Por restricciones de longitud no es posible resumir las respuestas asociadas a esta pregunta, invitamos cordialmente a leer la explicación para mayores detalles sobre el análisis de secciones cónicas.
¿Cómo analizar ecuaciones de secciones cónicas?
Según la geometría analítica, existen cinco tipos de secciones cónicas: (i) Circunferencia, (ii) Parábola, (iii) Elipse, (iv) Hipérbola, (v) Recta. 2) a) La ecuación estándar de la circunferencia se caracteriza con el centro (h, k) y la longitud del radio (r):
(x - h)² + (y - k)² = r²
(x - 2)² + (y + 1)² = 4²
b) La longitud del radio de la circunferencia se obtiene por el teorema de Pitágoras sobre la longitud del segmento CP:
r = √[(4 - 1)² + (6 - 3)²]
r = √(3² + 3²)
r = 3√2
(x - 1)² + (y - 3)² = 18
3) a) El eje focal forma parte del eje de simetría de la parábola. La ecuación estándar de la parábola es:
4 · p · x = y²
Donde p es la distancia entre el foco y el vértice.
Si tenemos que (x, y) = (2, 4), entonces la ecuación de la parábola es:
4 · p · 2 = 4²
p = 2
8 · x = y²
Las coordenadas del foco de la parábola son de la forma (x, y) = (h + p, k):
F(x, y) = (2, 0)
Ahora se determinan los extremos del lado recto: (x = 2)
8 · 2 = y²
y = ± 4
Los extremos del lado recto son (2, 4) y (2, - 4), cuya longitud de segmento es 8 unidades.
b) El eje focal forma parte del eje de simetría de la parábola. La ecuación estándar de la parábola es:
4 · p · x = y²
Si tenemos que (x, y) = (6, 3), entonces la ecuación de la parábola es:
4 · p · 6 = 3²
p = 8 / 3
(32 / 3) · x = y²
Las coordenadas del foco son F(x, y) = (8 / 3, 0).
Ahora se determinan los extremos del lado recto: (x = 6)
(32 / 3) · 6 = y²
y = ± 8
Los extremos del lado recto son (6, 8) y (- 6, - 8), cuya longitud de segmento es 16 unidades.
4) a) Tenemos una ecuación estándar de la forma 4 · p · y = x². A continuación, hallamos todas las variables requeridas:
x² = 8 · y
p = 2
Directriz: y = - 2, Foco: F(x, y) = (0, 2), Longitud del lado recto: 4
b) Tenemos una ecuación estándar de la forma 4 · p · x = y². A continuación, hallamos todas las variables requeridas:
y² = - (3 / 2) · x
p = - 3 / 8
Directriz: x = 3 / 2, Foco: F(x, y) = (- 3 / 2, 0), Longitud del lado recto: 3.
5) En esta parte debemos manipular algebraicamente las ecuaciones hasta su forma estándar para determinar los datos requeridos de cada caso. La ecuación estándar de la elipse tiene el siguiente problema:
(x - h)² / a² + (y - k)² / b² = 1
Donde:
(h, k) - Centro de la elipse.a, b - Longitudes de los semiejes.a) 81 · x² + 144 · y² = 11664
x² / 144 + y² / 81 = 1
x² / 12² + y² / 9² = 1
Longitud del semieje mayor: 12
Longitud del semieje menor: 9
c = √(12² - 9²)
c ≈ 7.937
Coordenadas de los focos: F₁ (x, y) = (- 7.937, 0), F₂ (x, y) = (7.937, 0)
Vértices: V₁ (x, y) = (- 12, 0), V₂ (x, y) = (12, 0)
Longitud del lado recto
144 · y² = 11664 - 81 · x²
y² = (11664 - 81 · x²) / 144
y = ± (1 / 12) · √(11664 - 81 · x²)
y = ± (1 / 12) · √(11664 - 81 · 7.937²)
y = ± 6.750
La longitud del lado recto es 13.5.
