Is X² always positive?

Answers

Answer 1

Yes, the square of any number like X² is always positive.

Define the term positive numbers?Positive numbers are those above zero or to the right of zero on the number line. Be aware that positive numbers can be either integers or fractions, irrational numbers, or both. For instance, the square root of 2 has an infinite number of non-repeating digits.A number can be multiplied by itself to find its square.

Example:

The result of two negative numbers is always positive, as explained.When two negative numbers are added together, the result is always positive.

If we calculate the square of a negative number, let's say -x, where x > 0, then (-x) (-x) = x².

Here, x² > 0.

Hence, the square of any number like X² is always positive.

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Related Questions

5th grade algebra. Pls help with these am offering brainliest + bonus points! :D

Answers

Answer:

3. 6 5. 3

Step-by-step explanation:

PEMDAS

3. 0.5 x (24) / 3 + 2

12/3 +2

4 + 2

6

5. (4 + 6/3) x 0.5

(4 + 2) x 0.5

6 x 0.5

3

Answer: number 3. is 6 and number 5. is 3

hope it helped

Solve:
-5/2 a + 5 = 25

a =

Answers

Answer:

A = -8

You're welcome! :)

Answer: a = -8

Step-by-step explanation:

Combine multiplied terms into a single fraction

then find a Find common denominator for the fraction

then Combine fractions with common denominator,

Multiply the numbers, Multiply all terms by the same value to eliminate fraction denominators, Cancel multiplied terms that are in the denominator,

Multiply the numbers making your equation like this -5a+10=50

subtract 10 by both sides and then you will need to simplify making it

-5a + 40 then you divide them both by the same factor which is -5 then you simplify again making the answer to your question -8  

Someone help me out on these 2 geometry questions, ASAP!!!
“Complete the proofs”

Answers

Question 11

1) [tex]\overline{BA} \cong \overline{FA}[/tex], [tex]\angle 1 \cong \angle 2[/tex] (given)

2) [tex]\angle A \cong \angle A[/tex] (reflexive property)

3) [tex]\triangle AEB \cong \triangle ACF[/tex] (ASA)

4) [tex]\overline{AC} \cong \overline{AE}[/tex] (CPCTC)

Question 12

1) Isosceles [tex]\triangle ACD[/tex] with [tex]\overline{AC} \cong \overline{AD}[/tex], [tex]\overline{BC} \cong \overline{ED}[/tex] (given)

2) [tex]\angle ACD \cong \angle ADC[/tex] (angles opposite congruent sides in a triangle are congruent)

3) [tex]\angle ACB[/tex] and [tex]\angle ACD[/tex] are supplementary. [tex]\angle ADC[/tex] and [tex]\angle ADE[/tex] are supplementary (angles that form a linear pair are supplementary)

4) [tex]\angle ACB \cong \angle ADE[/tex] (supplements of congruent angles are congruent)

5) [tex]\triangle ABC \cong \triangle AED[/tex] (SAS)

6) [tex]\overline{AB} \cong \overline{AE}[/tex] (CPCTC)

7) [tex]\triangle ABE[/tex] is an isosceles triangle (a triangle with two congruent sides is isosceles)

Note: I changed the names of the segments in Question 11 because of the word filter.

On a piece of paper, graph y ≤ -2x. Then determine which answer matches
the graph you drew.

Answers

Answer: Graph provided below.

Step-by-step explanation:

Draw the graph of y = -2x and then shade the region below it because y is less than and equal to -2x. To draw the graph of y = -2x, plug in x values into the equation and plot the corresponding coordinates. See this video on how to graph linear equations:

https://www.khanacademy.org/math/in-in-grade-9-ncert/xfd53e0255cd302f8:linear-equations-in-two-variables/xfd53e0255cd302f8:graph-of-a-linear-equation-in-two-variables/v/graphs-of-linear-equations

1/5n+3/5n=7/9

Can you help?

Answers

The value of n in 1/5n+3/5n=7/9 is 35/36

How to solve the equation?

The equation is given as:

1/5n+3/5n=7/9

Multiply through by 5

n + 3n = 35/9

Evaluate the sum

4n = 35/9

Divide both sides by 4

n = 35/36

Hence, the value of n in 1/5n+3/5n=7/9 is 35/36

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If A and B are independent events and P(A)=0.25 and P(B)=0.333, what is the probability P(ANB)?
a) 1.33200
b) 0.75075
c) 0.08325
d) -0.0830

Answers

The probability P(ANB), that is, P(A ∩ B), given that A and B are independent events and P(A) = 0.25 and P(B) = 0.333 is 0.08325. Hence, option C is the right choice.

