someone help me with this answer please !!

The side LO is congruent to the side MN, the diagonal LN is congruent to the diagonal MO, and the angle L is congruent to the angle M in an isosceles trapezoid, denoted by the symbols LMNO.

What are the conditions for an Isosceles Trapezoid?

The conditions listed below demonstrate that any trapezoid is an isosceles trapezoid:

When these conditions are met by the given trapezoid LMNO, it will be referred to as an isosceles trapezoid. Hence, the following conditions of trapezoid LMNO need to be fulfilled,

LN ≅ MO

LO ≅ MN

∠L ≅ ∠M

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✔ (A.) LN ≅ MO

✔ (C.) LO ≅ MN

✔ (E.) ∠L ≅ ∠M

Answer: Isosceles Trapezoid

Step-by-step explanation:

See the graph of the quadrilateral.

Answer:

37.44 cm²

Step-by-step explanation:

To find the width, follow these steps.

10.4*2=20.8

28-20.8=7.2

7.2/2=3.6

The width is 3.6.

To find the area, multiply the width and the length together.

10.4*3.6=37.44

The area of the rectangle is 37.44 cm²

Hope this helps!

Answer:

12

Step-by-step explanation:

Well they are similar I assume so 5 / 3.5 = roughly 1.43 and 8.4 x this number gives you 12 so I would say 12

Considering the linear functions on the graph, the inequality that matches the situation is:

B.

A linear function is modeled by:

y = mx + b

In which:

The lower bound of the interval is a linear function with y-intercept of b = 2, that also passes through (2,3), hence the slope is:

m = (3 - 2)/(2 - 0) = 1/2.

Hence the inequality is:

[tex]y \geq \frac{1}{2}x + 2[/tex]

The upper bound of the interval is a linear function with y-intercept of b = 1, that also passes through (2,5), hence the slope is:

m = (5 - 1)/(2 - 0) = 2.

Hence the inequality is:

[tex]y \leq 2x + 1[/tex]

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The y-value of the terminal point of the vector is 3.

In this question we must apply a matricial form of rotation, which is a kind of rigid transformation. This transformation is defined by the following formula:

[tex]\vec A' = \vec T\cdot \vec A[/tex], where [tex]\vec A' , \vec A \in \mathbb{R}_{1 \times 2}[/tex], [tex]\vec T \in \mathbb{R}_{2 \times 2}[/tex]

If we knw that [tex]\vec A = \left[\begin{array}{c}- 4\\3\end{array}\right][/tex] and [tex]\vec T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right][/tex], then the transformed vector column is:

[tex]\left[\begin{array}{cc}x\\y\end{array}\right] = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right] \cdot \left[\begin{array}{cc}-4\\3\end{array}\right][/tex]

[tex]\left[\begin{array}{cc}x\\y\end{array}\right] = \left[\begin{array}{cc}4\\3\end{array}\right][/tex]

The y-value of the terminal point of the vector is 3.

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The measure of angle 3 from the figure is 110 degrees

An angle is the intersection between two lines. From the given figure, we have the following parameters

m∠1= 40°,

m∠2= 70°.

Required

Measure of angle 3

The sum of the interior angles of the triangle is equal to the exterior

Sum of interior = <1 + <2

Sum of interior = 40 + 70

Sum of interior =110 degrees

Hence the measure of angle 3 from the figure is 110 degrees

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a) The variables are:

b)

x + y ≥ 12

x*$0.75 + y*$1.25 ≤ $15

a) First we need to define the variables, in this case we have:

b) Now we want to write the system, we know that he must buy at least 12 items, then:

x + y ≥ 12

And he can spend, at most, $15, then:

x*$0.75 + y*$1.25 ≤ $15

These two inequalities conform the system of inequalities:

x + y ≥ 12

x*$0.75 + y*$1.25 ≤ $15

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F is located on the number 4.5 on the number line.

We know that point D is at -6

Point E is at 8.