b) 36 · x² + 25 · y² = 3600
x² / 10² + y² / 12² = 1
Longitud del semieje mayor: 12
Longitud del semieje menor: 10
c = √(12² - 10²)
c ≈ 6.633
Coordenadas de los focos: F₁ (x, y) = (0, - 6.637), F₂ (x, y) = (0, 6.637)
Vértices: V₁ (x, y) = (0, - 12), V₂ (x, y) = (0, 12)
Longitud del lado recto
36 · x² = 3600 - 25 · y²
x² = 100 - (25 / 36) · y²
x = √[100 - (25 / 36) · y²]
x = √[100 - (25 / 36) · 6.637²]
x = ± 8.331
La longitud del lado recto es 16.662.
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An exponential function f ( x ) = a b x f ( x ) = a b x passes through the points (0, 10000) and (3, 2160). What are the values of a and b ?
The values of a and b of the exponential function are 10000 and 0.6 respectively
How to solve exponential functions?We are given that the exponential function is expressed in general form as; f(x) = abˣ
where;
a is a non-zero real number called the initial value
b is any positive real number such that
b ≠ 1.
The domain of f is all real numbers.
The range of f is all positive real numbers if a > 0.
The range of f is all negative real numbers if a < 0.
The y-intercept is (0, a)
The horizontal asymptote is; y = 0.
We are told that this exponential function passes through the coordinate points (0, 10000) and (3, 2160).
At coordinate point (0, 10000), we have;
10000 = ab⁰
a = 10000
Now, at the coordinate point (3, 2160), we have;
2160 = 10000(b)³
2160/10000 = b³
0.216 = b³
b = ∛0.216
b = 0.6
Thus, we can conclude that the values of a and b of the given exponential function are respectively 10000 and 0.6.
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There are 20 students in Mrs. Tanya's class and 24 kids in Mrs. Olga's class. The students need to be placed on teams of equal size with students from only their own class. What's the largest size of a team?
The largest size of a team according to the task content is; 20 kids.
What is the largest size of a team?It follows from the task content that the population is; 20 students in Mrs. Tanya's class and 24 kids in Mrs. Olga's class.
However, since, the team forming condition states that students be placed on teams of equal size with students from only their own class.
It therefore follows that the largest size of a team is 20 as only 20 students are in Mrs. Tanya's class hence leaving 4 kids in Mrs. Olga's class without a team.
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The board of education has decreed that a maximum student teacher ratio in a classroom be 18:1
If the current school has 235 total students then what is the minimum number if teachers that must be working in your school ?
Answer:
235÷18=
how many classes of 18 students for each teacher
Step-by-step explanation:
Assume a = b and c ≠ 0
Which of the following sentences is not true?
1) a+c=b+c
2) a-c=b-c
3) ac = bc
4) a/c = b/c
5) none of these
Answer:
None of these is not true
If the solutions of f(x)=0 are -1 and 2
then find the solutions of f(x/2)=0
Answer: -2 and 4
Step-by-step explanation:
Let [tex]t=x/2[/tex].
[tex]f(t)=0 \longrightarrow t=-1, 2\\\\\therefore x=-2, 4[/tex]
Given the coordinates below, what is the midpoint of AB?
