Answer:
18.
Step-by-step explanation:
3 x 6 = 18. He eats 3 slices every 5 minutes so 5 minutes x 6 is half an hour. so 18 is your answer.
If Takaya continues to eat three slices of pizza in five minutes, he could eat 18 slices in half of an hour.
What is the Linear equation in one variable?The Linear equation in one variable is an algebraic equation of degree one.
it can be expressed in the form of Ax +B = 0 where x is a variable, and A and B are two integers.
Takaya can eat three slices of pizza in five minutes.
for half an hour it would be 6 times five minutes.
So, in half an hour Takaya can eat 3 × 6 = 18
Therefore, If Takaya continues to eat three slices of pizza in five minutes, he could eat 18 slices in half of an hour.
Learn more about Linear equations in one variable here:
https://brainly.com/question/2501033
On a middle school basketball court, there is a large circle painted on the
floor. The diameter of the circle is 12 feet. What is the area of the circle?
Jse 3.14 for a
Answer:
113.04 feet²
Step-by-step explanation:
Use the circle area formula, A = [tex]\pi[/tex]r²
Sine the diameter is 12 feet, the radius is 6 feet
Plug in 6 as r into the formula, and 3.14 as pi, then solve:
A = [tex]\pi[/tex]r²
A = (3.14)(6²)
A = (3.14)(36)
A = 113.04
So, the area of the circle is approximately 113.04 feet²
Answer:
113.04 feet²
Step-by-step explanation:
Hope this helps
heelllpppppp plzzzzzzz
Answer:
-2x-6
Step-by-step explanation:
Distribute -2x -2(3) = -2x-6
Which of the following shows the least expensive unit price?
Answer:
A (3 Oranges For $1.02)
Step-by-step explanation:
3 Oranges for $1.02 is $0.34 for each Orange
4 Oranges For $1.52 is $0.38 for each Orange
6 Oranges for $2.46 is $0.41 for each Orange
5 Oranges for $1.75 is $0.35 for each Orange
Which Makes The First One The Cheapest Out Of All
whats .82 in simplest form'
Answer:
0.82 = 82/100
simplified= 41/50
Step-by-step explanation:
Answer:
.8
Step-by-step explanation:
you can round, and since two is a number lower than five, the number stays the same so...
.8
The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in grams, M.
after n half-lives have elapsed if there was an initial mass of 590 grams before decay. Then, use the equation to determine the mass remaining
after 36 hours have passed
Mn = 590. ()": M3 – 148
D
M, = 590 C4)*-* : My ~ 148
Mn = 590 - ()": Mz - 74
Mi = 590 - (1) * + : Mz - 74
The given equations are incomprehensible, I'm afraid...
You're given that osmium-183 has a half-life of 12 hours, so for some initial mass M₀, the mass after 12 hours is half that:
1/2 M₀ = M₀ exp(12k)
for some decay constant k. Solve for this k :
1/2 = exp(12k)
ln(1/2) = 12k
k = 1/12 ln(1/2) = - ln(2)/12
Now for some starting mass M₀, the mass M remaining after time t is given by
M = M₀ exp(kt )
So if M₀ = 590 g and t = 36 h, plugging these into the equation with the previously determined value of k gives
M = 590 exp(36k) = 73.75
so 73.75 ≈ 74 g of Os-183 are left.
Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:
590/8 = 73.75 ≈ 74
please help first image pleaseeeeee............................................
Answer:
1:2
Step-by-step explanation:
what does s equal?pls help me plsss.
Answer:
s< -7/11
Step-by-step explanation:
Solve for C.
5x – 4> 12
OR 12.c +5<-4
Answer:
x>16/5 or c<-1/12
Answer: x≥
x≥16/5 or x≤-3/4
Step-by-step explanation: I think this is the answer but i´m not completely sure of it.
4.6 isosceles and Equilateral Triangles
Step-by-step explanation:
3).20⁰
4).60⁰
180-70+70_180-140__20
Which equation below would be perpendicular to the line y = 2?
4ax + 2bx =??
Es urgente
Answer:
2x(2a + b)
Step-by-step explanation:
4ax+ 2bx
= 2x (2a + b)
Can someone please help me with this problem. Thank you
Answer:
B
Step-by-step explanation:
A linguist at a large university was studying the word length of papers submitted by students en
humanities programs. From a random sample of 25 papers, the linguist counted the number of words
used in each paper. The 95 percent confidence interval was calculated to be (20,995, 22,905).
Assuming all conditions for inference are met, which of the following is a correct interpretation of the
interval?
Answer:
We are 95 percent confident that the mean word length for all papers submitted by students in humanities programs is between 20,995 words and 22,905 words
Step-by-step explanation:
The confidence interval is used to predict the mean for the entire humanities program, not just the sample.
can someone help it’s due in 40mins!!
Answer:
Step-by-step explanation:
[tex] \frac{8}{32} = \frac{4}{16} = \frac{2}{8} = \frac{1}{4} [/tex]
[tex] \frac{27}{54} = \frac{9 }{18} = \frac{3}{6} = \frac{1}{2} [/tex]
[tex] \frac{36}{24} = \frac{18}{12} = \frac{9}{6} = \frac{3}{2} [/tex]
[tex] \frac{30}{60} = \frac{15}{30} = \frac{5}{10} = \frac{1}{2} [/tex]
for what value of x is JKLM a parallelogram?
help i’ll give brainliest
Answer:
Step-by-step explanation:
21
Point B has coordinates (4,1). The x-coordinate of point A is -8. The distance between point A and point B is 13 units. What are the possible coordinates of point A?
