Practice Problem 12.39 Partially correct answer. Your answer is partially correct. Try again. Acid-catalyzed hydration of 1-methylcyclohexene yields two alcohols. The major product does not undergo oxidation, while the minor product will undergo oxidation because the major product is Entry field with incorrect answer 2-methylcyclohexanol , which is a Entry field with incorrect answer secondary alcohol. These alcohols do not generally undergo oxidation. The minor product (Entry field with incorrect answer 1-methylcyclohexan-2-ol ) is asecondary alcohol and can undergo oxidation to yield a(n)
Answers
Answer:
See explanation and image attached
Explanation:
The acid-catalyzed hydration of 1-methylcyclohexene proceeds by an SN1 mechanism. The reaction involves the formation of carbocations.
Two carbocations are formed leading to the major and minor products. The major product is obtained from the tertiary (more stable) carbocation while the minor product is obtained from the secondary (less stable carbocation).
Tertiary alcohols are not oxidized, hence the major product does not undergo oxidation. However, secondary alcohols are oxidized to ketones.
Related Questions
Determine the number of sulfur atoms in 27.1 g of molecular sulfur (S8).
0.845
5.27 x 10^23
5.09 x 10^25
2.07 x 10^19
0.106
Answers
The correct response is C) [tex]5.09*10^{23}[/tex]. The number of sulfur atoms is [tex]5.09*10^{23}[/tex].
Chemical element sulphur has the symbol S and atomic number 16. Sulfur, which is categorized as a nonmetal, is a solid at ambient temperature. Due to the weak S=S double bonds that sulphur does not form, elemental sulphur is typically made up of cyclic S8 molecules, in which each atom completes its octet by creating single bonds to two adjacent atoms, as seen in the figure below. We are aware that sulphur, like SF6, can contain more than eight electrons using its vacant valence d orbitals. The Sulphur is once again six-coordinated in an alternate structure (b), which can be expressed with S=O double bonds. In 27.1 g of molecular Sulphur, there are the following Sulphur atoms:
27.1 g S8 x ([tex]1[/tex] mol S8/32.066 g S8) x ([tex]6.022*10^{23}[/tex] atoms/[tex]1[/tex] mole)
[tex]=5.09*10^{23}[/tex]
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Part A Which Of The Compounds Below Would Contain Polar Covalent Bonds? F2, N2O, KCI O KCI Only O Both F2 And N20 O N20 Only O F2 Only
Answers
F2 Of The Compounds Below Would Contain Polar Covalent Bonds.
How can you determine whether a bond is polar covalent?Although there are no strict guidelines, the general rule is that a bond is deemed nonpolar if the difference in electronegativities is less than or equal to 0.4; if the difference is larger than 0.4, the bond is termed polar.
Is there polar covalent bonding in f2?A fluorine molecule with two atoms is this. One covalent link exists because two fluorine atoms share the same valence electron pair. Due to the fact that the atoms are from the same element, the connection is nonpolar.
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The law of conservation of mater states that
matter can both be destroyed and created.
matter can be created but not destroyed.
matter can be destroyed but not created.
matter cannot be created or destroyed.
Answers
The law of conservation of matter states that d. matter cannot be created or destroyed.
What is the law of conservation of matter?
The law of conservation of matter is a model well sustained by scientific evidence which indicated that matter and energy are interchangeable but they can't be created or destroyed under any type of circumstance in space.
Therefore, with this data, we can see that the law of conservation of matter indicated it is unique and therefore cannot be created in the universe under normal conditions.
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use appendix b in the textbook to calculate the binding energy of 2/1h (deuterium).
Answers
The nuclear binding energy per nucleon for deuterium, ab/A, can be calculated by multiplying the mass defect m by the mass-energy equivalent 8 931.4941 MeV u1 and dividing the result by two to account for the deuterium mass number A.