A(-6, -10)
B(2,5)
Given :
[tex] \: [/tex]
A(-6, -10)B( 2, 5)
[tex] \: [/tex]
[tex] \gray{ \frak{The \: given \: two \: \: points \: are(x_{1 },y_{1})=(−6 , -10)and(x_{ 2 },y_{2} )=( 2,5 )\:}}[/tex]
[tex] \: [/tex]
Let's solve by using midpoint formula :
[tex] \: [/tex]
[tex] \bf \boxed{\color{red}\frak{Midpoint \: \: Formula : {( \: x ,\:y \: ) = }( \frak{ \frac{x_{1 } + y_{1}}{2} , \frac{x_{2 } + y_{2}}{2} )}}}[/tex]
[tex] \: [/tex]
[tex] \large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \frac{ -6 + 2}{2} , \frac{ - 10 + 5}{2} )}}[/tex]
[tex] \: [/tex]
[tex] \: \large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \frac{ -4}{2} , \frac{ - 5}{2} )}}[/tex]
[tex] \: [/tex]
[tex]\large \gray{ \frak{( \: x ,\:y \: ) = }( \frak{ \cancel\frac{ -4}{2} , \cancel\frac{ - 5}{2} )}}[/tex]
[tex] \: \: [/tex]
[tex] \underline{ \boxed{ \large \red{ \frak{option \: d }( \frak{ - 2, - 2.5)}}}}✓[/tex]
Hope Helps! :)
Name the figure below in two different ways.
Y
Symbol:
and
M
A
The line segment in the figure can be named as: IYM and MYI.
How to Name a Line Segment?If we have three points on a line segment, the point on the middle will be the alphabet in the center when naming the line, while the alphabets of both endpoints can be written either at the beginning or ending.
Given the figure above, Y will be at the center. The endpoints are I and M. Therefore, the line segment can be named as: IYM and MYI.
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A new plasma TV was marked down 20%. The new sale price of the TV was $380. What is the TV’s regular selling price?
x=regular selling price
X×80/100=380
= X×8/10=380
= 8X=380×10=3800
X=3800/8
X=475
the regular selling price is 475
Before the 20% discount, the TV's regular selling price was $475 as per the concept of percentage.
Let's denote the regular selling price of the plasma TV as "x". When the TV was marked down by 20%, the sale price became $380.
To find the regular selling price, we can set up an equation using the information given:
Sale Price = Regular Selling Price - (Discount Percentage × Regular Selling Price)
$380 = x - (0.20x)
Now, let's solve for "x" (the regular selling price):
$380 = x - 0.20x
$380 = 0.80x
To isolate "x," we divide both sides of the equation by 0.80:
x = $380 / 0.80
x = $475
The regular selling price of the plasma TV is $475.
Therefore, before the 20% discount, the TV's regular selling price was $475. After the discount, the sale price was reduced to $380, which is 20% less than the regular price.
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A manufacturer knows that their items have a normally distributed lifespan, with a mean of 7.9 years, and standard deviation of 0.9 years.
If you randomly purchase one item, what is the probability it will last longer than 9 years?
If you randomly purchase one item, the probability it will last longer than 9 years is; 11.12%
How to find the probability from z-score?
The formula for Z-score is;
z = (x' - µ)/σ
where;
x' = sample mean
µ = population mean
σ = standard deviation
Thus;
z = (9 - 7.9)/0.9
z = 1.22
From online p-value from z-score calculator, we have;
probability = 0.1112 = 11.12%
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The following table shows Jace's earnings based on the number of hours that he works.
Number of hours 111 222 333
Jace's Earnings \$20$20dollar sign, 20 \$30$30dollar sign, 30 \$40$40dollar sign, 40
Are Jace's earnings proportional to the number of hours that he works?
Answer:
no
Step-by-step explanation:
because no
19) Write the scientific notation of 1
Answer:
1.0 x 10^0
Step-by-step explanation:
The above works because 10^0 = 1, and 1 x 1 = 1.
Brainliest, please :)
A rectangle is 6 meters long and 4 meters wide. What is the area
of the rectangle?
Answer:
the rectangles area is 24 meters
Step-by-step explanation:
area = length x width
length is 6 using the words long and width is 4
Answer:
area = 24 cm²
Step-by-step explanation:
The area of a rectangle can be found using the formula:
[tex]\boxed {area = length \times width}[/tex].
Substituting the values into the equation:
[tex]area = 6 \space\ cm\times 4 \space\ cm[/tex]
⇒ [tex]\bf 24 \space\ cm^2[/tex]
Determine whether the relationship is linear, quadratic, or neither by completing each table. Be sure to give
a reason for your choice.
