What does a nonpolar covalent bond show about the electronegativities of its
two atoms?
A. The electronegativity of both of the atoms is zero.
B. The electronegativities of the two atoms are equal.
O c. The difference in electronegativities of the two atoms is very
small.
O D. The difference in electronegativities is greater than 1.7.

Answers

Answer 1

Answer:

B. The electronegativities of the two atoms are equal.


Related Questions

Which diagram is the correct electron dot diagram for magnesium?



A.
A symbol of magnesium M g has four dots representing four free electrons.

B.
A symbol of magnesium M g has three dots representing three free electrons.

C.
A symbol of magnesium M g has one dot representing one free electron.

D.
A symbol of magnesium M g has two dots representing two free electrons.

Answers

Answer:

D.) A symbol of magnesium Mg has two dots representing two free electrons.

Explanation:

Magnesium is located in the second group (column) of the periodic table. Elements located here have 2 valence electrons in their outermost shell. Thus, the electron dot diagram of magnesium has 2 dots symbolizing the 2 valence electrons.

a student carried out a combustion reaction with methane (ch4) as the limiting reagent. a 12.0g quantity of methane was used, and the student collected 22.0g of carbon dioxide. what was the percent yield

Answers

The total percent yield:

After the combustion reaction with methane, the percent yield was 66.7%.  

Combustion of Methane:

Methane produces a blue flame as it burns in the atmosphere.Methane burns in the presence of enough oxygen to produce carbon dioxide (CO₂) and water (H₂O). It creates a significant quantity of heat during combustion, making it an excellent fuel source.

The other reactant, air's excess oxygen, is always present, making methane the limiting reactant. As a result, the amount of CH₄ burned will determine how much CO₂ and H₂O are produced.

The following chemical process produces carbon dioxide from methane:

CH₄ + 2O₂ ⇒ CO₂ + 2H₂O

Calculations:

1. Theoretical quantity of carbon dioxide:

All calculations will be based on the amount of methane because the problem specifies that it is the limiting reagent:

12.0g of CH₄ × (1 mol of CH₄/16g CH₄) × (1 mole of CO₂/1 mole of CH₄) × (44g CO₂/1 mole of CO₂)

= 33g of CO₂

2. Percent yield:

= Actual yield/Theoretical yield × 100

= 22.0g/33g × 100

= 66.7%

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Organic molecules (amino acids) needed to be concentrated to stimulate reactions to form proteins concentration mechanisms do not include:___.

Answers

Organic molecules (amino acids) needed to be concentrated to stimulate reactions to form protein concentration mechanisms that do not include Boiling.

Amino acids are natural compounds composed particularly of nitrogen, carbon, hydrogen, and oxygen. Your body desires 20 awesome amino acids to grow and function. amino acid, any of a group of organic molecules that consist of a basic amino group (―NH2), an acidic carboxyl group (―COOH).

fruits have an excessive content of amino acid that allows modify insulin degrees. fruits like bananas, apples, berries, and so forth., are rich resources of amino acids.

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Which of the following results in an increase in the entropy? (4 points)
Freezing water
Cooling a solid
Condensing water vapor
Dissolving sugar in water

Answers

Dissolving sugar in water results in an increase in the entropy.

Hence, Option (D) is correct answer.

What is Entropy ?

Measurement of randomness of a system is called entropy. It is an extensive property. It is a state function. Unit of entropy is JK⁻¹ mol⁻¹.

Now lets check all options one by one

Option (A): Freezing water

Freezing water decreases the entropy because here second law of thermodynamics does not violate.

So it is incorrect option

Option (B): Cooling water

Cooling water does not increases entropy because entropy increases when solid melts to give liquid.

So it is incorrect option

Option (C): Condensing water vapour

In Condensing water vapour the temperature of liquid phase decreases and thus kinetic energy decreases. The randomness will decrease and hence entropy will also decrease.

So it is incorrect option.

