Factor by grouping.
30y + 3h + 10vr + hr

Answers

Answer 1

Answer:

30y+hr+10rv+3h

Step-by-step explanation:

Hope this helps

Answer 2
I decided to give you 2 answers because there’s no way you can continue factoring unless the “30y” was “30v”. So, I did it both ways for you, just in case! ;)
Factor By Grouping.30y + 3h + 10vr + Hr

Related Questions

$274 for 40 hours of work as a unit rate

Answers

Answer:

6.85 units per hour

Step-by-step explanation:

$274 for 40 hours of work as a unit rate

in practice you look for the hourly wage, you find it by dividing the wages divided by the working hours

274 : 40 = 6.85 units per hour

Rollin Corporation has 410,000 shares of 5$ per value common stock issued and outstanding. Record the following entries into the general journal

Answers

Answer:3522

Step-by-step explanation:222

2

F(x)=x^3*125 complex zeros

Answers

Answer: 0

Step-by-step explanation:

[tex]125x^3 =0\\\\x^3 =0\\\\x=0[/tex]

If two numbers are selected at random ,one after the other with replacement from the set A=(5,6,7,8,9) find the probability of selecting at least one prime number

Answers

Answer:

16/25

Step-by-step explanation:

(at least 1 prime selected)=1−(no primes selected)

There are 3 numbers in the set that are not prime (6,8,9)

(no primes selected)=(35)2=925

(at least 1 prime selected)=1−925

=1625

Has a base of 3, is reflected over the y-axis, has a horizontal shift right by 5 and an asymptote of y=-3

Answers

The equation of the exponential function is [tex]y = 3^{-x -5} - 3[/tex]

How to determine the equation?

An exponential equation is represented as:

y = b^x

Where b represents the base.

The base is 3.

So, we have:

[tex]y = 3^x[/tex]

When reflected over the y-axis, we have:

[tex]y = 3^{-x[/tex]

When shifted right by 5 units, we have:

[tex]y = 3^{-x -5[/tex]

Lastly, the function has an asymptote of y=-3

So, we have:

[tex]y = 3^{-x -5} - 3[/tex]

Hence, the equation of the exponential function is [tex]y = 3^{-x -5} - 3[/tex]

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The function f(x) = 300(0.5)x/100 models the amount in pounds of a particular radioactive material stored in a concrete vault, where x is the number of years since the material was put into the vault. Find the amount of radioactive material in the vault after Round to the nearest whole number.

Answers

The amount of the radioactive material in the vault after 140 years is 210 pounds

How to determine the amount

We have that the function is given as a model;

f(x) = 300(0.5)x/100

Where

x = number of years of the vault = 140 yearsf(x) is the amount  in pounds

Let's substitute the value of 'x' in the model

f(x) = 300(0.5)x/100

[tex]f(x) = \frac{300(0.5) * 140}{100}[/tex]

[tex]f(x) =\frac{21000}{100}[/tex]

f(140) = 210 pounds

This mean that the function of 149 years would give an amount of 210 pounds rounded up to the nearest whole number.

Thus, the amount of the radioactive material in the vault after 140 years is 210 pounds

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Marco has joined a bowling league, and is trying to raise his average to 130. On his last four games he scored 128, 127, 123, and 122. How much will he need to score on the next game to raise his mean to 130?

Answers

The score Macro needs in his next game to have a mean of 130 is 150.

What should be the next score?

Mean is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number

Mean = sum of the numbers / total number

130 = (128 + 127 + 123 + 122 + x) / 5

Where x represents the fifth score

130 = (500 + x) / 5

130 x 5 = 500 + x

650 = 500 + x

650 - 500 = x

x = 150

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You are training to compete in a 10-kilometer race, and you know the circular running trail at your park is one mile long. How many times will you need to run this trail in order to run 10 kilometers?

Answers

So to run 10km, you need to run 6.25 times the trail. (Or 7 if you only accept whole numbers as answers, we need to round up).

How many times will you need to run this trail in order to run 10 kilometers?