The 1st table represents a linear as well as the quadratic relationship, the 2nd table represents neither and the 3rd table also represents neither relationship.
Why do the given tables have the above relationship?The first table is having linear as well as quadratic because the 1st table has its first difference equal as well as the second difference is also equal i.e., why it is linear and quadratic respectively.The second table is having neither because 1st difference is not equal to each other as well as 2nd the difference is also not equal.The third table is having neither because 1st difference is not equal to each other as well as 2nd the difference is also not equal to each other. Therefore, the 3rd table is neither.Hence, the 1st table represents a linear as well as a quadratic relationship, the 2nd table represents neither and the 3rd table also represents neither relationship.
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Otto builds and sells model cars. He made a graph to compare the number of days to the number of model cars. Three of the points form a proportional relationship, but one does not. Which point does not fit in the proportional relationship? Coordinate plane with Number of Days on the x-axis and Number of Model Cars on the y axis. 4 points are plotted in the plane: 2, 1; 4, 2; 6, 2; and 8, 4. A (2, 1) B (4, 2) C (6, 2) D (8, 4)
\
Need HELP ASAP
Answer:
I have attached a really rough graph!!
Step-by-step explanation:
The point that does not fit in the proportional relationship is (6,2) when we plot the other three points and join the points they will give us a staright line but the point (6,2) isnt lying on that staright line.. Therefore, it does not fit in the proportional relationship!
Answer:
(6,2)
Step-by-step explanation:
Given the drawing, what would the value of x need to be in order
for it to be true that m ||n?
4x + 18
m
7x-21
Be sure to show all calculations and algebraic steps in your re-
sponse.
Hint: What must be true about alternate exterior angles in order
for lines to be parallel?
[tex]4x + 18 = 7x - 21 \\ 18 + 21 = 7x - 4x \\ 39 = 3x \\ x = \frac{39}{3} = 13 [/tex]
Your last five customer interactions lasted 2, 3, 6, 8, and 4 minutes."
Employee: "That means I've averaged __________ minutes across those 5 interactions."
Answer:
4.6 minutes
Step-by-step explanation:
Average = the sum of the numbers/ the number of numbers
Plug in the numbers: 2+3+6+8+4/5 = 23/5 = 4.6 minutes
solve the system of equations. y=3x+2 y=x^2-4+2
The solutions to the system of equations are (4, 15) and (-1,-1)
How to solve the system of equations?The system of equations is given as:
y=3x+2
y=x^2-4+2
Substitute y=3x+2 in y=x^2-4+2
3x + 2=x^2-4+2
Simplify
x^2 - 3x - 4 = 0
Expand
x^2 + x - 4x - 4x = 0
Factorize
x(x + 1) - 4(x + 1) = 0
This gives
(x - 4)(x + 1) = 0
Solve for x
x = 4 and x = -1
Substitute these values in y=3x+2
y = 3(4)+2 = 15
y = 3(-1)+2 = -1
Hence, the solutions to the system of equations are (4, 15) and (-1,-1)
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Last PreCalc Question, Need help with writing piecewise functions with graphs. Giving brainliest!
The piece-wise linear functions can be written as follows:
[tex]f(x) = x, x \leq -2[/tex].[tex]f(x) = -x - 7, -2 < x \leq 1[/tex].[tex]f(x) = 2x - 9, x > 1[/tex].What is a linear function?A linear function is modeled by:
y = mx + b
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.For x equal or less than -2, the line passes through (-3,-3) and (-2,-2), hence the rule is:
[tex]f(x) = x, x \leq -2[/tex].
For x greater than -2 up to 1, the y-intercept is of -7, and the line also passes through (1,-8), hence the rule is:
[tex]f(x) = -x - 7, -2 < x \leq 1[/tex].
For x greater than 1, the function goes through (2,-5) and (3,-3), hence the slope is:
m = (-3 - (-5))(3 - 2) = 2.
The rule is:
y = 2x + b.
