Answer:
Step-by-step explanation:
I am also in 8th grade, anyways
x reprsents = 30 nickles
y represents = $1.02.
I am very sorry i do not know EQ1 and EQ2, but hopefully this is helpful!
Answer:
Step-by-step explanation:
x reprsents = 30 nickles
y represents = $1.02.
what is an equivalent expression for 3(x-9) ?
There are seven roads that lead to the top of a hill. How many different ways are there to reach the top and come back ( you dont have to go on the same road there and back)?
Answer:
49 different ways
Step-by-step explanation:
If there are seven roads that lead to the top, you have seven possible choices to go to the top of the hill.
Then, to come back to the start, you also have seven possible choices (seven roads), and you can pick any road.
So, if you have seven ways to go up and seven ways to go down, the number of different ways of going to the top and coming back is the product of these numbers of possible choices.
N(total) = N(up) * N(down)
N(total) = 7 * 7
N(total) = 49 different ways
Brainliest pls and tysm!
10 cm
7 cm
8 cm
SA =
7 cm
2 cm
[?] cm²
6 cm
If you'd like,
you can use a
calculator.
Step-by-step explanation:
as the graphic shows, there are 2 objects : 1 block and 1 triangular shaped half-block.
the block is
7cm × 6cm × 2cm
the half-block is
8cm × 7cm × 6cm
with 10cm being the length of the tilted "roof" area.
the 2 sides facing each other are not visible to the observer, so, they are not part of the surface area of the composite figure.
let's start with the block :
top and bottom 7×2
front and back 6×2
no left (fully covered by the half-block)
right 6×7
that gives us :
2 × 7×2 = 2×14 = 28 cm²
2 × 6×2 = 2×12 = 24 cm²
6×7 = 42 cm²
in total : 94 cm²
the half-block :
top 10×7
bottom 8×7
front and back (triangles) 8×6/2
no left (due to being a half-block)
no right (fully covered by the block)
that gives us :
10×7 = 70 cm²
8×7 = 56 cm²
2 × 8×6/2 = 2×24 = 48 cm²
in total : 174 cm²
so, the complete surface area of the composite figure is
94 + 174 = 268 cm²
A(n) _________is an equation satisfied by every number that is a meaningful replacement for the variable
The correct answer is identity
PLS HELP!!
Reproduce the definition of theoretical probability.
Theoretical Probability = a/b
Answer:
Step-by-step explanation:
a = number of successful events
b = total number of events.
When tariq woke up this morning, the temperature was 0 degrees. the temperature rose 23 degrees in the afternoon, the temp decreesed in the evniing. and it was 11 degrees when tariq went to bed. what integer represents the temp when tariq went to bed?
The final temperature at the time Tariq goes to bed was +12 degrees, represented as integers.
The initial temperature of the day was 0 degrees.
The temperature rose 23 degrees in the afternoon.
This implies that we move +23 on the scale, represented as an integer.
The temperature decreased 11 degrees in the evening.
This implies that we move -11 on the scale, represented as an integer.
This moves the temperature to +23 -11 = +12 degrees, represented as an integer.
Thus, the final temperature at the time Tariq goes to bed was +12 degrees, represented as integers.
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Can someone help me please
Answer:
The slope of the line segment CD is ( - [tex]\frac{8}{9}[/tex] )
Step-by-step explanation:
( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] )
( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] )
Coordinates of the midpoint are
( [tex]\frac{x_{1} +x_{2} }{2}[/tex] , [tex]\frac{y_{1} +y_{2} }{2}[/tex] )
The slope of a line segment with coordinates of the ends
( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] )
( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] )
is m = [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]
~~~~~~~~~~~~~
Point D is the midpoint of a segment AB
A ( 4 , 12 )
B ( - 6 , - 8 )
( [tex]\frac{-6+4}{2}[/tex] , [tex]\frac{-8+12}{2}[/tex] ) = ( - 1 , 2 )
D ( - 1 , 2 )
C ( 8 , - 6 )
[tex]m_{CD}[/tex] = [tex]\frac{-6-2}{8-(-1)}[/tex] = - [tex]\frac{8}{9}[/tex]
The illustration below shows the graph of yyy as a function of xxx.
