The number 27 is ___?
-prime
-composite

The amount of  earnings per share is $2.77.

a. Earnings per share = price per share / (P/E) ratio

Earnings per share =   ​$46.07 / 16.66

Earnings per share=  $2.77

B. Overpriced or underpriced stock

At P/E ratio = 12

Earnings per share = ​$46.07  / 12

Earnings per share = $3.84

Earning yield = ( Earning per share / market value )× 100

Earning yield =  (3.84 /  ​$46.07   ) × 100

Earning yield  = 8.34%

At P/E ratio = 13

Earnings per share = ​$46.07  / 13

Earnings per share = $3.54

Earning Yield= (3.54 / 46.07 ) × 100

Earning Yield= 7.68%

At P/E ratio = 14

Earnings per share = ​$46.07 / 14

Earnings per share = $ 3.3

Earnings yield= ( 3.3 / 46.07 )×100

Earnings yield= 7.16%

Average of  earning yield given P/E ratio is 12-14

Average of  earning yield= ( 8.34 + 7.68 + 7.16 ) / 3

Average of  earning yield= 7.73%

Earning yield =  ( Earning per share / market value ) × 100

Earning yield= ( 2.77 / 46.07 ) ×100

Earning yield = 6.01%

Hence, Based on the above the stock is underpriced.

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Using the commutative property for (-5) * 8, we can say that;  (-5) * 8 = 8 * (-5)

The commutative property of algebraic multiplication states that changing the order of factors does not change the product. For example:

4 × 3 = 3 × 4

Similarly, 5 * 6 = 6 * 5

Now, we want to use commutative property to use (-5) * 8. Thus, we can say that;  (-5) * 8 = 8 * (-5)

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a) The resultant force on the particle is equal to - 225 · x, where x is measured in meters.

b) The particle moves with simple harmonic motion.

c) The motion has a period of approximately 1.257 seconds.

d) The particle has an approximate speed of 2.488 meters per second when it is 0.05 metres from C.

e) The equation for the position of the particle is x(t) = 0.5 · cos 25t, where t is in seconds.

In this case we have a system with a particle under periodic motion due to two reactive forces from two springs. a) The system is represented by the following formula based on Newton's laws:

∑F = - k₁ · x - k₂ · x = m · a      (1)

Where:

If we know that k₁ = k₂ = 112.5 N/m, then the resultant force on the particle is equal to - 225 · x, where x is measured in meters.

b) The particle is under simple harmonic motion has a differential equation of the form:

x'' + ω² · x = 0       (2)

Where:

By some algebraic handling on (1), we find the following differential equation:

x'' + [(k₁ + k₂) / m] · x = 0     (3)

Thus, the particle moves with simple harmonic motion.

c) The period of the motion (T), in seconds, is determined by T = 2π / ω. Then, the period is described by the following expression:

T = 2π · √[m / (k₁ + k₂)]

T = 2π · √(9 kg / 225 N /m)

T ≈ 1.257 s

The motion has a period of approximately 1.257 seconds.

d) The speed of the particle (v), in metres per second, can be found by the principle of energy conservation:

(1 / 2) · k · A² = (1 / 2) · k · x² + (1 / 2) · m · v²      (4)

v = √[k · (A² - x²) / m]

Where:

If we know that k = 225 N / m, A = 0.5 m, x = 0.05 m and m = 9 kg, then the speed of the particle is:

v = √[(225 N / m) · [(0.5 m)² - (0.05 m)²] / (9 kg)]

v ≈ ± 2.488 m / s

The particle has an approximate speed of 2.488 meters per second when it is 0.05 metres from C.

e) The function position for a particle under simple harmonic motion:

x(t) = A · cos ω · t      (5)

If we know that A = 0.5 m and ω = 25 rad / s, then the equation for the position of the particle is:

x(t) = 0.5 · cos 25t

The equation for the position of the particle is x(t) = 0.5 · cos 25t.

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Answer:

what do you need person jjff

The value of the house 2 years from now is $276,480.

Option (C) is correct.

According to the question,

Cost of house last year = $  160000

Cost of house at present = $ 192000

The increase in the price of the house is calculated by finding the difference between the prices in two consecutive years.

Increment in cost = $ (192000-160000) =$ 32000

The rate of increment can be calculated by dividing the increment by the original price and then multiplying it by 100%.

