easy please help area of a trapezoid using decomposition

Answer:

You are correct it is A. cos B

Step-by-step explanation:

Answer:

( $ 120 )

Step-by-step explanation:

cause

p they original price given

p - 2p = 96

8 p = 96

p = 120

sana makatulong carry on

Answer:

a) We have an aspect ratio of 4:3

This means that the width of the screen, W, is about 4/3 times the height of the screen, H.

Then we have the equation:

W = (4/3)*H

And the diagonal of a rectangle with width W and height H is:

D = √(W^2 + H^2)

Then if we have a 15 in TV, then we have D = 15 in.

Then we have:

15 in = √(W^2 + H^2)

Now we can use the relation W = (4/3)*H and replace this in the above equation:

15 in = √(((4/3)*H)^2 + H^2)

Now we can solve this for H:

15in = √( (16/9)*H^2 + H^2)

(15in)^2 = (16/9)*H^2 + (9/9)*H^2 = (25/9)*H^2

(9/25)*(15in)^2 = H^2

√( (9/25)*(15in)^2) = H

(3/5)*(15in) = H = 9 in

The height is 9 inches, and the width will be:

W = (4/3)*9in = 12in.

Now let's do the same for a 42 in tv.

We can use the same equation than before, this time we get:

42 in = √(((4/3)*H)^2 + H^2)

We can do the exact same procedure as before, and we will get:

(3/5)*(42in) = H = 25.2 in

Then the width is

W = (4/3)*H = (4/3)*25.2in = 33.6 in

b) Now we do the same, but now we have the relation:

W = (16/9)*H

Then if D is the diagonal, we have the equation:

D = √(W^2 + H^2) = √( ((16/9)*H)^2 + H^2)

This time we can simplify it for any general D.

D^2 = (16/9)^2*H^2 + H^2

D^2 = (256/81)*H^2 + H^2 = (256/81)*H^2 + (81/81)*H^2

D^2 = (337/81)*H^2

(81/337)*D^2 = H^2

√( (81/337)*D^2) = H

(9/18.36)*D = H

Then if we have a 42 in TV, the height is:

(9/18.36)*42in = H = 20.59 in

And the width will be:

W = (16/9)*H = (16/9)*20.59in = 36.60 in

If we have a 60 in TV, we get:

(9/18.36)*60in = H = 29.41 in

And the width will be:

W = (16/9)*H = (16/9)*29.41in = 52.29 in

c) if all the aspect ratios are always exactly 16:9, then no, the width and height should be exactly the same for all the TV with that ratio.

Answer:

so (-4/5)^9/(-4/5)^10=−1,25

um is this all one equation?

like -2.2×(-2)÷(-14)×5-2.2×(-2)÷(-41)×5?

Answer:

Company A's cost would be $530

Company B's cost would be $610

difference is $80

Step-by-step explanation:

Answer:

$30.00 fee

$45.00=total bill

$0.10 per minute of usage

x = minutes used

$30.00 + 0.10 per minute = $45.00

$30.00+$0.10(x) = $45.00

$0.10(x) = $45.00-$30.00 = $15.00

x = $15.00/$0.10 = 150 minutes used

Answer:

28

Step-by-step explanation:

if you asking for  how much it weighs then this is the answer

Answer:

gkcmh .dfjdjhdjkjihndbdndndfp

Answer:

A

Step-by-step explanation:

Answer:

12x

Step-by-step explanation:

3 + 4 + 5 = 12

Answer:

12x

Step-by-step explanation:

we add all of them and we get 12x

Answer:

Given: The mean of x + 2, 2x + 3, 3x + 4 and 4x + 5 is x + 2

 Mean = 4(x+2)+(2x+3)+(3x+4)+(4x+5)

 ⇒x+2=410x+14

 ⇒4x+8=10x+14   

 ⇒6x=−6   

 ⇒x=−1   

Answer:

Under -1 it will be 1/6

Under zero it would be 1

under 3 it would be 216

Explanation:

y = 6 to the power of x

Answer:

7/30

Step-by-step explanation:

1/6 = 1x5/6x5

    = 5/30

1/15= = 1x2/1x15

       =2/30

2/30 + 5/30 = 7/30

Answer:

Following are the solution to the given points:

Step-by-step explanation:

For point (a) :

In this, two points are  exclusive to one another,  it is a probability that first or the  second project will have breaches,

[tex]\to P = P(A) + P(B)[/tex]

       [tex]= 0.3 + 0.25\\\\= 0.55[/tex]

Since the p(A & B)=0  is mutually exclusive.

