The base value of a numeral system can be founded by counting the number of unique digits or symbols used in the system.
FIND THE BASE VALUEThe base value of a numeral system can be determined by counting the number of unique digits or symbols used in the system. For example, in the base 10 numeral system, which is commonly used in everyday life, the base value is 10 because it uses the digits 0 through 9. In the base 2 numeral system, which is also known as binary, the base value is 2 because it only uses the digits 0 and 1.
Another way to find the base value is to look at the exponent of the highest power of the base in the numeral system. For example, in the number 42 in base 10, the highest power of 10 is 10¹, which is 10. Therefore, the base value is 10. Similarly, in the number 1010 in binary, the highest power of 2 is 2³, which is 8. Therefore, the base value is 2.
It's important to note that when working with different numeral systems, it is essential to know the base value in order to understand the value of the number being represented.
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What must be added to x² + 6x²-x+ 5 to make it exact divisible by (x + 3)
Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Which of the following is
key property of the quadratic parent function?
A. Its vertex is at the origin.
B. It is not a function.
C. It iS not a parabola.
D It is in quadrants III and IV.
Answer:
Step-by-step explanation:
i think it is c
Answer:
A
Step-by-step explanation:
So let's look at each and determine whether they're true or not.
A. It's vertex is at the origin:
This is true! The reason for this is because you can express a quadratic in vertex form as such: [tex]f(x)=a(x-h)+k[/tex] where (h, k) is the vertex. If you remember the parent function is simply: [tex]f(x)=x^2[/tex] which we can express as: [tex]f(x) = (x-0)+0[/tex] meaning the vertex is at (0, 0). This also intuitively makes sense, the x^2 will only output positive values for real numbers, so when x<0, f(x) is still going to be positive because it's squaring the negative, so that means when you go from -5 to -4, even though you increased x by 1, the f(x) decreases by 1, since it's squaring the value to get a positive value. The lowest value this can output is 0 because 0^2 = 0. This means you vertex is at the origin.
B. It is not a function:
So the quadratic parent function only outputs 1 value for each input, although it isn't a one-to-one function, meaning that each output isn't unique, but each input still only outputs 1 output, which makes this a function
C. It is not a parabola:
parabolas are expressed as quadratic equations, so this is false.
D. It is in quadrants ||| and IV:
This is not true since the parent function opens upwards and has a vertex at (0, 0) so it will only be in quadrant I and II. I'll provide a diagram showing this.
seven twelfths plus two twelfths equals one half 1 one and one half 2
Answer:
the answer is 3/4 because 7/12 + 2/12 is 9/12 which simplified is 3/4
Step-by-step explanation:
Use the quadratic formula to solve the equation below.
x (x + 16) = − 64
Damian has 74 m of fencing to build a four-sided fence around a
rectangular plot of land. The area of the land is 342 square meters.
Solve for the dimensions (length and width) of the field.
Answer:
Step-by-step explanation:
Let the length be l and the width be y. We have the following:
l + w = 37
lw = 342
From here, we can find the factor pairs of 342, and see which pair has a sum of 37. Our desired pair is 18 & 19, so the dimensions of the field are 18 by 19 feet.
THIS IS VERY HARD PLSSS
Answer:
[tex]y=3\sqrt{x-1}-7[/tex]
Step-by-step explanation:
We are given the function [tex]y=\sqrt{x}[/tex]. Let's apply each transformation separately and see what we get. First, let's apply the vertical shift. We are told that the graph shifts downwards by 7 units. In other words, when x is 0, y should be -7 instead of 0. We can accomplish that by changing the y-intercept of the graph and subtracting our function by 7: [tex]y=\sqrt{x} -7[/tex]. Notice that the -7 is outside the square root.
Next, we can apply the horizontal transformation. We are told that the graph shifts to the right 1 unit. This means that, for [tex]y=\sqrt{x}[/tex], if y is 0, x should be 1. We can accomplish this by doing [tex]y=\sqrt{x-1}[/tex] (if x = 1, y will be 0). Now, we can combine the two transformations we have done so far: [tex]y=\sqrt{x-1}-7[/tex].