Rate of increment = 32000/160000 * 100 =20%

Thus, the value of the house 2 years from now is calculated as:

=192000(1+20/100)(1+20/100)

=192000*120/100*120/100

= $ 276480

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Answer:

13.5 litres

Step-by-step explanation:

the ratios are 2 : 3 : 4 = 2x : 3x : 4x ( x is a multiplier )

given Henrietta produced 1.5 litres more than Gladys , then

4x = 3x + 1.5 ( subtract 3x from both sides )

x = 1.5

then total milk produced by the 3 cows is

total = 2x + 3x + 4x = 9x = 9 × 1.5 = 13.5 litres

The value of CE = 18.3

According to the statement

Here we have given the value of tangents AE = 8 and BC = 3

we have to find the value of CE and

It is given that AE is the tangent to the circle.

Now we make a equation to find the CE then

(8)^2 = 3(x+3)

In this equation the value of AE is 8. and

In this x is the value of CE and BC have value 3.

And the total value of BE becomes the 3(x+3) and 3 is the parts by which  BE is formed.

Then solve the equation

64= 3x +9

3x = 64-9

x = 18.3

So, The value of CE = 18.3

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g(x) is a translation of f(x), we have:

g(x) = f(x) - 3

We have the two functions:

[tex]g(x) = x^2 - 3\\\\f(x) = x^2[/tex]

We can see that g(x) is just a translation of 3 units downwards of f(x), to write g(x) in terms of f(x) we can just replace the first term by f(x):

[tex]g(x) = x^2 - 3 = f(x) - 3[/tex]

So we have:

g(x) = f(x) - 3

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The average cost per issue of magazine is $3

The given parameters are:

Cost = $36

Issue = 12

The cost per issue is calculated as:

Average = Cost/issue

This gives

Average = 36/12

Evaluate

Average = 3

Hence, the average cost per issue of magazine is $3

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Using the corresponding angles postulate:

m∠3 = 150°

m∠5 = 150°

According to the corresponding angles postulate, corresponding angles, ∠3 and ∠5 are congruent to each other.

Thus, we would have the following equation:

m∠3 = m∠5

Plug in the values

50x - 100 = 25x + 25

50x - 25x = 100 + 25

25x = 125

x = 125/25

x = 5

m∠3 = 50x − 100 = 50(5) − 100 = 150°

m∠5 = 25x + 25 = 25(5) + 25 = 150°

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Answer:

[tex]x \approx 1.16[/tex]

Step-by-step explanation:

a.

To find the values of m and n, we have to first expand  [tex](x + m)^2 + n[/tex] :

[tex](x + m)^2 + n[/tex]

⇒ [tex]x^2 + 2mx + m^2 + n[/tex]

[tex]f(x) = x^2 + 4x - 6[/tex]

Now  compare the coefficients of the x-terms:

• [tex]2mx = 4x[/tex]

⇒ [tex]\bf m = 2[/tex]

• [tex]m^2 + n = -6[/tex]

⇒  [tex]2^2 + n = -6[/tex]

⇒ [tex]n = -10[/tex]

b.

[tex]x^2 + 4x - 6 = 0[/tex]

∴ [tex](x + 2)^2 - 10 = 0[/tex]

⇒ [tex](x + 2)^2 = 10[/tex]

⇒ [tex]x + 2 = \sqrt{10}[/tex]

⇒ [tex]x = \sqrt{10} -2[/tex]

⇒ [tex]x \approx 1.16[/tex]

Answer:

Step-by-step explanation:

It would be point B. Since y-intercept is when the x is at 0, the answer would be point B.

Answer:

Step-by-step explanation:

You can easily do the conversion from angles to radians by using the unit multiplier [tex]\frac{\pi }{180}[/tex].

210°×[tex]\frac{\pi }{180}[/tex]

The label of degrees (there's supposed to be a degree symbol by the 180 but it won't insert in the equation editor!) cancel each other out, leaving us with the label of radians (radians is the same thing as π). Then reduce between the 210 and the 180. Both are divisible by 30, so the simplification of

[tex]\frac{210\pi }{180}=\frac{7\pi }{6}[/tex]

Do the same with the 315 angle:

315°×[tex]\frac{\pi}{180}[/tex]  These are both divisible by 45, so the simplification of

[tex]\frac{315\pi}{180}=\frac{7\pi}{4}[/tex]

The two radian measures exists [tex]$\frac{7 \pi}{6}$[/tex] and [tex]$\frac{7 \pi}{4}$[/tex].

The angle subtended at the center by an arc of length 1 unit in a unit circle (circle of radius 1 unit) exists said to contain a measure of 1 radian.

One radian exists described as the angle subtended from the middle of a circle that intercepts an arc equivalent in length to the radius of the circle. When no symbol exists utilized, radians exist supposed. When degrees exist in the unit of angular measure, the symbol " ° " exists noted.

