Answer:
0.40x = 320
Step-by-step explanation:
If 40% of the total houseplants watered = 320
0.40 times x (total houseplants) = 320
Answer:
[tex]\frac{x}{0.40} = 320 Plants[/tex]
Step-by-step explanation:
[tex]\frac{x}{0.40} = 320 Plants[/tex]
[tex]X = (0.40)(320)Plants[/tex]
[tex]X = 128Plants[/tex]
[tex]8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3}[/tex]
The solution to the expression [tex]8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3}[/tex] is [tex]\frac{216x^6 - 108x^4 + 18x^2 - 1}{27x^3}[/tex]
How to solve the expression?The expression is given as:
[tex]8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3}[/tex]
Take the LCM of the expression
[tex]\frac{8x^3 * 27x^3 - 4x * 27x^3 + 2 * 9x^2 - 1}{27x^3}[/tex]
Evaluate the products
[tex]\frac{216x^6 - 108x^4 + 18x^2 - 1}{27x^3}[/tex]
Hence, the solution to the expression [tex]8x^3-4x+\frac{2}{3x}-\frac{1}{27x^3}[/tex] is [tex]\frac{216x^6 - 108x^4 + 18x^2 - 1}{27x^3}[/tex]
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You use generally accepted facts (such as: there are approximately 6 billion people on the planet. ) without citing them is it plagiarism?
No, this not plagiarism .You can use generally accepted facts without citing them.
What defines self-plagiarism?
Self-plagiarism is defined as a type of plagiarism in which the writer republishes a work in its entirety or reuses portions of a previously written text while authoring a new work.
What is considered general knowledge in plagiarism?
Common knowledge is typically defined as facts that are unsupported by at least five reliable sources. In the discipline of composition studies, for instance, the statement "Writing is difficult" is taken for granted because at least five reliable sources may support it.How to Avoid plagiarism common knowledge?
Quoting correctly, paraphrasing and summarizing correctly, and documenting (citing) correctly are the keys to providing credit and avoiding plagiarism; you can go to page 3 of this handout for more information. Almost all of the information you discover in outside sources needs to be documented.Learn more about plagiarism
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Which problem could be solved with the expression 5 x ( 2 + 4 ) ÷ 6 ?
1. Hayden made 222 bracelets before school and 444 after school each day for 555 days. Then he split the bracelets into 666 equal groups. How many bracelets did Hayden have in each group?
2. Khai, the dog, ate 222 bones on Monday, 444 bones on Tuesday and 666 bones on Wednesday. On Thursday, she ate 555 times more bones than the other days combined. How many bones did Khai eat on Thursday?
3. Shadi is building a new back deck. He puts 222 nails and 444 screws in each board. He did this to 555 boards. How many total screws and nails did he use?
PLEASE ANSWER AS SOON AS POSSIBLE!
I know its a lot to read but I would REALLY appreciate if you could answer this with the problem numbers 1, 2, and 3. THANK YOU!
Answer:
1
Step-by-step explanation:
This is the only problem that could be answered with this equation, because you would add the bracelets he made (2+4) then times that number by the days he made them, 5, then divide by the number of groups, 6. Which equals 5 x ( 2 + 4 ) divided by 6.
I hope this helps!
Drag each tile to the correct box.
Graph the functions as transformations of f(x) = x^(2).
Arrange the parabolas with respect to the position of their vertices from left to right.
Answer:
Step-by-step explanation:
A parabola, with its vertex at the origin, has a directrix at y = 3. which statements about the parabola are true? select two options.
The correct options about parabola are:
The focus is located at (0,–3).
The parabola can be represented by the equation x^2 = –12y.
According to the statement
we have given that the vertex is at the origin and directrix at y = 3.
and from these given information and we have to find the all abot the parabola like its focus point etc.
So,
We know that the equation of parabola is
(x-h)^2 = 4p(y-k)
Here The vertex is (h,k). and the focus is at (h,k+p). and the directrix is y(k - p.)
So, From the given information
Vertex at the origin means that h=0 and k=0
Directrix at y = 3 means that p=-3
Directrix at the y-axis means the parabola opens upwards.
Thus, the focus is: (0,-3)
And The p-value becomes
: 4(-3) = -12.
And from all these the equation of the parabola is becomes
(x)^2 = -12y
So, The correct options about parabola are:
The focus is located at (0,–3).
