Find an equation whose graph is a Parabola with vertex (1, 1) and focus (2, 2).

Answer:

10 and 11

Step-by-step explanation:

The square root of 104 is 10.1980390272. This falls between the whole numbers 10 and 11.

Answer:

Yes

Step-by-step explanation:

The line has to be loner to connect the other two.

Answer:

27x + 45 + 9x

37x + 45

it's here

Answer:

50°

Step-by-step explanation:

The sum of angles in a triangle is 180 degrees

Hence given that in a triangle ACB with angles 90°, 4x°, 7x - 20

As such

90 + 4x + 7x -20 = 180

simplify

11x + 70 = 180

11x = 180 - 70

11x = 110

Divide both sides by 11

x = 110/11

x = 10

m∠ACB is 7x - 20

Substitute the value of x into the expression

= 7(10) - 20

= 70 - 20

= 50

Answer:

The answer is 50 degrees

Step-by-step explanation:

Answer:

answer is

Step-by-step explanation:

2+4=6

and 6-32=26 answer

Answer:

-4√6-6√5

Step-by-step explanation:

-3√6-3√20-√6 = (-3√6-√6)-3√20 = -4√6-3√20

√20 = √4*√5 or 2√5

substitute that in and you get -4√6-3(2√5) which then becomes

-4√6-6√5

Answer:

n = 4

Step-by-step explanation:

3 = 2 + n/4

1 = n/4

4 = n

Answer:

n = 4

Step-by-step explanation:

take the 2 and subtract it from itself then you gotta do it to the other side so it be 3 -2 and you get 1 then you multiply 4 to n/4 and it crosses it out and what you do to one side you do to the other so you multiply 4 by 1 & get 4

Answer:

10.04 × 8.8 =?, ? = 88.352 :)

Answer:

88.352

Step-by-step explanation:

10.04

x. 8.8

=88.352

Answer:

[tex]y = 4(0.5) {}^{x} [/tex]

Step-by-step explanation:

By looking at your graph, The y intercept is (0,4).

This is an exponential function so it is represented by

[tex]y = ab {}^{x} [/tex]

where a is the vertical stretched and b is the constant rate and x is the nth power.

let plug in 0,4

[tex]4 = ab {}^{0} [/tex]

[tex]b {}^{0} = 1[/tex]

since anything to the 0 power is 1.

[tex]4 = a \times 1[/tex]

[tex]4 = a[/tex]

Know let plug it in to this equation.

[tex]y = 4b {}^{x} [/tex]

Let use 2,1 another point on the graph

[tex]1 = 4b {}^{2} [/tex]

Divide 4 by both sides

[tex]0.25 = {b}^{2} [/tex]

take sqr root of 0.25

[tex]0.5 = b[/tex]

So

the answer is

[tex]y = 4(0.5) {}^{x} [/tex]

Answer:

Option B:

[tex]-\frac{38.44}{6.2} = -6.2[/tex]

Step-by-step explanation:

Given

Options A to D

Required

Determine which is true

Option A:

[tex]-\frac{38.44}{6.2} = 6.2[/tex]

[tex]-6.2 = 6.2[/tex]

This is not true

Option B:

[tex]-\frac{38.44}{6.2} = -6.2[/tex]

[tex]-6.2 = -6.2[/tex]

This is true

There is no need to check further

[tex] - 2 \frac{1}{2} - ( - 1 \frac{3}{4} )[/tex]

[tex] - \frac{5}{2} - ( - \frac{7}{4} )[/tex]

[tex] - \frac{10}{4} - ( - \frac{7}{4} )[/tex]

[tex] - \frac{3}{4} [/tex]

Answer:

V = 14 m/s

Step-by-step explanation:

[tex]E = MV^2 ÷ 2 + mgh \\ \\ 4900 = 20V^2 ÷ 2 + 20 \times 9.8 \times 15 \\ \\ 4900 = 10V^2 + 2,940\\ \\ 4900 - 2940 = 10V^2 \\ \\ 1960 = 10V^2 \\ \\ V^2 = \frac{1960}{10} \\ \\ V^2 = 196 \\ \\ V = \sqrt{196} \\ \\ V = 14 \: m {s}^{ - 1} [/tex]

Answer:

Thanks for the point!

Step-by-step explanation:

Have a great day

Answer:

im going to say c

Step-by-step explanation:

if its has 160 units and goes to half-life after 2 months im assuming it loses 1/2 of the units so in order for it to lose that many it will have to lose 40 units a month so i say its c after 10 months there will be less than 1 unit in the potion

hope this helps im sorry if im wrong have a blessed day :)

Answer:

3

Step-by-step explanation:

I'm going to assume you meant "How many 2/9 cup serving are in 7/9 cup of juice" (since there are no 7/9 cups of serving in 2/9 cups of juice, since 7/9>2/9, and you can't have a serving of something greater than the amount you have).