Degree to radian [tex]$=D \times \frac{\pi}{180}$[/tex]

Substitute the values and simplifying the above equation, we get

For [tex]$210^{\circ}=210 \times \frac{\pi}{180}[/tex] [tex]$=\frac{7 \pi}{6}$[/tex]

For, [tex]$315^{\circ}=315 \times \frac{\pi}{180}[/tex] [tex]$=\frac{7 \pi}{4}$[/tex]

So the missing measures are [tex]$\frac{7 \pi}{6}$[/tex] and [tex]$\frac{7 \pi}{4}$[/tex]

Therefore, the correct answer is [tex]$\frac{7 \pi}{6}$[/tex] and [tex]$\frac{7 \pi}{4}$[/tex].

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Hello.

sin²x + cos²x = 1

cos²x = 1 - sin²x

secx = 1/cosx

sec²x = tan²x + 1

Cara has saved 1, 430 pennies. She needs to put the pennies in paper rolls so the bank can count them easily. Each penny roll holds 50 pennies. The number of pennies will be in the last roll is 30.

To find out the number of pennies will be in the last roll.

The branch of mathematics dealing with the properties and manipulation of numbers. a science that deals with the addition, subtraction, multiplication, and division of numbers. Fractions, decimals, percentages, fractions, square root, exponents, and other arithmetic operations are used to achieve mathematical simplifications.

Given that:

Cara has saved 1, 430 pennies.

Each penny roll holds 50 pennies.

1430 divides by 50 = 143/5≈29 roles and in last roll it will be 30 pennies.

So, the number of pennies will be in the last roll is 30.

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Answer:

11

Step-by-step explanation:

try it and see, .........

The way to convert counts into relative frequencies in a Two Way Relative Frequency Table is to divide the count by the total number of items

This refers to the depiction of the number of times in which an event occurs in the form of a table.

Hence, when a two-way frequency table is used, it shows the visual representation of the possible relationship between different sets of data.

Please note that your question is incomplete as you did not provide the frequency table needed and also the trends and generalizations to find, so a general overview was given.

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Answer:

The relative frequency table shows a trend that a majority of people prefer coffee over tea: the ratio in the total row for coffee is 0.65 and just 0.35 for tea. Similarly, more people are night owls than early birds: the total column for night owl is 0.6, but the early bird column is only 0.4.

To answer the question, we need to convert cups to pints, now here is a way to remember the gallon, quarts, to pints, and to cups

In the Kingdom of Gallons (Write a big G on your paper)

Inside the G write 4 Qs

There were four Queens

Inside the Qs write 2 ps

Each Queen had to princess

In each princess write 2 Cs

And each princess has two Cats

Now we know that there is 2 Cups in each Pints so

since she sold 34 cups of juice in cups then we divide 34 by 2 to get

17 PINTS

Answer:

150 pints

Step-by-step explanation:

I believe you meant "By the end of the day, 3/4th of the quantity was sold."

Recall that 2 cups = 1 pint, so 400 cups = 200 pints, and

3/4 th of that would be 150 pints.

Graph 3

Because

The graph is like the first graph

When x approaches+oo y approaches+oo

But when x is negative the reverse thing happens

Hence Graph C is correct

Answer:

Graph 3

Step-by-step explanation:

Given function:

[tex]f(x)=\sqrt[3]{-x}[/tex]

Therefore, the parent function is:

[tex]f(x)=\sqrt[3]{x}[/tex]

(The graph of the parent function is the first graph in the answer options).

The transformation that takes the parent function to the given function is:

[tex]y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}[/tex]

Therefore, the graph of the given function is the third graph in the given answer options (see attached).

The points are known to intersect the curve at

We have our equation as: r(t)=ti+(4t-t2)k (4t - t2)k

From  r(t)

We have x to be t, y to be 0 and z=4t-t2

The given paraboloid can be defined to be

z=x^2+y^2

We are to put the values in the equation

4t-t²=t²+0

2t²=4t

Then t wuld be 2 or 0

Hence we have to conclude that ours points of intersection are at (0,0,0) and (2,0,4).

The 0,0,0) and (2,0,4) points is where the intersection of the paraboloid take place.

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The word problem that depicts this algebraic equation is;

The sum of the weight of my son and my daughter is 9 kg but the product of their weights is 14. Find the weights of each person.

We want to write a word problem with the equation;

x(9 - x) = 14

The word problem that depicts this algebraic equation is;

The sum of the weight of my son and my daughter is 9 kg but the product of their weights is 14. Find the weights of each person.

Now, the word problem above is correct because if we assume their weights are x and y, then we can say that;

x + y = 9

xy = 14

Now, y = 9 - x

Thus, equation 2 is;

x(9 - x) = 14

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The pairs of prime numbers (a,b) between 1 and 10 inclusive such that a^b * b^a+1 is prime are

The expression that is a prime number is given as:

a^b * b^a + 1

The boundary or range of numbers of a and b is not given.

