Solve the system of equations by elimination:

−5x+3y=2
−5x−5y=−30

The equation that describes the number of bacteria in both the foods when they are mixed is; Option C: 35T₂ + 55T + 450

We are given the equations that describes the number of bacteria in both the foods when they are mixed.

Equation for first bacteria is;

N₁(T) = 15T₂ + 60T + 300

Equation for second Bacteria is;

N₂(T) = 20T² - 5T + 150

The equation that describes the number of bacteria in both the foods when they are mixed is;

N₁(T) + N₂(T) = 15T₂ + 60T + 300 +  20T² - 5T + 150

⇒ 35T₂ + 55T + 450

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Answer:

D

Step-by-step explanation:

Yep, what you did there is correct!

The expression was: [tex](\frac{5^2}{4} )^4[/tex]

So let's solve this step by step.

First the numerator

[tex](5^2)^4[/tex]

Is the same thing as

[tex]5^8[/tex]

Since the exponents are multiplied.

Next is the denominator
[tex]4^4[/tex]

This can stay the same, since solving it as 4 x 4 x 4 x 4 will only make the fraction more complicated. Also, the answer choices below show that the denominator stays in exponential form.

==> [tex]\frac{5^8}{4^4}[/tex] is our final answer!

So the answer to this question is D. You got the question correct! :)

I hope that helped!!

The population after 20 minutes is 14.

We have starting point that is 10 and increasing with 3 times per hour. So, in every hour the data varies as :-        

            After 1 hour, the population is 3*10

            After 2 hours, -> 3*3*10

            After 3 hours, -> 3*3*3*10

Make a function from above observation in the increasing

              number of the  insects per hour

              This can be generalized as a function of t, the time in hours:

              f(t) = (3^t) * 10

putting the values in the function and get the desired answer,

                             P = (3^t) * 10

             Since 20 minutes is equal to (1/3) hours, t can be substituted for

             (1/3) in order to calculate the population size after 20 minutes:

                  P = (3^(1/3)) * 10 = 14.422 ≈ 14

The population after 20 minutes is 14.

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Answer:The population after 20 minutes is 14.

We have starting point that is 10 and increasing with 3 times per hour. So, in every hour the data varies as :-        

           After 1 hour, the population is 3*10

           After 2 hours, -> 3*3*10

           After 3 hours, -> 3*3*3*10

Make a function from above observation in the increasing

             number of the  insects per hour

             This can be generalized as a function of t, the time in hours:

             f(t) = (3^t) * 10

putting the values in the function and get the desired answer,

                            P = (3^t) * 10

            Since 20 minutes is equal to (1/3) hours, t can be substituted for

            (1/3) in order to calculate the population size after 20 minutes:

                 P = (3^(1/3)) * 10 = 14.422 ≈ 14

The population after 20 minutes is 14.

Step-by-step explanation:

The double number line that shows the other values of packages and pencils is A. A double number line with 5 equally spaced tick marks. The line labeled Packages, reads from left to right: 0, 1, 2, 3, 4. The line labeled Pencils, reads from left to right: 0, 12, 24, 36, 48.

It should be noted that a number line simply means a line which numbers are marked a intervals to illustrated numerical operations.

In this case, the double number line with 5 equally spaced tick marks. The line labeled Packages, reads from left to right: 0, 1, 2, 3, 4. The line labeled Pencils, reads from left to right: 0, 12, 24, 36, 48 illustrate this information

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Answer:

Step-by-step explanation:

Solution

You want to find the probability of one certain event happening. For example, you want the die to come up 5 and you want the 6 to be drawn from the cards.

The total number of outcomes is 6 (for the die) times 10 for the cards.

One 1 outcome is possible.

So the vent probability is 1/6*10 = 1/60. You will have to translate this to the choices you have been given. 1/60 = 0.0167 is another possibility.

