given statement.
For the interval where about 99.7% of the sample means fall:
Interval = (Mean - 3 * SE, Mean + 3 * SE)
Interval = ($1.73 - 3 * $0.09299, $1.73 + 3 * $0.09299)
Interval ≈ ($1.54703, $1.91297)
So, about 99.7% of the sample means fall within the interval $1.55 and $1.91, which is different from the given statement.
The correct interval for about 99.7% of the sample means, rounded to the nearest hundredth, is $1.55 and $1.91, not $1.45 and $2.01 as mentioned in the statement.
A store is selling two mixtures of nuts in 20-ounce bags. The first mixture has 15 ounces of peanuts combined with five ounces of cashews, and costs $4.75. The second mixture has five ounces of peanuts and 15 ounces of cashews, and costs $6.25. How much does one ounce of peanuts and one ounce of cashews cost?
The cost of one ounce of peanuts is $0.20
The cost of one ounce of cashew is $0.35
What are the linear equations that represent the question?15p + 5c = 4.75 equation 1
5p + 15c = 6.25 equation 2
Where:
p = cost of one ounce of peanutsc = cost of one ounce of cashewWhat is the cost of one ounce of peanut and cashew?Multiply equation 2 by 3
15p + 45c = 18.75 equation 3
Subtract equation 1 from equation 3
40c = 14
c = 14/40
c = $0.35
Substitute for c in equation 1
15p + (5 x 0.35) = $4.75
15p + 1.75 = 4.75
15p = 4.75 - 1.75
15p = 3
p = 3/15
p = $0.20
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25 mice were involved in a biology experiment involving exposure to chemicals found in ciggarette smoke. 15 developed at least 1 tumor, 9 suffered re[iratory failure, and 4 suffered from tumors and had respiratory failure
The number of mice that didn't get a tumor is 9 mice out of the 25 mice.
How to know how many mice didn't have a tumor?Identify the total mice who did not have any effects or the effects did not include a tumor.
Repiratory failure: 9 mice
Based on this, it can be concluded 9 mice did not have a tumor, while 21 mice hat at least a tumor and some of them had a tumor and respiratory failure.
Note: This question is incomplete; here is the missing section:
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4. (a)(i)Show that log4x=2log16x. (ii)Show that log x=3logb³ x. (iii) Show that log₂x=(1+log₂3)logix.
that log4x=2log16x. (ii)Show that log x=3logb³ x. (iii) Show that log₂x=(1+log₂3)logix
A company is reviewing a batch of 28 products to determine if any are defective. On average,3.2 of products are defective.
What is the probability that the company will find 2 or fewer defective products in this batch?
What is the probability that 4 or more defective products are found in this batch?
If the company finds 5 defective products in this batch, should the company stop production?
Using the Poisson distribution, it is found that:
There is a 0.3799 = 37.99% probability that the company will find 2 or fewer defective products in this batch.There is a 0.3975 = 39.75% probability that 4 or more defective products are found in this batch.Since [tex]P(X \geq 5) > 0.05[/tex], the company should not stop production it there are 5 defectives in a batch.What is the Poisson distribution?In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
The parameters are:
x is the number of successese = 2.71828 is the Euler number[tex]\mu[/tex] is the mean in the given interval.In this problem, the mean is:
[tex]\mu = 3.2[/tex]
The probability that the company will find 2 or fewer defective products in this batch is:
[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]
In which:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-3.2}3.2^{0}}{(0)!} = 0.0408[/tex]
[tex]P(X = 1) = \frac{e^{-3.2}3.2^{1}}{(1)!} = 0.1304[/tex]
[tex]P(X = 2) = \frac{e^{-3.2}3.2^{2}}{(2)!} = 0.2087[/tex]
Then:
[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0408 + 0.1304 + 0.2087 = 0.3799[/tex]
There is a 0.3799 = 37.99% probability that the company will find 2 or fewer defective products in this batch.
The probability that 4 or more defective products are found in this batch is:
[tex]P(X \geq 4) = 1 - P(X < 4)[/tex]
In which:
P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3).
Then:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-3.2}3.2^{0}}{(0)!} = 0.0408[/tex]
[tex]P(X = 1) = \frac{e^{-3.2}3.2^{1}}{(1)!} = 0.1304[/tex]
[tex]P(X = 2) = \frac{e^{-3.2}3.2^{2}}{(2)!} = 0.2087[/tex]
[tex]P(X = 3) = \frac{e^{-3.2}3.2^{3}}{(3)!} = 0.2226[/tex]
P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0408 + 0.1304 + 0.2087 + 0.2226 = 0.6025
[tex]P(X \geq 4) = 1 - P(X < 4) = 1 - 0.6025 = 0.3975[/tex]
There is a 0.3975 = 39.75% probability that 4 or more defective products are found in this batch.
For 5 or more, the probability is:
[tex]P(X \geq 5) = 1 - P(X < 5)[/tex]
In which:
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).