When x = 2, y = -5, hence:
-5 = 2(2) + b
b = -9.
Hence:
[tex]f(x) = 2x - 9, x > 1[/tex].
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An agriculture company is testing a new product that is designed to make plants grow taller. This can be thought of as a hypothesis test with the following hypotheses.
H0: The product does not change the height of the plant.
Ha: The product makes the plant grow taller.
Is the following an example of a type I or type II error?
The sample suggests that the product does not change the height of the plant, but it actually does make the plant grow taller.
It is an example of Type I error.
About Type I error
The rejection of a null hypothesis (H0) when it is actually true is a Type I error. It is represented by the following condition,
Failure to reject a null hypothesis when it is true that it is false which is a Type II error.
How is this an example of Type I error?
The given case's hypothesis is described as follows:
H₀: The product has no effect on the plant's height.
Hₐ: The substance causes the plant to enlarge.
The sample claims that the product causes the plant to grow taller, however in reality, it has no effect on the plant's height.
Therefore, the sample recommends rejecting the null hypothesis even though it is true. Consequently, a result, this error is a Type I error.
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HELPP WILL GIVE BRAINLIEST
which graph represents the function f(x) = sqrt(x) + 3
Answer:
the real answer is 2 I hope that
Solution for the attached question below
The solution to the question is 265.
What is the logarithm of a number?Logarithm of a number A is the exponent or power or index n, a given number called the base B would be raised to give the number A.
So n is the logarithm of A to base B.
Analysis:
log 2( log2(x-9)) = 3
log2(x-9) = [tex]2^{3}[/tex]
log2(x-9) = 8
x-9 = [tex]2^{8}[/tex]
x-9 = 256
x = 256 + 9
x = 265
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question in the picture below
The doubling time after 4 and 7 years is 400 months and 700 months respectively
How to determine the doubling timeThe formula for finding doubling time is given as;
Doubling time = [tex]t \frac{In 2}{In 1 + \frac{r}{100} }[/tex]
Where t = time = 4 and 7 years
r = rate
For 4 years, we have
Doubling time = [tex]4 * \frac{In 2}{In ( 1 + \frac{0.7}{100}) }[/tex]
⇒ [tex]4 * \frac{In 2}{In 1. 0074}[/tex]
⇒ [tex]4 * \frac{0. 6931}{0. 0074}[/tex]
⇒ [tex]4[/tex] × [tex]93. 66[/tex]
⇒ 374. 65
⇒ 400 months in the nearest hundredth
For 7 years
⇒ [tex]7[/tex] × [tex]93. 66[/tex]
⇒ [tex]655. 62[/tex]
⇒ 700 months in the nearest hundredth
Thus, the doubling time after 4 and 7 years is 400 months and 700 months respectively
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In 2016, Alberta had about 4.2 million people.
Assuming they follow the same population
growth rate, it is predicted they will have 6.65
million people in 20 years. At what rate is the
province's population growing?
The province's population is growing at the rate of 58.34 %
Rate of change is used to mathematically describe the percentage change in value over a defined period of time, and it represents the momentum of a variable. The calculation for ROC is simple in that it takes the current value of a stock or index and divides it by the value from an earlier period.
Given:
Initial Population = 4.2 million
Population after 20 years = 6.65 million
Change in population = 6.65 - 4.2 = 2.45 million
Rate at which the province's population growing is
= [tex]\frac{Change in population}{Inital Population}[/tex] x100 %
= [tex]\frac{2.45}{4.2}\\[/tex] x 100%
= 58.34 %
Thus the province's population is growing at the rate of 58.34 %
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Anyone know the answer please teach me
Answer: Look at step by step
Step-by-step explanation:
(a) There are 119 stocks that increased in price out of 246 stocks so the probability of selecting a stock that is increased in price is 119/246 = 48.37%
(b) There are 112 stocks where it pays dividends so the probability so the probability of selecting a stock that pays dividends is 112/246 = 45.53%
(c) There are 49 stocks which satisfy the question so the probability is 49/246 = 19.92%
(e) There are 34 stocks which increase in price and pay dividends out of the 119 stocks that increase in price so the probability is 34/119 = 28.57%
(f) Using the same logic as (e), the probability is 85/134 = 63.43%
(g) From the requirements, we see that 49 stocks don't satisfy the requirements, so the probability is (246-49)/246 = 80.08%
f(x)=2x. If g(x) is a vertical stretch, compression, and or reflection of f(x) followed by a, what is the equation of g(x)?