Complete the following sentences based on the graph.
The slope of the graph of the function is equal to
for xxx between x=-3x=−3x, equals, minus, 3 and x=-2x=−2x, equals, minus, 2.
The slope of the graph is equal to
for xxx between x=3x=3x, equals, 3 and x=4x=4x, equals, 4.
The greatest value of yyy is y=\:y=y, equals
.
The smallest value of yyy is y=\:y=y, equals
.
By critically observing the graph shown in the image attached below, we can logically deduce that the slope of the graph of this function is equal to 0 for x, between x = -3 and x = -2.
Similarly, the slope of the graph of this function is also equal to 0 for x, between x = 3 and x = 4.
Based on the graph (see attachment), the greatest value of y is 4 while the smallest value of y is -3.
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hi can you please help me
Answer:
See attached image
Step-by-step explanation:
I'm uncertain as to the "best statement." None seem to accurately describe the situation. I picked the one that was least incorrect (if that makes any sense).
Paul has four paper strips of the same length. He glues two of them together with 4 cm overlap, and the new strip is 36 cm long. He wants to make a 30cm long strip with the other two strips how long should the overlap be?
Answer:
maybe the answer ris 36×4 and then 30×4 and subtract the result?!?!
The function f(x) is shown in the graph.
Which type of function describes f(x)?
a) Exponential
b) Logarithmic
c) Rational
d) Polynomial
The function that describes the graph is an exponential function
How to determine the function type?From the graph, we have the following highlights:
Initially, when x increases; y seem not to increaseThen, x and y increase at the same timeFinally, y increase and x seem not to increaseThe above is the description of an exponential function
Hence, the function that describes the graph is an exponential function
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Which equation is the inverse of 5y+4= (x+3)² +?
1
6 11
10
O y = x² +/
1/2 X+
7
Oy=3± √√5x+2
O-5y-4 = -(x+3)²--1/2
7
O y=-3± √√5x+2
Answer:
-5y-4=-(x+3)2-1/(2)
Step-by-step explanation:
ANSWER: It's D
Have a great day!!!
In 2015, around ____ percent of the world’s population had an internet connections.
I need help finding values of x,y,z. I want to know if there is an answer apart from 0, since that is what I need to find. Thanks and look at the pic.
Answer:
They all equal zero
Step-by-step explanation:
A number cannot equal itself times any number that isn't zero, unless it itself is zero.
A number with 100 digits is given. the first two digits of that number are 2 and 9 . how many digits has a square of that number?
The square of the given number will have 199 digits.
How to find the number digits in the square of the given number?A number with hundred digits is given.
The first two digits of the given number are 2 and 9.
We can use the following formula to find the total number of digits in the square of a number.
2n - 1
Where n is the total number of digits in the given number.
Let us take a number with 2 digits:
29*29 = 841 { 2*2 - 1 = 3}
We can see that the square of the 2-digit number has 3 digits in it.
Let us take a number with 3 digits:
299*299 = 89401 { 2*3 - 1 = 5}
We can see that the square of the 3-digit number has 5 digits in it.
Similarly, we can find the number of digits in the square of a 100-digit as shown below:
2n - 1 = 2*100 - 1
= 200 - 1
= 199
Therefore, we have found that the square of the given number will have 199 digits.
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If the ratio of y to x is equal to 3 and the sum of y and x is 80, what is value of y
Answer:
y = 60
Step-by-step explanation:
Step 1: Make sense of the given"The ratio of y to x is 3"
This means that, [tex]y\div x=3[/tex]
"The sum of y and x is 80"
This means, [tex]x+y=80[/tex]
Step 2: Make use of the factsIf [tex]y\div x=3[/tex], then [tex]y = (3*x)[/tex].
We can plug this into the other equation by substitution:
[tex]x + (3 * x)=80[/tex]
This simplifies to:
[tex]4x = 80[/tex]
Which we can solve out and get:
[tex]x=20[/tex].
We solved for x, but we need the value of y.
So, we go back to the equation we first derived: "[tex]y = (3*x)[/tex]".