For any two events A and B, the probability of event A and B, that is, P(A ∩ B) is given as:-

When the events are dependent, P(A ∩ B) = P(A).P(B|A).When the events are independent, P(A ∩ B) = P(A).P(B).

In the question, we asked the probability P(ANB), that is, P(A ∩ B), given that A and B are independent events and P(A) = 0.25 and P(B) = 0.333.

We know that when the events are independent, P(A ∩ B) = P(A).P(B).

Thus, P(A ∩ B) = (0.25)*(0.333),

or, P(A ∩ B) = 0.08325.

Thus, the probability P(ANB), that is, P(A ∩ B), given that A and B are independent events and P(A) = 0.25 and P(B) = 0.333 is 0.08325. Hence, option C is the right choice.

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Based on the estimated cost of college from step 1, determine how you are going to pay for college. You will need to do some research to learn about the various methods used to pay for college costs.



Complete the table below to document your financial needs.

Source Estimated Need
grants
loans
scholarships
work-study
other

Answers

This is a budgeting exercise. Based on the estimated cost of college which was set at $58,000, the following steps indicate how I intend to pay for college:

Scholarship - 70%   = $40,600Work Study - 17.2% = $10,000Loan - 12.76%         = $7, 400

                                        $58,000

What is budgeting?

Budgeting is simply the process of outlining the total expense requirements of an individual person or a corporate entity and how those expenses will be satisfied and efficiently allocated.

From the above, the total sum of $58,000 will be satisfied from three sources:

ScholarshipsWork-Study; andLoan.

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Find the missing side length of the triangle.

Answers

SOLUTION :

= 5² + 5²

c² = 25 + 25

c² = 50

c = 50 ft

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B.) what fraction of the cost is spent on food and entertainment? food- 17% entertainment- 24% they have 3000 dollars

Answers

The quantity spent on amusement = 720

quantity spent on food = 510

they have got 3000 for vacation.

amount spent on food = 17% of 3000

⇒ 17/one hundred*3000

17*30= 510

amount spent on amusement = 24% of 3000

⇒ 24/100*3000

24*30= 720

A person would possibly account for a terrible temper or general rude conduct by explaining that bad site visitors affected the morning travel, for example. someone who is exceeded over for a promotion would possibly rationalize the frustration by means of claiming to not have desired so much responsibility in the end.

To carry into accord with cause or reason something to appear reasonable especially: to characteristic (one's actions) to rational and creditable motives without evaluation of proper and especially unconscious motives he attempted to rationalize his merciless behavior. intransitive verb.

Ego protection wherein apparently logical motives are given to justify unacceptable behavior that is influenced by subconscious instinctual impulses. In the psychoanalytic concept, such conduct is considered to be a defense mechanism.

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Which
expression is equivalent to
(x^6y^8)^3/x^2y^2

Answers

Answer: [tex]x^{16}y^{22}[/tex]

Step-by-step explanation:

[tex]\frac{(x^6 y^8)^3}{x^2 y^2}=\frac{x^{18}y^{24}}{x^2 y^2}=x^{16}y^{22}[/tex]

Georgie buys a pack of chocolate which has 18 small chocolate bars. She ate three bars in the morning, Later in the
day, Georgie's brother ate three fifth of the chocolates bar that were left, what fraction of the chocolate bars is left in
the packet?

Answers

So if Georgie inceptively eats three small chocolate bars that would make fifteen remaining.

So if Georgie’s brother ate 3/5 you would figure out how many candy bars he ate by:

15 multiplied by the 3/5 = 9

So out of the 18 candy bars Georgie ate 3 and Georgie’s brother ate 9.

Figure TUVS is a parallelogram.

Parallelogram T U V S is shown. Angle U is (4 x + 9) degrees and angle V is (6 x minus 29) degrees.

Which angles equal 91°?
angles T and V
angles S and U
angles U and V
angles S and T

Answers

Angles T and V of the parallelogram are equal to 91°.

Calculating the Value of x

In the parallelogram TUVS, adjacent angles U and V are given as,

U = 4x+9

V = 6x-29

Since U and V are adjacent angles, and as per the properties of a parallelogram, sum of adjacent angles is equal to 180°.