The function g(x) is g(x)= (3x)^2
How to solve for g(x)?
The complete question is in the image
From the graph in the image, we have:
f(x) = x^2
The function f(x) is stretched by a factor of 3 to form g(x).
This means that:
g(x) = f(3x)
So, we have:
g(x)= (3x)^2
Hence, the function g(x) is g(x)= (3x)^2
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Write an equation of the line that passes through the point (4, –5) with slope 2.
answers:
A. y−4=2(x+5)
B. y+5=−2(x−4)
C. y−4=−2(x+5)
D. y+5=2(x−4)
Answer:
D. y+5=2(x−4)
Step-by-step explanation:
The point-slope form of the equation of a line is useful for writing an equation for a line through a given point with a given slope.
Point-slope formThe point-slope form of the equation of a line is ...
y -k = m(x -h) . . . . . . line through point (h, k) with slope m
ApplicationWe want a line through point (h, k) = (4, -5) with slope m = 2. Putting these numbers into the form gives ...
y -(-5) = 2(x -4)
y +5 = 2(x -4) . . . . . . simplifying the signs
Fill in the blank
Timothy runs a public transportation service in his town. He has learned from his accountant that his organization is a liable to a special kind of tax. Which tax would Timothy have to pay from his organization?
Timothy would have to pay the _______ tax for his transportation service.
Answer:
road
Step-by-step explanation:
The RLX Company just paid a dividend of $2.85 per share on its stock. The dividends are expected to grow at a constant rate of 4.5 percent per year, indefinitely. Assume investors require a return of 10 percent on this stock. What is the current price?
The current stock price is $54.15.
Given that RLX Company just paid a dividend of $2.85 per share on its stock and dividends are expected to grow at a constant rate of 4.5 percent per year, indefinitely.
Stock valuation alludes to the valuation of the natural worth per portion of an organization's stock which can help the organization in deciding its reasonable worth in case of twisting up or consolidation. One of the models used to esteem the stock cost is the profit development model. It expects the cost of the stock to be the current worth representing things to come profits of the stock accepted to develop at a consistent rate.
Dividend (D0) = $2.85
Growth rate (g) = 4.5%
Required return (r) = 10%
Firstly, we have to calculate the value of the current stock price.
The current stock price can be calculated by using the dividend growing model.
[tex]\begin{aligned}\text{Current stock price}&=\frac{D_{0}\times(1+g)}{r-g}\\ &=\frac{2.85\times (1+0.045)}{0.10-0.045}\\ &=\frac{2.85\times 1.045}{0.055}\\ &=\frac{2.97825}{0.055}\\ &=54.15\end[/tex]
Hence, the current stock price when dividend of $2.85 are expected to grow at a constant rate of 4.5 percent per year, indefinitely is $54.15.
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Find the sum of the geometric series given a1=−1, r=2, and n=7
A. -127
B. -116
C. 1
D. -118
Answer:
A
Step-by-step explanation:
the sum to n terms of a geometric series is
[tex]S_{n}[/tex] = [tex]\frac{a_{1}(r^{n}-1) }{r-1}[/tex] , then for n = 7
S₇ = [tex]\frac{-1(2^{7}-1) }{2-1}[/tex] = [tex]\frac{-1(128-1)}{1}[/tex] = - 1 (127) = - 127
46.Find the quotient and remainder
Answer:
30624; 1514,6; a1,6.