And now we substitute the value of x, into this.
[tex]y = (3 * (20))[/tex]
By solving this out, we get:
[tex]y=60[/tex]
So, the value of y is 60.
What is the area of this trapezoid?
Answer:
315
Step-by-step explanation:
in a recent survey,55% of cell phone owners said they text messages.what fraction of cell phone owners is this
Answer:
11/20
Step-by-step explanation:
55% = 55/100
by simplifying this fraction (divide top and bottom by 5), you get 11/20
A rectangular-prism-shaped toy chest is 2 \text { m}2 m2, start text, space, m, end text by 1 \text { m}1 m1, start text, space, m, end text by 1 \text { m}1 m1, start text, space, m, end text. A shipping crate is packed with 181818 of these toy chests. There is no extra space in the crate.
The volume of the shipping crate is 36 m per cube.
According to the statement
we have given that the
A rectangular-prism-shaped toy chest is 2 m by 1 m by 1 m. A shipping crate is packed with 18 of these toy chests.
And we have to find the volume of the crate.
So,
volume of toy = 2*1*1
Volume of toy = 2 meter per cube.
And Now,
The volume of shipping crate = Volume of one toy* total number of toys in crate
so, Substitute the values in the formula then
The volume of shipping crate = Volume of one toy* total number of toys in crate
The volume of shipping crate = 2*18
The volume of shipping crate = 36 m per cube.
So, The volume of the shipping crate is 36 m per cube.
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Select the correct answer. What is the approximate solution to this equation? 4lnx - 8 = 12
A. x = 148.4
B. x = 10.5
C. x = 1.61
D. x = 59,874
Answer:
Step-by-step explanation:
hello :
4lnx - 8 = 12
4lnx - 8 +8= 12+8
4lnx =20
lnx =5
coclusion : x =e^5
A. x = 148.4
A couple quick algebra 1 questions for 50 points!
Only answer if you know the answer, quick shout-out to Subtomex0, tysm for the help!
Answer:
[tex]\textsf{2.} \quad y=\dfrac{35}{x}[/tex]
[tex]\textsf{3.} \quad y=-\dfrac{90}{x}[/tex]
[tex]\textsf{4.} \quad y=\dfrac{63}{x}[/tex]
[tex]\textsf{5.} \quad y=-\dfrac{112}{x}[/tex]
Step-by-step explanation:
If y is inversely proportional to x, then:
[tex]y \propto\dfrac{1}{x} \implies y=\dfrac{k}{x} \quad \textsf{(for some constant }k)[/tex]
Question 2
Substitute one of the given ordered pairs into the inverse variation equation and solve for k:
[tex]\implies 7=\dfrac{k}{5}[/tex]
[tex]\implies 7 \cdot 5=\dfrac{k}{5} \cdot 5[/tex]
[tex]\implies k=35[/tex]
Substitute the found value of k into the formula to create the inverse variation equation for the given ordered pairs:
[tex]\implies y=\dfrac{35}{x}[/tex]
Question 3
Substitute y = -15 and x = 6 into the formula and solve for k:
[tex]\implies -15=\dfrac{k}{6}[/tex]
[tex]\implies -15 \cdot 6=\dfrac{k}{6} \cdot 6[/tex]
[tex]\implies k=-90[/tex]
Substitute the found value of k into the formula to create the inverse variation equation for the given values:
[tex]\implies y=-\dfrac{90}{x}[/tex]
Question 4
Substitute one of the given ordered pairs into the inverse variation equation and solve for k:
[tex]\implies 9=\dfrac{k}{7}[/tex]
[tex]\implies 9 \cdot 7=\dfrac{k}{7} \cdot 7[/tex]
[tex]\implies k=63[/tex]
Substitute the found value of k into the formula to create the inverse variation equation for the given ordered pairs:
[tex]\implies y=\dfrac{63}{x}[/tex]
Question 5
Substitute one of the given ordered pairs into the inverse variation equation and solve for k:
[tex]\implies -16=\dfrac{k}{7}[/tex]
[tex]\implies -16 \cdot 7=\dfrac{k}{7} \cdot 7[/tex]
[tex]\implies k=-112[/tex]
Substitute the found value of k into the formula to create the inverse variation equation for the given ordered pairs:
[tex]\implies y=-\dfrac{112}{x}[/tex]
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please help me with this im struggling
=======================================================
Explanation:
Triangle ABC is similar to triangle DEF. The order of the lettering is important because it tells us how the letters pair up.
