Answer:
It's the 4d orbital
Explanation:
n is the principal quantum number, n=4, means the 4th orbital, l=2, means 'f'(l=0,1,2,3 which means spdf respectively)
A normal adult jawbone contains 200 mg of Carbon-14 in a living person. If scientists found a jawbone that only had 50mg of Carbon-14, how old is the bone? (The half-life of C-14 is 5730 years).
Carbon-14 is a radioisotope of carbon that decays following first-order kinetics. There are four values of interest in this problem: the "normal" (or original) amount of carbon-14 for a jawbone ([tex]\mathrm{N_0}[/tex]), the actual amount of carbon-14 in a jawbone ([tex]\mathrm{N}[/tex]), the half-life of carbon-14 ([tex]\mathrm{t_{1/2}}[/tex]), and the actual time elapsed ([tex]\mathrm{t}[/tex]) from the original time. There is an equation that ties all these values in together,
[tex]N= N_0 e^{-kt}[/tex]
where k is the rate constant, which, for first-order decay, is related to the half-life by
[tex]k = \dfrac{\ln 2}{ t_{1/2} }.[/tex]
What you want to find here is the time elapsed (t). So, you can substitute the latter equation for k into the k in the former equation to get
[tex]N= N_0 e^{\frac{-\ln 2 \;t}{t_{1/2}}.[/tex]
Rearranging to solve for t, the equation becomes
[tex]t = \left(\dfrac{\ln \dfrac{N_0}{N}}{\ln 2} \right) t_{1/2}.[/tex]
You are given all three of the values necessary to solve for t: The normal amount of carbon-14 is 200 mg; the actual amount of carbon-14 in the sample is 50 mg; and the half-life of carbon-14 is 5730 years. Plugging them into the above equation, we get
[tex]t = \left(\dfrac{\ln \dfrac{200 \text{ mg}}{50 \text{ mg}}}{\ln 2} \right) \left(5730 \text{ years} \right) = 11460 \text{ years}.[/tex]
So the jawbone found is 11460 years old (or 11000 if accounting for sig figs).
It takes 38.6 kJ of energy to vaporize 1.00 mol of ethanol (MW: 46.07 g/mol). What will be ΔSsys for the vaporization of 8.00 g of ethanol at 79.6 °C
Answer:
[tex]\Delta S_{sys}=0.020kJ=20J[/tex]
Explanation:
Hello!
In this case, given the required energy to vaporize 1.00 mol of ethanol as the enthalpy of vaporization:
[tex]\Delta H_{vap}=\frac{38.6kJ}{1.00mol}=38.6kJ/mol[/tex]
We can compute the entropy of the system for the vaporization of 8.00 g of ethanol, by first computing the moles:
[tex]n_{et}=8.00g*\frac{1mol}{46.07g} =0.174mol[/tex]
And then setting up the following expression:
[tex]\Delta S_{sys}=\frac{n_{et}*\Delta H_{vap}}{T}[/tex]
Whereas the temperature is in kelvins; thus, we obtain:
[tex]\Delta S_{sys}=\frac{0.174mol*38.6\frac{kJ}{mol} }{79.6+273.15K}\\\\\Delta S_{sys}=0.020kJ=20J[/tex]
Best regards!
The entropy of the system ([tex]\Delta S_{sys}[/tex]) for the vaporization of 8.00 grams of ethanol at 79.6 °C is 0.0190 kilojoules.
Given the following data:
Quantity of energy = 38.6 kJNumber of moles of ethanol = 1 moleMolar mass of ethanol = 46.07 g/molMass of ethanol = 8 gramsTemperature = 79.6 °CConversion:
Temperature = [tex]79.6 + 273 = 352.6 \;K[/tex]
To find the entropy of the system ([tex]\Delta S_{sys}[/tex]) for the vaporization of 8.00 grams of ethanol at 79.6 °C:
First of all, we would determine the heat of vaporization.
[tex]Heat\; of \;vaporization = \frac{Energy}{moles} \\\\Heat\; of \;vaporization = \frac{38.6}{1}[/tex]
Heat of vaporization = 38.6 kJ/mol.