In this case:

7/9 divided by 2/9=3

Since 7/9 and 2/9 have the same denominater, you can cross them off, since when you divide them, 9 divided by 9=1. 7 divided by 2=3.5, but I'll assume you want full cups.

Answer:

I would say the answer is D because the figure is rotated 180 degrees. Letters C and D are pretty much the same just with some differences, but I would say D. Let me know if it's wrong :)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Prime factorization

30 = 2 × 3 × 5

36 = 2² × 3²

HCF = 2 × 3 = 6

Answer:

-2, -1, 0, 1, 2.

Solution

Let x be the middle term of this sequence of 5 terms.

Then the sequence is x-2, x-1, x, x+1, x+2.

The sum of the terms is (x-2) + (x-1) + x + (x+1) + (x+2) = 5x.

Thus 5x = 0.

It gives x = 0.

So the sequence is -2, -1, 0, 1, 2.

[tex]10x-25+8[/tex]

Simplify:

[tex]10x+-25+8[/tex]

Combine Like Terms:

[tex](10x)+(-25+8)\\10x+-17(ANSWER)[/tex]

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Answer:

Solve the linear equation [tex]2.25 - 11 - 7.75 + 1.5j= 0.5j - 1[/tex]

✔ [tex]j[/tex] = –0.45

[tex]j[/tex]  = –0.25

[tex]j[/tex] = 0.25

[tex]j[/tex] = 0.45

Simplify [tex]2.25 - 11j - 7.75 + 1.5j[/tex] .

Subtract [tex]7.75[/tex] from [tex]2.25[/tex] .

[tex]- 11j - 5.5 + 1.5j = 0.5j -1[/tex]

Add [tex]-11j[/tex] and [tex]1.5j[/tex] .

[tex]- 9.5j - 5.5 = 0.5j - 1[/tex]

Move all terms containing [tex]j[/tex] to the left side of the equation.

Subtract [tex]0.5j[/tex] from both sides of the equation.

[tex]- 9.5j - 5.5 = 0.5j - 1[/tex]

Subtract [tex]0.5j[/tex] from [tex]- 9.5j[/tex].

[tex]- 10j - 5.5 = - 1[/tex]

Move all terms not containing [tex]j[/tex] to the right side of the equation.

Add [tex]5.5[/tex] to both sides of the equation.

[tex]-10j = -1 +5.5[/tex]

Add [tex]-1[/tex] and [tex]5.5[/tex] .

[tex]10j=4.5[/tex]

Divide each term in [tex]-10[/tex][tex]j[/tex] [tex]=4.5[/tex] by [tex]-10[/tex] and simplify.

Divide each term in [tex]-10j = 4.5[/tex] by [tex]-10[/tex].

[tex]\frac{-10j}{-10} = \frac{4.5}{-10}[/tex]

Simplify the left side.

Cancel the common factor of [tex]-10[/tex].

[tex]j= \frac{4.5}{-10}[/tex]

Cancel the common factor.

[tex]\frac{-10j }{-10} = \frac{4.5}{-10}[/tex]

Divide [tex]j[/tex] by [tex]1[/tex]

[tex]j=\frac{4.5}{-10}[/tex]

Simplify the right side.

Divide [tex]4.5[/tex] by [tex]-10[/tex].

[tex]j=-4.5[/tex]

The Final Answer is

[tex]j=-4.5[/tex]

Answer:

a leveled line or a straight line

Answer:

The exterior angle of triangle XYZ is;

∠JXM

Step-by-step explanation:

The question is a word problem with the given parameters;

The points on line 'a' = L and M

The points on line 'b' = O and N

The point line 'c' intersect line 'a' = X

The point line 'c' intersect line 'b' = Z

The points on line 'c' = H and G

The point line 'd' intersect line 'a' = X

The point line 'd' intersect line 'b' = Y

The points on line 'd' = J and K

From the drawing of triangle XYZ created with Microsoft Visio, the exterior angle is ∠JXM

Answer:

Step-by-step explanation:

the answer is JXZ

Answer:

Let w be the width of the rectangle. The length would be 2w+3. The area of the rectangle would be w(2w+3)=189.

So 2w2+3w-189=0 Solving for w you get w=9 or -10.5. Ignoring negative value Width of the rectangle would be 9mm and length of the rectangle would be 21mm giving you the area 189 square mm.

Hope this helps:)

Answer:

72 inches!

Step-by-step explanation:

since there are 12 inches in a foot, and there are 6 feet, you would multiply 6 x 12, so the answer would be 72 inches !!

i hope this helps ! ! :D

Answer:

The answer would be the number 3

Answer:

(A): As year increases the number of pikas reduces.

