Tell types of mirros and
each
one​

Answers

Answer 1

Answer: We can identify the different types of mirrors without touching them by looking at the image it produces. Look into each mirror, the nature of the image produced will tell you the type of mirror it is.

- A plane mirror will produce an image of the same size as your face.

- A concave mirror will produce a magnified image of your face.

- A convex mirror will produce a diminished image of your face.

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Related Questions

an airplane flies due west at an airspeed of 406mph. the wind is blowing from the northeast at 15mph. determine the bearing of the airplane in degrees relative to the positive x-axis, rounded to two decimal places. provide your answer below:

Answers

The aircraft's bearing with relation to the positive x-axis in degrees is Q= 1.94

Using the principal compass direction (north or south), angle, and an indication of east or west, bearing produces a direction. A bearing identifies a line's direction as either north or south, with a deflection to the east or west of a certain number of degrees. Therefore, a bearing will never have an angle greater than 90 degrees.

As per the data given in the above question are as bellow,

The provided details are as follow,

An airplane flies due west at an airspeed of 406mph

Wind speed is 15 mph and coming from the northeast.

find the aircraft's bearing with relation to the positive x-axis in degrees.

To determine bearing of airplane.

We have,

[tex]$$\begin{aligned} \tan Q & =\frac{20 \sin (45)}{406+20 \cos (45)} \\& =0.033902 \\Q & =1.9417 \\Q & \cong 1.94\end{aligned}$$[/tex]

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One of the earliest practical uses of astronomy was the timing of crop planting by
Choose one:
A. lunar eclipses.
B. the appearance of comets.
C. solar eclipses.
D. the appearance of specific planets.
E. the appearance of specific constellations.

Answers

Option- E. the appearance of specific constellations is the correct answer.

What is astronomy ?

Astronomy, a science that includes the study of all extraterrestrial objects and phenomena. Until the invention of the telescope in the 17th century and the discovery of the laws of motion and gravity, astronomy was primarily concerned with finding and predicting the positions of the sun, moon, and planets. Initially for calendar and astrological purposes, later for navigation and astronomy. Scientific use Interest. The catalog of celestial bodies currently being studied is much more extensive, including in order of increasing distance, the solar system, the stars that make up the Milky Way, and other more distant galaxies. With the advent of scientific space probes, the Earth has also been studied as one of the planets, but more detailed study remains the realm of Earth science.

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A bar magnet is positioned near a coil of wire, as shown in the figure below.
What is the direction of the current in the resistor when the magnet is moved to the left and to the right?
(a) to the left
O The current is right to left.
O No current is induced.
O The current is left to right.
(b) to the right
O No current is induced.
O The current is left to right.
O The current is right to left.

Answers

When the bar magnet is moved to the left , no current is induced. when the magnet is moved to to the right, the current is right to left.

Are there electric currents in magnets?

If a coil magnet remains static, there is no current flowing. However, if you spin it vigorously enough, you will induce a current. By rotating a coil of wire around a magnet or vice versa, an electrical current is produced by pushing the wire's electrons. In essence, kinetic energy—the energy of motion—is transformed into electrical energy via electricity generators.

What is the magnet's current flow direction?

The magnetic field is parallel to the wire and oriented in that direction. The direction of the current can be determined by wrapping the fingers of your right hand around a wire while pointing your thumb towards the direction of the current.

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Estimate the magnitude of the normal force n acting on an apple that rests on a flat surface.

Answers

The magnitude of the normal force acting on an object that rests on a flat surface is equal to the weight of the object, which is the force of gravity acting on it.

To estimate the magnitude of the normal force acting on an apple, we need to know its mass. On average, an apple weighs around 150 grams. To convert this to kilograms we divide by 1000, so the mass of an apple is 0.15 kg.

On substituting this values into the equation, we get:

F = m * g

F = 0.15 kg * 9.8 m/s^2

F ≈ 1.47 N

So the magnitude of the normal force acting on an apple that rests on a flat surface is approximately 1.47 N. It's worth noting that this is an estimate and the normal force could change due to various factors such as the friction of the surface, the angle of the surface, or the shape of the apple.

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energy is ____ when an electron is added to H+ ion and ends up in n=3 shell

Answers

Ionisation energy is the correct answer .

What is Energy ?