Option (D): Dissolving sugar in solute

In dissolving sugar in solute the solid dissociates to ions and  the randomness will increase and hence entropy will also increase.

So it is correct option

Thus from the above conclusion we can say that Dissolving sugar in water results in an increase in the entropy.

Hence, Option (D) is correct answer.

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A cabbage p h indicator color key. entries are 0 to 2, bright red; 3 to 4, pink; 5 to 6, purple; 7, dark violet; 8 to 9, blue; 10 to 11, bright green; 12 to 13, lighter green. why would you use a solution, such as a cabbage ph indicator, to measure the ph of household items? to see if food went bad to test the safety of water to make sure conditions are safe to use up old cabbage

Answers

We use a solution, such as a cabbage ph indicator, to measure the ph of household items :

to see if food went badto test the safety of waterto make sure conditions are safe

Cabbage ph indicator:

Anthocyanin, a water-soluble pigment found in red cabbage, can change color when combined with an acid or a basic. The color changes to red in situations with a pH under 7, and to bluish-green in alkaline (basic) environments with a pH above 7. Cabbage isn't known to cause acid reflux, but plenty of other common foods are.

Anthocyanin turns pink when it interacts with the hydronium ions in an acid, and blue or green when it interacts with the hydroxide ions in a base. Because it may inform us if a substance is acidic or basic by changing color, cabbage juice is referred to as a pH indicator.

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A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively. What is the partial pressure in torr of the carbon dioxide in the mixture

Answers

A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively.  27.1 torr is the partial pressure of the carbon dioxide in the mixture.

What is Dalton's Law of Partial Pressure ?

Dalton's Law of partial pressure states that the total pressure exerted by non reacting gaseous mixture at a constant temperature and given volume is equal to the sum of partial pressure of all gases.

It is expressed as:

[tex]P_{A} = X_{A} P_{T}[/tex]

where,

[tex]P_{A}[/tex] = Partial pressure of gas A

[tex]X_{A}[/tex] = Mole fraction of gas A

[tex]P_{T}[/tex] = Total pressure

Mole Fraction of Nitrogen

= [tex]\frac{930}{930 + 850}[/tex]

= 0.52

Mole Fraction of Oxygen

= [tex]\frac{850}{850 + 930}[/tex]

= 0.47

Now,

Mole fraction of nitrogen + Mole fraction of oxygen + Mole fraction of carbon dioxide = 1

⇒ 0.52 + 0.47 + Mole fraction of carbon dioxide = 1

⇒ 0.99 + Mole fraction of carbon dioxide = 1

⇒ Mole fraction of carbon dioxide = 1 - 0.99

⇒ Mole fraction of carbon dioxide = 0.01

Now put the value in above expression we get

[tex]P_{A} = X_{A} P_{T}[/tex]

     = 0.01 × 2710

     = 27.1 torr

Thus from the above conclusion we can say that A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively.  27.1 torr is the partial pressure of the carbon dioxide in the mixture.

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With a good mask-to-face seal and an oxygen flow rate of 15 L/min, the nonrebreathing mask is capable of delivering up to ______% inspired oxygen.

Answers

With a good mask-to-face seal and an oxygen flow rate of 15 L/min, the nonrebreathing mask is capable of delivering up to  90% inspired oxygen.

What is fraction of inspired oxygen?

FiO2 is the fraction of inspired oxygen which is explained as the concentration of oxygen inhaled by a person.

Non breather mask:

It delivers a high concentration of oxygen. Hence the liter flow will be 8-15L/min with the percentage of oxygen between 60-90%.

The liter flow of nonbreathing mask must not be less than 8L/min.

From the above information we can conclude that the fraction of inspired oxygen for a nonbreathing mask is 90%

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The molecule CH₂O contains two single bonds and one double bond. True or false

Answers

Answer:

The answer to your question is True

Explanation:

CH2O is a polar molecule. It has three polar bonds that are arranged asymmetrically, thus allowing their dipole moments to add up and give the molecule an overall dipole moment. CH2O has a central carbon atom that forms two single bonds with the two hydrogen atoms and a double bond with the oxygen atom.