If you run the trail x times, then you will run:

y = x*1mi

Now remember that:

1 mi = 1.6 km

Replacing that, we get the linear equation:

y = x*1.6km

Now we want to find the value of x such that:

x*1.6km = 10km

Dividing both sides by 1.6km

x = 10km/1.6km = 6.25

So to run 10km, you need to run 6.25 times the trail. (Or 7 if you only accept whole numbers as answers, we need to round up).

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Please Evaluate C(6,3)

Answers

The value of the expression C(6,3) is 20

How to evaluate the expression?

The expression is given as:

C(6, 3)

This means 6 combination 3.

And it can be written as:

[tex]^6C_3[/tex]

Apply the combination formula

[tex]^6C_3 = \frac{6!}{3!3!}[/tex]

Evaluate the expression

[tex]^6C_3 = 20[/tex]

Hence, the value of the expression C(6,3) is 20

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Mr. Bellman orders a cube of clay for each of his art classes. The height of the
cube is 20 inches. How much clay, in cubic inches, would Mr. Bellman order
for three classes?
Write and evaluate an expression to find your answer.
20 cubed is 20 times 20 and then that answer times 20.
length X width x height = cube
20 to the 3rd power or 203
A
B
C
60 cubic inches
400 cubic inches
8,000 cubic inches

Answers

Answer:

20 x 20 x 20 = 8000

What type of polynomial is: 3x4−2x3−2

Answers

The given polynomial is a Quartic trinomial

Types of polynomial

From the question, we are to determine the type of the given polynomial

The given polynomial is

3x⁴−2x³−2

The highest degree of the polynomial is 4. Thus, it is a Quartic Polynomial.

Also, the expression contains exactly 3 terms. Thus, it is a trinomial.

Hence, the given polynomial is a Quartic trinomial

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Select the statement that best describes √ 1 5

Answers

There are no statements to select from

18. Find the value of 3x² x 2(x-3y) divide by 6 when x is 6 and y is 1

Answers

Answer:

11664

Step by Step:

Evaluate for x=6,y=1

3(6^2)(6^2)(6−(3)(1))

3(6^2)(6^2)(6−(3)(1))

=11664

How many cubicle blocks each with ages of length 2 cm are needed to fill a rectangular box that has inside dimensions 10 cm x 12 cm x 60 cm

Answers

we conclude that 900 cubes enter in the given box.

How many blocks are needed to fill the box?

We need to find the volumes of both figures.

The blocks are cubes of 2cm by 2cm by 2cm, then the volume of each block is:

[tex]V = (2cm)^3 = 8cm^3[/tex]

The box has dimensions of 10cm by 12cm by 60cm, then the volume is:

[tex]V = 10cm*12cm*60cm = 7,200 cm^3[/tex]

The number of cubes that enter in the box is N such that:

[tex]N*8cm^3 = 7,200cm^3[/tex]

Solving for N, we get:

[tex]N = 7200cm^3/8cm^3 = 900[/tex]

In this way, we conclude that 900 cubes enter in the given box.

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A group of yeast cells grows by 75% every 3hrs. At 9am, there are 200 yeast cells [9 marks].
a) write an equation that models the number of cells, given the number of hours after 9am
b) Determine the number of yeast cells after 10 hours.

Answers

a) The exponential function that models the number of cells is: [tex]A(t) = 200(1.75)^{\frac{t}{3}}[/tex]

b) There will be 1292 cells after 10 hours.

What is an exponential function?

An increasing exponential function is modeled by:

[tex]A(t) = A(0)(1 + r)^{\frac{t}{n}}[/tex]

In which:

A(t) is the amount after t hours.A(0) is the initial amount.r is the rate of change, as a decimal.n is the time it takes to change.

For this problem, the parameters are:

A(0) = 200, r = 0.75, n = 3.