Energy, in physics the ability to do work. It can exist in electrical, kinetic, thermal, electrical, chemical, nuclear, or various other forms. There is also heat and work. H. After transmission, energy is always referred to according to its nature. Thus, the heat transferred can become thermal energy, while the work done can appear as mechanical energy. All forms of energy are associated with movement. For example, any object has kinetic energy when it is in motion. A taut device such as a bow or spring can create motion even when stationary. Because of its composition, it contains potential energy. Similarly, nuclear energy is potential energy as it results from the composition of subatomic particles within the nucleus .

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Driving in a car with a constant speed of 12 m>s, you
encounter a bump in the road that has a circular crosssection, as shown in Figure 9.30. If the radius of curvature
of the bump is 35 m, find the apparent weight of a 67-kg
person in your car as you pass over the top of the bump.

Answers

As you pass over the top of the bump, the apparent weight of a 67 kg person in a car is therefore -17.80N.

What is constant speed with example?

Constant motion is a sort of motion that takes place when either the object's speed varies by the same amount every second or its distance travelled is the same every second. A car that goes continuously for 5 seconds in a straight line at 20 metres per second is said to be in motion. An object is considered to be moving at a constant speed when it covers the same distance in the same amount of time. When moving at a constant pace, an object covers a certain distance in a fixed amount of time. S = d t is a formula that can be used to express the speed.

What is uniform or constant speed?

The body is said to be moving at a uniform speed if it travels the same distance in the same amount of time. If the body goes in a straight line without changing its direction, the velocity is said to be constant. In all scenarios, there is no acceleration. Recall that the uniform velocity is a constant velocity as well.

-mg+N = -mass (v2/r) -(67(9.8) +N

= -(67(9.30/35) +N

=-17.80N

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true/false. the earth and the moon are attracted to each other by gravitational force. the more massive earth attracts the less massive moon with a force that is (greater than, less than, the same as) the force with which the moon attracts the earth.

Answers

Yes, the earth and the moon are attracted to each other by gravitational force.

The greater an object's mass, the more gravitational force it exerts. So, Earth has a greater gravitational pull than the moon simply because the Earth is more massive.

Let m and M be the mass of moon and earth respectively which are separated by a distance r

Force of attraction that earth exert on moon,

                             Fe = GMm/ r^2

Force of attraction that moon exert on earth, Fm = GmM / r^2

Thus earth attracts the moon with same force by which moon attracts the  earth.

Also the gravitational force is an internal force of attraction between the two bodies, thus they have to be equal.

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The figure(Figure 1) shows four sides of a 6.0cm×6.0cm×6.0cm cube.
Part A
What is the electric flux Φ1 through side 1?
Express your answer using two significant figures.
Part B
What is the electric flux Φ2 through side 2?
Express your answer using two significant figures.
Part C
What is the electric flux Φ3 through side 3?
Express your answer using two significant figures.
Part D
What is the electric fluxe Φ4 through side 4?
Express your answer using two significant figures.
Part E
What is the net flux through these four sides?
Express your answer using two signifi​cant figures.

Answers

The electric flux of various sides of cube are found to be - 1.558845727 N m2 , 0.9 N m2 /C, 1.558845727 N m2 /C and - 0.9 N m2 /C.

What is electric flux ?

Electric flux is a characteristic of an electric field that can be conceptualised as the quantity of electric lines of force (or electric field lines) that cross a specific region. Positive electric charges are thought to be where electric field lines begin, while negative electric charges are thought to be where they end.

What is net flux?

The total number of electric field lines that are perpendicular to the surface and crisscross it is known as net electric flux. Scalar quantity is used to represent the electric flux. D = E in mathematics.

Electric flux is nothing but the dot product between the Electric field vector and the area vector whose direction is given by the outward normal (indicated by the green arrows)

Area S = 0.06 x 0.06 = 0.0036 m2

a.)  ? = E.S = ESCos?    = 500 x 0.0036 x Cos 150 = - 1.558845727 N m2 /C  

b.)  ? = E.S = ESCos?    = 500 x 0.0036 x Cos 60 = 0.9 N m2 /C

c.)  ? = E.S = ESCos?    = 500 x 0.0036 x Cos 30 =  1.558845727 N m2 /C

d.)  ? = E.S = ESCos?    = 500 x 0.0036 x Cos 120 = - 0.9 N m2 /C

e.) Net flux through these four sides is the sum of all the fluxes through the individual sides.