I hope this helps and have a good day!

Which law relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions?
Boyle’s law
Charles’s law
ideal gas law
combined gas law

Answers

The law that relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions is ideal gas law (option C).

What is ideal gas law?

Ideal gas law in physics refers to the equation of state of an ideal gas. The law equation is as follows:

PV = nRT

Where;

P = pressureV = volumen = number of molesT = temperatureR = gas law constant

Therefore, it can be said that the law that relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions is ideal gas law.

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Answer:

C. Ideal Gas Law

Explanation:

edge ;)

How many molecules of H₂O are
equivalent to 97.2 g H₂O?
(H = 1.008 g/mol, O = 16.00 g/mol)
[?]
[?]x10 molecules
Enter your answer with the correct number of
significant figures and be sure the prefix is a number
between 1 and 10!
dro's Number = 6.02 x 1023 molecules/mole

Answers

Answer:

3.25 x 10²⁴ molecules H₂O

Explanation:

To find the number of H₂O molecules, you need to (1) convert grams to moles (via molar mass) and then (2) convert moles to molecules (via Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the amount of sig figs in the given value.

Atomic Mass (H): 1.008 g/mol

Atomic Mass (O): 16.00 g/mol

Molar Mass (H₂O): 2(1.008 g/mol) + 16.00 g/mol

Molar Mass (H₂O): 18.016 g/mol

Avogadro's Number:

6.02 x 10²³ molecules = 1 mole

97.2 g H₂O            1 mole              6.02 x 10²³ molecules
------------------  x  -------------------  x  ------------------------------------  =
                              18.016 g                      1 mole

=  3.25 x 10²⁴ molecules H₂O

What type of molecule is shown below?
S
H-C=C-CH2-CH3
O A. An alkene-alkyne
OB. An alkane-alkyne
OC. An alkyne
O D. An alkane

Answers

H - C ≡ C - CH₂ - CH₃ this is an alkyne molecule.

Hence, Option C is correct answer.

What is Alkane ?

The saturated hydrocarbon which have only single bonds between the carbon atoms is called Alkanes.

What is Alkene ?

The unsaturated hydrocarbon which have at least one carbon carbon double bond is called Alkene.

What is Alkynes ?

The unsaturated hydrocarbon which have one or more than one carbon carbon triple bonds is called Alkynes.

H - C ≡ C - CH₂ - CH₃ in this molecule one triple bond is present so it is alkyne.

Thus from the above conclusion we can say that H - C ≡ C - CH₂ - CH₃ this is an alkyne molecule.

Hence, Option C is correct answer.

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For the calculating change in pH question, some of the volumes of acid required were very very small. The smallest volume that can be reasonably transferred with pipetteman is 2 microliters (2 x 106 liters) If the volume of acid that needs to be added is so small that there is no equipment available to measure and transfer the correct volume of acid, what could be done to successfully adjust the pH? a) Use a less concentrated acid to adjust the pH so the required volume would be larger b) Use a more concentrated acid to adjust the pH so the required volume would be larger c) Use a less concentrated acid to adjust the pH so the required volume would be smaller d) Use a more concentrated acid to adjust the pH so the required volume would be smaller

Answers

To successfully adjust the pH, as there was no equipment to measure and transfer the correct volume of acid, then A. Use a less concentrated acid to adjust the pH so the required volume would be larger.

What is an acid?

This is a substance that changes the taste in water solution and changes blue litmus paper to red, reacts with some metals to liberate hydrogen, reacts with bases to form salts, and promotes chemical reactions (acid catalysis).

Hence because there was no equipment available to measure and transfer the correct volume of acid, the best and safest and most successful thing to be done is to use a less concentrated acid to adjust the pH so the required volume would be larger.