Lastly, we need to vertically stretch the function by a factor of 3. All we have to do here is multiply sqrt(x) by 3 (this way, if x is equal to 1, y should be 3 instead of 1 (3 times x)). So, we get something like this: [tex]y=3\sqrt{x}[/tex]. Now, we can combine all of the transformations we did to get our final answer:
[tex]y=3\sqrt{x-1}-7[/tex]
Factor the greatest common factor: −6m2 18m − 36. −6(m2 − 3m 6) −1(6m2 − 18m 36) −6m(m2 − 3m 6) −6(m2 3m − 6)
Answer:
Step-by-step explanation:
−6m2 18m − 36
= -6(m2 - 3m + 6)
please help me with this problem
please show steps so i know for next time
=========================================================
Explanation:
You could use the AC method to factor this, but the quadratic formula is the most efficient route in my opinion. This will avoid any guess-and-check.
Compare the original equation to the form [tex]a\text{x}^2 + b\text{x} + c = 0[/tex]
We have a = 9, b = 6, and c = -8
Those values lead to...
[tex]\text{x} = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{x} = \frac{-6\pm\sqrt{(6)^2-4(9)(-8)}}{2(9)}\\\\\text{x} = \frac{-6\pm\sqrt{324}}{18}\\\\\text{x} = \frac{-6\pm18}{18}\\\\\text{x} = \frac{-6+18}{18} \ \text{ or } \ \text{x} = \frac{-6-18}{18}\\\\\text{x} = \frac{12}{18} \ \text{ or } \ \text{x} = \frac{-24}{18}\\\\\boldsymbol{\text{x} = \frac{2}{3} \ \text{ or } \ \text{x} = -\frac{4}{3}}\\\\[/tex]
Side notes:
2/3 = 0.667 approximately-4/3 = 1.333 approximatelySince your teacher did not give rounding instructions, I'll assume s/he wants the fraction form of each x value (rather than the decimal form). Be sure to follow all instructions given, and ask for clarification if need.To confirm the solutions, replace every copy of x with either 2/3 or -4/3 (pick one value only). Simplifying the left hand side should lead to 0. I'll let you check each answer.HELPPP DOES ANYONE KNOW THE ANSWER???
Answer:
B
Step-by-step explanation:
solve equation.
Mateo teaches a continuing education class at the library on tuesday nights. he estimates that 75% of his students are satisfied or very satisfied with the class. last week, he asked a random sample of students to take a survey on their experience in the class. however, the results showed that only 70% indicated that they are satisfied or very satisfied with the class. he decides to randomly survey more of his students. how will mateo know whether his model is valid or not?
The computed value must closely match the real value for a model to be considered valid. If the percentage of pleased or very satisfied students remains close to 75% after Mateo surveys additional students, Mateo's model is still viable. The model is faulty if the opposite is true.
How will mateo know whether his model is valid or not?In general, a valid model is one whose estimated value is close to the real value. This kind of model is considered to be accurate. It must be somewhat near to the real value if it doesn't resemble the real value.
If the findings of the survey are sufficiently similar to one another, then the model may be considered valid.
P1 equals 75%, which is the real assessment of the number of happy pupils
P2 is 70 percent; this represents the second assessment of happy pupils
In conclusion, The estimated value of a model has to be somewhat close to the real value for the model to be considered valid. If the number of students who are either pleased or extremely satisfied remains close to 75 percent following Mateo's survey of more students, then Mateo's model is likely accurate. In any other scenario, the model cannot be trusted.
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Find the volume of the prism. Round to the nearest tenth if necessary.
Answer:
14.7 (Because you asked for no units)
Step-by-step explanation:
The volume of this triangular prism is 1/2 BHL
0.5 * 3.5 * 2 * 4.2 = 14.7 ft^3
Use the grouping method to factor this polynomial completely. 3x^3+12x^2x+8
Answer:171x+8
Step-by-step explanation:
3x^3+12x^2x+8
=27x+144x+8
=171x+8
Please explain your steps as I'm a bit confused about the process... thanks!!!
Answer:
x = -1.5056Step-by-step explanation:
To solve this equation log both sides and apply log rules.