For point (b):

[tex]\to P = ( \frac{1 -p(A)) \times P(B)}{((1-P(A)) \times P(B) + P(A&B)}) \\\\[/tex]

       [tex]= \frac{(1 -0.3)\times 0.25}{(1-0.3)*0.25 + 0} \\\\ = 1[/tex]

For point (c):

 if both a and b are independent:

(a):

[tex]P = P(A) + P(B) - P(A)\times P(B) \\\\[/tex]

   [tex]= 0.3 + 0.25 - 0.3 \times 0.25\\\\ = 0.475[/tex]

(b):

[tex]P = \frac{(1 -p(A)) \times P(B)}{((1-P(A)) \timesP(B) + P(A&B))} \\\\[/tex]

   [tex]= \frac{(1 - 0.3)\times 0.25}{((1-0.3)\times0.25 + 0.3\times0.25)}\\\\ = 0.7[/tex]

Answer: Hey here’s your answer: 2/3 divided by 5=2/15

Hth

Step-by-step explanation:

Answer:

2/15 is ur answer

Step-by-step explanation:

2/3 ÷ 5

2/3 x 1/5

2/15

Step-by-step explanation:

option A is the correct answer according to me .

plz mark my answer as brainlist if you find it useful.

Answer:

The answer is B

P=a*b

a=P/b

a=18/b

Pairs of the solution (only integer numbers):

b=9, a=2

b=2, a=9

b=6, a=3

b=3, a=6

b=18, a=1

b=1, a=18

I'm guessing ordinary language means not in scientific method and in words. So...

First we combine the exponent because they are multiplied with the same base getting...

10^2+5=10^7

Now we can convert this into everyday numbers...

10,000,000

Or...

10 million

Since I do not know what ordinary language means to your teacher, just choose the answer that is the one your teacher wants! If you have any more questions about this just ask in the comments.

Answer:

X= 29

Step-by-step explanation:

Answer:

x = 29

Step-by-step explanation:

Let's solve your equation step-by-step.

−18=−1(x−11)

Step 1: Simplify both sides of the equation.

−18=−1(x−11)

−18=(−1)(x)+(−1)(−11)(Distribute)

−18=−x+11

Step 2: Flip the equation.

−x+11=−18

Step 3: Subtract 11 from both sides.

−x+11−11=−18−11

−x=−29

Step 4: Divide both sides by -1.

-x/1 = -29/-1

hope this helped:')

Answer:

Continuous random variable - The practically infinite number of possible                   values that a random variable can take on in an experiment

Random experiment - The process of observing the outcome of a random   chance event

Probability - The number that quantifies the likelihood that a certain  random event will happen

Sample space -  All possible outcomes that can result from a random experiment

Variability - This exist when successive observations of a particular system variable or phenomenon do not produce the exact same result.

Statistical inference - The use of information from a sample to draw conclusions about the population

Sample mean - The most commonly used measure of central tendency of a distribution of data

Event - A subset of the sample space

Standard deviation - A measure of the extent to which the values in the data set differ from the mean

Outlier - An observation point that is distant from other observation.

Answer:

The 99 percent confidence interval for the proportion of all employees at the company who own an electric car is (0.0104, 0.0496).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

In a random sample of 500 employees, 15 reported owning an electric car.

This means that [tex]n = 500, \pi = \frac{15}{500} = 0.03[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.03 - 2.575\sqrt{\frac{0.03*0.97}{500}} = 0.0104[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.03 + 2.575\sqrt{\frac{0.03*0.97}{500}} = 0.0496[/tex]

The 99 percent confidence interval for the proportion of all employees at the company who own an electric car is (0.0104, 0.0496).

You can find the standard mean error and then use that to find the confidence interval limits.