4x+9 + 6x-29 = 180

10x - 20 =180

10x = 200

x = 20

Calculating the Angles of the Parallelogram

∠U = 4x + 9

∠U = 4(20) + 9

∠U = 80 + 9

∠U = 89°

∠V = 6x - 29

∠V = 6(20) - 29

∠V = 120 - 29

∠V = 91°

According to the properties of a parallelogram, opposite angles are of equal measure.

∠T = ∠V and ∠S = ∠U

⇒ ∠T = 91° and ∠S = 89°

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Answer:

angles t and v

Step-by-step explanation:

edge

What is the coordinate point of the linear function 5x+3y=15

Answers

Answer: Y-intercept: (0,5) X-intercept: (3,0)

Step-by-step explanation: Set x and y equal to 0.

What is the solution to this system of equations x-2 y=15 2x+4y=-18

Answers

Answer:

(3, - 6 )

Step-by-step explanation:

x - 2y = 15 ( add 2y to both sides )

x = 2y + 15 → (1)

2x + 4y = - 18 → (2)

substitute x = 2y + 15 into (2)

2(2y + 15) + 4y = - 18 ← distribute parenthesis and simplify left side

4y + 30 + 4y = - 18

8y + 30 = - 18 ( subtract 30 from both sides )

8y = - 48 ( divide both sides by 8 )

y = - 6

substitute y = - 6 into (1)

x = 2(- 6) + 15 = - 12 + 15 = 3

solution is (3, - 6 )

Answer:

x is 3 y is -6 I really hope this helps

WILL MAKE BRAINLIEST
5. If m2ABC= 180°, is the angle right, straight, obtuse, or acute?
obtuse
acute
straight
right

Answers

Straight line because it’s 180 degrees.

How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and contain no three consecutive 1s

Answers

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

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The sum of all but one interior angle of a heptagon is 776°. What is the measure of the final interior angle? 42º 56º 124º 304º

Answers

The measure of the seventh interior angle of the heptagon is 124°. (Correct choice: C)

What is the measure of the missing interior angle in a heptagon?

Heptagons are polygons with seven sides, seven vertices, seven interior angles and seven central angles. Herein we know the value of the sum of six interior angles and we need to know the measure of the seventh interior angle. We can determine the measure of the seven interior angles by using the following expression:

θ = (n - 2) · 180°, where n is the number of sides of the polygon.     (1)

If we know that n = 7, then sum of the internal angles in the heptagon is:

θ = (7 - 2) · 180°

θ = 900°

And the measure of the final interior angle is found by subtraction:

θ₇ = 900° - 776°

θ₇ = 124°

The measure of the seventh interior angle of the heptagon is 124°. (Correct choice: C)

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id love some help!!!

Answers

Answer : 12.56 inches²
Explanation :
Diameter is twice the radius.
Radius = 4 ÷ 2 = 2 inches
Area = 3.14r² = 3.14 × 2² = 12.56 inches²

Answer:

Circle:

circle is a special kind of ellipse in which the eccentricity is zero and the two foci are coincident.

[tex] \sf{formula \: to \: find \: the \: area \: is}[/tex]

[tex] \large{ \boxed{ \tt{A = {\pi \times r}^{2} }}}[/tex]

[tex] \sf{formula \: to \: find \: perimeter \: of \: circle \: is}[/tex]

[tex] \large {\boxed{ \tt{p = 2 \times \pi \times r}}}[/tex]

Continue to Question.

If the radius is 2 inches and

Use 3,14 for π So:

[tex] \tt{ {A = \pi \times {r}^{2} }}[/tex]

[tex] \tt{A = (3.14 \times 2 \times 2)} [/tex]

[tex] \red{ \boxed{ \bold{A = 12.56 {inches}^{2} }}}[/tex]

So, The Area of circle is 12.56inches²

Simplify 4/9 + 1/3
A 5/12
B 7/9
C 1 1/9
D 15/9

Answers

Answer:

B) 7/9

Step-by-step explanation:

Fraction addition: If the denominators are not same, find the LCM of the denominators.

          LCM of 3 and 9 is 9.

Now, find equivalent fractions with denominator as 9.

          [tex]\sf \dfrac{1}{3}=\dfrac{1*3}{3*3}\\\\[/tex]

              [tex]\sf =\dfrac{3}{9}[/tex]

Now add.