Answer:
The possible coordinates of point A are (-8,-4) or (-8,6)
Step-by-step explanation:
The distance between two points is given by the formula
[tex]d = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2} }[/tex]
For point A [tex](x_{1} , y_{1})[/tex]; [tex]x_{1}= -8[/tex] and [tex]y_{1}[/tex] is unknown
For point B [tex](x_{2} , y_{2})[/tex]; (4,1) i.e [tex]x_{2}=4[/tex] and [tex]y_{2}=1[/tex]
and d = 13
Putting the values into the equation,
[tex]13= \sqrt{[(4-(-8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{[(4+8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{12^{2} + (1-y_{1})^{2} }\\13^{2} = 12^{2} + (1-y_{1})^{2} \\169 = 144 +(1-y_{1})^{2}\\169-144 = (1-y_{1})^{2}\\25 = 1 -2y_{1} +y_{1}^{2} \\y_{1}^{2} -2y_{1}+1-25 =0\\y_{1}^{2} -2y_{1}-24 =0\\y_{1}^{2} -6y_{1} + 4y_{1} -24 =0 \\y_{1}(y_{1}-6) +4(y_{1} -6) = 0\\(y_{1}+4)(y_{1}-6) =0\\(y_{1}+4)=0 or (y_{1}-6) =0[/tex]
[tex]y_{1}+4= 0[/tex] or [tex]y_{1}-6 =0[/tex]
[tex]y_{1} =-4[/tex] or [tex]y_{1} = 6[/tex]
Hence, the possible coordinates of point A are (-8,-4) or (-8,6)
Ali and Jake went on a cross-country
trip. They took a train part of the way,
and took a bus the rest of the way. They
traveled a total of 1100 kilometers,
riding on the train 350 more kilometers
than on the bus.
Let x = kilometers traveled by bus. Let
y = kilometers traveled by train.
Answer:
Let x = Kilometers by bus
then x + (x + 350) = 1100
2x = 750
x = 375 by bus
x - 350 + x = 1100
2x = 1450
x = 725 by train
i hope this helps a little bit
A rocket travels in a trajectory given by the equation s = -4.9t 2 + v0t, where s is meters above ground, t is time in seconds and v0 is the initial velocity.
If the intial velocity is 49 m/sec, after how many seconds will the rocket reach its maximum height?
a. 5
b. 15
c. 10
Which equation has a solution of k = 6.5? F -3k = 19.5 G-1 + k = 7.5 H -7k = -45.5 J -2 + k = -8.5
Answer:
i don't know
Step-by-step explanation:
Two data sets contain an equal number of values. The double box and whisker plot represents the values in the data set. Compare the data sets using measures of center and variation.
Answer with explanation:
From the box and whisker plot of seventh grade we have:
The minimum value =6
First quartile or lower quartile i.e. = 14
Median or second quartile i.e. = 18
Third quartile or upper quartile i.e. =22
and maximum value = 26
From the box and whisker plot of eighth grade we have:
The minimum value =22
First quartile or lower quartile i.e. = 26
Median or second quartile i.e. = 30
Third quartile or upper quartile i.e. = 34
and maximum value = 38
a)
The overlap of the two sets of data is as follows.
The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
And the maximum value of seventh grade is same as the lower quartile of eighth grade.
b)
IQR is calculated as the difference of the Upper quartile and the lower quartile
i.e.
so, IQR of seventh grade is:
22-14=8
IQR of seventh grade=8
IQR of eighth grade is:
34-26=8
Hence, IQR of eighth grade=8
c)
The difference of the median of the two data sets is:
30-18=12
Hence, the difference of median is: 12
d)
As the IQR of both the sets is same i.e. 8.
Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:
Hence, the number is : 1.5
Answer:
ive seen this before
Step-by-step explanation:
answer to 8–5+5r+9r+8
Answer:
14r+11
Step-by-step explanation:
3+5r+9r+8
=11+14r
Plz help will mark you brainliest if correct
Answer:
B
Step-by-step explanation:
5/1 is not equal to 6/2 or 7/3 or 8/4
Answer:
The answer would be B instead of D
Michael's class held a food drive for the holidays. There are a total of 29 students in his class. On average, each boy and girl bought 3 cans of food apiece. If the class brought in a total of 87 cans of food, how many boys and how many girls are in the class ?
Answer:
19 girls snd 10 boys
Can someone please help? I will mark brainliest random answers will be reported
Answer:
5.1
Step-by-step explanation:
hope it helps thank you
What is decimal of 78
please please i need this
Answer:
for 3. the answer is 9
for 4. the answer is 12
Step-by-step explanation:
hope this helped!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
what is the sum of (5m+9)+(9b-3)+(8c+6) simplified
meena has 2 boxes the first box weighs 3 and one half pounds the secound box is three fourths the weight of the first box what is the weight of the secound box
Answer:
The second box is 1.125 pounds
Step-by-step explanation:
This is found by multiplying 1.5 by .75
1. y-23=55 2. x-14= -8
3. -15 = n + 18 4. 18.3 + a = 2.7
what are the answers for all of these i need help FAST!!!
Answer:
1. y = 32
2. x = 6
3. -33 = n
4. a = -15.6
Step-by-step explanation:
1.
y-23=55
+23 +23 (23 cancels)
y = 32
2.
x - 14 = -8
+14 +14 (-14 cancels)
x = 6
3.
-15 = n + 18
-18 -18 (18 cancels)
-33 = n
4.
18.3 + a = 2.7
-18.3 -18.3 (18.3 cancels)
a = -15.6
Of 77 third graders, on Monday 3 were absent from Room 101, 4 were absent from Room 102, and 2 were absent from Room 103. How many third graders attended school that day?
Answer:
68
Step-by-step explanation:
Their are 77 total, 77-3= 74-4= 70-2= 68