Hence the equation is:

[tex]A(t) = A(0)(1 + r)^{\frac{t}{n}}[/tex]

[tex]A(t) = 200(1 + 0.75)^{\frac{t}{3}}[/tex]

[tex]A(t) = 200(1.75)^{\frac{t}{3}}[/tex]

The number of cells after 10 hours is:

[tex]A(t) = 200(1.75)^{\frac{t}{3}}[/tex]

[tex]A(10) = 200(1.75)^{\frac{10}{3}}[/tex]

A(10) = 1292.

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You deposit $2000 in an account earning 2% interest compounded monthly. How much will you have in the account in 10 years?

Answers

Answer:Principal P = 2000

Amount= A

years=n 10.00

compounded 12 times a year t

Rate = 2.00 0.02

Amount = P*((n+r)/n)^n*t

Amount = = 2000 *( 1 + 0.02 /t)^ 10 * 12

Amount = 2000 *( 1 + 0 )^ 120

2000 *( 1 )^ 120

Amount = 2442.4

Step-by-step explanation:

Show the calculation to find the μ and σ of a binomial variable whose probability of success if 0.3 with a total number of attempts of 20.

Answers

Using the binomial distribution, we have that:

The mean is of [tex]\mu = 6[/tex].The standard deviation is of [tex]\sigma = 2.05[/tex].

What is the binomial probability distribution?

It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.

The expected value of the binomial distribution is:

[tex]\mu = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

For this problem, the parameters are:

n = 20, p = 0.3.

Hence:

[tex]\mu = np = 20 \times 0.3 = 6[/tex][tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20 \times 0.3 \times 0.7} = 2.05[/tex]

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solve each equation.
a)2/3-5/6=1/x
b)x+6/x=5
c)x+1/3-x-1/2=1
d)x-5/x+1=3/5

Answers

Answer:

a.

2 / 3 + 5 / 6 - 1 / 2a.

2 / 3 + 5 / 6 - 1 / 2

= 0,66... + 0,833... - 0,5

= 1,5 - 0,5

= 1

Step-by-step explanation:

sorry I only know the letter A hope I helped anyway

Which table shows a linear function?

Answers

The first table with the following values of x and y, shows a linear function.

x = -4, y = 8

x = -1, y = 2

x = 1, y = 2

x = 2, y = 4

x = 3, y = 6

Definition of a Linear Function:

A polynomial function of degree zero or one that has a straight line as its graph is referred to as a linear function in calculus and related fields.

For the above chosen option, the value of y corresponding to a value of x is twice that of its x value. This linear function can be represented as follows,

y = | 2x | .......... (1)

In this linear function, mod represents, that y is always maintained positive. Besides, the value of y is always twice that of the x. Hence, the linear function can also be written as, y ± 2x = 0.

Since, equation (1) is of the form, y = mx + c, it produces a straight line. Here, m = 2 and c = 0. Thus, it is a linear function.

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Does this table represent a function? Why or why not

Answers

Answer:

No

Step-by-step explanation:

This table does not represent a function. The domain(x) can have only one range(y) in order for a set of data to represent a function. However, the domain value 2 has the range of both 1 and 4. Therefore, the table does not represent a function.

Preeta’s book has 300 pages. Each day she reads 10 more pages than the day before. She finishes her book in 6 days. How many pages does she read?

Answers

Step-by-step explanation:

1. if the number of pages in the 1st day is 'x', then the 2d day - 'x+10', the 3d day - 'x+20', the 4th day - 'x+30', the 5th day - 'x+40' and the last day - 'x+50' pages;

2. if the sum of all the pages is 300, then it is possible to make up the equation:

x+x+10+x+20+x+30+x+40+x+50=300;

3. x=25, it means:

1st day - 25;

2d day - 35;

3d day - 45;

4th day - 55;

5th day - 65;

6th day - 75 pages.

Solve for x.
A) 6
B) 4
C) 5
D) 7

Answers

Answer:

c

Step-by-step explanation:

Aight, let's hop to it:

So we got

[tex] \frac{5x}{45} = \frac{20}{36} = = > \\ \frac{x}{9} = \frac{5}{9} = = > \\ x = 5[/tex]

and boom

While traveling in Europe, you notice that the price of gas is $1.12 per liter. What is the price per gallon?