A neutron weighs 1.6749 x 10-27 kg and a proton weighs 1.6726 x 10-27 kg, respectively. 2) Subtract the known nucleus mass. = 36 x 10-14 J = 3.6 x 10-13 J E. One deuterium nucleus and one tritium nucleus combine to form deuterium-tritium fusion, a type of nuclear fusion that releases one helium nucleus, one free neutron, and 17.6 MeV of energy. The binding energy is the amount of energy necessary to disassemble the nucleus into its component parts.
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Will the following bases favor an E1 or E2 mechanism? Sort them into the appropriate boxes below. Table Bases (6 items)(Drag and drop into the appropriate area below) a. NaH b. H20 c. CH3CH2OH d.NH2 e. tBuo f. CH3CO2
Answers
The number of stages in the mechanism is the easiest method to tell the difference between E1 and E2.
What favors an E2 reaction?Strong bases support the E2 mechanism while merely a weak base is necessary for the E1 mechanism. 2) The solvent: Effective ionising solvents (polar protics) support the E1 process by stabilising the intermediate carbocation.
The base's composition plays a crucial role in an E2 reaction since it is involved in the step that determines rate. More reactive bases will encourage an E2 reaction.
Steps in the process. Counting the steps in the mechanism is the most straightforward approach to tell E1 from E2 in a system. In contrast to E2, which occurs in a single step without an intermediate step, E1 involves two stages and a carbocation intermediate.
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Glycine is the only naturally occurring amino acid that is negatively charged. positively charged. achiral.
neutral.
in the L-form.
Answers
Glycine is the only naturally occurring amino acid that is: achiral.
What does glycine do in proteins?Body requires the amino acid glycine to make proteins, which are necessary for tissue development and maintenance as well as the production of critical compounds like hormones and enzymes.
Two atoms of carbon, five atoms of hydrogen, one atom of nitrogen, and two atoms of oxygen make up the organic molecule glycine. It is one of the 20 amino acids that are frequently found in the proteins of mammals. NH₂-CH₂-COOH is the formula for the chemical compound glycine.
The smallest and most basic amino acid is glycine. The fact that 2-H is connected to the same carbon atom makes it the only amino acid without a chiral carbon. As a result, it is the sole achiral amino acid.
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Modify the following three molecules so that they show the form that is dominant at physiological pH a) formic acid b) acetylsalicylic acid (aspirin) CHa c) citric acid H_O- CH2 CHz'
Answers
Modifications of the a) formic acid b) acetylsalicylic acid (aspirin) CHa c) citric acid H_O- CH2 CHz' are attached below.
What is formic acid, aspirin and citric acid?With only one carbon, formic acid is the most basic carboxylic acid. is a useful organic synthetic reagent that naturally occurs in a variety of sources, including the venom of bee and ant stings. used primarily as an antibacterial and preservative in animal feed.
A non-steroidal anti-inflammatory drug (NSAID), aspirin is an acetylated salicylate (acetylsalicylic acid) (NSAIDs). These medicines have a variety of pharmacologic effects, including analgesic, antipyretic, and antiplatelet properties, and they lessen the signs and symptoms of inflammation.
Citric acid is primarily used as a flavouring and preservation agent, especially in soft drinks and candies, due to its acidic, sour taste. As a disinfectant and to stabilise or preserve medicines, it is also used. Lemon juice was the original source of the compound known as citric acid.
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Which of the following molecular formulas is also an empirical formula
Answers
Answer: The molecular formula of ethyl ether is the same as its empirical formula.
Explanation:
Use bond energies to predict Δ H for the isomerization of methyl isocyanide to acetonitrile. C H 3 N ≡ C ( g ) → C H 3 C ≡ N ( g )
Answers
The isomerization of methyl isocyanide to acetonitrile is an exothermic process with a predicted enthalpy change of -287 kJ/mol.
Write about isomerization of methyl isocyanide.The isomerization of methyl isocyanide to acetonitrile is a complex process that involves breaking several bonds and forming new ones. The enthalpy change (ΔH) for this process can be estimated by considering the bond energies of the bonds that are broken and formed during the reaction.