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PLEASE HELP!
You are preparing standard acid and base solutions for the laboratory, using potassium hydrogen phthalate (KHC₈H₄O₄, abbreviated KHP) as the primary standard. KHP (molar mass = 204.22 g/mol) has one acidic hydrogen. You prepared solutions of both NaOH and HCl. It took 22.65 mL of the NaOH solution to titrate (react exactly with) 1.55 g KHP. It then took 25.35 mL of HCl solution to titrate 25.00 mL of the NaOH solution. What is the molarity of the HCl solution?

Answers

we will first calculate the concentration of sodium hydroxide, knowing the massive K hp. That was required to neutralize the 22.65 ml of sodium hydroxide solution. So the polarity sodium hydroxide will be take the massive K HP divided by its molar mass to get moles K HP. Then recognize one mol K HP reacted with one mole sodium hydroxide. Now we have mold sodium hydroxide to get concentration. We simply multiply by the leader volume of the sodium hydroxide solution. 22.65 ml is .02265 L. And we get a polarity of zero 0.3351 Molar sodium hydroxide. Now to calculate the concentration of hcl, we need to know the molds hcl divided by the volume of the hcl solution. To get the moles. Hcl will take the 25 ml of sodium hydroxide used in the tight rations converted to leaders. 25 ml is .02500 l multiply that by the concentration of sodium hydroxide that we just determined up here to get mold sodium hydroxide, then convert moles sodium hydroxide into molds. Hcl, recognizing it's a 1 to 1 molar relationship. Now that we have moles hcl, we just divide by the leaders of the hcl solution that was titrate, id 0.2. Sorry, 23.35 mL is 0.2335 liters. And we get a concentration of 0.3588 molar hcl. I hope that helps

(ii) Calculate the maximum mass of ethanol that could be obtained
g from 30.0 g of glucose.

Answers

Taking into account the reaction stoichiometry, 15.33 grams ethanol could be obtained from 30 grams of glucose.

Reaction stoichiometry

In first place, the balanced reaction is:

C₆H₁₂O₆  → 2 C₂H₅OH + 2 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

C₆H₁₂O₆: 1 mole  C₂H₅OH: 2 molesCO₂: 2 moles

The molar mass of the compounds is:

C₆H₁₂O₆: 180 g/moleC₂H₅OH: 46 g/moleCO₂: 44 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

C₆H₁₂O₆: 1 mole ×180 g/mole= 180 gramsC₂H₅OH: 2 moles ×46 g/mole= 92 gramsCO₂: 2 moles ×44 g/mole= 88 grams

Mass of C₂H₅OH formed

The following rule of three can be applied: if by reaction stoichiometry 180 grams of glucose form 92 grams of ethanol, 30 grams of glucose form how much mass of ethanol?

[tex]mass of ethanol=\frac{30 grams of glucosex 92 grams of ethanol}{180 grams of glucose}[/tex]

mass of ethanol= 15.33 grams

Then, 15.33 grams ethanol could be obtained from 30 grams of glucose.

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Calculate the pH of a buffer solution prepared by mixing 75.0 mL of 1.00 M lactic acid and 25.0 mL of 0.50 M sodium lactate.

Answers

From the calculations, the pH of the buffer is 3.1.

What is the pH of the buffer solution?

The  Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;

pH = pKa + log[(salt/acid]

Amount of the salt = 25/1000 *  0.50 M = 0.0125 moles

Amount of the acid = 75/1000 *  1.00 M = 0.075 moles

Total volume = ( 25 + 75)/1000 = 0.1 L

Molarity of salt = 0.0125 moles/0.1 L = 0.125 M

Molarity of the acid = 0.075 moles/0.1 L = 0.75 M

Given that the pKa of lactic acid is 3.86

pH = 3.86 + log( 0.125/0.75)

pH = 3.1

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What component of NADH is a vitamin, and how does this part of the cofactor function in oxidation-reduction reactions

Answers

The Part of Nicotinamide Adenine Dinucleotide NADH that is a vitamin is niacin, a type of B vitamin.