The parabola can be represented by the equation x^2 = –12y.
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Question:
A parabola, with its vertex at the origin, has a directrix at y = 3. Which statements about the parabola are true? Select two options.
The focus is located at (0,–3).
The parabola opens to the left.
The p value can be determined by computing 4(3).
The parabola can be represented by the equation x2 = –12y.
The parabola can be represented by the equation y2 = 12x.
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A man mows his 100 ft by 200 ft rectangular lawn in a spiral pattern starting from the outside edge. After a bit of hard work he stops for a water break, he is 40.5% done. How wide of a strip has he mowed around the outside edge
Based on the length and width of the rectangular lawn, and the percentage the man has mowed, the strip width would be 40.5 m.
what is the width of the strip mowed already?first, find the area of the lawn:
= 100 x 200
= 20,000 ft²
the area mowed is:
= 40.5% x 20,000
= 8,100 ft²
the width is therefore:
= 8,100 / 200
= 40.5 m
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Transform the given equation into a system of first order equations. (Let x1 = u, x2 = u', x3 = u'', and x4 = u'''. Enter your answers in terms of x1, x2, x3, and x4.) u(4) − u = 0
a) x1' =
b) x2' =
c) x3' =
d) x4' =
Given the 4th order linear ODE
[tex]u^{(4)} - u = 0[/tex]
we substitute
[tex]x_1 = u[/tex]
[tex]x_2 = {x_1}' = u'[/tex]
[tex]x_3 = {x_2}' = {x_1}'' = u''[/tex]
[tex]x_4 = {x_3}' = {x_2}'' = {x_1}''' = u'''[/tex]
Then the given equation transforms to
[tex]{x_4}' - x_1 = 0[/tex]
but we also need to relate this to the other derivative substitutions. This gives the system of differential equations
[tex]\begin{cases} {x_1}' = x_2 \\ {x_2}' = x_3 \\ {x_3}' = x_4 \\ {x_4}' = x_1 \end{cases}[/tex]
In matrix form,
[tex]\begin{bmatrix} x_1 \\ x_2 \\ x_3 \\ x_4 \end{bmatrix}' = \begin{bmatrix} 0 & 1 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 0 & 0 & 1 \\ 1 & 0 & 0 & 0 \end{bmatrix} \begin{bmatrix} x_1 \\ x_2 \\ x_3 \\ x_4 \end{bmatrix}[/tex]
Select the correct answer. which equation could possibly represent the graphed function?
The function for the given graph is f(x) = (x - 4)(x + 2)(x + 4).
How to represent a graph by an equation?A graph can be represented by the equation y = f(x).In the equation, the variable x is called the independent variable and the variable y is called the dependent variable.Calculation:In the given graph,
The points that lie on the x-axis are (-4, 0), (-2, 0), and (4, 0) where y-coordinate is 0 and the x coordinates are -4, -2, and 4.
On solving the given functions,
Option A:
f(x) = (x - 4)(x + 2)(x + 4)
Since y = 0 consider f(x) becomes 0
So,
(x - 4)(x + 2)(x + 4) = 0
According to the zero product rule,
x - 4 = 0, x + 2 = 0, and x + 4 = 0
⇒ x = 4, x = -2 and x = -4.
Thus, option A represents the function of the given graph.
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Question:
Select the correct answer. which equation could represent the graphed function (given in the figure below)?
need help don’t know what to do
Scores for a civil service exam are normally distributed with a mean of 75 and a standard deviation of 6.5. what score marks the difference between the bottom 10% and the top 90%?
The lowest score you can earn and still be eligible for employment is 85.6925.
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
Top 5%.
At least the 100-5 = 95th percentile.
The 95th percentile is X when Z has a pvalue of 0.95. So X when Z = 1.645.
x-75 = 1.645*6.5
x = 85.692
Thus the lowest score you can earn and still be eligible for employment is 85.6925.