Answers

Here is the solution

Use an outside source to search for a quadratic equation that models something from your daily life. (Be sure to cite the source you use.)
Solve the equation in two ways.
Discuss which method you liked better and why.
In your responses to peers, compare and contrast your preferences for how to solve quadratic equations.

Answers

A quadratic equation that models something from one's daily life is when calculating areas, and determining a product's profit.

What is a quadratic equation?

It should be noted that a quadratic equation means an algebraic equation of the second degree in x.

The quadratic equation in its standard form is ax² + bx + c = 0. Here, a and b are the coefficients, x is the variable, while c is the constant term.

Quadratic equations are used in everyday life, as when calculating areas, and the determination of a product's profit and formulating the speed of an object.

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Q.3. Set up the equations and solve them to find the unknown numbers in the cases given below:
1) If you add 6 to five times a number, it gives 46.
2) Two-third of a number minus 5 gives 11.
3) If you take onethird of a number and add 4 to it, gives 45.
4) When person X subtracts 12 from thrice of a number, it gives 18.
5) When Jenny subtracts twice the number of pens, she has from 40, she gets 16.
6) Virat guesses a number. If he adds 18 to that number and then divides the sum by 6, he gets answer 7.
7) Ami guesses anumber. If she subtracts 8 from two third of a number, she gets 6

I want Answer quickly ​

Answers

The following expressions set up as an equation to solve for the unknown numbers in the cases given below:

Algebraic equation

let

The unknown number = x

5x + 6 = 46

5x = 46 - 6

5x = 40

x = 40/5

x = 8

2/3x - 5 = 11

2/3x = 11 + 5

2/3x = 16

x = 16 ÷ 2/3

x = 16 × 3/2

x = 48/2

x = 24

1/3x + 4 = 45

1/3x = 45 - 4

1/3x = 41

x = 41 ÷ 1/3

x = 41 × 3/1

x = 123

3x - 12 = 18

3x = 18 + 12

3x = 30

x = 30/3

x = 10

40 - 2x = 16

-2x = 16 - 40

-2x = -24

x = -24/-2

x = 12

(x + 18) / 6 = 7

(x + 18) = 7 × 6

x + 18 = 42

x = 42 - 18

x = 24

2/3x - 8 = 6

2/3x = 6 + 8

2/3x = 14

x = 14 ÷ 2/3

x = 14 × 3/2

= 42/2

x = 21

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Tornadoes Use the frequency distribution from Exercise 12 in Section on page 49 to construct a frequency polygon. Does the graph suggest that the distribution is skewed? If so, how?

Answers

The distribution is skewed because it's on the right side of the polygon and this illustrates that's it's positively skewed.

How to illustrate the information?

It should be noted that the polygon can be gotten by plotting the data.

After the analysis of the distribution, the distribution is skewed to the right.

This illustrates that it is skewed.

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z^4-4z^3+4z^2+48=0 how to find value of z?​

Answers

There are no real solutions to solve Z. If there may be a typo or something, there are no solutions.

Christine is putting money into a savings account. She starts with $650 in the savings account, and each week she adds $60. Let S represent the total amount of money in the savings account (in dollars), and let W represent the number of weeks Christine has been adding money. Write an equation relating S to W. Then use this equation to find the total amount of money in the savings account after 11 weeks.

Answers

Total amount of money in the savings account after 11 weeks is $1310.

Total money in the account =

 Initial Money + Money added per week x Number of weeks

Given:

Initial Money = $650

Money added per week = $60

Total money in the account = S

Number of weeks = W

Substituting it in the above equation we get,

S = $650 + $60xW                                          (General Equation)

Total amount of money in the savings account after 11 weeks

S = $650 + $60x11

S = $650 + $660

S = $1310

Thus total amount of money in the savings account after 11 weeks is $1310.

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Which inequality in standard form represents the
shaded region?