Answer

1/60 or 0.0167

Answer:

y = -6x + 7.5

Explanation:

To find perpendicular bisector equation:

Given points: B(-2, 1), C(4, 2)

First find slope:

[tex]\sf slope: \dfrac{y_2 - y_1}{x_2- x_1} \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]

[tex]\sf slope: \dfrac{2-1}{4-(-2)} } = \dfrac{1}{6}[/tex]

Then the perpendicular slope will be negatively inverse.

[tex]\sf perpendicular \ slope \ (m) : -(\dfrac{1}{6} )^{-1} = -6[/tex]

Then find the mid point coordinates between BC:

[tex](x_m, y_m)= \sf (\dfrac{x_1 + x_2}{2} , \dfrac{y_2 + y_1}{2} )[/tex]

[tex](x_m, y_m) = \sf (\dfrac{-2 + 4}{2} , \dfrac{1 + 2}{2} )[/tex]

[tex](x_m, y_m) = \sf ( 1 , 1.5 )[/tex]

Then find equation:

y - yₘ = m(x - xₘ)

y - 1.5 = -6(x - 1)

y = -6x + 6 + 1.5

y = -6x + 7.5

The answer is y = -6x + 15/2.

First, find the slope of BC.

m = Δy/Δx

m = 2 - 1 / 4 - (-2)

m = 1/6

Hence, the slope of the perpendicular bisector will be the negative reciprocal of the given line.

m' = - (1/ [1/6])

m' = -6

Now, find the midpoint of BC.

M = (-2 + 4 / 2, 2 + 1 / 2)

M = (1, 3/2)

Now, we can find the equation of the perpendicular bisector using the point slope form of equation.

y - y₁ = m (x - x₁)

y - 3/2 = -6 (x - 1)

y - 3/2 = -6x + 6

y = -6x + 15/2

Answer:

13500 ft²

Step-by-step explanation:

     We can find the width of the rectangle using Pythagorean theorem.

AD² + DC² = AC²

180² + DC²  = 195²

32400 + DC² = 38025

              DC² = 38025 - 32400

                     = 5625

               DC = √5625

                      = 75 ft

length = 75 ft

Width = 180 ft

[tex]\sf \boxed{\text{\bf Area of rectangle = length * width}}[/tex]

                                 =  75 * 180

                                  = 13500 ft²

Answer:

9

Step-by-step explanation:

See the attached image.

Answer:

1/12

Step-by-step explanation:

the chances of rolling a 3 is 1/6

there are 3 numbers more than 3 on a number die, 4,5, and 6

which is 3/6 or 1/2 if you decide to simplify

to find the probability you want you have to multiply the fractions by each other

1/6x1/2=1/12

Q14)

a) The smallest prime number is 2. The smallest composite number is 4.

b) Rs 720 - 20 [as loss]

=> Rs 790 = SP

c) Rs 500 - 30 [as profit]

=> Rs 470 = CP

d) a° + b° = 180°

Hope it helps you!

The equation of the perpendicular bisector of BC with B(-2, 1), and C(4, 2) is y = 7.6 - 6•x

The slope, m, of the line BC is calculated as follows;

The slope of the perpendicular line to BC is -1/(1/6) = -6

The midpoint of the line BC is found as follows;

[tex] \left( - 2 + \frac{4 - ( - 2)}{2}, \: 1 + \frac{2 - 1}{2} \right) = (1,\: 1.5)[/tex]

The perpendicular bisector is the perpendicular line constructed from the midpoint of BC.

The equation of the perpendicular bisector in point and slope form is therefore;

(y - 1.5) = -6•(x - 1)

y - 1.6 = -6•x + 6

y = -6•x + 6 + 1.6 = 7.6 - 6•x

Which gives;

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For each of the following distance matrices of graph, the

This is used to refer to the fact that there would be a maximum distance that exists between the pair of vertices.

This used to refer to the minimum eccentricities of the vertices

This is used to show all of the vertices that have minimum eccentricities.