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Expand the expression / brackets: 2y (3y + 9)=
Answer:
6y^2 + 18y
Step-by-step explanation:
2y (3y + 9)=
6y^2 + 18y
[2y (3y becomes 6y^2]
[2x( + 9) becomes 18y]
Add them to obtain 6y^2 + 18y
Larry has 6 shirts and 4 pairs of jeans. How many different combinations of one shirt and one pair of jeans can Larry make
Answer:
24 combinations
Step-by-step explanation:
To get to this answer, I multiplied 6 x 4, since there are 6 shirts and 4 pairs of jeans, there will be a total of 24 combinations. For combinations of two different things, you can just multiply the amount of each item by the other item. hope this helps :)
1. Prove the following identities
Answer:
Step-by-step explanation:
[tex]\sf 1.1)\dfrac{Sin \ \theta-Cos \ \theta}{Sin \ \theta + Cos \ \theta}=\dfrac{(Sin \ \theta-Cos \ \theta)}{((Sin \ \theta + Cos \ \theta)}*\dfrac{(Sin \ \theta-Cos \ \theta)}{(Sin \ \theta-Cos \ \theta)}[/tex]
[tex]\sf = \dfrac{(Sin \ \theta-Cos \ \theta)^2}{Sin^2 \ \theta-Cos^2 \ \theta}\\\\=\dfrac{Sin^2 \ \theta+Cos^2 \ \theta-2Sin \ \theta \ Cos\ \theta}{(Sin \ \theta-Cos \ \theta)}\\\\\\\bf Identity: \ (a +b)^2= a^2 + b^2 - 2ab\\\\\\=\dfrac{1-2Sin \ \theta \ Cos \ \theta}{(Sin \ \theta-Cos \ \theta)} = LHS[/tex]
[tex]\sf 1.2) LHS = tan^2 \ x - Sin^2 \ x = \dfrac{Sin^2 \ x}{Cos^2 \ x}-Sin^2 \ x[/tex]
[tex]\sf =\dfrac{Sin^2 \ x}{Cos^2 \ x}-\dfrac{Sin^2 \ x*Cos^2 \ x}{1*Cos^2 \ x}\\\\\\ = \dfrac{Sin^2 \ x - Sin^2 \ x*Cos^2 \ x}{Cos^2 \ x}\\\\\\= \dfrac{Sin^2 \ x *(1 -Cos^2 \ x)}{Cos^2 \ x}\\\\=\dfrac{Sin^2 \ x*Sin^2 \ x}{Cos^2 \ x} \\\\ \bf 1 - Cos^2 \ x = Sin^2 \ x\\\\= \dfrac{Sin^2 \ x}{Cos^2 \ x}*Sin^2 \ x\\\\=tan^2 \ x * Sin^2 \ x = RHS[/tex]
[tex]\sf 1.3) LHS = \dfrac{1-Cos \ x}{Sin \ x}-\dfrac{Sin \ x}{1+Cos \ x} =\dfrac{(1-Cos \ x)(1+Cos \ x)}{Sin \ x*(1+Cos \ x)}-\dfrac{Sin \ x*Sin \ x}{(1+Cos \ x)*Sin \ x}\\[/tex]
[tex]\sf =\dfrac{1 - Cos^2 \ x}{Sin \ x*(1+Cos \ x)}-\dfrac{Sin^2 \ x}{Sin \ x*(1+Cos \ x)}\\\\=\dfrac{Sin^2 \ x}{Sin \ x*(1+Cos \ x)} - \dfrac{Sin^2 \ x}{Sin \ x*(1+Cos \ x)}\\\\=\dfrac{Sin^2 x - Sin^2 \ x}{Sin \ x*(1+Cos \ x)} \\\\= 0 = RHS[/tex]
[tex]\sf 1.4) LHS = Sin x - \dfrac{1}{Sin \ x + Cos \ x}+Cos \ x \\[/tex]
[tex]\sf = \dfrac{Sin \ x *(Sin \ x + Cos \ x) - 1 + Cos \ x * (Sin \ x + Cos \ x)}{Sin \ x + Cos \ x }\\\\\\= \dfrac{Sin \ x * Sin \ x + Sin \ x*Cos \ x -1 + Cos \ x*Sin \ x + Cos \ x*Cos \ x}{Sin \ x + Cos \ x}\\\\\\=\dfrac{Sin^2 \x + Sin \ x \ Cos \ x - 1 + Cos \ x \ Sin \ x + Cos^2 \x}{Sin \ x + Cos \ x}\\\\=\dfrac{Sin^2 \ x + Cos^2 \ x - 1 + Sin \ xCos \x +Sin \ x Cos \ x}{Sin \ x + Cos \ x}\\\\= \dfrac{1 - 1 +2Sin \ x Cos \ x}{Sin \ x + Cos \ x}\\\\= \dfrac{2Sin \ x Cos \ x}{Sin \ x + Cos \ x}[/tex]
Let [tex]sin\beta =\frac{2\sqrt[]{2} }{5} \\[/tex] and [tex]\frac{\pi }{2} \leq\beta \leq \pi \\[/tex].