(B): As year increases the number of pikas increases as opposed to when the rate reduces.

Step-by-step explanation:

See comment for complete question

Given

[tex]a = 144[/tex] --- Initial Population

[tex]r = 8\%[/tex] --- rate

(A) WHEN THE RATE DECREASES

First, we need to write out the function when the population decreases.

This is given as:

[tex]f(x) = a(1-r)^x[/tex]

Substitute values for a and r

[tex]f(x) = 144(1-8\%)^x[/tex]

Convert % to decimal

[tex]f(x) = 144(1-0.08)^x[/tex]

[tex]f(x) = 144(0.92)^x[/tex]

Next, we calculate the average rate of change for both intervals using:

[tex]Rate = \frac{f(b) - f(a)}{b-a}[/tex]

For 1 to 5:

[tex]Rate = \frac{f(5) - f(1)}{5-1}[/tex]

[tex]Rate = \frac{f(5) - f(1)}{4}[/tex]

Calculate f(5) and f(1)

[tex]f(x) = 144(0.92)^x[/tex]

[tex]f(1) = 144*0.92^1 =144*0.92=132.48[/tex]

[tex]f(5) = 144*0.92^5 =144*0.66=95.04[/tex]

[tex]Rate = \frac{95.04 - 132.48 }{4}[/tex]

[tex]Rate = \frac{-37.44}{4}[/tex]

[tex]Rate = -9.36[/tex]

For 6 to 10:

[tex]Rate = \frac{f(10) - f(6)}{10-6}[/tex]

[tex]Rate = \frac{f(10) - f(6)}{4}[/tex]

Calculate f(6) and f(10)

[tex]f(x) = 144(0.92)^x[/tex]

[tex]f(6) = 144*0.92^6 =144*0.61=87.84[/tex]

[tex]f(10) = 144*0.92^{10} =144*0.43=61.92[/tex]

[tex]Rate = \frac{61.92-87.84}{4}[/tex]

[tex]Rate = \frac{-25.92}{4}[/tex]

[tex]Rate = -6.48[/tex]

So, we have:

[tex]Rate = -9.36[/tex] for year 1 to 5

This means that the number of pikas reduces by 9.36 yearly

[tex]Rate = -6.48[/tex] for year 6 to 10

This means that the number of pikas reduces by 6.48 yearly

So, we can say that, as year increases the number of pikas reduces.

(B) WHEN THE RATE INCREASES

First, we need to write out the function when the population decreases.

This is given as:

[tex]f(x) = a(1-r)^x[/tex]

Substitute values for a and r

[tex]f(x) = 144(1+8\%)^x[/tex]

Convert % to decimal

[tex]f(x) = 144(1+0.08)^x[/tex]

[tex]f(x) = 144(1.08)^x[/tex]

Next, we calculate the average rate of change for both intervals using:

[tex]Rate = \frac{f(b) - f(a)}{b-a}[/tex]

For 1 to 5:

[tex]Rate = \frac{f(5) - f(1)}{5-1}[/tex]

[tex]Rate = \frac{f(5) - f(1)}{4}[/tex]

Calculate f(5) and f(1)

[tex]f(x) = 144(1.08)^x[/tex]

[tex]f(1) = 144(1.08)^1 = 144*1.08= 155.52[/tex]

[tex]f(5) = 144(1.08)^5 = 144*1.47= 211.68[/tex]

[tex]Rate = \frac{211.68 - 155.52}{4}[/tex]

[tex]Rate = \frac{56.16}{4}[/tex]

[tex]Rate = 14.04[/tex]

For 6 to 10:

[tex]Rate = \frac{f(10) - f(6)}{10-6}[/tex]

[tex]Rate = \frac{f(10) - f(6)}{4}[/tex]

Calculate f(6) and f(10)

[tex]f(x) = 144(1.08)^x[/tex]

[tex]f(6) = 144(1.08)^6 = 228.52[/tex]

[tex]f(10) = 144(1.08)^{10} = 310.89[/tex]

[tex]Rate = \frac{310.89-228.52}{4}[/tex]

[tex]Rate = \frac{82.37}{4}[/tex]

[tex]Rate = 20.59[/tex]

So, we have:

[tex]Rate = 14.04[/tex] for year 1 to 5

This means that the number of pikas increases by 14.04 yearly

[tex]Rate = 20.59[/tex] for year 6 to 10

This means that the number of pikas increases by 20.59 yearly

So, we can say that, as year increases the number of pikas increases as opposed to when the rate reduces.

Answer:

g(h(n)) = 4n² + 12n

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Distributive Property

Algebra I

Algebra II

Step-by-step explanation:

Step 1: Define

g(n) = 4n

h(n) = n² + 3n

g(h(n)) is n = h(n)

Step 2: Find