? =   - 1.558845727 + 0.9 +  1.558845727  - 0.9 =  0  N m2 /C

Therefore, all the parts of questions are explained above.

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Help me with this q please

Answers

i think it’s y but not sure

What is a quantum number?

a) the number representing a discrete orbit or energy level
b) number of whole electron wavelengths absorbed by an object
c) the number of whole electron orbits in an electron wavelength
d) number of whole electron wavelengths removed from a continuous spectrum when it passes through a substance

Answers

A number that designates a specific orbit or energy level.

What are examples of energy level?

How Do Energy Levels Work? Energy levels are the fixed locations outside of an atom's nucleus where electrons may be located (also known as electron shells). The tiny, negatively charged electrons encircle the smaller, positively charged nucleus in an atom. Energy levels mirror a ladder's rungs in a number of ways.

What level of energy does an atom have?

Energy levels are nothing more than the electrons' set distances from an atom's nucleus. The electron shell is another name for the energy levels. An electron can migrate across energy levels, but it cannot remain in one energy level while in another.

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The ball is ejected horizontally from the tube with a speed of 8m/s Find on of the path, y=f(x) and then find the ball's velocity and the angential components of acceleration when t=025 s

Answers

The path of the ball can be represented by the equation y(x) = (1/2)(-9.8)[tex](x/8)^2[/tex] + [tex]y_{0}[/tex], where [tex]y_{0}[/tex] is the initial vertical position of the ball. This equation describes a parabolic trajectory, the horizontal component of velocity is constant, so the equation for the horizontal position of the ball is x(t) = x0 + [tex]v_{x0}[/tex]*t, where [tex]x_{0}[/tex] is the initial position and [tex]v_{x0}[/tex] = 8 m/s.

The vertical position of the ball is given by y(t) = [tex]y_{0}[/tex] + [tex]v_{y0}[/tex]*t + (1/2)[tex]at^2[/tex], where [tex]y_{0}[/tex] is the initial position, [tex]v_{y0}[/tex] = 0 m/s, and a = -9.8 [tex]m/s^2[/tex] (the acceleration due to gravity).

At t = 0.25 s, the velocity of the ball is ([tex]v_{x0}[/tex], [tex]v_{y0}[/tex] + at) = (8 m/s, -2.45 m/s). The angular components of acceleration are (0 [tex]m/s^2[/tex], -9.8[tex]m/s^2[/tex]).

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Could you please help me with this?? I literally failed my quiz 3 times

Answers

The answer is D :)))))))

Find the total positive charge of all the protons in 1.0mol of water.

Answers

The total positive charge of all the protons in 1.0mol of water is  6.022x10²⁴

What is a proton made of?

Two up protons and the one down quark are found in protons. One up particle and two downwards quarks make up neutrons. The "strong nuclear force," one of the four basic forces, holds the nucleus together (gravity and electromagnetism are two others).The number many protons within an atom is crucial since it determines the atom's identity. A hydrogen atom will be recognized as having just one proton, a carbon atom as having six protons, and so on. An atom's elemental composition is determined by the number or protons in it.

Hence, each molecule has 10 protons.

We have 6.022 x 10²³ molecules in one mole of water,

therefore,

multiply this by 10 to get the amount of protons:

Protons in a mole of water: 6.022x10²⁴.

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Determine distance between two charges Q1=500nC and Q2=- uC which interact with each force 670mN. The charges are immersion in the medium with relative permittivity Er=2 E0=8.85

Answers

The distance between the two charged particles is 8.2 cm.

What is the distance between the two charges?

The distance between the two charges is calculated by applying Coulomb's law of electrostatic force as shown below.

Mathematically, the formula for the force of attraction or repulsion between two charged particles is given as;

F = ( kq₁q₂ ) / ( r² )

where;

k is the coulomb's constantq₁ is the charge of the first particleq₂ is the charge of the second particler is the distance between the charges

r² = ( kq₁q₂ ) / ( F )

r = √ [ ( kq₁q₂ ) / ( F ) ]

The distance between the two charged particles is calculated as;

r = √ [ (  9 x 10⁹ x 500 x 10⁻⁹ x 1 x 10⁻⁶ ) / ( 670 x 10⁻³ ) ]

r = 0.082 m

r = 8.2 cm

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Suppose the distance from the lens system of the eye (cornea +lens) to the retina is 17 mm.
(a) What must the power of the lens be whenlooking at distant objects?
(b) What must the power of the lens be when looking at an object20.0 cm from the eye?