The process involves breaking a C-N triple bond and forming a C-C single bond, and a C-N single bond. The bond energies of these bonds are:
C-N triple bond: 945 kJ/mol
C-C single bond: 347 kJ/mol
C-N single bond: 311 kJ/mol
To predict the enthalpy change for the reaction, we can use the following equation:
ΔH = (bonds formed) - (bonds broken)
The bonds that are broken are the C-N triple bond and the bonds that are formed are the C-C single bond and the C-N single bond.
ΔH = (347 kJ/mol + 311 kJ/mol) - (945 kJ/mol) = -287 kJ/mol.
Therefore, the isomerization of methyl isocyanide to acetonitrile is an exothermic process with a predicted enthalpy change of -287 kJ/mol.
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Q3 Compare the pH of the milk sample and the pH at which the casein solid forms. Q4 How does a change in pH affect the structural levels of a protein?
Answers
Milk — pasteurized, canned, or dry — is an acid-forming food. Its pH level is below neutral at about 6.7 to 6.9. This is because it contains lactic acid.
What is the pH of the milk?However, keep in mind that more essential than the precise pH level is whether it is acid-forming or alkaline-forming. Additionally acid-forming dairy products include butter, hard cheeses, cottage cheese, and ice cream. Despite having low pH values between 4.4 and 4.8, yoghurt and buttermilk are foods that contribute to alkalinity.
Raw milk is another exception, according to the American College of Healthcare Sciences, as it may generate an alkaline environment. However, drinking untreated milk might not be a good idea.
The taste of milk is not acidic. It's even suggested as a treatment for heartburn or acid reflux. Milk might provide symptom relief momentarily. This is so that the oesophagus and stomach can be protected by the fat in milk.
Milk consumption, however, could exacerbate heartburn symptoms. Milk increases stomach production.
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3. A certain atom in the 2nd period has an unusually high 3rd ionization energy. Name this
element. Draw a Bohr diagram and use it to illustrate why you were able to identify this
atom.
Answers
Answer:
he element is Neon (Ne).
Neon's unusually high third ionization energy is due to its stable electron configuration. On a Bohr diagram, Neon has two electrons in the 1s orbital, eight electrons in the 2s and 2p orbitals, and two electrons in the 3s orbital, giving it a complete shell of eight electrons (a stable configuration). This means that it takes more energy to first remove an electron from the third orbital, accounting for its unusually high 3rd ionization energy.
Neon (Ne), which is in the second period and possesses an incredibly high third ionization energy, is the element.
What is neon?The persistent electron structure of neon contributes to its very high third ionization energy. Neon has two electrons in the 1s orbital, eight electrons in the 2s and 2p orbitals, two electrons in the 3s orbital, and a total of eight electrons in the entire eight-element shell on a Bohr diagram (a stable configuration).
As a result, the explanation for the exceptionally high third ionization energy is that it requires more energy to first remove an electron from the third orbital.
Chemically speaking, neon is an element with the symbol Ne and atomic number 10. Noble gas describes it. Under normal circumstances, neon is a colorless, odorless, inactive monatomic gas, with roughly two-thirds of its mass.
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When a solution of lithium chloride and a solution of ammonium sulfate are mixed O a new salt is formed. O no reaction occurs. O a precipitate forms. O an acid and a base are formed.
Answers
Answer:
No reaction occurs
Explanation:
trust me on this one :)
Which of the following statements concerning cyclins is not correct?
(A) They catalyze the phosphorylation of cyclin-dependent protein kinases.
(B) They are regulatory subunits for enzymes that catalyze the phosphorylation of proteins.
(C) They are activated and degraded during the cell cycle.
(D) They can become linked to ubiquitin.
(E) They contain specific amino acid sequences that target them for proteolysis.
Answers
Reaction of cyclin, mitotic promoting factor or maturing-promoting factor catalyzes the phosphorylation of receptor superfamily of cyclin-dependent kinases.
