Use the discriminant to determine the number of real solutions to the quadratic equation.
6a2−11a+9=0
What is the number of real solutions?
Select the correct answer below:
0

1

2

Answer:

18.75 percent

Step-by-step explanation:

150 / 800 x 100 = 18.75

Answer:

there shouldnt be an answer, they are not like terms, for a proper answer it would have to be like terms, for example:

x^2+x^2=2x^2

or

w^12+w^12=2w^12

they need to have the same exponent for addition to happen

The value of x using the alternate exterior angle theorem is 82°

An equation is an expression that shows the relationship between two or more numbers and variables.

An angle is formed from the intersection of two or more lines. Types of angles are acute, obtuse and scalene.

From the diagram:

x = 82° (alternate exterior angles)

The value of x using the alternate exterior angle theorem is 82°

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The quantity of product that would result in the same profit is 1 thousand. Option A

Given the polynomial function as;

P(t) = –2t³ + 8t² + 2t

Where;

Let's equate the values

–2t³ + 8t² + 2t = 8

–2t³ + 8t² + 2t - 8 = 0

Factorize the expression

(-2t³ + 8t²) + ( 2t -8) = 0

- t² ( 2t - 8) + (2t -8) = 0

We take the similar factor

2t - 8 = 0

2t = 8

t = 8/2

t = 4

But we have that the company produced 4 thousand products for $8 million profit, so we have

= 4/ 4

= 1 thousand

Thus, the quantity of product that would result in the same profit is 1 thousand. Option A

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based on the given results, the coefficient of variation can be found to be 45.54.

first, find the mean:
= (30 + 60 + 90 + 45) / 4

= 56.25

find the standard deviation using a spreadsheet:

= 25.61737691

the coefficient of variation is therefore:

= standard deviation / mean x 100

= 25.61737691 / 56.25 x 100

= 45.54

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The area of the shaded part is 52 sq. inches. The correct option is b. 52 sq. inches

From the question, we are to determine the area of the shaded part

In the given diagram, the shaded part is a rectangle

Area of a rectangle = Length × Width

Length of the shaded part = 18 inches - 4 inches - 1 inch = 13 inches

Width of the shaded part = 6 inches - 2inches = 4 inches

Then,

Area of the shaded part = 13 inches × 4 inches

Area of the shaded part = 52 sq. inches

Hence, the area of the shaded part is 52 sq. inches. The correct option is b. 52 sq. inches

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The ways to illustrate the shapes are given.

11.  In each new figure, one vertex is introduced, and each vertex is joined to each other vertex.

12.  In each new figure, 2 rows and 1 column are introduced, and the shading at the corner moves 90 degrees clockwise.

13.  In each new figure, one row and one column are introduced, and exactly half of the rectangles are shaded.

14.  In each new figure, except at the bottom vertex, two perpendicular lines are introduced at the remaining vertices.

15.  In each new figure, one inverted white triangle is inscribed in the orange triangle.

16.  The number of squares increases in the pattern. There are blue circles inscribed in one diagonal square and there are yellow circles inscribed in the remaining squares. Also, the blue circles in the diagonal alternate.

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8. The length of the support is 7. 9 m

9. The length of the conveyer is 12m

3. a = 59m

A = 44°

B = 52°

4. c = 88. 6 mm

b = 49. 1 m

B = 34°

8. We have the angle to be 20 degrees

Opposite side = x

hypotenuse = 23m

Using the sine ratio

sin θ = opposite/ hypotenuse

[tex]sin 20 = \frac{x}{23}[/tex]

Cross multiply

[tex]sin 20[/tex] × [tex]23 = x[/tex]

[tex]x = 0. 3420[/tex] × [tex]23[/tex]

x = 7. 9 m

The length of the support is 7. 9 m

9. The angle of elevation is 37. 3 degrees

Hypotenuse = 19 . 0m

Opposite = x

Using the sine ratio

sin θ = opposite/ hypotenuse

[tex]sin 37. 3 = \frac{x}{19}[/tex]

cross multiply

[tex]x = 0. 6059[/tex] × [tex]19[/tex]

x = 11.5

x = 12 m in 2 significant figures

The length of the conveyer is 12m

3. To determine the sides and angles, we use the sine rule;

[tex]\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}[/tex]

For side a, we use the Pythagorean theorem

[tex]c^2 = a^2 + b^2[/tex]

[tex]85^2 = a^2 + 67^2[/tex]