Answers

a) Power of lens is 0.058D

Focal length =17mm

Power=1/focal length

Power=1/17

Power=0.058D

b) Power of the lens when looking at an object 20.0 cm from the eye is 0.05D

Focal length =20cm

Power=1/focal length

Power=1/20

Power=0.05D

What is the power of the lens?

The power of a lens is defined as the reciprocal of its focal length. It is represented by the letter P. The power P of a lens of focal length f (in m) is given by. P=1f. The SI unit of power of a lens is 'dioptre'.

How do you calculate eye lens power?

The power of a lens is defined as the reciprocal of its focal length in meters, or D = 1/f, where D is the power in diopters and f is the focal length in meters.

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The rod shown below moves to the right on essentially
zero-resistance rails at a speed of v = 3.0 m/s. If
B = 0.75 T everywhere in the region, what is the current
through the 5.0-Ω resistor? Does the current circulate
clockwise or counterclockwise?

Answers

The required, current 0.018 A circulates counterclockwise through the 5.0-Ω resistor. Option B is correct.

The induced emf causes a current to flow through the loop (the rod and the 5.0-Ω resistor). Since the resistance (R) of the resistor is given as 5.0 Ω, we can find the current (I) through the resistor:
I =E/R

Substitute the value of the induced emf:
I = -[Bwv]/R

Substitute the value in the above equation:
I = -[0.75*4/100*3]/5
I = 0.018 A counterclockwise direction

Thus, the required, current 0.018 A circulates counterclockwise through the 5.0-Ω resistor. Option B is correct.

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7) A 2 kg cart rolls down a frictionless ramp. It starts with 58.8 J of energy at the top of the ramp. How fast would the cart be moving when it is halfway (in height) down?​

Answers

Answer:

The problem is asking one to assume that the potential energy at the top of the ramp is 58.8 J and the potential bottom is zero:

then 1/2 m v^2 = 29.9 J or 1/2 the energy - one cannot solve for v without knowing a value for KE

v^2 = 58.8 / 2 = 29.9

v = 5.47 m/s

(if the cart had any KE at the top of  the ramp then one cannot solve the problem because the speed of the cart is not defined)

: Consider the following statement made by a student about each of the four motions in problem The magnitude of the force exerted by the Mock on an individual string is the same as the magnitude of the force exerted by that string on the block. They are a third law force pair. So I don't understand why the block doesn't move at constant speed if that is true.
" The student has correctly identified a Newton's third law (act ion-react ion) force pair. Explain why this does not mean that the block must move at constant speed.

Answers

The block does not move at constant speed because the force exerted by the string on the block is not the only force acting on the block.

What is velocity?

Velocity is a measure of the rate and direction of change in the position of an object. It is a vector quantity, meaning it has both magnitude and direction. Velocity is usually expressed in meters per second (m/s).

For example, the block could also be subject to a frictional force from the surface it is resting on.

This force is acting in the opposite direction to the force from the string and it is not equal in magnitude, which means the net force acting on the block is not zero and it will not move at constant speed. Furthermore, the magnitude of the force from the string may also be changing due to the changing length of the string due to the motion of the block. As a result, the net force on the block will be constantly changing, leading to an acceleration and a change in the block's velocity.

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If the current carried by a conductor is doubled, how are each of the following affected?
(a) The charge carrier density.
(b) The current density.
(c) The electron drift velocity.
(d) The average time interval between collisions.

Answers

According to the given statement the current carried by a conductor is doubled then the charge carrier density are remains constant.

Assume that I is the original current conduction. I' = 21

(a) charge density on doubling current The density of charge carriers is unaffected by the passage of current. It is dependent on the material's volume and atomic mass. carrier for electron density

As a result, the carrier's charge density doesn't change.

Current density (J)

J = Current / Area = I / A

the present J ∝ I. As a result, when the current doubles, so does the density.

velocity of electron drift.

Vd = I / nea

because Vd ∝ I. Therefore, the election drift velocity twice with a doubling of current.