In relation to protein kinases, each of the following claims is untrue?They remove diphosphate form proteins is the response that is untrue. Proteins do not lose phosphate groups when they are added by kinases. The enzymes known as phosphatases are in charge of removing phosphate groups off proteins. The other claims made concerning protein kinases are all accurate.
Which one of the following sentences concerning cyclin cdk is untrue?Option d is the erroneous statement. Throughout the cell cycle, CDK levels fluctuate. Throughout the cell cycle, each CDK is present in the same quantity. However, each CDK's activity is reliant on the other.
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The following initial rates data were obtained for 5Br1- + BrO31- + 6H1+ 3Br2 + 3H2O EXP [Br1-]o [BrO31-]o [H1+]o -[Br1-]/ t (M/s) 1 0.130 0.150 0.270 8.10e-03 2 0.195 0.150 0.270 1.22e-02 3 0.130 0.300 0.270 1.62e-02 4 0.130 0.150 0.675 5.06e-02 What are the reactant orders? Order of Br1- = Order of BrO31- = Order of H1+ = What are the units of the rate constant. Use exponents but no superscript. Separate M and s with a space. For example, use M-5 s-2 to indicate M-5·s-2. What is the value of the specific rate constant for the reaction (no units)? Hint: the rate constant for the reaction is not the same as the rate constant for the disappearance of Br1-. k =
Answers
The value of the specific rate constant for the reaction is 0.0426 (M/s)^3. To determine the reactant orders, we need to use the initial rate data and the method of initial rates.
The method of initial rates involves changing the concentration of one reactant while keeping the other reactants constant. From the initial rate data, we can see that when [Br1-] is changed, the rate of the reaction changes (experiments 1, 2, and 3). Therefore, the order of Br1- is not zero. When [BrO31-] is changed, the rate of the reaction changes (experiments 2 and 3). Therefore, the order of BrO31- is not zero. When [H1+] is changed, the rate of the reaction changes (experiments 1, 2, and 4). Therefore, the order of H1+ is not zero.
From this, we can conclude that the reactant orders are:
= Order of Br1- = 1
= Order of BrO31- = 1
= Order of H1+ = 1
The rate constant k is the proportionality factor between the rate of the reaction and the concentrations of the reactants. The units of k depend on the reactant orders. Since the overall order of the reaction is the sum of the individual reactant orders, in this case the overall order of the reaction is 1+1+1=3. Therefore, the unit of k is (M/s)^3.
To find the value of the specific rate constant for the reaction, we can use the following equation:
= -d[Br1-]/dt
= k[Br1-][BrO31-][H1+]
By substituting the experimental value of the initial rates, we can find the specific rate constant for the reaction.
= -d[Br1-]/dt
= k[Br1-][BrO31-][H1+]
= 8.10e-03
= k10.1300.1500.270
= k
= 8.10e-03/(10.1300.150*0.270)
= k
= 0.0426
The specific rate constant for the reaction is 0.0426 (M/s)^3. It's worth to mention that the rate constant for the disappearance of Br1- is not the same as the rate constant for the reaction because it only consider the disappearance of one of the reactants, but the rate constant for the reaction consider all the reactants.
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What's another name for the magnitude (absolute value) of the change in chemical energy? a) energy output b) efficiency c) power output d) metabolic energy
Answers
Here, we'll see at a few sorts of vitality that are especially critical in organic frameworks, counting motor vitality, potential vitality, and chemical vitality (the potential vitality of chemical bonds).
Why does the body utilize chemical energy?They are broken down into fundamental atoms, like amino acids and glucose, which are either utilized as vitality or reassembled and put away in other shapes, like glycogen. The nearness of chemical vitality in nourishment is pivotal to giving our bodies with the vitality they ought to keep us moving and lively.
What sort of vitality is chemical energy?Chemical vitality is vitality put away within the bonds of iotas and atoms. Batteries, biomass, petroleum, normal gas, and coal are cases of chemical vitality. For case, chemical vitality is changed over to warm vitality when individuals burn wood in a chimney or burn gasoline in a car's motor.