[tex]a = \sqrt{89^2-67^2}[/tex]

[tex]a = \sqrt{3432}[/tex]

a = 58. 58, a = 59m

To find angle A and B, use the sine rule

[tex]\frac{59}{sin A } = \frac{85}{sin 90}[/tex]

cross multiply

[tex]sin A[/tex] × [tex]85[/tex] = [tex]sin 90[/tex] × [tex]59[/tex]

make sin A subject of formula

[tex]sin A = \frac{59}{85}[/tex]

[tex]sin A = 0. 6941[/tex]

A = [tex]sin^-^1(0. 6941)[/tex]

A = 44°

[tex]\frac{67}{sin B} = \frac{85}{sin 90}[/tex]

cross multiply

[tex]sin B[/tex] × [tex]85[/tex] = [tex]sin 90[/tex] × [tex]67[/tex]

make sin b subject of formula

[tex]sin B = \frac{67}{85}[/tex]

[tex]sin B = 0. 7882[/tex]

B = [tex]sin^-^1( 0. 7882)[/tex]

B = 52°

4. To find the sides, we use the sine rule;

[tex]\frac{74. 0}{sin 56. 6} = \frac{c}{sin 90}[/tex]

Cross multiply

[tex]sin 56. 6[/tex] × [tex]c = sin 90[/tex] × [tex]74[/tex]

make 'c' subject of formula

[tex]c = \frac{74}{0. 8348}[/tex]

c = 88. 6 mm

To find length b, we use the Pythagorean theorem

[tex]c^2 = a^2 + b^2[/tex]

[tex]b^2 = c^2 - a^2[/tex]

[tex]b^2 = 88. 8^2 - 74^2[/tex]

[tex]b = \sqrt{7885. 44 - 5476}\\\\ b = \sqrt{2409. 44}[/tex]

b = 49. 1 m

[tex]\frac{74. 0}{sin 56. 6} = \frac{49. 1}{sin B}[/tex]

cross multiply

[tex]sin B = \frac{40. 99}{74. 0}[/tex]

B = [tex]sin^-^1(0. 5539)[/tex]

B = 34°

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Answer:

$42,600

Step-by-step explanation:

284000 x .15

The number of square feet of carpet needed for the rooms is 889 ft².

The total square footage of your house is 1200 square feet.

He wants to put new carpet in all rooms except for  the kitchen, dining room and bathroom.

Therefore,

total area = 1200 ft²

Area of the other rooms with no carpet  = (10 × 12) + (11 × 13) + (6 × 8)

Area of the other rooms with no carpet  = 120 + 143 + 48

Area of the other rooms with no carpet  = 311 ft²

Hence, the number of square feet for the house = 1200 - 311 = 889 ft²

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It is possible to arrange the total of mangoes by using 20 piles of 9 mangoes, 18 piles of 10 mangoes, or 15 piles of 12 mangoes.

The conditions for mangoes to be arranged are that the piles should have either 9, 10 or 12 mangoes and reminders are not allowed. This means you need to fit all the mangoes and no mangoes can be left.

Based on the conditions and the total number of mangoes (180 mangoes), here are the possibilities that you can determine using division:

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a)

b) Conditions:[tex]\sigma[/tex] is understood to have a regular distribution of weights

c) Interpretation: 80 percent of the time, this range will include the actual average weight of Allen's hummingbirds, hence its reliability may be counted on

d) sample size [tex]n \approx 27[/tex].

Generally,
Here n = 17

T= 3.15

[tex]\sigma=0.40[/tex]

confidence level =c = 0.80

Here we will usethe  z critical value.

z critical value for (1+c) /2 = (1+0.80)/2

z critical value for (1+c) /2= 0.9

Zc = 1.28

Critical value = 1.28

a) Margin of error (E) :

[tex]E = Zc*\frac{\sigma}{\sqrt{n}}\\\\\E = 1.28*\frac{0.40}{\sqrt{17}}[/tex]

E =0.124

Margin of error = E =0.124

Lower limit = x-E

L= 3.15 - 0.124

L= 3.026

Lower limit =3.026

Upper limit = x + E

U= 3.15 + 0.124

U= 3.274

Upper limit =  3.274

The following is a confidence interval with a value of 80 percent for the mean weights of Allen's hummingbirds in the area under study: (3.02,3.28)

b) Conditions:[tex]\sigma[/tex] is understood to have a regular distribution of weights

c) Interpretation: 80 percent of the time, this range will include the actual average weight of Allen's hummingbirds, hence its reliability may be counted on.