Next, we would determine the number of moles in 8.00 grams of ethanol:
[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{8}{46.07}\\\\Number\;of\;moles = 0.1737 \;moles[/tex]
Mathematically, the entropy of a system ([tex]\Delta S_{sys}[/tex]) is given by the formula:
[tex]\Delta S_{sys} = \frac{n\Delta H }{T}[/tex]
Where:
n is the number of moles.T is the temperature.[tex]\Delta H[/tex] is the heat of vaporization.Substituting the given parameters into the formula, we have;
[tex]\Delta S_{sys} = \frac{0.1737 \times 38.6 }{352.6}\\\\\Delta S_{sys} = \frac{6.7048 }{352.6}\\\\\Delta S_{sys} = 0.0190 \;kJ[/tex]
Read more: https://brainly.com/question/6366973
can you help me with my science
MQ: A disease affecting which of the following might results in a problem with the production of blood cells ?Plsss help!!
Answer:
B bone marrow
Explanation:
I hope it will help
write the chemical equation of the reaction with a change in colour
Answer:
(i) Change in colour (ii) Change in temperature (iii) Formation of precipitate
Explanation:
(i) Change in colour: Reaction between lead nitrate solution and potassium iodide solution. Pb(NO3)2(aq)+2KI → PbI2(s)+2KNO3(aq) In this reaction, colour changes from colourless to yellow. (ii)Change in temperature: Action of dilute sulphuric acid on zinc. Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2 In this reaction, heat is evolved (iii) Formation of precipitate: Action of barium chloride on sodium sulphate. BaCl2(aq) +Na2SO4(aq) → BaSO4(s) +2NaCl(aq) BaSO4(s)
20 POINTS! NEED HELP!!!
When naming covalent bonds, do all of the following except?
1. use prefixes
2. write the left-most element first
3. add -ide to the end of the 2nd element
4. write the metal first
Answer:
number 2
Explanation:
even though i have never done this i still got it right
Because metals do not form covalent bonds, when naming covalent bonds, all the given rules apply except write the metal first; option 4.
What are covalent bonds?Covalent bonds are bonds formed by the sharing of valence electrons between the atoms involved in the bonding.
In naming covalent bonds, the following rules are applied:
Name the non-metal furthest to the left on the periodic table by its elemental name.Name the other non-metal by its elemental name and an -ide ending.Use the prefixes mono-, di-, tri-, tetra etc. to indicate the number of that element in the molecule.If the first prefix is mono, it is not written add -ide to the end of the second elementFor example, CO₂, is carbon dioxide.
Therefore, when naming covalent bonds, all the given rules apply except write the metal first because metals do not form covalent bonds.
Learn more about covalent bonds at: https://brainly.com/question/12407985
Order the sequence of steps that occur when you add heat to a chemical reaction. Place these steps in a logical order keeping in mind how adding temperature affects the rate of reaction.
The reaction rate of the experiment is recorded and found to have occurred at a faster rate than it did without the addition of heat.
Temperature increases due to the higher ketic energy of particles.
Two chemicals are mixed together and slowly some bubbles appeanr
Heat is added to the experiment with a Bunsen burner.
More collisions of particles occurs due to the increased kinetic energy.
Answer:
C,A,B,D
Explanation:
That's the correct order, hope this helps
suppose you start out with only reactants in a rigid container. if the initial concentration of SO2Cl2(g) is 0.543 M, and 43.6% of this initial concentration remains when the system has reached equilibrium, what are the equilibrium concentrations of each gas in the system
Answer:
Explanation:
From the information given:
The Chemical equation is:
[tex]SO_2Cl_{2(g)} \iff SO_{2(g)} + Cl_{2(g)}\\[/tex]
since 43.6% of the initial concentration remains at equilibrium
Then; the amount of [tex]SO_2Cl_2[/tex] that is being reacted is:
= 0.543 × (100 -43.6)%
= 0.306 M
The ICE table can be computed as follows:
[tex]SO_2Cl_2[/tex] ⇔ [tex]SO_{2(g)[/tex] + [tex]Cl_{2(g)[/tex]
I 0.543 0 0
C 0.306 +0.306 0.306
E 0.237 0.306 0.306
[tex]K_c = \dfrac{[SO_2] [Cl_{2}]}{[SO_2Cl_2]}[/tex]
[tex]K_c = \dfrac{0.306 \times 0.306}{0.237}[/tex]
[tex]K_c = 0.995[/tex]
Thus; the concentration at equilibrium for the species are:
[tex]SO_2Cl_2[/tex] = 0.237 M
[tex]SO_{(2g)[/tex] = 0.306 M
[tex]Cl_{2(g)[/tex] = 0.306 M
73. Wind blows off of the ocean cooling the land near the ocean. This is an example of what type of heat transfer?
convection
induction
conduction
radiation
Help plz
Answer:
Convection
Explanation:
Convection is the circular motion that happens when warmer air or liquid — which has faster moving molecules, making it less dense — rises, while the cooler air or liquid drops down.
Same as in the case of sea breeze where the the lighter wind in surface of land rises up and the cooler wind from the sea comes to fill up that place. This is an example of convection.
Suppose that X represents an arbitrary cation and that Y represents an anionic species. Using the charges indicated in the superscript of X and Y, fill in the remaining blanks below by writing the appropriate subscript for each X and Y to balance the net charge on the ionic XaYb compound formed (where a and b represent positive, whole numbers of X and Y, respectively).
Y- Y2- Y3-
X+
X2+ XY2
X3+
Answer:
See explanation.
Explanation:
Hello!
In this case, when having the cationic and anionic species with the specified charges, in order to abide by the net charge rule, we need to exchange the charges in the form of subscripts and without the sign, just as shown below:[tex]X^{m+}Y^{n-}\rightarrow X_nY_m[/tex]
Thus, for all the given combinations, we obtain:
- Y⁻
[tex]X^+Y^-\rightarrow XY\\\\X^{2+}Y^-\rightarrow XY_2\\\\X^{3+}Y^-\rightarrow XY_3[/tex]
- Y²⁻
[tex]X^+Y^{2-}\rightarrow X_2Y\\\\X^{2+}Y^{2-}\rightarrow X_2Y_2\rightarrow XY\\\\X^{3+}Y^{2-}\rightarrow X_2Y_3[/tex]
- Y³⁻
[tex]X^+Y^{3-}\rightarrow X_3Y\\\\X^{2+}Y^{3-}\rightarrow X_3Y_2 \\\\X^{3+}Y^{3-}\rightarrow X_3Y_3\rightarrow XY[/tex]
Best regards!
mhanifa, can you answer this question pls?
Solve for x.
1. 5(2x +15) = 55
2. 9(6x +4) = 166
3. 3(8x +20) = 356
Answer:
1. x=-2
2. x=65/27
3. x=37/3
Explanation:
Isolate x
1. Divide by 5: 2x+15=11
2x=11-15
x=-2
2. Distribute: 54x+36=166
54x=166-36
x=130/54
Simplify by dividing by 2: x=65/27
3. Distribute: 24x+60=356
24x=356-60
x=296/24
Simplify by dividing by 8: x=37/3
Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 17.2 g of hexane is mixed with 19. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.
Answer:
16.5g of CO₂ could be produced
Explanation:
The combustion of hexane occurs as follows:
C₆H₁₄(l) + 19/2O₂ → 6CO₂ + 7H₂O
Where 1 mole of hexane reacts with 19/2 moles of O₂.
To solve this question we need to find the moles of each reactant in order to find limiting reactant. The moles of the limiting reactant will determine the moles of CO₂ produced:
Moles C₆H₁₄ -Molar mass: 86.18g/mol-:
17.2g hexane * (1mol / 86.18g) = 0.200 moles hexane
Moles O₂ -Molar mass: 32g/mol-:
19g O₂ * (1mol / 32g) = 0.594 moles oxygen.
For a complete reaction of 0.594 moles of oxygen are required:
0.594 moles O₂ * (1mol C₆H₁₄ / 19/2 moles O₂) = 0.0625 moles C₆H₁₄.
As there are 0.200 moles of hexane, hexane is the excess reactant and oxygen the limiting reactant.