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Draw the structure of 3-lodo-2,2,4,4-tetramethylpentane.
• Show stereochemistry only if given in the name.
• You do not have to explicitly draw H atoms.
• If a group is achiral, do not use wedged or hashed bonds on it.
• In cases where there is more than one answer, just draw one.
Answers
the structure of 3-lodo-2,2,4,4-tetramethylpentane is shown in the below image.
Tetramethylpentane is a hydrocarbon compound with the molecular formula C8H18. It is a saturated aliphatic compound, which means it is composed of only carbon and hydrogen atoms and has no double or triple bonds. It is also a branched-chain compound, meaning that its carbon atoms are connected in a branching pattern. It is a liquid at room temperature and is used as a reference fuel in engine research.A hydrocarbon is a compound that is composed of only carbon and hydrogen atoms. Hydrocarbons can be classified into two main categories: saturated and unsaturated. Saturated hydrocarbons are compounds that have only single bonds between carbon atoms and are therefore considered "fully saturated" with hydrogen atoms.
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Draw curved arrows to show the movement of electrons in this step of the mechanism Arrow-pushing Instructions ~X OH OH H3C HaC CH3 CH3
Answers
The flow of electrons during this process stage Pushing Instructions for Arrows.
[tex]$$\mathrm{X} \mathrm{OH} \mathrm{OH}\mathrm{H}_3 \mathrm{C} \mathrm{HaCl}_3 \mathrm{CH}_3$[/tex]
To depict how electrons are moving throughout this stage of the process, draw curving arrows.
The mobility of an electron during a bond-making or bond-breaking process is depicted by curved arrows. The location of the electron or electron pair's origin is shown by the foot of the arrow, and their destination is indicated by the head of the arrow.
The shorthand for describing how electrons are moving in a process is "arrow pushing." The electron-rich chemical serves as the starting point for an arrow, while the electron-deficient compound serves as its destination.
A negatively charged subatomic particle known as an electron can either be free or attached to an atom. One of the three main types of particles inside an atom, along with protons and neutrons, is an electron that is linked to the atom. Protons, neutrons, and electrons collectively
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a tank at is filled with of carbon monoxide gas and of chlorine pentafluoride gas. you can assume both gases behave as ideal gases under these conditions.calculate the mole fraction of each gas. round each of your answers to significant digits.
Answers
The ideal gas law and the equation for the mole may be used to compute the mole fraction and partial pressure.
The definition of ideal gases states that they are hypothetical gases that may be used to simulate the behaviour of actual gases. Individual gaseous particles must have no volume and neither be attracted to nor repelled by one another in order for it to be termed perfect. The ideal gas law is referred to as,
PV = n RT
Consider the scenario where 18.0g of carbon monoxide and 10.6g of chlorine pentafluoride gas are added to a 6.000L tank at 19.2°C.
CO mole = 18/28 = 0.6428
mole ClF5 is equal to 10.6/130.445, or 0.081260.
then
mole total is 0.081260 + 0.6428 = 0.72406 mole.
PV = n RT
P = n RT/V equals (0.72406) (0.082) (19.2+273) / (6) = 2.89146 atm.
Mole fraction CO is equal to 0.6428/0.72406, or 0.8877.
CO has a partial pressure of 2.5667 atm (0.8877 * 2.89146).
CF5's mole fraction is 1-0.8877 = 0.1123.
CF5 has a partial pressure of = 0.1123*2.89146= 0.32471 atm,
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Note: The correct question would be as bellow,
A tank at is filled with of carbon monoxide gas and of chlorine pentafluoride gas. you can assume both gases behave as ideal gases under these conditions. calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank. be sure your answers have the correct number of significant digits. carbon monoxide mole fraction: partial pressure: chlorine pentafluoride mole fraction: partial pressure: total pressure in tank:
Ideal gas equation is used that relates the pressure, temperature, volume and number of moles of a gas, the given parameters' that are asked solved in the below section.