Point F is between D and E, such that the ratio:

DF:FE is 3:1

So if we divide the distance between D and E in 4 parts, 3 of these parts are DF, and one of these parts is FE.

First, the distance between E and D is:

distance = 8 - (-6) = 14 units.

Now, if we divide that by 4, we get:

14/4 = 3.5

Then we have:

DF = 3*(3.5) = 10.5

This means that F is at 10.5 units to the right of D, then:

F = D + 10.5 = -6 + 10.5 = 4.5

F is located on the number 4.5 on the number line.

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Answer:

4.5 is the answer :D

Step-by-step explanation:

Answer:

In order to go from the first point to the second, we need to rise from 4 to 7, i.e. by 3. We also need to run from -4 to -2, i.e. by 2. Therefore the slope is 32 .

Step-by-step explanation:

Answer:

D. continuous

Step-by-step explanation:

the equation in the standard form is :

( x - 2 ) 2+ ( Y + 3 ) 2 = 18

the center is at the point ( 2, - 3 ).

its radious is : /18 = 3/ 2 units

The smallest number by which 29160 should be divided so that the quotient becomes a perfect cube is 5

The given number is 29160

Note that:

29160 can be factored into 5832

That is, 29160 = 5832 x 5

Take the cube of 5832:

[tex]\sqrt[3]{5832}=18[/tex]

Since it has been confirmed that 5832 is a perfect cube, the smallest number by which 29160 should be divided so that the quotient becomes a perfect cube is 5

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Answer:

53 degrees

Step-by-step explanation:

If the two lines intersected by a transversal are parallel then the same side interior angle should add up to 180 degrees.

180-127 = 53 degrees

The equivalent expression of [tex](1 + \frac{1}{y}) \div (1-\frac 1y)[/tex] is [tex]\frac{y + 1}{y-1}[/tex]

The fraction is given as:

[tex](1 + \frac{1}{y}) \div (1-\frac 1y)[/tex]

Take the LCM

[tex]\frac{y + 1}{y} \div \frac{y-1}y[/tex]

Express as products

[tex]\frac{y + 1}{y} \times \frac{y}{y-1}[/tex]

Evaluate the product

[tex]\frac{y + 1}{y-1}[/tex]

Hence, the equivalent expression of [tex](1 + \frac{1}{y}) \div (1-\frac 1y)[/tex] is [tex]\frac{y + 1}{y-1}[/tex]

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The length of the side QR in the task content can be determined as; 12.22cm.

It follows from the task content that 2 lengths and one included angle are given in the task content. It therefore follows that the length of side QR can be evaluated by the cosine rule as follows;

QR² = 13² + 4² - (2×4×13×cos70)

QR = √149.4

QR = 12.22cm

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By definition of surface area, the composite figure reports an area of 233.6 square centimeters.

In this question we need to determine the surface area of a composite figure, which is the sum of all the areas of the faces, which are combinations of triangles and quadrilaterals. Now we proceed to calculate the surface area:

A = 2 · (6 cm) · (3 cm) + 2 · (8 cm) · (6 cm) + 2 · (8 cm) · (3.6 cm) + 2 · (8 cm) · (2 cm) + 4 · (1/2) · (3 cm) · (2 cm)

A = 233.6 cm²

By definition of surface area, the composite figure reports an area of 233.6 square centimeters.

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For finding the given literal equation is necessary to apply the power 2 on both sides of the given equation and after that you should rewrite the equation as a function of the variable m .

There are different power rules, see some them:

1. Multiplication with the same base: you should repeat the base and  add the exponents.

2. Division with the same base: you should repeat the base and  subctract the exponents.

3.Power. For this rule, you should repeat the base and multiply the exponents.

4. Zero Exponent. When you have an exponent equals to zero, the result must be 1.

The question gives: [tex]t=2\pi *\sqrt{\frac{m}{k}}[/tex] and from the previous equation, you should find [tex]m=\frac{kt^2}{4\pi ^2}[/tex].

