Part C
Close the simulation window for carbon dioxide and return to the Cool Molecules Explore page.
Next, click C and H in the periodic table and repeat the process for methane (CH₂). In the table below, record the names of its vibrational modes
and describe the vibration of the molecule in each mode. Also record the number of unique possible states for each mode.
Vibration Mode
Al stretch
E bend
T2 stretch
T2 bend
Number of States in the:
Mode
Description:
Answers
The vibrational modes and unique possible states for each mode are detailed in the table below.
What is the vibrational mode of a molecule?A vibrational mode of a molecule refers to a specific way in which the atoms inside a molecule can move relative to each other. Molecules are made up of atoms that are connected to each other by chemical bonds, and these bonds act like springs that can vibrate.
When a molecule absorbs energy, it can cause the bonds to stretch, bend, or twist in specific ways, creating different vibrational modes. The vibrational modes of a molecule can provide important information about its structure and chemical properties.
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Related Questions
Background: At present, the debate on what will provide secure and sustainable
energy for the United States is of great concern to Americans. How the United
States uses energy is largely determined by policies set by National and State
Politicians. For this extension topic, you should create a letter to a government
official (governor, senator, president, etc.) that clearly states your
claim/conclusion about the best options for Energy Production. You should attempt
to convince your reader of the claim by using evidence from this activity as well as
additional research that you complete. (20 pts)
Answers
The debate on what will provide secure and sustainable energy for the United States is of great concern to Americans, and the policies set by National and State Politicians play a crucial role in determining how the United States uses energy.
In this context, a letter can be written to a government official such as a governor, senator, or president, to clearly state the claim/conclusion about the best options for energy production.
Evidence from this activity, as well as additional research, can be used to persuade the reader of the claim.
Thus by doing so, it can be ensured that energy policies are developed with the best options for energy production in mind, leading to a more secure and sustainable future for the United States.
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You are in a laboratory creating a new chocolate bar. You want to create the sweetest chocolate bar by maximizing the sugar concentration. You are doing this by adding the sugar to a chocolate mixture. Which would allow you to dissolve more sugar?
The answer: Add the sugar after heating the mixture.
Answers
Adding the sugar after heating the mixture would allow you to dissolve more sugar, which would result in a sweeter chocolate bar.
When you dissolve sugar in a liquid, such as in a chocolate mixture, there is a limit to the amount of sugar that can be dissolved at a given temperature. This limit is known as the solubility of the sugar in that liquid. The solubility of sugar in water is higher at higher temperatures, which means that you can dissolve more sugar in hot water than in cold water. The same principle applies to chocolate mixtures.
By heating the chocolate mixture, you increase the temperature of the mixture, which in turn increases the solubility of the sugar in the mixture. This allows you to dissolve more sugar in the mixture than if you were to add the sugar to the mixture at room temperature or when it is cold.
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--The given question is incorrect, the correct question is
"You are in a laboratory creating a new chocolate bar. You want to create the sweetest chocolate bar by maximizing the sugar concentration. You are doing this by adding the sugar to a chocolate mixture. Which would allow you to dissolve more sugar?"--
help w calorimeter problems pls.
Answers
1. The specific heat capacity of the metal is 0.102 J/gºC
2. The specific heat capacity of the metal is 0.432 J/gºC
3. The final temperature of water is 16.7 °C
1. How do I determine the specific heat capacity of the metal?First, we shall obtain the heat absorbed by the water. This is shown below:
Volume of water = 125 mLMass of water (M) = 125 gInitial temperature (T₁) = 22 °CFinal temperature (T₂) = 25.4 °CChange in temperature (ΔT) = 25.4 - 22 = 3.4 °CSpecific heat capacity of water (C) = 4.184 J/gºC Heat absorbed by water (Q) =?Q = MCΔT
Q = 125 × 4.184 × 3.4
Q = 1778.2 J
Finally, we shall determine the specific heat capacity of the metal. This is shown below:
Heat absorbed by water (Q) = 1778.2 JHeat released by metal (Q) = -1778.2 JMass of metal (M) = 2.36×10² gInitial temperature (T₁) = 99.5 °CFinal temperature (T₂) = 25.4 °CChange in temperature (ΔT) = 25.4 - 99.5 = -74.1 °CSpecific heat capacity of metal (C) = ?Q = MCΔT
-1778.2 = 2.36×10² × C × -74.1
-1778.2 = -17487.6 × C
Divide both sides by -17487.6
C = -1778.2 / -17487.6
Specific heat capacity of metal = 0.102 J/gºC
2. How do I determine the specific heat capacity of the metal?As discussed above, we shall first obtain the heat absorbed by the water. This is shown below:
Volume of water = 75.2 mLMass of water (M) = 75.2 gInitial temperature (T₁) = 20.5 °CFinal temperature (T₂) = 28.6 °CChange in temperature (ΔT) = 28.6 - 20.5 = 8.1 °CSpecific heat capacity of water (C) = 4.184 J/gºC Heat absorbed by water (Q) =?Q = MCΔT
Q = 75.2 × 4.184 × 8.1
Q = 2548.56 J
Finally, we shall determine the specific heat capacity of the metal. This is shown below:
Heat absorbed by water (Q) = 2548.56 JHeat released by metal (Q) = -2548.56 JMass of metal (M) = 95.3 gInitial temperature (T₁) = 90.5 °CFinal temperature (T₂) = 28.6 °CChange in temperature (ΔT) = 28.6 - 90.5 = -61.9 °CSpecific heat capacity of metal (C) = ?Q = MCΔT
-2548.56 = 95.3 × C × -61.9
-2548.56 = -5899.07 × C
Divide both sides by -5899.07
C = -2548.56 / -5899.07
Specific heat capacity of metal = 0.432 J/gºC
3. How do i determine the final temperature of water?The final temperature is the same as the equilibrium temperature of the mixture. Thus, we shall obtain the equilibrium temperature. Details below:
Mass of warm water (Mᵥᵥ) = 100Temperature of warm water (Tᵥᵥ) = 50 °CMass of cold water (M) = 50 gTemperature of cold water (T) = 20 °CEquilibrium temperature (Tₑ) =?Heat loss by warm water = Heat gain by cold
MᵥᵥC(Tᵥᵥ - Tₑ) = MC(Tₑ - T)
Cancel out C
Mᵥᵥ(Tᵥᵥ - Tₑ) = M(Tₑ - T)
100 × (50 - Tₑ) = 50 × (Tₑ - 20)
Clear bracket
1500 - 100Tₑ = 50Tₑ - 1000
Collect like terms
1500 + 1000 = 50Tₑ + 100Tₑ
2500 = 150ₑ
Divide both side by 150
Tₑ = 2500 / 150
Tₑ = 16.7 °C
The equilibrium temperature is 16.7 °C.