d) When is already known, the following equation may be used to determine the appropriate number of samples, n:

[tex]n=(\frac{z_c*\sigma }{E})^2[/tex]

Margin of error = 0.13

Sample size (n):

[tex]n= (\frac{z_c*\sigma }{E})^2[/tex]

[tex]n=(\frac{ 1.28*0.36}{0.09})^2[/tex]

n = 26.21

[tex]n \approx 27[/tex]

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it would take Janis 14 minutes to complete a package alone

From the information given,

Let's say that

Carol working time = x = 30 minutes

Janis working time = y

x + y = 16 minutes

Let's make 'y' the subject

30 - 16 = y

y= 14 minutes

Thus, it would take Janis 14 minutes to complete a package alone

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Answer:

1±2i.

Step-by-step explanation:

1. if to evaluate the expression given, it can be written

(x-5)(x²-2x+5)=0;

2. where the nonreal roots are 1±2i.

Answer: The graph of f(x) is horizontally stretched

Answer: 23 inches by 7 inches

Step-by-step explanation:

161 = 7 x 23 (or 1 x 161 but that doesn't help...)

And to check:

7 x 3 + 2 = 23

Answer:

23inches by 7inches

Step-by-step explanation:

7 ×3+2=23

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Information : The given ellipse is a horizontal ellipse, and it's centre lies on origin, as the foci are given on x - axis.

The foci of the ellipse can be written in form :

[tex]\qquad \sf  \dashrightarrow \: ( \pm ae , 0)[/tex]

So,

[tex]\qquad \sf  \dashrightarrow \: ae = 5[/tex]

and Vertex of the ellipse can be written as

[tex]\qquad \sf  \dashrightarrow \: (\pm a,0)[/tex]

Now, plug the value in first equation ~

[tex]\qquad \sf  \dashrightarrow \: ae = 5[/tex]

[tex]\qquad \sf  \dashrightarrow \: 11e = 5[/tex]

[tex]\qquad \sf  \dashrightarrow \: e = \cfrac{5}{11} [/tex]

Now, we have to find b (length of semi minor axis)

we can use the formula ~

[tex]\qquad \sf  \dashrightarrow \: b {}^{2} = {a}^{2} (1 - {e}^{2} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: b {}^{2} = 121(1 - \frac{25}{121} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: b {}^{2} = 121( \frac{121 - 25}{121} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: b {}^{2} = 96[/tex]

Now, we can write the equation of ellipse as :

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {x}^{2} }{ {a}^{2} } + \cfrac{ {y}^{2} }{ {b}^{2} } = 1[/tex]

[ plug the values ]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {x}^{2} }{ {121}^{} } + \cfrac{ {y}^{2} }{ {96}^{} } = 1[/tex]

Answer:

[tex]\dfrac{x^2}{121}+\dfrac{y^2}{96}=1[/tex]

Step-by-step explanation:

General equation of an ellipse:

[tex]\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1[/tex]

where:

If a > b the ellipse is horizontal, a is the major radius, and b is the minor radius.

If b > a the ellipse is vertical, b is the major radius, and a is the minor radius.

Given:

Therefore, the ellipse is horizontal with its center at (0, 0):

⇒ h = 0 and k = 0

⇒ a = 11

⇒ c = 5

To find b², use  c² = a² − b²:

⇒ 5² = 11² − b²

⇒ b² = 11² − 5²

⇒ b² = 96

Therefore, the standard form of the equation of the ellipse is:

[tex]\implies \dfrac{(x-0)^2}{11^2}+\dfrac{(y-0)^2}{96}=1[/tex]

[tex]\implies \dfrac{x^2}{121}+\dfrac{y^2}{96}=1[/tex]

Answer:

about 19.31 years

Step-by-step explanation:

[tex]10000( {1.11}^{x} ) = 75000[/tex]

[tex] {1.11}^{x} = 7.5[/tex]

[tex]x ln(1.11) = ln(7.5) [/tex]

[tex]x = \frac{ ln(7.5) }{ ln(1.11) } = 19.31[/tex]

A logarithmic function is the inverse of an exponential function.

A logarithmic function is the inverse of an exponential function.

Now we have the function;

f(x) = log(x) and the translated function f(x) = log (x-h) + k.