We have

e 1 = 3

e 2 = 3

e3 = 2

e4 = 3

e 5 = 3

e 6 = 3

e 7 = 3

e8 = 2

e 9 = 3

e 10 = 2

Then the the diameter = maximum eccentricity = 3

The radius = minimum eccentricity = 2

center = [3, 8,10]

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Using the Pythagorean theorem and the law of sines, the correct lengths to the nearest hundredth and the angle measures to the nearest degree are: A) ME = 5; ER = 6, MR ≈ 7.81 m∠E = 90°, m∠M ≈ 50°, m∠R ≈ 40°

The theorem states that the square of the longest side of a right triangle equals the sum of the squares of the lengths of the other two smaller sides of the right triangle.

The points, M(3,2), E(3,−3), and R(9,−3) has been plotted on the graph which shows that angle E  is a right triangle, therefore:

m∠E = 90 degrees.

Find ME and ER:

ME = 5 units

ER = 6 units.

Using the Pythagorean theorem, find MR:

MR = √(ME² + ER²)

MR = √(5² + 6²)

MR = √(25 + 36)

MR = 7.81 units

Using the law of sines, find m∠M:

sin M/ER = sin E/MR

sin M/6 = sin 90/7.81

sin M = (sin 90 × 6)/7.81

sin M = 0.7682

M = sin^(-1)(0.7682)

m∠M ≈ 50°

m∠R = 180 - 50 - 90

m∠R = 40°

Thus, the correct lengths to the nearest hundredth and the angle measures to the nearest degree are:

A) ME = 5; ER = 6, MR ≈ 7.81 m∠E = 90°, m∠M ≈ 50°, m∠R ≈ 40°

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Answer:

80

Step-by-step explanation:

Answer:

80 balls

Step-by-step explanation:

Julie's brother's balls x 20 = Julie's balls

4 x 20 = 80

Brainliest, please :)

Answer:

Step-by-step explanation:

b = a + b table chart what equation represents the relationship between a and b shown in the table .

The number of cuboids of dimension 2 cm x 3 cm x 4 cm, required to make a cube is 9.

Dimensions of the cuboid Deeksha made are given as 2 cm x 3 cm x 4 cm.

Thus, the volume of this cuboid = 2*3*4 cm³ = 24 cm³.

Using the formula for the volume of cuboid as the product of the three sides.

Deeksha wants to make a cube combining some number of these cuboids.

Assuming the side length of the cube to a, the volume of the cube = a³.

Assuming the number of cuboids required to make 1 cube to be n, we can write that a³ = n*(24 cm³).

To make this relation true, we need the right-hand side to be a perfect cube.

Prime factorizing the volume of the cuboid, we get 24 cm³ = 2³ * 3 cm³.

To make it a perfect cube, we need to multiply 3², by it.

Thus, n = 3² = 9.

Thus, the number of cuboids of dimension 2 cm x 3 cm x 4 cm, required to make a cube is 9.

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The provided question is incorrect. The correct question is:

"Deeksha made cuboid of size 2 cm x 3 cm x 4 cm. how many such

cuboids will be required to make a cube?"

The angles ∠1 ≅ ∠4 since the line BD bisects ∠ABC, AD║ BC, and AB ║ CD. This is obtained by using the angle bisector theorem, alternate interior angles, and the transitive property of congruence.

Transitive property:

If ∠a and ∠b are congruent and ∠b and ∠c are congruent, then ∠a and ∠c are also congruent.

I.e., If ∠a ≅ ∠b and ∠b ≅ ∠c, then ∠a ≅ ∠c.

The angles bisector theorem states that the ray or line which bisects the angle divides the angle into two equal parts.

I.e., If line BD bisects the angle ∠ABC, then ∠B = ∠B1 + ∠B2

(where ∠B1 = ∠B2)

The line BD bisects ∠ABC, AD║BC, and AB║CD

The line BD bisects ∠ABC. So,

∠B = ∠3 + ∠4

According to the angle bisector theorem, ∠3 ≅ ∠4.