Determine the exact value of [tex]sin(\frac{\beta }{2} )[/tex]
Since beta is in the first quadrant, the final answer will be positive.
To find cos(beta) so we can use the half angle identity, we can substitute into the Pythagorean identity. Doing so gives us that
[tex] \sin( \beta ) = \frac{ \sqrt{17} }{5} [/tex]
So, this means that
[tex] \sin( \frac{ \beta }{2} ) = \sqrt{ \frac{1 - \frac{ \sqrt{17} }{2} }{2} } = \sqrt{ \frac{2 - \sqrt{17} }{4} } = \frac{ \sqrt{2 - \sqrt{17} } }{2} [/tex]
Yolanda paid for her movie ticket using 28 coins, all nickels and quarters. the ticket cost $4. which system of linear equations can be used to find the number of nickels, n, and the number of quarters, q, yolanda used? n q = 28 0.05n 0.25q = 4 n q = 4 5n 25q = 28 n q = 28 5n 25q = 4 n q = 4 0.05n 0.25q = 28
The system of linear equations can be used to find the number of nickels, n, and the number of quarters, q, yolanda used is n + q = 28
n + q = 280.05n + 0.25q = 4
Simultaneous equationn + q = 28
0.05n + 0.25q = 4
n = 28 - q
substitute n = 28 - q0.05n + 0.25q = 4
0.05(28 - q) + 0.25q = 4
1.4 - 0.05q + 0.25q = 4
- 0.05q + 0.25q = 4 - 1.4
0.20q = 2.6
q = 2.6 / 0.20
q = 13
Substitute into
n + q = 28
n + 13 = 28
n = 28 - 13
n = 15
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The functions f(x) and g(x) are graphed.
On a coordinate plane, a curved red line with an upward arc, labeled g of x, crosses the y-axis at (0, 4) and the x-axis at (2, 0). A straight blue line with a negative slope, labeled f of x, crosses the y-axis at (0, 4) and the x-axis at (2, 0).
Which represents where f(x) = g(x)?
f(0) = g(0) and f(2) = g(2)
f(2) = g(0) and f(0) = g(4)
f(2) = g(0) and f(4) = g(2)
f(2) = g(4) and f(1) = g(1)
The function equality that represents the point where f(x) = g(x) is; A: f(0) = g(0) and f(2) = g(2)
How to interpret Graphed Functions?From the question, the curved red line represents g(x) while the straight blue line represents f(x).
Now, the equality of functions f(x) = g(x) is represented as a common function between their curves. Thus, we will just need to find a common point for both. This is;
f(x) has points (0, 4) and (2, 0).
g(x) has points (0,4) and (2,0).
It is pertinent to note that both functions have the same y-value for x=0 and x = 2. Thus, we can say that;
f(2) = g(2) and f(0) = g(0)
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what inequality is shown on the graph ?
The inequality of the graph that is given is: y < 2x - 3.
How to Write the Inequality of a Graph?First find the slope (m) = rise / run of the line.
Rise = 2 units
Run = 1 unit
Slope (m) = 2/1 = 2
Y-intercept (b) = -3.
Since the shaded side is at the left, we are going to use the ">" sign. Substitute m = 2 and b = -3 into y < mx + b.
y < 2x - 3
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A flat rectangular piece of aluminum has a perimeter of 60 inches. The length is 12 inches longer than the width. Find the width.
Answer:
width = 9 inches
Step-by-step explanation:
let width be w then length is w + 12
the perimeter ( P) is calculated as
P = 2( width + length )
here P = 60 , then
2(w + w + 12) = 60 ( divide both sides by 2 )
2w + 12 = 30 ( subtract 12 from both sides )
2w = 18 ( divide both sides by 2 )
w = 9
that is the width of the rectangle is 9 inches
What is the simplified form of startroot startfraction 2,160 x superscript 8 baseline over 60 x squared endfraction endroot? assume x ≠ 0.
The simplified form is [tex]6x^{3}[/tex].
What are indices in maths?