A and D are the 1st letters, so they pair upB and E are the 2ndletters, so that's another pairC and F are the 3rd letters, which is the final pair of pointsBased on that, we can determine how the segments pair up
AB and DE correspond to each other. The segments are composed of the 1st and 2nd points.BC and EF correspond as well. The segments use the 2nd and 3rd points.AC and DF correspond also. They use the 1st and 3rd points.We want to find how long EF is, which means we'll involve BC = 17 since it is paired with it.
The diagram shows that AC = 14 and DF = 3, which is another pair we'll use
--------------------------
The key takeaway is that
AC = 14 and DF = 3 pair up togetherBC = 17 and EF also pair up togetherThose two facts lead to the steps below
[tex]\frac{AC}{DF} = \frac{BC}{EF}\\\\\frac{14}{3} = \frac{17}{EF}\\\\14*EF = 3*17\\\\14*EF = 51\\\\EF = \frac{51}{14}\\\\EF \approx 3.642857\\\\EF \approx 3.6\\\\[/tex]
The proportion in step 1 is valid due to the similar triangles, and because of the corresponding side pairs mentioned. In step 3, I cross multiplied.
Answer:
3.6 cm
Step-by-step explanation:
Similar Triangle Theorem
If two triangles are similar, the ratio of their corresponding sides is equal.
Given triangles:
ΔABC and ΔDEFTherefore the corresponding sides are:
AC and DF, BC and EF, AB and DETo find the measure of side EF, use the Similar Triangle Theorem:
[tex]\implies \sf AC:DF=BC:EF[/tex]
[tex]\implies \sf \dfrac{AC}{DF}=\dfrac{BC}{EF}[/tex]
[tex]\implies \sf \dfrac{14}{3}=\dfrac{17}{EF}[/tex]
[tex]\implies \sf EF=17 \cdot \dfrac{3}{14}[/tex]
[tex]\implies \sf EF=\dfrac{51}{14}[/tex]
[tex]\implies \sf EF=3.642857...[/tex]
[tex]\implies \sf EF=3.6\:cm\:\:(nearest\:tenth)[/tex]
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In order for a gear to work in a piece of machinery, the radius of the gear, r, must be greater than 4 cm, but not exceed 4.1 cm. Which compound inequality represents the situation?
r > 4 and r ≤ 4.1
r > 4 or r ≤ 4.1
r < 4 and r ≥ 4.1
r < 4 or r ≥ 4.1
The compound inequality represents the situation is r > 4 and r ≤ 4.1
Compound inequalityRadius of the gear = rr must be greater than 4 cmr > 4
r must not exceed 4.1 cmr ≤ 4.1
Therefore, r > 4 and r ≤ 4.1 is the compound inequality which represent the situation.
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Its A: r > 4 and r ≤ 4.1
Find the length of side DF
The length of side DF is 3.75.
Given that within the figure there are two triangles that are similar.
Congruent triangles will be triangles that have a comparable measure and shape. This infers that the comparing sides are comparable and the relating focuses are equivalent.
Two comparative triangles are given.
If two triangles are comparable at that point their comparing sides are relative and comparing points are congruent.
DF/AB=EF/BC
Substitute the values from the given figure
DF/15=6/24
Cross multiply both sides, and we get
DF×24=6×15
DF×24=90
Divide both sides by 24, we get
(DF×24)/24=90/24
DF=15/4
DF=3.75
Hence, the length of side DF from the given figure is 3.75.
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6x^2-19xy-7y^2 HELP ME PLS??
Answer:
(3x+y) (2x-7y)
Step-by-step explanation:
first write -19xy as a difference and you get 6x^2+2xy-21xy-7y^2
and then take the factor 2x from the expression that is 2x(3x+y) and do the same with the -7 that is = -7(3x+y). So this is you answer= (3x+y)(2x-7)
What is the approximate number of minutes that avery spends in extra circular activities
The approximate number of minutes that Avery spends on the extra curricular activities are 122 minutes.