[tex]14^{x-7}=12^{6x}[/tex][tex]log14^{x-7}=log12^{6x}[/tex][tex](x - 7)log14=6xlog12[/tex]Substitute the values of logs:
[tex](x - 7)*1.1461 = 6x*1.0791[/tex]Solve it as linear equation:
[tex]1.1461 x - 7*1.1461 = 6.4746x\\[/tex][tex]1.1461x - 6.4746x = 8.0227[/tex][tex]-5.3285x = 8.0227[/tex][tex]x = 8.0227/-5.3285[/tex][tex]x = -1.5056[/tex]In a professional division of a Hockey league, there are 9 total teams. How many different rankings are possible at the end of the year
The half-life of a radioactive material is about 2 years. How much of a 5.0 kg sample of this material will remain after 4 years
The remaining amount after 4 years is 1.25 kg
How to determine the remaining amount?The half life of a function is represented as:
[tex]A = A_o * (1/2)^{t/h}[/tex]
Where
Ao represents the initial amount
So, we have:
[tex]A = 5 * (1/2)^{t/2}[/tex]
In 4 years, t = 4.
So, we have:
[tex]A = 5 * (1/2)^{4/2}[/tex]
This gives
[tex]A = 5 * (1/2)^2[/tex]
Evaluate the expression
A = 1.25
Hence, the remaining amount after 4 years is 1.25 kg
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Which of these is a characteristic of certificates of deposit (CDs)? O They are always offered at variable rates They last for a set period of time They can be opened with any amount of money O They allow access to the money at any time without penalty
The characteristic of certificates of deposit (CDs) is that it last for a set period of time and is denoted as option B.
What is Certificate of deposit?This is also referred to as time deposit and is characterized by a lump sum being saved at a fixed period of time and is stricter than the normal savings system.
This type of savings has a fixed interest rate and can't be withdrawn before the maturity date unlike savings account which can be accessed at any point in time which makes it unique and is therefore the most appropriate choice.
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Suppose that f'(4) = 3 , g'(4) = 7 , g(4) = 4 and g(x) not= to 4 for xnot= to 4 . then cmpute lim xgose to 4 f(g(x))/x-4-f(4)/x-4
It looks like the limit you want to compute is
[tex]\displaystyle \lim_{x\to4} \frac{f(g(x)) - f(4)}{x-4}[/tex]
Since [tex]g(4)=4[/tex], this limit corresponds exactly to the derivative of [tex](f\circ g)(x) = f(g(x))[/tex] at [tex]x=4[/tex]. Recall that
[tex]f'(a) = \displaystyle \lim_{x\to a} \frac{f(x) - f(a)}{x - a}[/tex]
By the chain rule,
[tex](f\circ g)'(4) = f'(g(4)) \times g'(4) = f'(4) \times g'(4) = 3\times7 = \boxed{21}[/tex]
Since [tex]g'(4)[/tex] exists, [tex]g[/tex] is differentiable at [tex]x=4[/tex] so it must be continuous.
(The two triangles are not the same)
In the quadrilateral ABCD, in which angle A = 60° and angle B = 50°. The measure of angles C and D are,
∠C = 200° and ∠D = 50°
In the quadrilateral ABCD, it is given that,
A = 60° and angle B = 50°
Now, since AC is the angle bisector of angles A and C, we have,
∠DAC = ∠BAC ......... (1)
And ∠ACD = ∠ACB ............ (2)
Also, AC divides the quadrilateral ABCD into two triangles, ΔABC and ΔACD.
In ΔABC, ∠BAC = 30° [from (2)] and ∠ABC = 50°
Using angle sum property of a triangle, we have,
∠BAC + ∠ABC + ∠ACB = 180°
⇒ 30° + 50° + ∠ACB = 180°
80° + ∠ACB = 180°
∠ACB = 180° - 80°
∠ACB = 100°
From (1), ∠ACD = ∠ACB = 100°
∠C = ∠ACD + ∠ACB
⇒ ∠C = 100° + 100°
∠C = 200°
Now, according to the angle sum property of a quadrilateral,
∠A + ∠B + ∠C + ∠D = 360°
Substituting the values of ∠A, ∠B, and ∠C, we get,
60° + 50° + 200° + ∠D = 360°
310° + ∠D = 360°
∠D = 360° - 310°
∠D = 50°
Hence, in quadrilateral ABCD, ∠C = 200° and ∠D = 50°
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The average household income for a recent year was $30,000. five years earlier the average household income was $24,500. assume sample sizes of 34 were used and the population standard deviation of both samples were $5928. at 5% level of significance is there enough evidence to believe that the average household income has increased?
Using hypothesis test, we conclude that there is evidence to believe that the average household income has increased.
According to the question,
The average household income for a recent year (x₁⁻) = $30,000
The average household income for a recent year (x₂⁻) = $24,500
sample sizes n₁ = n₂ = 34
standard deviation of both samples were $24,500. Thus, s₁ = s₂ = $5928.