Thus, we can conclude that the final temperature of the water is 16.7 °C
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1. HCI (aq) + NaOH (aq) → NaCl (aq) + H₂O (1)
a. What are the reactants?
b. What are the products?
Answers
In the given reaction, the reactants are hydrochloride acid (HCI) and sodium hydroxide (NaOH). The products are sodium chloride (NaCl) and water.
The chemical equation provided represents a neutralization reaction between hydrochloric acid (HCI) and sodium hydroxide (NaOH) in aqueous solution.
A neutralization reaction is a type of double displacement reaction in which an acid and a base react to form salt and water.
The reactants in this equation are hydrochloric acid (HCI) and sodium hydroxide (NaOH). Hydrochloric acid is a strong acid that dissociates in water to form hydrogen ions (H+) and chloride ions (Cl-). Sodium hydroxide, on the other hand, is a strong base that dissociates in water to form sodium ions (Na+) and hydroxide ions (OH-).
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2
Select the correct answer.
Which phrase best describes heat?
OA.
B.
OC.
D.
the energy that an object has as a result of its temperature
the average translational kinetic energy of the particles in an object
the energy transferred between objects at different temperatures
the total amount of energy possessed by the particles in an object
Answers
Heat is most accurately described as "the energy transferred between objects at different temperatures" (C). Until they reach thermal equilibrium, or the same temperature, heat is a type of energy that flows freely from a hotter to a colder item.
Heat can be transferred through conduction, convection, or radiation. The temperature differential between the items and the thermal conductivity of the materials involved determine how much heat is transported.
Temperature, a measurement of the average kinetic energy of the particles in an item, is not the same as heat. Internal energy is the entire amount of energy held by an object's particles, which includes both their kinetic and potential energies.
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3: Given 12.3 grams of NH3, how many moles of N₂ were needed?
Answers
0.361 moles of N₂ were required to produce 12.3 g of NH₃, using the balanced chemical equation N₂ + 3H₂ → 2NH₃.
The balanced chemical equation for the reaction is N₂ + 3H₂ → 2NH₃. We can use the balanced equation and the molar mass of NH₃ to calculate the number of moles of N₂ required to produce 12.3 g of NH₃,
1 mol NH₃ = 2 mol N₂ (from the balanced equation)
molar mass of NH₃ = 17.03 g/mol
moles of NH₃ = 12.3 g / 17.03 g/mol
moles of NH₃ = 0.722 mol
moles of N₂ = (0.722 mol NH₃) / 2
moles of N₂ = 0.361 mol
Therefore, 0.361 moles of N₂ were needed to produce 12.3 grams of NH₃.
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Complete question - For the reaction, N₂ + 3H₂ → 2NH₃. Given 12.3 grams of NH3, how many moles of N₂ were needed?
Which climatic change in Earth's history has resulted in glaciers?
cold climate
tropical climate
temperate climate
warm climate
Answers
The climatic change in Earth's history that has resulted in glaciers is the cold climate.
During the last 2.6 million years, the Earth has experienced a series of ice ages, or periods of colder global climate, which have led to the growth of glaciers in regions with sufficient snowfall.
These colder periods are associated with changes in the Earth's orbit, tilt, and precession, which affect the amount and distribution of solar radiation received by the Earth. These climatic changes have had significant impacts on the Earth's surface and have influenced the evolution of life on our planet.
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Similar to For Practice 14.8) Determine the freezing point of an aqueous solution that contains 0.867 m glycerin (CHgOz).
Ki(water) = 1.86°C/m and Kg(water) - 0.512°C/m. Freezing point of water = 0.0 °C.
Similar to For Practice 14.3) Find the mass (in grams) of glucose (CH1206) in 505 mL of 10.5% glucose solution by mass. Assume the density of the solution is 1.04g/mL
Answers
The freezing point of the solution containing 0.867 m glycerin is -1.61442 °C. Option C is correct
The mass of glucose in 505 mL of 10.5% glucose solution is 53.01 g or 5.30 x 10^2 g.
Option C is correct
To find the freezing point depression of the solution containing 0.867 m glycerin:
ΔTf = Kf * molality
ΔTf = (1.86°C/m) * 0.867 m
ΔTf = 1.61442 °C
The freezing point depression is 1.61442 °C.
The freezing point of the solution is:
Freezing point = 0.0 °C - ΔTf
Freezing point = 0.0 °C - 1.61442 °C
Freezing point = -1.61442 °C
To find the mass of glucose in 505 mL of 10.5% glucose solution:
Mass of glucose = Volume of solution * Density of solution * % mass
Mass of glucose = 505 mL * 1.04 g/mL * 10.5%
Mass of glucose = 53.01 g
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