Given that Avery spent 10 minutes outside, 64 minutes in riding her bike, 48 minutes on the trampoline.
We have to calculate the approximate time that Avery spends on extra curricular activities.
Time spent by Avery outside=10 minutes
Time spent by Avery in riding her bike=64 minutes
Time spent by Avery on trampoline=48 minutes
Total time spent by Avery on extra curricular activities is equal to 10+64+48
=122 minutes
Hence the total time spent by Avery on extra curricular activities is 122 minutes.
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Question is incomplete as the question should include that Avery spent 10 minutes outside,64 minutes in riding her bike, 48 minutes on trampoline and rest of the time in swimming.
What is the range of possible sizes for side x?
Answer:
Should be 3.9
Step-by-step explanation:
prove me wrong
Which pairs of triangles appear to be congruent? Check all that apply. 2 A. Triangles 1 and 2 B. Triangles 2 and 3 C. Triangles 1 and 4 D. Triangles 1 and 3 E. Triangles 3 and 4 Triangles 2 and 4 A
Pairs of triangles appear to be congruent are :
Triangles 2 and 3. Option B
Triangles 2 and 4. Option D
Triangles 3 and 4. Option E
What are congruent triangles?Congruent triangles can be defined as the pairs of triangles with same measurement
Triangles 2 and 3 :
After observing triangles 2 and 3 it appears that triangle is congruent to triangle .
Option C
Triangles 2 and 4
After observing triangles 2 and 4 it appears that triangle 2 is congruent to triangle 4 .
Option D
E. Triangles 3 and 4
After observing triangles 3 and 4. They are congruent
Option E
Hence, Option B, D and E are correct of the triangles
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Answer:
Triangles 3 and 4
Triangles 1 and 4
Triangles 1 and 3
Step-by-step explanation:
if this is wrong tell me so i can edit the answer, but this is what i got
Solve for x |2x+1|=-13
Answer:
no solution
Step-by-step explanation:
Your question is in the form:
absval of something
= a NEGATIVE number
The absolute value is always positive. So it can never be negative.
There are no values that x can be that will make this math sentence true.
It's not really a trick question, but the course/teacher/book/program just wants you to recognize that an absolute value CANNOT be negative.
Consider the graph of the function f(x)=2^x which statements describe key features of function g if g(x)=3f(x)?
it's multiple choice, select all the correct answers:
y-intercept at (0,1)
y-intercept at (0,3)
horizontal asymptote of y=3
x-intercept at (3,0)
horizontal asymptote of y=0
no x-intercept
Answer:
y-intercept at (0,3)horizontal asymptote of y=0no x-interceptStep-by-step explanation:
The y-intercept of f(x) is (0,1), so the y-intercept of g(x) is (0,3).
f(x) has a horizontal asymptote at y=0. and so does g(x).
f(x) does not have an x-intercept, and neither does g(x).
Answer:
y-intercept at (0, 3)
horizontal asymptote of y = 0
no x-intercept
Step-by-step explanation:
Definitions
y-intercept: the point(s) at which the curve crosses the y-axis (when x=0).
x-intercept: the point(s) at which the curve crosses the x-axis (when y=0).
Asymptote: a line that the curve gets infinitely close to, but never touches.
Given function:
[tex]f(x)=2^x[/tex]
Properties of function f(x):
y-intercept at (0, 1)As x → -∞, y → 0 therefore there is a horizontal asymptote at y=0 and no x-intercept (since the curve never crosses the x-axis).As x → ∞, y → ∞[tex]\textsf{If }g(x)=3f(x):[/tex]
[tex]\implies g(x)=3(2)^x[/tex]
Properties of function g(x):
y-intercept at (0, 3)As x → -∞, y → 0 therefore there is a horizontal asymptote at y=0 and no x-intercept (since the curve never crosses the x-axis).As x → ∞, y → ∞Therefore the true statements are:
y-intercept at (0, 3)horizontal asymptote of y = 0no x-intercept