(d) average time between collisions (1) The value of I is independent of the wire's current flow. Therefore, it has no impact on the current's doubling. Therefore, b/w collision does not change.

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An inductor used in a dc power supply has an inductance of 11.5 H and a resistance of 150 Ohm. It carries a current of 0.650 A. Part A
What is the energy stored in the magnetic field? Part B
At what rate is thermal energy developed in the inductor? Part C
Does your answer to part B mean that the magnetic-field energy is decreasing with time? a. No. Energy does not come from the energy stored in the inductor. b. Yes. Energy comes from the energy stored in the inductor. c. Yes. The rate of thermal energy development is not zero. d. No. The rate of thermal energy development is zero.

Answers

An inductor is a passive two-terminal electrical component which resists changes in electric current and can store energy in a magnetic field when electric current flows through it.

What is an  Magnetic field ?

A magnetic field is a region of space around a magnet or a current-carrying conductor in which a magnetic force exists. It is a vector field, meaning that at any point in the field, a vector can be defined that describes the direction and strength of the field at that point.

We need given the following data:

The inductance of an inductor is: Lo=12.50H.

The resistance of a resistor is: Ro=180.0Ω.

The current is: io=0.60A.

(A)The expression for the energy stored in the magnetic field is

Eo=1 / 2 x Loi2o

Solve for the energy stored in the magnetic field

Eo=1/2  ×12.50H×(0.60A)2

=2.25J

Thus the energy stored in the magnetic field is 2.25J.

(B)The expression for the rate of thermal energy developed in the inductor is

Po=i2oRo

Solve for the rate of thermal energy developed in the inductor

Po=(0.60A)2×180.0Ω

=64.80W

Thus the rate of thermal energy developed in the inductor is

64.80W.

(C)Energy does not come from the energy stored in the inductor.

Because of the ohmic resistance of the wire, the energy is delivered to the inductor.

So the magnetic field energy is not decreasing with time.

Thus the option (iii) is correct.

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determine the force exerted by the bicep muscle, assuming that the hand is holding a ball with a mass of 5.00kg. Assume that the mass of the forearm is 8.50kg with the center of the mass located 20.0cm away from the elbow joint. Assume also that the center of the mass of the ball in the hand is 30.0 cm away from the elbow joint.

Answers

In the event when the hand is carrying a ball with a mass of 5.00 kg, the bicep muscle will exert  132.3 N of force. Let's say the forearm weighs 8.50 kg, with the mass's centre 20.0 cm from the elbow.

M = the ball's mass

mass of the forearm is mf.

rf = distance of centre of mass of forearm from elbow, which is 20 cm (0.20 m) away from elbow, and rb = distance of ball from elbow

force exerted by the biceps, F

r = distance of biceps force from elbow

Using elbow-based torque equilibrium

F r = mf rf + mb rb

using the equilibrium of force in the vertical direction, F r = 3.2 eq-1 where F r = 5 x 0.30 + 8.50 x 0.20

F = mb + mf g

F = 8.50* 9.8 + 5 * 9.8

F = 132.3 N

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Two objects are placed 74 meters apart and the resulting force is 0.0103 Newtons. One object has 12 times the mass of the other object. Find the mass of both objects.

Answers

The mass of the both objects are 4.24 × 10⁵ kg and 2.544×10⁶ kg respectively.

What is gravitational force?

The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of their distance, according to Newton's universal law of gravitation.

As two objects are placed 74 meters apart and the resulting force is 0.0103 N.

The Force between two objects = GMm/r²

0.0103  = 6.6×10⁻¹¹× m × 6m/(74)²

m = 4.24 × 10⁵ kg.

hence, the mass of the both objects are 4.24 × 10⁵ kg and (6×4.24 × 10⁵ kg) = 2.544×10⁶ kg respectively.

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A car drives to 215 km East and then 45 km north what is the magnitude of the car displacement? round your answer to the nearest whole number?

Answers

The answer is.....

= 220

David is driving a steady 30 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2.0 m/s2 at the instant when David passes.
a. How far does Tina drive before passing David?
b. What is her speed as she passes him?

Answers

With an acceleration of 2 m/s2, Tina must go distance of 900 metres before passing David.

David's speed is 30 m/s.

Tina's vehicle accelerates at a = 2 m/s2.