Then:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-3.2}3.2^{0}}{(0)!} = 0.0408[/tex]
[tex]P(X = 1) = \frac{e^{-3.2}3.2^{1}}{(1)!} = 0.1304[/tex]
[tex]P(X = 2) = \frac{e^{-3.2}3.2^{2}}{(2)!} = 0.2087[/tex]
[tex]P(X = 3) = \frac{e^{-3.2}3.2^{3}}{(3)!} = 0.2226[/tex]
[tex]P(X = 4) = \frac{e^{-3.2}3.2^{4}}{(4)!} = 0.1781[/tex]
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0408 + 0.1304 + 0.2087 + 0.2226 + 0.1781 = 0.7806
[tex]P(X \geq 5) = 1 - P(X < 5) = 1 - 0.7806 = 0.2194[/tex]
Since [tex]P(X \geq 5) > 0.05[/tex], the company should not stop production it there are 5 defectives in a batch.
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15v - 2v + 29 = 5v - 27
Answer:
v=-7
Step-by-step explanation:
13v-5v=-27-29
8v=-56
v=-56/8=-7
One solution to the problem below is 3.
What is the other solution?
b²-9=0
By algebra, if one solution for the second order polynomial b² - 9 = 0 is 3, then the other solution to the expression is - 3.
How to find the remaining root of second order polynomial
Herein we have a quadratic equation, that is, a second order polynomial, of the form b² - a² = 0. By algebra we know that the polynomial of such form have the following equivalence:
b² - a² = (b - a) · (b + a), which means that the roots of the interval are x₁ = a and x₂ = - a.
If we know that a² = 9, then the roots of the second order polynomial are:
b² - 9 = (b - 3) · (b + 3)
By algebra, if one solution for the second order polynomial b² - 9 = 0 is 3, then the other solution to the expression is - 3.
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I have tried finding the answer for this but 1.4 or anything like that is wrong and i dont know why, what is 2.1 / 1.488, and then rounded to the nearest tenth.
After rounding to the nearest tenth, we get:
[tex]\frac{2.1}{1.488} = 1.5[/tex]
How to get the quotient?We have the quotient:
[tex]\frac{2.1}{1.488}[/tex]
If you multiply the numerator and denominator by 1000, you will get the simpler quotient:
[tex]\frac{2100}{1488}[/tex]
It gives:
[tex]\frac{2100}{1488} = 1.45[/tex]
Now we want to round it to the nearest tenth, which is the first digit after the decimal point.
To do so, we need to look at the number at the right of it.
If is between 0 and 4, then we round down.If it is between 5 and 9, we round up.In this case, we can see a 5, so we should round up, then we have:
[tex]\frac{2100}{1488} = 1.5[/tex]
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Equilateral Triangle. 6in 6in 6in 5in
the square of a whole number is between 500 and 900. the number must be between...
A. 20 and 30
B. 30 and 40
C. 40 and 50
D. 50 and 60
The number must be between 20 and 30.
How to find the square of whole number?The square of the whole number can be found as follows;
The square of the whole number is between 500 and 900. The number must be between 20 and 30.
The number is an whole number.
Therefore, the number will be between 20 and 30.
20² = 400
30² = 900
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The graph shows the solution to a system of inequalities:
pe
Which of the following inequalities is modeled by the graph?
O 2x + 5y = 14; x = 0
O2x + 5y s 14; x 20
O2x - 5y 14; x 20
O-2x - 5y 14; x = 0
Answer: option (2)
Step-by-step explanation:
The slanted line has a negative slope.
Eliminate options 3 and 4.Also, the line is shaded below.
Eliminate option 1.This leaves option (2) as the correct answer.
Two trees are 120 m apart. From the point halfway between them, the angle of elevation to the top of the trees is 36 and 52. How much taller is one tree than the other.
One tree is 31.044 m taller than the other one in height.
Given Information and Formula Used:
The distance between the trees, BC (from the figure) = 120 m
Elevation of angles to the top of the trees,
∠AMB = 52°
∠DMC = 36°
In a right angled triangle,
tan x = Perpendicular/Height
Here, x is the angle opposite to the Perpendicular.
Calculating the Height Difference:
Let's compute the height of the taller tree first.
In ΔAMB,
tan 52° = AB / BM
Now, since M is the point halfway between the trees,
BM = CM = BC/2
BM = CM = 60 m
⇒ 1.2799 = AB / 60
AB = 1.2799 × 60
Thus, the height of the taller tree, AB = 76.794 m
Now, we will compute the height of the smaller tree.
In ΔDCM,
tan 36° = DC / CM
⇒ 0.7625 = DC / 60
DC = 0.7625 × 60
Thus, the height of the smaller tree, DC = 45.75 m
The difference in the heights of the trees, AP = AB - DC
AP = (76.794 - 45.75)m
AP = 31.044m
Hence one tree is 31.044m taller in height than the other.
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Find the missing angle and side, A is 25 degrees, C is 90 degrees, and B is 16.
The missing angle is B = 65° and the missing sides are a ≈ 7.461 and c ≈ 6.762.
How to find all missing sides and angles of the triangle
In this case, we know two angles (A = 25°, C = 90°) and a side of a triangle (b = 16) and Euclidean properties and the law of the sines must be used to find the rest of variables:
B = 180° - A - C
B = 180° - 25° - 90°
B = 65°
a = 16 × (sin 25°/sin 65°)
a ≈ 7.461
c = 16 × (sin 25°/sin 90°)
c ≈ 6.762
The missing angle is B = 65° and the missing sides are a ≈ 7.461 and c ≈ 6.762.
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