Ideal gases are hypothetical gases that may be used to simulate the behavior's of actual gases. The ideal gas law can be expressed as follows,
PV = n RT
Consider the scenario where 18.0g of carbon monoxide and 10.6g of chlorine pentafluoride gas are added to a 6.000L tank at 19.2°C.
CO mole = 18/28 = 0.6428
Mole ClF5 is equal to 10.6/130.445, or 0.081260.
then
Total number of moles= 0.081260 + 0.6428 = 0.72406 mole.
PV = n RT
P = n RT/V equals (0.72406) (0.082) (19.2+273) / (6) = 2.89146 atm.
Mole fraction CO is equal to 0.6428/0.72406, or 0.8877.
CO has a partial pressure of 2.5667 atm (0.8877 * 2.89146).
CF5's mole fraction is 1-0.8877 = 0.1123.
CF5 has a partial pressure of = 0.1123*2.89146= 0.32471 atm,
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Complete question-
A tank at is filled with of carbon monoxide gas and of chlorine pentafluoride gas. you can assume both gases behave as ideal gases under these conditions. calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank. be sure your answers have the correct number of significant digits. carbon monoxide mole fraction: partial pressure: chlorine pentafluoride mole fraction: partial pressure: total pressure in tank.
What volume of 12.0 M HCl is required to make 75.0 mL of 3.50 M HCI? 21.9 mL B) 0.560 mL C) 257 mL D) 560. mL E) none of the above Answer: A Show your calculations below:
Answers
To make 75.0 mL of 3.50 M HCI, 21.9 mL of 12.0 M HCl must be added. The letter A, 21.9 mL, is the right response among the options.
What is the straightforward meaning of volume?The space consumed within an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity.
What is volume, for instance?The potential of an object is gauged by its dimensions. For instance, a cup's capacity is stated to really be 100 ml if it can accommodate 100 ml of distilled water in its brim. The quantity of volume occupied by a three-dimensional object can also be used to describe volume.
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How many gold atoms are in a 0.434 ounce, 18 K
gold bracelet? (18 K
gold is 75 %
gold by mass.)
Answers
The number of gold atoms in 0.434 ounces, 18 K gold bracelet would be 2.82 x [tex]10^{21[/tex] atoms.
Dimensional analysis1 ounce = 28.35 grams
0.434 ounce = 0.434 x 28.35
= 12.3039 grams
Since 18 K gold is 75% gold by mass, the actual amount of gold in the bracelet would be:
12.3039 x 0.75 = 9.23 grams
Equivalent mole of 9.23 grams of gold: mole = mass/molar mass
= 9.23/196.967 = 0.0469 mol
1 mole of substances = 6.022 x [tex]10^{23[/tex] atoms
0.0469 mole of gold = 0.0469 x 6.022 x [tex]10^{23[/tex]
= 2.82 x [tex]10^{21[/tex] atoms
In other words, 0.434 ounces, 18 K gold bracelet would contain 2.82 x [tex]10^{21[/tex] atoms of gold.
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Construct the d-orbital energy diagram of octahedral complex [CoCl_6]^4-. How many unpaired electrons are there in [CoCl_6]^4-? Calculate the Ligand Field Stabilization Energy (LFSE) of this octahedral complex with respect to delta_0.
Answers
The d-orbital energy diagram of octahedral complex [CoCl_6]^4- is as follows:
What is octahedral complex?Octahedral complexes are a type of coordination complex consisting of a central atom or ion bound to six peripheral atoms, ions, or groups. The peripheral atoms or groups are arranged in an octahedral structure, consisting of six equidistant vertices connected by eight edges. The most common examples of octahedral complexes are those composed of metal ions and ligands. These complexes can be used in a variety of applications, including catalysis, metal extraction, and drug delivery.
The energy levels of the d-orbitals are organized in a set of 4 degenerate orbitals and each of these orbitals consists of 2 electrons. The 4 degenerate orbitals are: dxy, dyz, dxz and dz2. The dxy and dyz orbitals are the highest in energy and the dz2 orbital is the lowest in energy.