Allow Tina's time to pass David is t.

The distance between Tina when she was at rest and when Tina passes her will be equal to the distance David travelled, based on the information provided.

David has travelled the same distance as Tina has.

David has gone a distance of s = v x t s = 30t.

Utilizing the second motion equation

[tex]s=ut+\frac{1}{2} at^2[/tex]

Substitute,

[tex]30t=(0)t+\frac{1}{2} (2)t^2[/tex]

[tex]t^2 = 30t\\t=30[/tex]

As a result, Tina needs 30 seconds to pass David.

Tina's distance travelled equals David's distance travelled,

hence

s = v x t

s = 30 x 30

s = 900m.

Therefore, Tina travelled 900 metres before passing David at a 2 m/s2 acceleration rate.

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With an acceleration of 2 m/s², Tina must go a distance of 900 meters before passing David.

David's speed is 30 m/s.

Tina's vehicle accelerates at a = 2 m/s².

Allow Tina's time to pass David is t.

The distance between Tina when she was at rest and when Tina passes her will be equal to the distance David traveled, based on the information provided.

David has traveled the same distance as Tina has.

David has gone a distance of s = v x t s = 30t.

Utilizing the second motion equation

[tex]S=ut+\frac{1}{2}at^{2}[/tex]

Substitute,

[tex]30t=(0)t+\frac{1}{2}(2)t^{2}[/tex]

[tex]t^{2} =30t\\t=30[/tex]

As a result, Tina needs 30 seconds to pass David.

Tina's distance traveled equals David's distance traveled,

Hence

s = v x t

s = 30 x 3

s = 900m.

Therefore, Tina traveled 900 meters before passing David at a 2 m/s² acceleration rate.

The distance between two points in bodily space is the length of an instant line among them, which is the shortest possible route. this is the usual meaning of distance in classical physics, which includes Newtonian mechanics.

Distance is a numerical or now-and-again qualitative dimension of ways some distance apart gadgets or points are. In physics or regular utilization, the distance may additionally refer to a physical duration or an estimation based totally on other standards (e.g. " counties over"). because spatial cognition is a rich supply of conceptual metaphors in human concepts, the time period is also regularly used metaphorically to intend a measurement of the amount of distinction between comparable items (along with statistical distance among opportunity distributions or edit distance among strings of text) or a degree of separation (as exemplified with the aid of distance between human beings in a social network). maximum such notions of distance, both bodily and metaphorical, are formalized in mathematics using the notion of a metric area.

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A number of wires carry currents into or out of the page as indicated in the figure. (a) Using loop 1 for Ampère's law, what is the net current through the interior of the loop? (b) Repeat for loop 2

Answers

The net current through the interior of the loop is 9 I into the screen.

And for loop two is 8 I out of the screen.

As per the given data, several wires carry currents into or out of the page.

Here we have to determine the net current through the interior of the loop.

For loop 1, the inward currents are 10 I and 14 I. The outward current is 15 I, so, the net current through loop 1 is,

I net = 10 I + 14 I - 15 I

= 9 I into the screen.

The net current through the interior of the loop is 9 I.

For loop 2, the inward current is 7 I, and the outward current is 15 I, so, the net current through loop 2 is,

I net = 15 I - 7 I

= 8 I Out of the screen.

Therefore the answer is 8 I.

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The stability of a vehicle is often rated by the static stability factor, which is one-half the track width divided by the height of the center of gravity above the road.
Part A
One SUV has a static stability factor of 1.2. What is the critical angle?
Express your answer using two significant figures.

Answers

The critical angle of SUV has a static stability factor of 1.2 is found to be Ф = 47.73

How is the static stability factor determined?

The static stability factor (SSF) is defined as the ratio of the height of the centre of gravity to one half the track width.

static stability factor (SSF)= tan Ф

 => Ф = tan^-1 (SSF)

=> tan^-1(1.2) =>  47.73

How can you gauge the stability of a vehicle?

The formula SSF=T/2H is used to determine a vehicle's SSF, where T denotes "track width" and H denotes "height of centre of gravity."

Where is the gravity's centre?

The average location of an object's weight is known as its centre of gravity. Any object's motion through space may be completely explained in terms of how its centre of gravity moves from one location to another and that is how it rotates around its axis.