The moles of CO₂ produced assuming a yield of 100% -All moles of oxygen react producing carbon dioxide.:
0.594 moles O₂ * (6mol CO₂ / 19/2 moles O₂) = 0.375 moles of CO₂ could be produced. The mass is:
0.375 moles of CO₂ * (44.01g / mol) =
16.5g of CO₂ could be producedPut these elements in order of decreasing electronegativity, with the highest electronegative element as number 1.
a. tin (Sn, Group 14, Period 5)
b. rubidium (Rb, Group 1, Period 5)
c. bromine (Br, Group 17, Period 4)
d. lithium (Li, Group 1, Period 2)
e. cadmium (Cd, Group 12, Period 5)
Answer:the answer is a c and e
Explanation:
MEDICAL FORENSICS
please help me i only get one chance to do this please
Answer:
i think the answer is b temperature
Answer:
no
Explanation:
For the following reaction, 29.9 grams of sulfur dioxide are allowed to react with 6.26 grams of oxygen gas . sulfur dioxide(g) + oxygen(g) sulfur trioxide(g) What is the maximum mass of sulfur trioxide that can be formed? grams What is the FORMULA for the limiting reagent? What mass of the excess reagent remains after the reaction is complete? grams
Answer: a) The maximum mass of sulfur trioxide that can be formed is 31.4 grams
b) The FORMULA for the limiting reagent is [tex]O_2[/tex]
c) Mass of excess reagent remains is 4.8 grams
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} SO_2=\frac{29.9g}{64g/mol}=0.467moles[/tex]
[tex]\text{Moles of} O_2=\frac{6.26g}{32g/mol}=0.196moles[/tex]
[tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)[/tex]
According to stoichiometry :
1 mole of [tex]O_2[/tex] require = 2 moles of [tex]SO_2[/tex]
Thus 0.196 moles of [tex]O_2[/tex] will require=[tex]\frac{2}{1}\times 0.196=0.392moles[/tex] of [tex]SO_2[/tex]
Thus [tex]O_2[/tex] is the limiting reagent as it limits the formation of product and [tex]SO_2[/tex] is the excess reagent as (0.467-0.392) = 0.075 moles or [tex]0.075mol\times 64g/mol=4.8g[/tex] are left.
As 1 mole of [tex]O_2[/tex] give = 2 moles of [tex]SO_3[/tex]
Thus 0.196 moles of [tex]O_2[/tex] give =[tex]\frac{2}{1}\times 0.196=0.392moles[/tex] of [tex]SO_3[/tex]
Mass of [tex]SO_3=moles\times {\text {Molar mass}}=0.392moles\times 80g/mol=31.4g[/tex]
Thus 31.4 g of [tex]SO_3[/tex] will be produced from the given masses of both reactants.
You are boiling water to cook some noodles. You notice bubbles forming on the bottom of the pot. Your brother thinks it is a chemical change. Is he correct?
Yes. The bubbles contain hydrogen and oxygen that separated from the water.
Yes. The bubbles are now filled with air.
No. The water changes into carbon dioxide.
No. It is a physical change when water is heated and is converted into water vapor.
Answer:
i think its Yes. The bubbles contain hydrogen and oxygen that separated from the water but i could be wrong so i would just wait to see if anybody else says anything
Explanation:
In the periodic table what is the 65th element? (pls help me)
Answer:
Terbium
Explanation:
All elements are put in squares on the periodic table. They represent the number of protons in the nucleus. They are the largest number in the square. The elements go up in order. Number 65 is in the row following Calcium. It is about in the middle of that row.A sample of 523.1 mg of impure KBr is treated with an excess of AgNO3 and 814.5 mg of AgBr is obtained. What is the purity of KBr?
Answer:
98.68%
Explanation:
Step 1: Write the balanced equation
KBr + AgNO₃ ⇒ AgBr + KNO₃
Step 2: Calculate the moles corresponding to 814.5 mg (0.8145 g) of AgBr
The molar mass of AgBr is 187.77 g/mol.
0.8145 g × 1 mol/187.77 g = 4.338 × 10⁻³ mol
Step 3: Calculate the moles of KBr needed to produce 4.338 × 10⁻³ moles of AgBr
The molar ratio of KBr to AgBr is 1:1. The moles of KBr needed are 1/1 × 4.338 × 10⁻³ mol = 4.338 × 10⁻³ mol.