The 99% confidence interval for the proportion of all employees at the company who own an electric car is given by

Lower limit = 0.0104

Upper limit = 0.0496

The confidence interval is (0.0104, 0.0496) (can include those end points too)

Let the sample size be n

Let the interested quantities in the sample be present x times

Let the confidence level be of p%.

Then the level of significance is given by [tex]\alpha = 1 - p/100[/tex]

The standard mean error is calculated by:

[tex]SME = \sqrt{\dfrac{x(n-x)}{n^3}}[/tex]

Then the confidence interval limits can be found by

[tex]CI = \dfrac{x}{n} \pm Z_{\alpha/2}(SME)[/tex]

We have n = 500, x = 15 and [tex]\alpha = 1 - 0.99 = 0.01[/tex]

Finding the standard mean error:

[tex]SME = \sqrt{\dfrac{x(n-x)}{n^3}}\\\\SME = \sqrt{\dfrac{15 \times 485}{500^3}} \approx 0.00763[/tex]

From the z tables, at [tex]\alpha/2 = 0.01/2 = 0.005[/tex], we get z = 2.5758

Thus, the confidence interval is obtained by

[tex]CI = \dfrac{x}{n} \pm Z_{\alpha/2}(SME)\\\\CI = \dfrac{15}{500} \pm 2.575 \times 0.00763\\\\CI = 0.03 \pm 0.0196[/tex]

Lower limit = 0.0104

Upper limit = 0.0496

Thus,

The 99% confidence interval for the proportion of all employees at the company who own an electric car is given by

Lower limit = 0.0104

Upper limit = 0.0496

The confidence interval is (0.0104, 0.0496) (can include those end points too)

Learn more about confidence interval here:

https://brainly.com/question/16427118

Answer:

solve the 3y and 2y first

Step-by-step explanation:

Answer:

y = 2.

Step-by-step explanation:

We need to have  y terms on one side of the equation and numbers on the other side:-

3y - 4 = 6 -  2y    

 Add 2y to both sides:              

3y + 2y - 4 = 6 - 2y + 2y

5y - 4 = 6    

Add 4 to both sides:                      

5y  - 4 + 4 = 6 + 4

5y = 10

y = 10/5

y = 2.

Answer:

Expanded Notation Form:

234.2

=

200

+

30

+

4

+

0.2

Expanded Factors Form:

234.2

=

2 ×

100

+

3 ×

10

+

4 ×

1

+

2 ×

0.1

Expanded Exponential Form:

234.2 =

2 × 102

+

3 × 101

+

4 × 100

+

2 × 10-1

Word Form:

234.2 =

two hundred thirty-four and two tenths

Answer:

Step-by-step explanation:

A∪B = {1,2,3,4,5}

B∩C = {4}

I don't know what CD means.

A' = {5,6,7,8,9}

Answer:

$140

Step-by-step explanation:

Answer:

a) 0.1125 = 11.25% probability that you play someone ranked high and lose.

b) 0.5435 = 54.35% probability that you win

c) 0.0690 = 6.90% probability that you played a high rated opponent

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

(a) For a randomly assigned match, what is the probability that you play someone ranked high and lose?

15% probability that you play someone that is ranked high.

If you play someone ranked high, 100 - 25 = 75% probability you lose

0.15*0.75 = 0.1125

0.1125 = 11.25% probability that you play someone ranked high and lose.

(b) For a randomly assigned match, what is the probability that you win?

75% of 30%(novice oponent)

50% of 55%(mid oponent)

25% of 15%(high opponent). So

[tex]p = 0.77*0.3 + 0.5*0.55 + 0.25*0.15 = 0.5435[/tex]

0.5435 = 54.35% probability that you win

(c) You play a match and win. What is the probability that you played a high rated opponent?

Here, we use the conditional probability formula.

Event A: Winning

Event B: Playing a high opponent.

0.5435 = 54.35% probability that you win

This means that [tex]P(A) = 0.5435[/tex]

Intersection of events A and B:

25% of 15%(high opponent). So

[tex]P(A \cap B) = 0.25*0.15 = 0.0375[/tex]

Question:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0375}{0.5435} = 0.0690[/tex]

0.0690 = 6.90% probability that you played a high rated opponent