Null hypothesis: There is no evidence to believe that the average household income has increased.
H₀ : μ₁ ≤ μ₂
Alternative hypothesis: There is evidence to believe that the average household income has increased.
H₁: μ₁ > μ₂
To check hypothesis we have the formula
Standard error= [tex]\sqrt{\frac{s_{1} ^{2} }{n_{1} } + \frac{s^{2} _{2} }{n_{2} } }[/tex]
= [tex]\sqrt{2067128.4706}[/tex]
= 1437.7512
Thus, standard error is $1437.7512.
Formula for test statistic = [(x₁⁻ - x₂⁻) - (μ₁ - μ₂)]/standard error
= [(30000 - 24500) - 0]/1437.7512
= 3.8254
The critical value of z at 5% level of significance is 1.6449.
Here, the calculated value is greater than the critical value so we reject H₀.
Hence using hypothesis test, we conclude that there is evidence to believe that the average household income has increased.
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The seismic activity density of a region is the ratio of the number of earthquakes during a given time span to the land area affected. A state had 424 earthquakes over a given time span and a land area of 71,300 square miles.
What is the seismic activity density for this state? Round to the nearest ten thousandth, if necessary.
0.0046 earthquakes per square mile
0.0059 earthquakes per square mile
168.1604 earthquakes per square mile
179.0049 earthquakes per square mile
Using proportions, it is found that the seismic activity density for this state is of 0.0059 earthquakes per square mile.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
In this problem, the density is the proportion given by the number of earthquakes divided by the area, hence:
424/71,300 = 0.0059 earthquakes per square mile.
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Answer: Using proportions, it is found that the seismic activity density for this state is of 0.0059 earthquakes per square mile.
Step-by-step explanation:
Richard wants to weed 33% of his garden today. The total garden is 144 square yards. How many square yards should Richard weed to reach his goal?
What are the potential solutions of log4X+log4(x+6)=2?
Ox=-2 and x=-8
Ox=-2 and x = 8
O x=2 and x=-8
Ox=2 and x=8
Answer:
x = 2 ; x = -8
Step-by-step explanation:
Log rule: Log a + log b = log a*b[tex]\sf \ log_4 \ x +log_4 \ (x +6) = 2\\\\ log_4 \ (x)*(x +6) = 2\\\\[/tex]
log₄ ( x² + 6x) = 2
4² = x² + 6x
x² + 6x - 16 = 0
x² - 2x + 8x - 16 = 0
x(x - 2) + 8(x - 2) = 0
(x - 2) (x + 8) = 0
x - 2 = 0 or x + 8 = 0
x = 2 or x = - 8
A cylindrical pain can has a diameter of 12 centimeters and height of centimetrs which is closest to the volume of the paint can in cubic centimeters
The volume of the cylinder having diameter 12 cm and height of 4 cm is 452 [tex]cm^{3}[/tex].
Given diameter of cylinder be 12 cm and height of cylinder be 4cm.
We are required to find the volume of cylinder.
Volume is the quantity of substance a container can hold in its capacity.
Diameter=12 cm
Radius=6 cm (Radius is always equal to half of diameter)
Volume of cylinder=π[tex]r^{2} h[/tex]
We have to just put the values of r, h and π in the formula to get the volume of the cylinder.
Volume=π[tex](6)^{2} 4[/tex]
=3.14*4*36
=452.57 [tex]cm^{3}[/tex]
After rounding off we will get 452 [tex]cm^{3}[/tex].
Hence the volume of cylinder is 452 [tex]cm^{3}[/tex].
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Question is incomplete as it should include height of cylinder be 4cm.
11. Find the slope of the line that passes through the pair of points. (1, 7), (10, 1)
Answer:
m = [tex]-\frac{2}{3}[/tex]
Step-by-step explanation:
m = [tex]\frac{y2-y1}{x2-x1}[/tex]
m = [tex]\frac{1-7}{10-1}[/tex]
m = [tex]\frac{-6}{9}[/tex]
m = [tex]-\frac{2}{3}[/tex]
Answer:
-2/3
Step-by-step explanation:
slope = (y_2 - y_1)/(x_2 - x_1)
slope = (1 - 7)/(10 - 1)
slope = -6/9
slope = -2/3
Which explicit formula generates the infinite sequence 2, 9, 28, 65, 126,.?