Step 4: Calculate the pure mass corresponding to 4.338 × 10⁻³ moles of KBr
The molar mass of KBr is 119.00 g/mol.
4.338 × 10⁻³ mol × 119.00 g/mol = 0.5162 g
Step 5: Calculate the purity of KBr
0.5162 g of KBr are in a 0.5231 g-sample. The purity of KBr is:
P = 0.5162 g/0.5231 g × 100% = 98.68%
Determine the number of molecules in 0.0500 mole of boron tribromide
(show work)
Answer:
There are 0.5 moles
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.
To calculate the moles, we use the equation:
Thus there are 0.5 moles
Explanation:
Which is the most soluble substance listed
Which process breaks down sugars to release energy that powers bodily functions?
Answer:
Cellular respiration
Explanation:
How many grams of silver chloride can be produced by reacting excess silver nitrate with 2.4 moles of zinc chloride? _____AgNO3 + ____ZnCl2 ____AgCl + _____Zn(NO3)2
690 g AgCl
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableWriting CompoundsStoichiometry
Using Dimensional AnalysisLimiting Reactant/Excess ReactantExplanation:Step 1: Define
[RxN - Unbalanced] AgNO₃ + ZnCl₂ → AgCl + Zn(NO₃)₂
↓
[RxN - Balanced] 2AgNO₃ + ZnCl₂ → 2AgCl + Zn(NO₃)₂
[Given] 2.4 mol ZnCl₂
[Solve] x g AgCl
Step 2: Identify Conversions
[RxN] 1 mol ZnCl₂ → 2 mol AgCl
[PT] Molar Mass of Ag - 107.87 g/mol
[PT] Molar Mass of Cl - 35.45 g/mol
Molar Mass of AgCl - 107.87 + 35.45 = 143.32 g/mol
Step 3: Stoich
[DA] Set up: [tex]\displaystyle 2.4 \ mol \ ZnCl_2(\frac{2 \ mol \ AgCl}{1 \ mol \ ZnCl_2})(\frac{143.32 \ g \ AgCl}{1 \ mol \ AgCl})[/tex][DA] Multiply/Divide [Cancel out units]: [tex]\displaystyle 687.936 \ g \ AgCl[/tex]Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
687.936 g AgCl ≈ 690 g AgCl
Specific Gravity is also known as ______________
A sample of potassium has an average atomic mass of 39.0983amu. There are three isotopic forms of potassium element in the sample. About 93.2581% of the potassium atoms are 38.9637amu mass (39K); 0.0117% are 39.9639amu mass (40K), and the remaining isotope 41K is of 40.9618amu mass. Calculate the percentage composition of 41K. Report your answer with five significant figures.
Answer:
Percent Composition of 41K = 6.7302%
Explanation:
The explination is in the image.
The percentage composition of 41K isotope of potassium according to the given data is 6.7302 percent.
Composition of isotopes:Given that the atomic masses of the potassium isotopes are:
mass of 39K = 38.9637amu
mass of 40K = 39.9639amu
mass of 41K = 40.9618amu
and the percentages are:
percentage of 39K = 93.2581%
percentage of 40K = 0.0117%
percentage of 41K = x
Given average mass of potassium = 39.0983amu
sum (mass of isotopes × percentage abundance) = average mass
38.9637 × 93.2581% + 39.9639 × 0.0117% + 40.9618 × x = 39.0983
x = 6.7302%
So the percentage composition of 41K is 6.7302%
Learn more about composition of isotopes:
https://brainly.com/question/24291471?referrer=searchResults
Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical equation for it. Be sure your chemical equation is balanced and has physical state symbols. situation chemical reaction.
A strip of solid tin metal is put into a beaker of 0.074M MgBr2 solution .
Answer:
Sn(s) + MgBr2(aq) --> SnBr2(aq) + Mg(s)
Explanation:
Decide whether a chemical reaction happens in either of the following situations.
- A reaction happens. The type of this reaction is the single replacement reaction.
If a reaction does happen, write the chemical equation for it.