This cofactor acts as a hydrogen acceptor in oxidation-reduction reactions.

What Is NADH?

NADH  is the reduced form of the NAD+, which means that it gains the electron lost by NAD+. NADH is a very important coenzyme central to metabolism.

   NADH is a dinucloetide because it consists of two nucleotides joined through their phosphate groups.

 

 One nucleotide contains an adenine nucleobase and the other nicotinamide.

What Is a Cofactor?

A cofactor is a non-protein chemical compound or metallic ion that is required for an enzyme's role as a catalyst in a chemical reaction. A cofactor binds to an enzyme to bring about its  catalytic reaction.

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what causes a wavy pattern of dark and light bands on the bottom of a pond? A P E X learning

Answers

A wavy pattern of dark and light bands on the bottom of a pond is caused by refraction of light waves through a rough surface; option D.

What is destructive interference?

Destructive interference occur when two waves come in contact with each other and cancel each other out.

Reflection and refraction of light waves can result in destructive interference. An example of destructive interference due to refraction of light is a wavy pattern of dark and light bands on the bottom of a pond.

In conclusion, destructive interference occurs when waves cancel each other out.

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The answer to the question is D.

The heat of combustion for the combustion of propane, c3h8 5o2 3co2 4h2o , is equal to -2,200 kj. this is an example of a(n) _________ reaction.

Answers

Answer:

This is an example of an exothermic reaction.

Explanation:

When the heat of combustion is negative, the reaction is exothermic. This means the reaction releases heat as a product.

Calculate the molar mass of powdered fruit drink mix, made from sucrose (c12h22o11). appreciate it.

Answers

molar mass of sucrose is 342 g/mol.

Concept:

It is the substance's molecular mass. M is the abbreviation for it, and g/mol is the standard unit for measuring molar mass.

Given:

Sucrose (C12H22O11)

Find:

Calculate the molar mass of the powdered fruit drink mix, made from sucrose (C12H22O11).

Solution:

The molar mass of carbon = 12 g/mol

The molar mass of hydrogen = 1 g/mol

The molar mass of oxygen = 16 g/mol

Thus, the molar mass of sucrose can be calculated as:

C12H22O11 12 C + 22 H + 11 O

= 12 12 g/mol + 22 * 1 g/mol + 11 * 16 g/mol

= 144 g/mol + 22 g/mol + 176 g/mol = 342 g/mol

Therefore, the molar mass of sucrose is 342 g/mol.

Hence, the molar mass of the powdered fruit drink mix, made from sucrose

Hence, the molar mass of the powdered fruit drink mix, made from sucrose(C12H22O11) is 342 g/mol.

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Other than reducing greenhouse gas emissions, why would an entity switch to an alternative energy solution

Answers

Answer:

renewable energy sources such as solar and wind DONT emit carbon dioxide and other greenhouse gases that contribute to global warming

Explanation:

50.) a 26 m tall statue of buddha in tibet is covered with 279 kg of gold. if the gold
was applied to a thickness of 0.0015 mm, what surface area (in square units) was
covered? [gold's density is 19,320 kg/m?]

Answers

The surface area of the statute covered with the gold is 9,627.32 m².

What is Volume?

Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.

Volume of the statute covered with gold

The volume of the statute covered with gold is calculated as follows;

Volume = mass/density

Volume = (279 kg) / (19,320 kg/m³)

Volume = 0.0144 m³

Surface area of the statute covered with gold

The surface area of a solid object is a measure of the total area that the surface of the object occupies.

V = S.A x h

where;

S.A is surface areah is thickness

S.A = V/h

S.A = (0.0144) / (0.0015 x 10⁻³)

S.A = 9,627.32 m²

Thus, the surface area of the statute covered with the gold is 9,627.32 m².

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If sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose. A solution of sucrose at room temperature does not readily decompose to form a solution of simple sugars because

Answers

The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose because the activation energy of the reaction is high.

Hence, Option (B) is correct answer.

What is Activation Energy ?