O a-n²
O a-n²+1
O a-n³
O a-n³+1
Mark this and return
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Answer:
n^3 + 1.
Step-by-step explanation:
Each term is 1 more than a perfect cube.
2 = 1^3 + 1
9 = 2^3 + 1
28 = 3^3 + 1
65 = 4^3 + 1
126 = 5^3 + 1
So the explicit formula is n^3 + 1.
The explicit formula that generates the given sequence is indeed aₙ = n³+1.
What is Sequence?Sequence is an enumerated collection of objects in which repetitions are allowed and order matters.
The nth term of the sequence can be obtained by substituting n = 1, 2, 3, ... into the expression n³+1:
a₁ = 1³+1 = 2
a₂ = 2³+1 = 9
a₃ = 3³+1 = 28
a₄ = 4³+1 = 65
a₅ = 5³+1 = 126
Hence, the explicit formula that generates the given sequence is indeed aₙ = n³+1.
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Instructions: Find the missing side. Round your answer to the nearest tenth.
Using the sine ratio, the length of the missing side is: 11.8.
How to Find Missing Side Using the Sine Ratio?The sine ratio is, sin ∅ = opposite/hypotenuse.
Given the following:
∅ = 24°
Opposite = x
Hypotenuse = 29
sin 24 = x/29
x = (sin 24)(29)
x = 11.8
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The cross-sectional areas of a triangular prism and a right cylinder are congruent. The triangular prism has a height of 5 units, and the right cylinder has a height of 3 units. Which conclusion can be made from the given information? (1 point) The volume of the prism is half the volume of the cylinder. The volume of the prism is twice the volume of the cylinder. The volume of the prism is equal to the volume of the cylinder. The volume of the prism is not equal to the volume of the cylinder.
Answer:
Step-by-step explanation:
The volume of the prism is not equal to the volume of the cylinder.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Let x represent the cross sectional areas of a triangular prism and a right cylinder.
Volume of cylinder = cross sectional area * height = 3 * x = 3x
Volume of triangular prism = cross sectional area * height = 5 * x = 5x
The volume of the prism is not equal to the volume of the cylinder.
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Can we write 0 in the form of p by q?
Answer:
Yes
=======================
Any rational number can be written in the form of p/q as per definition of a rational number.
In case with zero, it can be:
p = 0,q = any number other than zero.So, we'll have:
0/any number = 0As a fundraiser, the music boosters wrapped gifts at the mall one weekend. out of the 100 gifts they wrapped, 310 3 10 were for weddings, and 37100 37 100 were for baby showers. the rest of the gifts were for birthdays. what fraction of the gifts was for birthdays? enter your answer in the boxes.
For birthday events 33/100 gifts were packed by the music boosters at the mall.
Calculation of the fractionTotal number of gift items = 100
For the wedding purpose,out of 100 gifts, 3/10 number of gifts were boxed = 3/10*100 = 30
For the baby shower, out of 100 gifts, 37/100 gifts were packed = 37
The rest amount of the gift = 100-( wedding + baby shower)
= 100-(30+37) = 33
So, according to the question, these 33 numbers gift was for a birthday.
When it is expressed as a fraction,
The fraction should be = 33/100
Therefore, it is concluded that 33/100 gifts were packed for birthday occasions.
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Find the area of this circle
Answer:
[tex] {75ft}^{2} [/tex]
Step-by-step explanation:
[tex]a = \pi{r}^{2} = 3 {r}^{2} \\ a =3 ({ \frac{10}{2} })^{2} = 3 \times {5}^{2} \\ a = 3 \times 25 = 75[/tex]
First, we replace π with 3, since we were told to.We know 10 is the diameter and the radius is half of the diameter, so we divide 10 by 2.We get 5. 5 squared is the same as (5×5). Finally, we multiply 3 by 25.To start solving this exercise, we obtain as data:
π = 3r = 10 ft²a = ?To find the area of the circle. We apply the following formula: A =π r², where
a = areaπ = pir = radiusWe substitute our data in the formula and solve:
Substituting values into the equation:
[tex]\boldsymbol{\sf{A=3*(10 \ ft)^{2} }}[/tex]Taking the square root:
[tex]\boldsymbol{\sf{A=3*100 \ ft^{2} }}[/tex]Multiplying
[tex]\boxed{\boldsymbol{\sf{A=300 \ ft^{2} }}}[/tex]Therefore, the area of the circle is 300 ft².