Sn(s) + MgBr2(aq) --> SnBr2(aq) + Mg(s)
The hydrolysis of adenosine triphosphate (ATP) is represented by the equation below. This reaction is critically important in cellular biology, but the reaction itself proceeds at a very slow rate. Based on the information given, which of the following best explains why an enzyme (biological catalyst) is required for the reaction to occur at a faster rate?
ATP+ H2O ADP+ Pi
ΔG= -30.5Kj/mol
a. Because ΔG < 0, the hydrolysis of ATP is not thermodynamically favorable. In cells, ΔS is increased by increasing the amount of H2O consumed, resulting in ΔG >0 and an increase in the reaction rate.
b. Because ΔG < 0, the hydrolysis of ATP is not thermodynamically favorable. In cells, enzymes act as catalysts that decrease ΔH for the reaction, resulting in ΔG >0 and an increase in the reaction rate.
c. Although the hydrolysis of ATP is thermodynamically favorable, without a catalyst the reaction occurs at a very slow rate because it has a small activation energy.
d. Although the hydrolysis of ATP is thermodynamically favorable, without a catalyst the reaction occurs at a very slow rate because it has a large activation energy.
Answer:
d. Although the hydrolysis of ATP is thermodynamically favorable, without a catalyst the reaction occurs at a very slow rate because it has a large activation energy.
Explanation:
Hello!
In this case, since negative Gibbs free energies of reaction stand for thermodynamically favored processes, we can immediately rule out choices a. and b.
Moreover, since the reaction is slow without the presence of a catalyst, which the context of biochemistry is an enzyme, we infer that correct choice is d. Although the hydrolysis of ATP is thermodynamically favorable, without a catalyst the reaction occurs at a very slow rate because it has a large activation energy because the higher the activation energy the slower the reaction according to the Arrhenius equation.
Best regards!
A student is given a sample of matter and asked to determine whether it is an element, compound, or mixture. The student discovers that she cannot separate
the components of the sample by physical means. However, she is able to separate the sample by chemical means into three different pure substances. The
sample must be______.
A. an element
B. a compound
C. a mixture
D. a solution
Answer is B
A mixture means two compounds mixed together but not atomically. For example, sand and water solution. A water with sand mixed inside is a mixture because the sand can be separated by physical means.
Water is H2O. This means it is a compound, because hydrogen and oxygen is bonded together atomically. Hydrogen however is an element, because you can't seperate it anymore (You could seperate it in the sense of protons and neutrons, but the definition of element is something you can see on the periodic table)
Compound means more than one element bonded together.
The sample must be a compound because it couldn't be seperated by physical means but can be seperated by chemical means into three pure substances (synonym of element)
The volume and number of moles of a gas are held constant. Which of the following is true for the pressure of the gas?
It is inversely proportional to the temperature of the gas.
It is directly proportional to the temperature of the gas.
It is inversely proportional to the mass of the gas.
It is equal to the mass of the gas.
Answer:
it is directly proportional to the temperature of the gas
Explanation:
What is the percent composition of dinotrogen pentoxide? With work shown please
Answer:
%N = 25.94%
%O = 74.06%
Explanation:
Step 1: Calculate the mass of nitrogen in 1 mole of N₂O₅
We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.
m(N): 2 × 14.01 g = 28.02 g
Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅
We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.
m(O): 5 × 16.00 g = 80.00 g
Step 3: Calculate the mass of 1 mole of N₂O₅
We will sum the masses of N and O.
m(N₂O₅) = m(N) + m(O) = 28.02 g + 80.00 g = 108.02 g
Step 4: Calculate the percent composition of N₂O₅
We will use the following expression.
%Element = m(Element)/m(Compound) × 100%
%N = m(N)/m(N₂O₅) × 100% = 28.02 g/108.02 g × 100% = 25.94%
%O = m(O)/m(N₂O₅) × 100% = 80.00 g/108.02 g × 100% = 74.06%
How many grams of water are formed if 3.5 moles of ammonia are used?
Ammonia chemical formula : NH3
Ammonia molar mass : 14 + (1×3) = 17
Mass = Mol × mm
= 3.5mol × 17 = 59.5g
See pic for formula
nvm i think your question is incomplete. pls report my answer i thought u are asking the mass of ammonia