Similarly;

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Missing parts;

Use the graphing calculator to graph the parent function.

f(x) = log(x)

Add the translated function.

f(x) = log (x-h) + k

Plug in different values of h and k to answer the following questions.

What happens when h is positive?

What happens when h is negative?

What happens when k is positive?

What happens when k is negative?

Answer:

When h is positive: horizontal shift to the right

When h is negative: horizontal shift to the left

When k is positive: vertical shift up

When k is negative: vertical shift down

Step-by-step explanation:

got it right on Edge

30 Jagged rocks are the same 3 shiny rocks using the exchange rates provided(i.e. option D)

What is an exchange rate?

Exchange rate means the rate at which one item exchanges hands with another, for instance, in this case, 6 jagged rocks are equivalent to 2 smooth pebbles.

6 jagged rocks=2 smooth pebbles

divide both sides by 2

6/2 jagged rocks=2/2 smooth pebbles

3 jagged rocks=1 smooth pebble

We can rewrite as below:

1 jagged rock=1/3 smooth pebble

30jagged rocks=1/3*30 smooth pebbles

30 jagged rocks=10 smooth pebbles

Now we need to convert 10 smooth pebbles to shiny rock equivalence

3 smooth pebbles=1 shiny rock

1 smooth pebble=1/3 shiny rock

10 smooth pebbles=1/3*10 shiny rocks

10 smooth pebbles=3 shiny rocks( even though it is 3.33, but the final answer should be rounded to a whole number)

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The volume of the glasses is as follows;

The volume of cylinder glass 1 = πr²h

The volume of cylinder glass 1 = 3.14 × 3² × 6

The volume of cylinder glass 1 = 3.14 × 9 × 6

The volume of cylinder glass 1 = 169.56 cm³ = 170 cm³

The volume of the glass 2 = 2 / 3 π r³ + πr²h

The volume of the glass 2 = 2 / 3 × 3.14 × 3³ + 3.14 × 3² × 3

The volume of the glass 2 = 56.52 + 84.78

The volume of the glass 2 = 141.3 cm³ = 141 cm³

The volume of conical glass 3 = 1 / 3 πr²h

The volume of conical glass 3 = 1 / 3 × 3.14 × 3² × (√7² - 3² = √40)

The volume of conical glass 3 = 9.42 × √40

The volume of conical glass 3 = 59.5773111176

The volume of conical glass 3 = 60 cm³

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The solution to the given system of equation is (3, 3, 3)

Given the following system of equation expressed as:

2x-y+5z=16

X-6у +2z=-9

3x+4y- z=32

Multiply equation 2 by 2 to have:

2x-y+5z=16

2X-12у +4z=-18

Subtract

10y+z = 34 .........4

Similarly

3X-18у +6z=-27

3x+4y- z=32

Subtract

-22y+7z = -59 ........... 5

Equate 4 and 5

10y+z = 34 .........4 * 7

-22y+7z = -59 ........... 5 * 1

_______________________

70y+7z = 238

-22y+7z = -59

Subtract

92y = 297

y = 3

Recall that

10y+z = 34

10(3) + z = 34

z = 3

Since x - 6y +2z = -9

x-6(3)+2(3) = -9
x - 18 + 6 = -9
x = 3

Hence the solution to the given system of equation is (3, 3, 3)

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The boat in discuss is 9.03 miles from lighthouse B.

The distance of the boat from lighthouse B as required can be determined by means of the cosine law in which case we have;

c² = 10² + 6² - (2×6×10Cos 63)

c = 81.52

c = 9.03miles.

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Answer:

C) The volume of the prism is equal to the volume of the cylinder.

Step-by-step explanation:

volume of triangular prism = area of base × height

volume of cylinder = area of base × height

The cross sectional area are equal, so the bases have the same area.

The heights are also equal.

The volumes must be equal.

Answer: C) The volume of the prism is equal to the volume of the cylinder.

Answer:

C) The volume of the prism is equal to the volume of the cylinder.

Step-by-step explanation:

If the cross-sectional areas of the triangular prism and the right cylinder are congruent, it means that when you look at their shapes from the top or bottom, they have the same size and shape.

Since both the triangular prism and the right cylinder have a height of 5 units, and their cross-sectional areas are the same, it implies that they have the same volume as well. So, the volume of the triangular prism is equal to the volume of the cylinder.

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Answer: D. slides the graph 1 unit right

Step-by-step explanation:

See attached image.

Answer:

The answer is choice C from the given alternatives.