The octahedral complex [CoCl_6]^4- has 6 chloride ligands in an octahedral arrangement around the central cobalt metal ion. The 6 chloride ligands will interact with the metal ion’s d-orbitals, resulting in a splitting of the d-orbitals and the formation of a d-orbital energy diagram.
The d-orbital energy diagram of [CoCl_6]^4- is shown below, with the dxy and dyz orbitals at the highest energy, the dz2 orbital at the lowest energy and the dxz orbital in the middle.
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Draw the structure of:
5,5-dibromo-2-methyloctane
Answers
The bond line and condensed formulae for 3-methyloctane are provided below.
What is meant by methyl octane?Pentane is an alkane that has a methyl group replaced at position 3 to make 3-methylpentane. It serves as a lubricant, a solvent in the synthesis of organic compounds, and a starting point for the production of carbon black. It serves as an allelochemical, a non-polar solvent, and a human metabolite.
Condensed structural formula: This is a formula where the atoms are also shown and no lines are used to indicate where bonded atoms are located. Straight lines are used to write it.
The line-angle formula, also known as the bond line formula, represents the carbon atoms at the corners and ends of the lines with an angle while concealing the hydrogen atoms. Below are the bond line and condensed formulas for 3-methyloctane.
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draw a structure, with a formula of c4h10o, which has an integration of 6h, 2h, 1h, and 1h.
Answers
Hydrocarbons 6H, 2H, 1H, and 1H are all present as constituents of the molecule C4H10O.
What does a double bond equate to using an example?The double bond equivalent, to put it simply, is the ratio of the number of double bonds and triple bonds present in organic compounds. Consider the case of benzene, which has four double bonds, or three double bonds and one ring.
a type of chemical connection when two atoms within the same molecule share two pairs of electrons (see single bond, triple bond).
We must first determine the double bond equivalent, which is equal to C – H/2 + 1.
To C4H10O
Double-bond equivalent: 4 - 10/2 + 1
equivalent of a double bond is zero
Both rings and the double bond don't exist.
So it is an aliphatic molecule with four different proton kinds.
The compound given is attached below with its structure.
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Which of the following solvents would be good to use for 1H NMR analyses? A. chloroform-d B. dimethyl sulfoxide C. acetone D. deuterium oxide E. acetone-d6.
Answers
Options (c), (d), and (e) are correct. The solvent that can be used for proton NMR analyses would be chloroform-d, acetone-d6, and deuterium oxide. This is because all the above solvents are deuterated.
What is 1H NMR analyses?The use of nuclear magnetic resonance in NMR spectroscopy with respect to hydrogen-1 nuclei within a substance's molecules in order to ascertain the structure of its molecules is known as proton nuclear magnetic resonance (proton NMR, hydrogen-1 NMR, or 1H NMR). In terms of NMR interpretation, it is crucial to comprehend the chemical shift trend. Nearness to electronegative atoms (O, N, halogen) and unsaturated groups (C=C, C=O, aromatic) affects the proton NMR chemical shift. Moving to the down field are electronegative groupings (left; increase in ppm).Alternatives (c), (d), and (e) are accurate. Chloroform-d, acetone-d6, and deuterium oxide are suitable solvents for proton NMR studies. Because all of the aforementioned solvents are deuterated, this is.To learn more about 1H NMR analyses refer to:
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What mass of sodium hydroxide is required to make 200 cm^3 of sodium hydroxide solution of concentration 0.4 mol/dm^3.
0.4 g
3.2 g
8.0 g
16.0 g
Answers
The mass of sodium hydroxide required to make 200 cm³ of sodium hydroxide solution of concentration 0.4 mol/dm³ is 3.2 g/
The correct option is B.
What is the molar concentration of a solution?In terms of the amount of material per unit volume of solution, molar concentration is a measurement of the concentration of a chemical species, specifically a solute in a solution. The most frequent measure of molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm³ in SI units.