Since AD║BC and AB║CD, the alternate angle are congruent.

I.e., ∠3 ≅ ∠1

Thus, by the transitive property of congruence,

∠1 ≅ ∠4

Hence proved.

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Statements is TRUE

Based on the graph of the general solution to the differential equation dy over dx equals 2 times x - 2 times y = dy/dx=2x-2y.

A differential equation's solution is an expression for the dependent variable in terms of one or more independent variables that satisfy the relationship.

The statement which is true is the slopes are all positive in quadrant I.

Given the differential equation is dy/dx=2x-2y

A differential equation is an equation that contains at least one derivative of an unknown function, either a normal differential equation or a partial differential equation.

Given dy/dx=2x-2y

now slope=2x-2y

Along x-axis, y=0. So, slope=2x+0.

Since it depends upon x hence the slope along the y-axis are not horizontal.

Along y-axis, x=0. So, slope -2y+0.

The slope along the x-axis are also not horizontal.

In quadrant I:

x,y≥20

So, dy/dx ≥20

Therefore, the slopes are all positive in quadrant I. In quadrant IV,

x≥0,y≤0

so, dy/dx is not always positive.

The slope are not all positive in quadrant IV:

Therefore, the slope are all positive in quadrant I for the differential equation dy/dx=2x-2y.

General solution to the differential equation =

dy/dx=2x-2y.

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Complete Question:

Based on the graph of the general solution to the differential equation dy over dx equals 2 times x plus y comma which of the following statements is true?

The slopes along the y-axis are horizontal.

The slopes along the x-axis are horizontal.

The slopes are all positive in Quadrant 1.

The slopes are all positive in Quadrant 4.

Hello,

I think it is 9y² + 21y - 18 = 0

we have a = 9 ; b = 21 and c = -18

∆ = b² - 4ac = 21² - 4 × 9 × (-18) = 1089 > 0

x1 = (-b - √∆)/2a = (-21 - 33)/9 = 6

x2 = (-b + √∆)/2a = (-21 + 33)/9 = 12/9 = 4/3

S = {4/3 ; 6}

The probability that a prize ticket with a vowel will be chosen, not replaced, and then another prize ticket with a vowel will be chosen is 0.031 or 3.1%. The events are dependent events.

Given that there are five vowels, which come from the letters A, E, I, O, and U, the likelihood of drawing a vowel is:

5/26

since there are a total of 26 alternatives available. After choosing that, we are left with 25 alternatives, 4 of which are vowels, thus the probability is:

4/25

The final likelihood is thus:

5/26 * (4/25) = 0.031

In other words, the likelihood is 3.1% when choosing a vowel and then another (without replacement).

The first event has an impact on the second event since there are fewer vowels and overall possibilities, hence the events are dependent.

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Answer:

  10.  20.9°

  11.  73.2°

Step-by-step explanation:

The inverse sine function is used to find the angle from its sine value.

In each case, the equation is of the form ...

  a/sin(x) = b/c

Multiplying both sides by c/b·sin(x), we find the solution is ...

  sin(x) = ac/b . . . . . find sin(x)

  x = arcsin(ac/b) . . . . . find the corresponding angle

For the given values a=7.2, b=13, c=sin(40°), we have ...

  x = arcsin(7.2sin(40°)/13) ≈ 20.9°

For the given values a=6.53, b=√40, c=sin(68°), we have ...

  x = arcsin(6.53sin(68°)/√40) ≈ 73.2°

Answer:

D: (-∞,∞)

R: (0,∞)

Step-by-step explanation:

This is a parabola, so the domain of this function is always:
D:(-∞,∞)
The y-values of this parabola do not go any lower than 0, and it goes upwards in the positive y-direction. So, the range for this function is:
R:(0,∞)

Answer:

4ft^3

Step-by-step explanation:

1.333333*3*1^3=4

To start finding the volume of this sphere, we get the following data:

To find the volume we apply the following formula:

We substitute our data in the formula and solve:

Substituting values into the equation

Calculate exponent cubed

Multiplying

Therefore, the volume of the sphere is 32 ft³.