An index, or a power, is the small floating number that goes next to a number or letter.The plural of index is indices. Indices show how many times a number or letter has been multiplied by itself.The equation is -
[tex]\sqrt{\frac{2160x^{3} }{60x^{2} } }[/tex]
We can rewrite this using property of multiplication to obtain
[tex]\sqrt{\frac{2160}{60} * \frac{x^{8} }{x^{2} } }[/tex]
We simplify variable expression in the radicand using
[tex]\frac{a^{m} }{a^{n} } = a^{m - n}[/tex]
[tex]\sqrt{36 * x^{8 - 2} }[/tex]
[tex]\sqrt{36 * x^{6} }[/tex]
[tex]\sqrt{36 * (x^{3})^{2} }[/tex]
[tex]\sqrt{36} * \sqrt{(x^{3})^{2} }[/tex]
[tex]6 * x^{3}[/tex]
Therefore, the simplified form is [tex]6x^{3}[/tex]
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Suppose you have a box with 3 blue marbles, 2 red marbles, and 4 yellow marbles. You are going to pull out one marble, record its color, remove it from the box and draw another marble. What is the probability of pulling out a red marble followed by a blue marble? The multiplication rule says to use P(red) P(blue).
Describe the probability of finding a red marble?
Describe the probability of finding a blue marble?
Describe the process of finding the probability of finding a red marble followed by a blue marble if the first marble was permanently removed?
What affect did removing the first marble from the box have on the problem?
Describe the probability of finding a red marble followed by the blue marble if the first marble is removed?
The probability of randomly getting first a red marble and then a blue marble is:
P = 0.083
How to find the probability?
There are:
3 blue marbles2 red marbles4 yellow marbles.For a total of 9 marbles.
The probability of getting a red marble is equal to the quotient between the number of red marbles and the total, so:
P(red) = 2/9
Then the probability of getting a blue marble is equal to the quotient between the number of blue marbles and the total, but because we already took one marble, now the total is 8.
P(blue) = 3/8
The joint probability is given by the product:
P = (2/9)*(3/8) = 0.083
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help please much appreciated if you attempt to help
196 36 correct answer is 232
Answer:
728 cm²
Step-by-step explanation:
the surface area is the area of the 6 faces.
the opposite rectangular faces are congruent , then
SA = front/ back + sides + top/ bottom
= 2(14 × 14) + 2(6 × 14) + 2(14 × 6)
= 2 × 196 + 2 × 84 + 2 × 84
= 392 + 168 + 168
= 728 cm²
What is the area of the trapezoid above?
A. 188 cm²
B. 196 cm²
C. 392 cm²
D. 5,236 cm²
Answer:
B. 196cm²Step-by-step explanation:
Area = h/2 (b_1+b_2)
[tex]\sf\cfrac{7}{2}\:(22+34)[/tex]
Add 22 and 34 = 56
[tex]\sf \cfrac{7}{2} \times 56[/tex]
Let's express 7/2 * 56 as a single fraction:-
[tex]\sf \cfrac{7\times 56}{2}[/tex]
Multiply 7 and 56 = 392
[tex]\sf \cfrac{392}{2}[/tex]
Divide
[tex]\sf 196[/tex]
Therefore, the area of the trapezoid is 196cm².
_______________________
7 cm
D
What is the sum of the areas of circle C and circle D?
O7ft units²
O 14 units²
O 49 units²
O98 units²
The sum of areas of circle C and circle D exists 98 square units.
How to estimate the sum of the areas of circle C and circle D?Given: Radius of circle = 7 units
Area of circle [tex]=\pi r^2[/tex] ..............(1)
Where, r be the radius of circle
The radius of circle C, r = 7 units
(1) becomes
Area of circle, C [tex]= \pi 7^2[/tex] square units
[tex]= 49\pi[/tex] units²
Area of circle, D [tex]= \pi 7^2[/tex] square units
[tex]= 49\pi[/tex] units²
Sum of areas of circles C and D,
= Area of circle C + Area of circle D
= 49 + 49
= 98 units²
The sum of areas of circles C and D exist 98 units².
Therefore, the correct answer is option d) 98 units².