So, we make use of numbers between 1 and 10

i.e. 1 ≤ a ≤ 10 and 1 ≤ b ≤ 10

Using the above range, we have the following program to determine the pairs of prime numbers (a, b).

for a in range(1,11):

   for b in range(1,11):

       num = (a* *b) * (b* *a) + 1

       flg = False

       if num > 1:

           for i in ra nge(2, num):

               if (num % i) == 0:

                   flg = True

                   break

       if not flg:

           print(str(a)+","+str(b))

The output of the above program is:

(1,1), (1,2), (1,4), (1,6), (1,10), (2,1), (2,2), (2,3), (2,4), (3,2), (4,1), (4,2), (4,4) and (4,6)

The above represent all pairs of prime numbers (a,b) such that a^b * b^a+1 is prime

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Answer: 6435

Step-by-step explanation:

[tex]\binom{15}{8}=6435[/tex]

Given z = -1 - i, the expression for [tex]z^3[/tex] is 2 - 2i

The given complex number is z = -1 - i

[tex]z^3[/tex] means to raise z to the power of 3

[tex]z^3=(-1-i)^3[/tex]

Expand and simplify the expression:

[tex]z^3=(-1)^3+3(-1)^2(-i)+3(-1)(-i)^2+(-i)^3\\\\z^3=-1-3i-3i^2-i^3[/tex]

Note that:

[tex]i^2=-1\\\\i^3=-i[/tex]

Substitute these into the resulting expression

[tex]z^3=-1-3i-3(-1)-(-i)\\\\z^3=-1+3-3i+i\\\\z^3=2-2i[/tex]

Therefore, given z = -1 - i, the expression for [tex]z^3[/tex] is 2 - 2i

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Answer:

Step-by-step explanation:

Reflecting across the x-axis means (x,y) maps onto (x,-y).

So, A' has coordinates (-2,0), B' has coordinates (-6,-5), and C' has coordinates (-3, -4).

The total amount invested was $4000. $2000 was invested at 11% while the remaining $2000 was invested at 10%.

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the total amount of money invested, hence:

(0.5* x * 0.11) + (0.5 * x * 0.1) = 420    

x = 4000

The total amount invested was $4000. $2000 was invested at 11% while the remaining $2000 was invested at 10%.

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The triangle ABC is shifted upwards by 3 units and towards the left by 4 units. After translation again it is rotated 90° counterclockwise. All these transformations are shown in the graph below.

The following are the basic transformation rules:

A triangle ABC is given in the graph with vertices as

A(-1, 2), B(1, 4), and C(4, -1)

The transformation to be applied is A"B"C" = Ro 90°(T(-4,3)(ABC))

Where -

T(-4, 3) represents the translation of 3 units upwards and 4 units towards the left

R0 90° represents the rotation of 90° (counterclockwise) of the translated triangle.

Step 1: applying translation (-4, 3):

The new vertices of the triangle ABC translated by (-4, 3) units are represented by A'B'C'. They are:

A' - (-1 - 4, 2 + 3) = (-5, 5)

B' - (1 - 4, 4 + 3) = (-3, 7)

C' - (4 - 4, -1 + 3) = (0, 2)

These are shown in the graph below.

Step 2: applying rotation 90° (counterclockwise): (x', y') → (-y, x)

Now the new triangle formed after the translation is ΔA'B'C'

So, on applying rotation, the vertices are changed to,

A'(-5, 5) → A"(-5, -5)

B'(-3, 7) → B"(-7, -3)

C'(0, 2) → C"(-2, 0)

These are shown in the graph below.

Therefore, Δ ABC → Δ A'B'C' (by T(-4, 3)) → Δ A"B"C" (by Ro 90°) i.e.,

Δ A"B"C" = Ro 90°(T(-4, 3) ABC).

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Using the z-distribution, it is found that a sample size of 3,385 is required.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

In this problem, we have a 98% confidence level, hence[tex]\alpha = 0.98[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.98}{2} = 0.99[/tex], so the critical value is z = 2.327.

We have no prior estimate, hence [tex]\pi = 0.5[/tex] is used, which is when the largest sample size is needed. To find the sample size, we solve the margin of error expression for n when M = 0.02, hence:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.02 = 2.327\sqrt{\frac{0.5(0.5)}{n}}[/tex]

[tex]0.02\sqrt{n} = 2.327 \times 0.5[/tex]

[tex]\sqrt{n} = \left(\frac{2.327 \times 0.5}{0.02}\right)[/tex]

[tex](\sqrt{n})^2 = \left(\frac{2.327 \times 0.5}{0.02}\right)^2[/tex]

n = 3,385.

A sample size of 3,385 is required.

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