Answers

The figure is represented by the inequality y ≥ 5 · x² - 40 · x - 45. (Correct choice: C)

What inequality represents the figure

In accordance with the figure, we have an inequation of the form y ≥ f(x). Now we proceed to find the quadratic equation of the parabola:

f(x) = a · (x + 1) · (x - 9)

- 125 = a · (4 + 1) · (4 - 9)

- 125 = a · 5 · (- 5)

- 125 = - 25 · a

a = - 5

f(x) = 5 · (x + 1) · (x - 9)

f(x) = 5 · (x² - 8 · x - 9)

f(x) = 5 · x² - 40 · x - 45

The figure is represented by the inequality y ≥ 5 · x² - 40 · x - 45. (Correct choice: C)

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Find the angle between the vectors.
U=< -4,-3>
V = < -1,5>

Answers

Step-by-step explanation:

The formula for the angle between vectors

[tex] \alpha = \cos {}^{ - 1} ( \frac{uv}{ |u| |v| } ) [/tex]

To multiply vectors, multiply the first component and multiply the second component and add them.

(-4*-1) + (-3*5)= 4-15=-11.

To find magnitude of vectors, use the Pythagorean theorem

[tex]u = \sqrt{ { - 4}^{2} + { - 3}^{2} } = 5[/tex]

[tex]v = \sqrt{ - 1 {}^{2} + 5 {}^{2} } = \sqrt{26} [/tex]

so

[tex] |u| |v| = 5 \sqrt{26} [/tex]

Know we have,

[tex] \alpha = \cos {}^{ - 1} ( \frac{7}{5 \sqrt{26} } ) [/tex]

[tex] \alpha = 105.94[/tex]

in degrees,

[tex] \alpha = 1.849[/tex]

in radians

Answer:

115.6° (1 d.p.)

Step-by-step explanation:

To find the angle between two vectors:

Create a triangle with the vectors as two sides and the included angle θ between them.Find the magnitude of each vector (the length of each side of the triangle).Use the cosine rule to find the angle θ.

**Please see attached for the triangle diagram**

Given vectors:

[tex]\textbf{u}=-4\textbf{i}-3\textbf{j}[/tex]

[tex]\textbf{v}=-\textbf{i}+5\textbf{j}[/tex]

Use Pythagoras Theorem to find the magnitude of each vector:

[tex]\implies |\textbf{u}|=\sqrt{(-4)^2+(-3)^2}=5[/tex]

[tex]\implies |\textbf{v}|=\sqrt{(-1)^2+5^2}=\sqrt{26}[/tex]

[tex]\overrightarrow{\text{UV}}=\textbf{v}-\textbf{u}=(-\textbf{i}+5\textbf{j})-(-4\textbf{i}-3\textbf{j})=3\textbf{i}+8\textbf{j}[/tex]

[tex]|\overrightarrow{\text{UV}}|=\sqrt{3^2+8^2}=\sqrt{73}[/tex]

Cosine Rule (for finding angles)

[tex]\sf \cos(C)=\dfrac{a^2+b^2-c^2}{2ab}[/tex]

where:

C = anglea and b = sides adjacent the anglec = side opposite the angle

Find angle θ using the cosine rule:

[tex]\implies \cos(\theta)=\dfrac{|\textbf{u}|^2+|\textbf{v}|^2-|\overrightarrow{\text{UV}}|^2}{2|\textbf{u}||\textbf{v}|}[/tex]

[tex]\implies \cos(\theta)=\dfrac{5^2+\left(\sqrt{26}\right)^2-\left(\sqrt{73}\right)^2}{2(5)\left(\sqrt{26}\right)}[/tex]

[tex]\implies \cos(\theta)=\dfrac{-22}{10\sqrt{26}}[/tex]

[tex]\implies \theta=\cos^{-1}\left(\dfrac{-22}{10\sqrt{26}}\right)[/tex]

[tex]\implies \theta=115.5599652...^{\circ}[/tex]

Therefore, the angle between the vectors is 115.6° (1 d.p.).

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