The minimum amount of energy that must be provided by a reacting molecules to get converted into the product is called Activation energy.

It is expressed as:

[tex]k = Ae^{\frac{-E_a}{RT}}[/tex]

where,

k = rate constant

A = pre-exponential factor

Eₐ = activation energy

R = universal gas constant

T = absolute temperature in K

Thus from the above conclusion we can say that The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose because the activation energy of the reaction is high.

Hence, Option (B) is correct answer.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose. Why?

A. The change in free energy of the reaction is positive.

B. The activation energy of the reaction is high.

C. The change in free energy of the reaction is negative.

D. This is a hydrolysis reaction, so it requires an input of energy.

E. The free energy of the products is higher than the free energy of the reactants.

What is the molar solubility of AgCl in a 0.050 M NaCl solution? The Ksp of AgCl is 1.6 x 10-10. (Assume that the contribution of [Cl-] from AgCl is negligible relative to the [Cl-] from NaCl)

Answers

The molar solubility of AgCl:

The molar solubility of AgCl in a 0.050 M NaCl solution is 8 x [tex]10^{-8}[/tex] M [tex]Ag^{+}[/tex]

What is solubility?

The solubility is the quantity of reagent required to saturate the solution or bring about the dissociation reaction's equilibrium.

Reaction:

The dissociation reaction of AgCl in water is:

[tex]AgCl[/tex]  ⇄ [tex]Ag^{+} + Cl^{-}[/tex]

Each mole of AgCl that dissolves in this reaction yields 1 mole of both [tex]Ag^{+}[/tex] and  [tex]Cl^{-}[/tex]. The concentration of either the Ag or Cl ions would then be equal to the solubility.

Solubility= [[tex]Ag^{+}[/tex]] = [[tex]Cl^{-}[/tex]]

Calculation:

in 0.050 M NaCl, the [[tex]Cl^{-}[/tex]] = 1 x [tex]10^{-2}[/tex]

ksp = [[tex]Ag^{+}[/tex]] x [[tex]Cl^{-}[/tex]]

1.6 x [tex]10^{-10}[/tex] = [[tex]Ag{+}[/tex]] x ( 5 x [tex]10^{-2}[/tex])

[[tex]Ag^{+}[/tex]] = 5 x [tex]10^{+2}[/tex] x 1.6 x [tex]10^{-10}[/tex]

[[tex]Ag^{+}[/tex]] = 5 x 1.6 x [tex]10^{-10+2}[/tex]

[[tex]Ag^{+}[/tex]] = 8 x [tex]10^{-8}[/tex] M

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The correct placement of the coefficient in a chemical equation is...
Select one:
a. within the formula of a reactant or product.
O b. in front of the formula of a reactant or product.
O c. in front of the chemical equation.
O d. after the formula of a reactant or product.

Answers

Answer:

B.)  in front of the formula of a reactant or product.

Explanation:

Coefficients modify the amount of a particular molecule. As such, they are placed directly in front of the molecule's formula.

how many moles are in 2.00g of H2O​

Answers

n = m/M = 2/18 = 1/9 ~0,1 mol

Answer:

.111 mole    (using 3 significant digits)

Explanation:

Mole weight of H2O  = 2 x 1.008  + 15.999 = 18.015 gm/mole

2 gm / 18.015 gm/mole = .111 mole

3H2 + blank, reaction arrow, 2NH3
How to complete this equation so that it is a Synthesis reaction

Answers

The reaction is completed by the equation below: [tex]3H_2 + N_2 --- > 2NH_3[/tex]

What are synthesis reactions?

They are chemical reactions in which two or more molecules react to produce a single product.

In this case, the synthesis reaction is that of ammonia. Molecules of hydrogen gas and nitrogen gas combine to produce ammonia.

The equation of the reaction is as follows: [tex]3H_2 + N_2 --- > 2NH_3[/tex]

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The emission spectrum of sodium is shown below. What do the two bright
yellow vertical lines in the spectrum show about sodium atoms?