Mathematically;
Molar concentration = number of moles/volume in liters
Hence: the number of moles = molar concentration * volume in liters
The number of moles of sodium hydroxide in the solution will be:
number of moles = 0.4 * 200 * 1/1000
number of moles = 0.08
The mass of sodium hydroxide required is obtained from the formula below:
mass = number of moles * molar mass
molar mass of sodium hydroxide = 40 g/mol
Mass of sodium hydroxide required = 0.08 * 40
Mass of sodium hydroxide required = 3.2 g
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How many orbitals are described by each of the below combinations of quantum numbers?
n-3, 2-0______________ orbitals
n-4,2-2, m,- 2 ___________orbitals
Answers
The number of orbitals is five, and ml=2 refers to the last (fifth) orbital space 4d.
What is quantum numbers?Quantum numbers are used in quantum physics and chemistry to explain the values of conserved quantities in the dynamics of a quantum system. Quantum numbers are the collection of numbers used to characterize the location and energy of an electron in an atom. There are four types of quantum numbers: primary, azimuthal, magnetic, and spin. There are four quantum numbers in atoms: the primary quantum number (n), orbital angular momentum quantum number (l), magnetic quantum number (ml), and electron spin quantum number (ms).
Here,
Quantum numbers (n,l,ml, ms)
n=3. refers to 3rd energy level
3rd energy level has 3 possible values of l
d has 5 different orientations
s=0. p=1. d=2
-2,-1,0,1,2
answer- n=3 l=2. number of orbitals-5
n=4 refers to 4th energy level
4th level has 4 possible l values
Repeat from above for d
s=0 p=1 d=2 f=3
n=4 l=2. ml=2
The number of orbitals is 5 and the ml=2 is referring to the last(5th) orbital space 4d.
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Which one of the following combinations of names and formulas of ions is incorrect?
A O2- oxide
B Ca2+ calcium
C ClO3- chlorate
D HCO3- hydrogen carbonate
E NO2- nitrate
Answers
The combinations of names and formulas of ions that is incorrect is NO2- nitrate.
What is ions?An ion is an atom or molecule with a charge because it has a different amount of electrons than protons. Any atom or group of atoms with one or more positive or negative electrical charges is referred to as an ion. An ion is an electrically charged atom (or collection of atoms). It is generated when an atom loses or gains an electron. Ions are classified into two types: cations and anions. When a sodium atom loses one electron, a sodium ion (Na+) is created. A cation is a sodium ion.
Here,
NO2- nitrate is an erroneous combination of ion names and formulae.
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When an air bubble rises in water, what happens to its mass, volume, and density?
Answers
When an air bubble rises in water, it's mass remains same whereas density decreases and volume increases.
What happens to mass, volume, and density when an air bubble rises in water?When an air bubble rises in the water, then mass of the air in the bubble does not change. The volume of bubble increases as the pressure on it decreases. Volume of the bubble becomes almost 1.6 times to initial volume of bubble.
Pressure decreases as as it ascends, less water is above it that is pressing down on it. As, the mass is unchanging but volume is increasing, then the density decreases.
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What are the types of plasma enzymes?
Answers
Anion transport protein
Glyceraldchyde
Protein kinases
Calculate the ratio of imidazole to the imidazolium ion in a solution at pH 7.4.
Answers
2.5 to 1. Imidazolium ion will deprotonate to imidazole at pH 7.4 because it is more basic than pKa, which results in more imidazole being present overall.
What is imidazole used for?Imidazole becomes charged when it is protonated (i.e., in acid or HA+ form). It is uncharged when it is in its deprotonated (basin or A) form. Therefore, the uncharged:charged species ratio is [A][HA+], or 10:1.
The chromatography column's beads that are coated with nickel ions to which tagged proteins are bound are eluted using imidazole. In order to release the His-tagged proteins from nickel coordination, too much imidazole is delivered through the column. This causes the His-tag to be dislodged from nickel coordination.
2.5 to 1. Imidazolium ion will deprotonate to imidazole at pH 7.4 because it is more basic than pKa, which results in more imidazole being present overall.
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