Work:

First it's a rectangle so its area is equal to the product (multiplication) of both sides of the rectangle (dimensions). A = a x b = ab

NOW: knowing the the circumference or perimeter is equal to 400m, we can say that P = 400 = 2(a+b) = 2a + 2b since the given polynom is rectangle. 2a + 2b = 400 <==> 2a = 400 - 2b <==> a = 200 - b.

We gave an expression of a in function of b. Now we can replace the variable a by 200 - b in the first expression of the area.

A = ab = (200-b)b = 200b-b^2 = -b^2 + 200b

A is now a quadratic equation. We note A(b) the epression -b^2 +200b so:

A(b) = -b^2 +200b

We can already see that A is a quadratic equation of the form:

ax^2 + b + c. The a coefficient is negative which will lead to closed parabola when looking from the top. Now we need to find the maximum of the function by using the derivatives:

A(b) = -b^2 +200b <==> A'(b) = -2b + 200b

and -2b + 200b = 0 <==> b = 100;

So the derivative function crosses the x-axis at (100; 0).

So is increasing over ]-∞; 100] and decreasing over [100; ∞[.

We obtain a maxima on (100; x) with A. To find it we need to replace 100 by b in the function A.

A(b) = -b^2 + 200b

<==> A(100) = -100^2 + 200 x 100 = - 10000 + 20000 = 10000

Now let's find a: if b = 100 what equals a ?

We know that ab = 10000 <==> 100a = 10000 <==> a = 100;

And we verify that ab = 100 x 100 = 10000.

The rectangle needs to be a square to reach the maximum area of 10000m^2 or also 0.01 km^2.

Q.E.D.

Answer: D and B

Step-by-step explanation:

Formula for two terms = a + b

Therefore,

D and B have two terms aka one plus sign

D. a + c

B. m^4 + 6m

Hi! ❄

  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -  

The sum of two terms is what we get after adding these two terms.

If you add two positive terms, you put a + sign in between these terms.

[tex]\sf{Example\!\!:a+b}[/tex]

If you add two negative terms, you put a - sign in between these terms.

[tex]\sf{Example\!\!:a-b}[/tex] (this is the same as [tex]\sf{a+-b}[/tex])

Let's look at the provided choices to see which one works.

It doesn't, because [tex]\sf{xy\neq x+y}[/tex]. In this expression a number x was multiplied by a number y. So this one doesn't check.

One down, three to go.

It does, because [tex]\sf{m^4+6m\stackrel\checkmark{=}m^4+6m}[/tex]. A number m was multiplied by itself 4 times, and then the product of that samee number m and 6 was added to it.

So this one checks.

It doesn't. It is indeed a sum, but we need 2 terms, not 3

So this one doesn't work.

It does, because [tex]\sf{a+c\stackrel\checkmark{=}a+c}[/tex]. So Choice D. also works.

Hope that made sense !!

  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -  - - - - - - - - - - - - - - - - - - - - - - - - -

[tex]\star\tiny\pmb{calligraphy}\star[/tex]

The mean of the data given is 13.4364 and.the standard deviation is 1.788.

It should be noted that the mean is the average of the giving set of numbers. In this situation, the mean is 3.1998.

E(X²) will be:

= (0² × 0.0408) + (1² × 0.1304) .... + (12² × 0.0001)

= 13.4364

Var(X) = 13.4364 - 3.1998²

= 3.198

The standard deviation will be:

= ✓3.198

= 1.788

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Answer: (2, 18)

Step-by-step explanation:

When x=2, [tex]f(2)=2(3)^{2}=18[/tex].

So, it should pass through (2, 18).

Answer:

(2, 18)

Step-by-step explanation:

i posted this at 1:19 in the morning, good day