      [tex]\sf \dfrac{4}{9}+\dfrac{1}{3}=\dfrac{4}{9}+\dfrac{3}{9}\\\\[/tex]

                 [tex]\sf =\dfrac{7}{9}[/tex]

4/9 + 1/3 = (12 + 9)/9x3 = 21/27
7/9

If RT = 90, find the length of RO. (SU = 25)(SO is perpendicular to RT)

Answers

In the given figure of circle, if RT = 90, SU = 25, and SO is perpendicular to RT, the length of the radius RO is 53.

In the given figure,

RT = 90

SU = 25

SO is perpendicular to RT.

Here, SO and RO are the radii of the circle and RT is a chord.

The length of the chord, RT is given as,

RT = 2 √(r² - d²)

Here, r is the radius and d is the distance of the chord RT from the center O.

Radius, r = RO and distance, d = OU

∴ RT = 2 √(RO² - OU²)

Substituting RT = 90 in the above equation, we get,

90 = 2 √[(RO)² - (OU)²]

√[RO)² - (OU)²]  = 45

(RO)² - (OU)² = 45²

(RO)² - (OU)² = 2025 ........... (1)

Now, OU = SO - SU   [From the figure]

⇒ OU = SO - 25

Substituting OU = SO - 25 in equation (1), we obtain,

(RO)² - (SO - 25)² = 2025

(RO)²- [(SO)² + (25)² - 2(SO)(25)] = 2025    [ ∵ (a-b)² = a²+b²-2ab ]

(RO)²- (SO)² - (25)² + 50(SO) = 2025 ........... (2)

Since, RO and SO both are the radii of the same circle, we have,

SO = RO

Thus, we can write equation (2), as follows,

⇒ (RO)² - (RO)² - (25)² + 50(RO) = 2025

⇒ -625 + 50RO = 2025

⇒ 50RO = 2025 + 625

⇒ RO = 2650/50

⇒ RO = 53

Hence, the length of the radius RO of the given circle is 53.

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Use cylindrical coordinates to find the volume of the region in the first octant bounded by the cylinder r and the plane z.

Answers

The volume of the region in first octant is 9.

Given that the region in the first octant bounded by the cylinder r=3 and the plane z=y.

The graph is shown below.

we are given that first octant is bound by r=3  and z=y

We will use the conversion formula, i.e.

x²+y²=r² where x=rcos∅ and y=rsin∅

Firstly, we will find bound octant

0≤∅≤π/2

0≤r≤3

0≤z≤r sin∅

Now, we can set up integral

[tex]V=\int_{0}^{\frac{\pi}{2}}\int_{0}^{3}\int_{0}^{rsin(\theta)}rdzdrd\theta[/tex]

Further, we can solve it.

Firstly, we solve integral for z then we solve for r and after that we will solve for ∅, we get

[tex]\begin{aligned}V&=\int_{0}^{\frac{\pi}{2}}\int_{0}^{3}r^2 \sin (\theta)dr d\theta\\&=\int_{0}^{\frac{\pi}{2}}\frac{1}{3}r^3\sin \theta d\theta\left|_{0}^{3}\\ &=\int_{0}^{\frac{\pi}{2}}\left(\frac{1}{3}\sin\theta d\theta(27-0)\right)\\ &=\int_{0}^{\frac{\pi}{2}}9\sin \theta d\theta\\ &=0-(-9)\\ &=9\end[/tex]

Hence, the volume of the region in the first octant is bounded by the cylinder r=3 and the plane z=y is 9.

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Please help
The area of a circle is 354 cm². Find in degrees and minutes, the angle subtended at the centre of the circle by a 2.9cm arc.

Answers

The angle subtended at the centre of the circle by a 2.9 centimeter arc is  equal to 15° 38.46'/15° 38' 27.6''.

What is the measure of the central angle of a circular section?

In this problem we have to determine the measure of a central angle of a circular section in DMS (Degrees - Minutes - Seconds) system, in which a degree is equal to 60 minutes and a minute to 60 seconds. First, we must calculate the radius of the circle by the area formula:

r = √ (A / π)     (1)

r = √ (354 / π)

r ≈ 10.615 cm

Then, the measure of the central angle in radians is found by the equation of circular arc:

θ = s/r

θ = 2.9 cm / 10.615 cm

θ = 0.273 radians

Finally, we convert the angle into DMS system:

θ = 0.273 rad × 180°/π

θ = 15.641°

Degrees: 15°

Minutes and seconds: 0.641° (38.46')

Minutes: 38'

Seconds: (0.46' = 27.6'')

The angle subtended at the centre of the circle by a 2.9 centimeter arc is  equal to 15° 38.46'/15° 38' 27.6''.