Answers

The two lines show that these are the only two lines  that do not cause energy transition in the sodium atom. Option D

What are the two lines in the spectrum of sodium atom?

The spectrum of the sodium atom appears as a doublet. This implies that there are two lines in the spectrum and they appear as bright yellow lines that are not spaced apart in the spectrum.

The  two bright yellow vertical lines in the spectrum shows that these are the only two lines  that do not cause energy transition in the sodium atom.

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Consider the reaction: icl(g) cl₂(g) → icl₃(s). the ∆g(f)° of icl(g) is -5.5 kj/mol and the ∆g(f)° of icl₃(s) is -22.59 kj/mol what is the ∆g° of the reaction, in kj/mol?

Answers

The ΔG° for the reaction in kJ/mol is -17.09.

Calculation,

The reaction is given below.

[tex]ICl(g)+Cl_{2} (g)[/tex]  → [tex]ICl_{3} (s)[/tex]

The ΔG° for [tex]ICl(g)[/tex] = -5.5  kJ/mol

The ΔG° for [tex]ICl_{3} (s)[/tex]  = -22.59  kJ/mol

The ΔG° for  [tex]Cl_{2} (g)[/tex]  = 0  kJ/mol ( change in gibb's free energy of standard state )

ΔG° for the reaction =  ΔG° (product) -  ΔG° (reactant)

ΔG°  for the reaction = -22.59  kJ/mol - ( -5.5  kJ/mol + 0  kJ/mol )

 ΔG°  for the reaction = -17.09  kJ/mol

The value of change standard gibb's free energy for the standard state ( most stable form of elements) is zero.

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a plant cell has a solute potential of -2.0 bars and pressure potential of 0.0. what is its water potential? show your work if it is placed in a solution with a water potential of -1.0 what will happen to this plant cell

Answers

A plant cell has a solute potential of -2.0 bars and pressure potential of 0.0. Its water potential is -2 bar. The cell will gain water or swell.

What is Water Potential ?

Water Potential is the potential energy of water in a system per unit volume relative to pure water , when both pressure and temperature are kept same. Water potential is never positive. It is expressed in kPa (Kilopascals). The symbol of water potential is ψ.

How to find the Water Potential ?

To find the water potential use this formula

[tex]\Psi = \Psi_{s} + \Psi_{p}[/tex]

where,

ψ = Water Potential

[tex]\Psi_{s}[/tex] = Solute Potential

[tex]\Psi_{p}[/tex] = Pressure potential

Now put the value in above expression we get

[tex]\Psi = \Psi_{s} + \Psi_{p}[/tex]

   = -2.0 + 0.0

   = - 2 bar

Thus from the above conclusion we can say that A plant cell has a solute potential of -2.0 bars and pressure potential of 0.0. Its water potential is -2 bar. The cell will gain water or swell.

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A saturated solution of baso4 has a concentration of 0.5mol/l. a 55ml sample is taken by you. what is the mass of baso4 in the solution

Answers

Answer:

6.4 g BaSO₄

Explanation:

You have been given the molarity and the volume of the solution. To find the mass of the solution, you need to (1) find the moles BaSO₄ (via the molarity ratio) and then (2) convert moles BaSO₄ to grams BaSO₄ (via the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to reflect the sig figs of the given values.

Molarity (mol/L) = moles / volume (L)

(Step 1)

55 mL / 1,000 = 0.055 L

Molarity = moles / volume                             <----- Molarity ratio

0.5 (mol/L) = moles / 0.055 L                        <----- Insert values

0.0275 = moles                                             <----- Multiply both sides by 0.055

(Step 2)

Molar Mass (BaSO₄): 137.33 g/mol + 32.065 g/mol + 4(15.998 g/mol)

Molar Mass (BaSO₄): 233.387 g/mol

0.0275 moles BaSO₄          233.387 g
---------------------------------  x  -------------------  =  6.4 g BaSO₄
                                                1 mole

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