STEP 1 - Applying the power 2 on both sides of the equation [tex]t=2\pi *\sqrt{\frac{m}{k}}[/tex].

[tex]t=2\pi *\sqrt{\frac{m}{k}}\\ \\ t^2=(2\pi *\sqrt{\frac{m}{k}})^2\\ \\ t^2=4\pi ^2*\frac{m}{k}[/tex]

STEP 2 - Rewriting the equation  [tex]t^2=4\pi ^2*\frac{m}{k}[/tex]  as a function of the variable m .

[tex]t^2=4\pi ^2*\frac{m}{k}\\ \\ t^2k=4\pi ^2m\\ \\ m=\frac{kt^2}{4\pi ^2}[/tex]

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Answer:

1. divide both sides of the equation by 2pi

2. square both sides of the equation

3. use the rule to simplify a fraction to a power

4. multiply both sides of the equation by k

Step-by-step explanation:

edg '22

The equation that can be used to find y, the year in which both bodies of water have the same amount of mercury is 0.05 + 0.1y = 0.12 + 0.06y. Hence, the 3rd option is the right choice.

In the question, we have been asked for the equation that can be used to find y, the year in which both bodies of water have the same amount of mercury.

First, we will find the equations showing the level of mercury in each body of water.

For the first water body:

Initial measure of mercury = 0.05 ppb.

Rate of rising = 0.1 ppb each year.

Number of years = y.

Thus, the equation showing level of mercury = 0.05 + 0.1y.

For the second water body:

Initial measure of mercury = 0.12 ppb.

Rate of rising = 0.06 ppb each year.

Number of years = y.

Thus, the equation showing level of mercury = 0.12 + 0.06y.

We are looking for the equation, to find y, the year in which both bodies of water have the same amount of mercury.

As they will have the same amount of mercury, their respective equations showing the level of mercury should be equal, that is:

0.05 + 0.1y = 0.12 + 0.06y, which is the required equation.

Thus, the equation that can be used to find y, the year in which both bodies of water have the same amount of mercury is 0.05 + 0.1y = 0.12 + 0.06y. Hence, the 3rd option is the right choice.

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For the complete question, refer to the attachment.

Answer:

b

Step-by-step explanation:

b shows direct variation because we can clearly tell that the slope of the graph is 1/2. The graph is also linear, and it crosses the origin (0,0).

a: This graph can be represented as y=2, and that is not a direct variation.

b: Above explanation. This graph is a direct variation.

c: This graph can be represented as x=-8, and that is not a direct variation.

d: This graph has the slope, but it does not cross the origin, so it is not a direct variation.

Answer:

Graph b

Step-by-step explanation:

Direct variation means "y varies directly as x”:

Direct variation equation:

[tex]y=kx[/tex]

where k is the (non-zero) constant of variation.

Note, therefore, that a direct variation equation passes through the origin,  as when x = 0:  

[tex]\implies y=k(0) \implies y=0[/tex]

Graph a

y does not change as x varies.

Therefore this graph does not model a direct variation.

Graph b

As x gets bigger, so does y.  As x gets smaller, so does y.  

The line passes through the origin (0, 0).

Therefore this graph models a direct variation.

Graph c

x does not change as y varies.

Therefore this graph does not model a direct variation.

Graph d

As x gets bigger, so does y.  As x gets smaller, so does y.  

However, the line does not pass through the origin (0, 0).

Therefore this graph does not model a direct variation.

Answer:

y = 27

Step-by-step explanation:

The given are two similar triangles.

We can use the following equation to find the variables:

[tex]\frac{y-3}{32} = \frac{18}{24}[/tex]

Cross multiply fractions

32*18 = 24(y-3)

576 = 24y - 72

add 72 to both sides

648 = 24y

divide both sides by 24

27 = y

Answer:

Total cost is $177.50.

Step-by-step explanation:

Rackets:

Divide the cost for racket by 6 to find the cost per racket.