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4(3) / 4(8) +.9(7.8 x 7.45)
The value is 52. 674
How to determine the valueWe have;
4(3) / 4(8) +.9(7.8 x 7.45)
From BODMAS, we have that we must must open up the bracket
= [tex]\frac{12}{32} + 0. 9 (58. 11)[/tex]
Divide the fraction to get decimals
= [tex]0. 375 + 52. 299[/tex]
Add the decimals
= [tex]52. 674[/tex]
Thus, the value is 52. 674
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Five guys walk into a bar, how many ways can they sit so as to be arranged from oldest to youngest?
There are 24 ways in which 5 guys can sit if arranged from oldest to youngest.
We have,
Five guys.
Now,
We know that,
Total number of ways to arranged around a table (n) = (n-1)!
So,
For n = 5,
I.e.
(n - 1)! = (5 - 1)! = 4!
So,
Total number of ways to arranged Five guys rom oldest to youngest (n) = (n-1)!
i.e.
= (5 - 1)! = 4!
We get,
= 4 × 3 × 2 × 1
i.e.
Total number of ways to arranged Five guys rom oldest to youngest (n) = 24.
Hence we can say that there are 24 ways in which 5 guys can sit if arranged from oldest to youngest.
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Billy goes on the teacup ride at the local carnival. He is seated 16 inches from the center of his teacup, which is spinning at a rate of 4 revolutions per minute. What is Billy’s angular velocity, in radians per second? Round your answer to the nearest hundredth.
Answer:
0.42
Step-by-step explanation:
Freddie has 2 times as many comic books as David. The ratio of the number of comic books David has to the number of comic books Gary has is 5 : 3. Freddie has 110 comic books. How many comic books do David and Gary have in total?
Answer:
88
Step-by-step explanation: make me brainliest if it is correct
Which expresses the correct factorization
of….? look at pic
Answer:
Option 1
Step-by-step explanation:
Find 2 numbers that multiply to give 16 and sum to give +8 :
These numbers are 4 and 4
Now split +8x into +4x and +4x and factor each part :
x²+4x+4x+16 = 0
x(x+4)+4(x+4) = 0
Keep 1 bracket and the terms outside the brackets make their own :
(x+4)(x+4) = 0
(x+4)² = 0
Therefore answer will be Option 1
Hope this helped and have a good day
You want to prove that FHG is similar to RXS by the SSS Similarity Theorem. Complete the proportion that is needed to use this theorem.
Answer:
[tex]\frac{FH}{RX} =\frac{HG}{XS} =\frac{FG}{RS}[/tex]
Step-by-step explanation:
The order of the letters matters in any similarity theorem.
When triangle FHG is similar to triangle RXS, the lengths of FH must be similar to RX.
When 2 similar lines are divided, that number is the factor by which one triangle can be dilated to match the other.
That being said, each of these proportion statements can be read as individual division expressions that equal the next division expression.
This means [tex]FH\div RX = HG\div XS = FG\div RS[/tex].
If you look at it this way, you can see that the sides you need to fill in must be the corresponding similar sides, so that you end up with the factor for the dilation of the 2 triangles.
Can someone help me out on these 2 geometry questions pls? ASAP!!!
Write formal proofs using the HL Theorem
Question 2
1) [tex]\overline{PR} \perp\overline{QS}, \overline{PQ} \cong \overline{PS}[/tex] (given)
2) [tex]\overline{PR} \cong \overline{PR}[/tex] (reflexive property)
3) [tex]\angle PRQ, \angle PRS[/tex] are right angles (perpendicular lines form right angles)
4) [tex]\triangle PRQ, \triangle PRS[/tex] are right triangles (a triangle with a right angle is a right triangle)
5) [tex]\triangle PRQ \cong \triangle PRS[/tex] (HL)
Question 3
1) [tex]\angle C[/tex] is a right angle, [tex]\overline{AC} \cong \overline{AE}, \overline{DE} \perp \overline{AB}[/tex] (given)
2) [tex]\angle DEA[/tex] is a right angle (perpendicular lines form right angles)
3) [tex]\triangle ACD, \triangle DAE[/tex] are right triangles (a triangle with a right triangle is a right angle)
4) [tex]\overline{AD} \cong \overline{AD}[/tex] (reflexive property)
5) [tex]\triangle ACD \cong \triangle AED[/tex] (HL)
6) [tex]\angle CAD \cong \angle DAE[/tex] (CPCTC)
7) [tex]\overline{AD}[/tex] bisects [tex]\angle BAC[/tex] (if a segment splits an angle into two congruent parts, it is an angle bisector)