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Area=
Help me please thanks so much :)

Answers

Answer:

48π

Step-by-step explanation:

To find the area of the shaded region, find the area of the large circle and the small circle then subtract.

Large circle:

8²π=64π

Small circle:

4²π=16π

Now subtract 16 from 64.

64-16=48

The area of the shaded region is 48π.

Hope this helps!

Gavin has nickles, dimes, and quarters in the ratio of 1:3:6 if 57 of Gavin's coins are dimes how many nickels and quarters does Gavin have?

Answers

Answer:

Gavin has 19 nickels & 114 quarters

Step-by-step explanation:

N : D : Q

1 : 3 : 6 = 57

x : 57 : y

57 / 3 = 19

1 x 19 : 3 x 19 : 6 x 19

19 : 57 : 114

PLRASE HELPPP PLS IM STUCK

Answers

Answer:

Khan Academy.

Step-by-step explanation:

You can go on khan academy and search up "percentages and numbers." The videos should immediately pop up. there are also lessons if you don't want to risk getting your problem wrong. If you are still confused and do not understand please just comment and I will respond.

Find the vertex and axis of symmetry

Answers

Answer:

Below in bold.

Step-by-step explanation:

f(x) = 2x^2 - 12x + 24

Convert to vertex form:

f(x) = 2(x^2 - 6x) + 24

     = 2[(x - 3)^2 - 9] + 24

     = 2(x - 3)^2 - 18 + 24

     = 2(x - 3)^2 + 6

So the vertex is at (3, 6) and the axis of symmetry is x = 3.

please help!
A) A top-class tennis player can serve the ball, of mass 57 g, at an initial horizontal speed of 50 m/s. The ball remains in contact with the racket for 0.05 s. Calculate the average force exerted on the ball during the serve.

B) A motor car of mass 3000 kg moving with 72 km h-1 made to reduce its speed to 18 km h^-1, in 40 s, by applying brakes. Find the resistive force.

Answers

The average force exerted on the ball during the serve is 57 N the resistive force is -1125 N.

Force

a. Average force

Using  this formula

Force (F) = Mass ×Acceleration

Where:

Mass (m) = 57 g = 57 / 1000= 0.057 Kg

Acceleration (a) = u / t = 50 / 0.05 = 1000 m/s²

Let plug in the formula

Force (F) = 0.057 × 1000

Force (F) = 57 N

b. Resistive force

F = m(v – u) / t

Where:

Force (F) = ?

Mass (m) = 3000 Kg

Initial velocity (u) = 72 Km/h = 72 / 3.6 = 20 m/s

Final velocity (v) = 18 Km/h = 18 / 3.6 = 5 m/s

Time (t) = 40s

Let plug in the formula

Force = 3000(5 – 20) / 40

Force = 3000(-15) / 40

Force=-45,000/40

Force = -1125 N

Therefore the average force exerted on the ball during the serve is 57 N the resistive force is -1125 N.

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Geometric series
2 + 6 + 18 + 54 + ... , find tn

Answers

The function that gives the value of tn for the geometric series is presented as follows;

[tex]t_n = 2 \times 3^{(n - 1)} [/tex]

How can the expression that represents the geometric series be found?

The given geometric series is presented as follows;

2 + 6 + 18 + 54 +...

From the above series, we have;

First term, a = 2

Common ratio, r = 6 ÷ 2 = 18 ÷ 6 = 54 ÷ 18 = 3

The nth term of the geometric series is therefore;

[tex]t_n = a \cdot r^{(n - 1)} [/tex]

Which gives;

[tex]t_n = 2 \times 3^{(n - 1)} [/tex]

Where, tn is the nth term

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1/5n+3/5n=7/9


Can you help?

Answers

The value of n from the given expression is 35/36

Solving linear equation

Given the equation below expressed as:

1/5n+3/5n=7/9

Find the LCM

(n+3n)/5 = 7/9

4n/5 = 7/9

Cross multiply

4n * 9 = 5* 7

36n = 35

n = 35/36

Hence the value of n from the given expression is 35/36

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Transformation example

Answers

Answer:

Rotation, Reflection, Dilation.

Step-by-step explanation:

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