186÷6=31

Multiply 31 by 5 to find the cost for 5 rackets.

31×5=155

$155

Tubes of balls:

Divide 27 by 6 to find the cost per a tube of balls.

27÷6=4.50

Multiply 4.50 by 5 to find the cost for 5 tubes of balls.

4.50×5=22.50

$22.50

Add the amounts for rackets and tubes of balls to find the total cost.

155+22.50=177.50

The total cost is $177.50.

Hope this helps!

Answer:

150 [tex]m^{2}[/tex]

Step-by-step explanation:

Consider the figure as an isosceles triangle and a rectangle combined.

ISOSCELES TRIANGLE

[tex]A = \frac{1}{2} bh[/tex]

[tex]A = \frac{1}{2} *15*12[/tex]

A = 90

RECTANGLE

[tex]A=lw[/tex]

[tex]A = 5*12[/tex]

[tex]A = 60[/tex]

60 + 90 = 150

Answer:

150m

Step-by-step explanation:

break up the polygon into a triangle and a rectangle.

Triangle:

to find the height of the triangle, subtract 5 from 20

height = 15m     base = 12m

[tex]area=\frac{1}{2}bh\\ A=\frac{1}{2} (12)(15)\\A=6(15)\\A=90m[/tex]

rectangle:

[tex]A=bh\\A=12(5)\\A=60m[/tex]

Add both areas together:

[tex]90+60=150m[/tex]

Answer:

[tex]\huge\boxed{\sf 7x + 10\ cm}[/tex]

Step-by-step explanation:

= 5 + 2x + 2x + 5 + 3x

Combine like terms

= 2x + 2x + 3x + 5 + 5

= 7x + 10 cm

[tex]\rule[225]{225}{2}[/tex]

Answer:

7x + 10

Step-by-step explanation:

Perimeter is the sum of all the sides together, the distance around a shape.

3x + 5 + 2x + 2x + 5

Organize so the variables are on one side

3x + 2x + 2x + 5 + 5

Combine like terms:

7x + 10

Your answer would be: 7x + 10

I hope it helps! Have a great day!

bren~

Answer:

Step-by-step explanation:

You answer

The constant of proportionality is 2.5.

First, There is a proportional relationship

Two values x  and y are said to be in a proportional relationship if y=kx, where x and y are variables and k is a constant.

y = kx

The constant k is the constant of proportionality

As shown that ,

A 2-column table with 3 rows.

Column 1 is labeled x with entries 2, 4, and 5.

Column 2 is labeled y with entries 5, 10, and 12.5.

According to the Above statement, the calculation is as follows:

5/2 = 2.5 , here we get is 2.5

10/ 4 = 2.5 so Here we get 2.5 and so on

Hence, The constant of proportionality is 2.5.

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The width of the freezer is 2.25ft

The formula for calculating the volume of rectangular prism is expressed as:

V = lwh

Given the following

length l = 8feet

w is the width

height h = 3feet

Substitute

54 = 8*3w

54 = 24w

w = 54/24

w = 2.25ft

Hence the width of the freezer is 2.25ft

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The solution to the given fraction 7/11 = x/9 to the nearest tenth is 5.7

7/11 = x/9

7 × 9 = 11 × x

63 = 11x

x = 63/11

x = 5.72727272727272

Approximately,

x = 5.7

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Answer:

D

Step-by-step explanation:

The correct statement comparing the theoretical and experimental probabilities is given as follows:

[tex]\frac{1}{4} < \frac{7}{25}[/tex].

A probability is given by the number of desired outcomes divided by the number of total outcomes.

The theoretical probability is taken before any experiment. Since the four sections are equal, the theoretical probability is:

T(H) = 1/4.

The experimental probability is taken considering previous experiments. Out of 100 tosses, 28 landed on H, hence:

E(H) = 28/100 = 7/25.

Hence the correct statement is:

[tex]\frac{1}{4} < \frac{7}{25}[/tex].

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