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A 2-C charge and 4 -C charge attract each other with 10 N of force. How much will a 2-C charge and 8-C charge attract each other when placed the same distance apart?

Answers

The 2 C charge and the 8 C charge will attract each other by a force of 20 N

How do I determine the force of attraction?

We'll begin by obtaining the distance between the 2 C charge and the 4C charge. Details below:

1st charge (q₁) = 2 C2nd charge (q₂) = 4 CForce (F) = 10 NElectric constant (K) = 9×10⁹ Nm²/C²Distance (r) = ?

F = Kq₁q₂ / r²

10 = (9×10⁹ × 2 × 4) / r²

Cross multiply

10 × r² = 9×10⁹ × 2 × 4

Divide both sides by 10

r² = (9×10⁹ × 2 × 4) / 10

Take the square root of both sides

r = √[(9×10⁹ × 2 × 4) / 10]

r = 84852.8 m

Finally, we shall determine the force of attraction between the 2 C charge and the 8 C charge. Details below:

1st charge (q₁) = 2 C2nd charge (q₂) = 8 CDistance apart (r) = 84852.8 mElectric constant (K) = 9×10⁹ Nm²/C²Force of attraction (F) =?

F = Kq₁q₂ / d²

F = (9×10⁹ × 2 × 8) / (84852.8)²

F = 20 N

Thus, the force of attraction between them is 20 N

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A 10,000 kg shipping container is on a truck moving at 75 mph on a flat road. The driver brings the container to a stop with an average force of 2500 N exerted on the container. Calculate the stopping distance.

Answers

When Shipping container is on a truck moving on a flat road then stopping distance is 180 meters.

Given,

mass m = 10000kg

speed v= 75mph

Average force F=2500N

When a car skids to a stop, the work done by friction upon the car is equal to the change in kinetic energy of the car. Work is directly proportional to the displacement of the car (skidding distance) and the kinetic energy is directly related to the square of the speed (KE=0.5*m*v2).

For this reason, the skidding distance is directly proportional to the square of the speed. So if the speed is tripled from 75 km/hr to 120 km/hr, then the stopping distance is increased by a factor of 9 (from 20 m to 9*20 m; or 180 m).

When analyzing forces in a structure or machine, it is conventional to classify forces as external forces.  Constraint forces or internal forces.External forces arise from interaction between the system of interest and its surroundings.

Examples of external forces include gravitational forces; lift or drag forces arising from wind loading, electrostatic and electromagnetic forces; and buoyancy forces; among others.

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A very large plastic sheet carries a uniform charge density of -6.00 nC/m^2 on one face.
a) As you move away from the sheet along a line perpendicular to it, does the electric field increase or decrease? Explain.

Answers

The work done on the unit positive charge to move away from the sheet along a line perpendicular to it and the electric field increase with distance.

What does "electric potential" mean?

Against an electric field, the amount of labour required to transport a unit charge from one location to another is known as electric potential. Although any location beyond the range of the electric field charge can be used, Earth is typically selected as the reference point. potential electricity.

How are charge and the electric field related?

The presence of an electric charge results in a modification of space known as the electric field. Between a source charge and a test charge, the electric field mediates the electric force. A vector by definition points away from positive charges and toward negative charges, which is what the field does.

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How much heat does the air exchange with its surroundings during the process abc? Express your answer using two significant figures.

Answers

The amount of heat does the air exchange with its surroundings during the process abc is 4kJ.

This query is based on the first law of thermodynamics, which is formally defined as, Q = ΔU + W where, Q and ΔU is the changes in internal energy of the system and W is the work performed by the system. There is no change in the gas's internal energy since the temperature at states a and c remains constant. ΔU thus equals 0. Consequently, the heat generated during the process ABC, is Q = ΔU + Wabc

Q = 0 + Wab + Wbc

Q = 0 + 0+ 1 x 10^5Pa x (0.06-0.02) m^3

Here Wab = 0 as  volume remains constant along ab

Q = 4 x 10^3J = 4kJ

Because Q is positive, air will heat up during the process.

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complete question: A volume of air (assumed to be an ideal gas) is first cooled without changing its volume and then expanded without changing its pressure, as shown by the path abc. How much heat does the air exchange with its surroundings during the process abc? Does the air absorb heat or release heat during this process? Explain.

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