Answer: mmm... If you mean most like Basketball it's net ball but i don't know much about Basket ball teams
Explanation:
7. A car is moving at 50.0 mph when the driver applies brakes. Determine the distance it
covers before coming to a halt. Coefficient of static friction between the tires and surface of
the road is 0.514. Mass of the car is 1000 kg.
Answer:
The distance to come to a halt is approximately 49.53 meters
Explanation:
Thee given parameters are;
The speed of the car, v = 50 mph = 22.35 m/s
The mass of the car, m = 1000 kg
The coefficient of friction, = 0.514
The force of friction of the brake = Mass × Gravity × Friction = 1000 × 9.81 × 0.514 = 5042.34 N
The initial kinetic energy of the car = 1/2×m×v² = 1/2 × 1000 × 22.35² = 249761.25 J
The work done by the brake = Force of the brake × Distance, d, to come to halt
By conservation of energy, we have;
The work done by the brake = The initial kinetic energy of the car
∴ The initial kinetic energy of the car = Force of the brake × Distance, d, to come to halt
The initial kinetic energy of the car = 249761.25 J = 5042.34 N × Distance, d, to come to halt
∴The distance to come to a halt = 249761.25 J /(5042.34 N) ≈ 49.53 meters
The distance to come to a halt ≈ 49.53 meters.
The car will cover 49.65 m distance before stopping due to application of brake.
Given data:
The mass of car is, M = 1000 kg.
The initial speed of car is, u = 50.0 mph = (50)(0.447 m/s) = 22.35 m/s.
The coefficient of static friction is, [tex]\mu = 0.514[/tex].
The given problem can be solved using the third kinematic equation of motion. Which is,
[tex]v^{2}=u^{2}+2as[/tex] ....................................................(1)
Here, v is the final speed, v = 0 (Because car is finally stopping)
s is the distance covered before stopping and a is the magnitude of acceleration.
Now, since frictional force opposes the motion. Then,
[tex]F = f\\\\ma = \mu \times m \times g\\\\a = 0.514 \times 9.8\\\\a =5.03 \;\rm m/s^{2}[/tex]
Substituting the values in equation (1) as,
[tex]0^{2}=23.35^{2}+2(-5.03)s\\\\s = \dfrac{2500}{2 \times 5.03}\\\\ s=49.65 \;\rm m[/tex]
Thus, the car will cover 49.65 m distance before stopping due to application of brake.
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Which event is an example of condensation?
A. Wet clothes are drying on a clothesline.
B. A mirror fogs up when someone takes a hot shower.
C. Water drips from an icicle on the edge of a roof.
O D. Rain turns to sleet as it nears the ground.
Answer:
the answer to your question is b a mirror fogs up when someone takes a hot shower.
The process of conversion of gaseous water to its liquid form is called condensation. The fogs formed on the mirror from the hot shower is an example of condensation.
What is condensation?Condensation is the process of cooling up of water vapor to liquid water. Water vapor condenses when it cools. Condensation can be best understood from the reason behind raining.
When water vaporizers from resources and cools from the sky, and the vapor condenses to form liquid droplets. Similarly we can observe water droplets in the window pane due to the similar effect.
The water vapor arises from the hot shower condenses in the atmosphere and forms the drops on the mirror. Therefore, the mirror fogs up by the hot shower is an example of condensation.
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PLEASE HELP ME IM GONNA DIE 49 POINTS A motorcycle cop with a radar gun spots a speeder doing 100 mph. The cop begins to accelerate just as the speeder goes by. The motorcycle can do zero to 100 km/h in 5.6s. How long will it take for the cop to catch up to the speeder and how fast will the cop being going when he catches up to the speeder?
Answer:
Is there any thing miss from the question
A person takes a ride to the top of a building in an elevator. If the elevator starts with
electrical energy, what types of energy does the electrical energy transform into during
this process? Put at least four answers.
Answer:
mechanical energy
Explanation:
A 1500 kg car traveling at 15m/s to the south collides with a 4500 kg truck that is initially at rest at a stoplight. the car and truck stick together and move together after the collision, what is the final velocity of the two vehicles
Answer: 3.75 m/s
Explanation:
Here's what you know: The car has mass 1500 kg, and initial velocity 15.0 m/s. The truck has mass 4500 kg and initial velocity 0 m/s. The final mass is 6000 kg (4500 kg plus 1500 kg, because they stick together) and we are looking for the final velocity. Using the formula p = mv, and the concept that p before equals p after, the p of the car plus p of the truck equals the p of them together. So, 1500 x 15 + 4500 x 0 = 6000 x v final. 22500 = 6000 v, and v = 3.75 m/s. The velocity is positive, and the initial velocity of the car was positive, so the two vehicles together are traveling to the south just like the car was initially.
Cody’s car accelerates from 0M/S 245 in/at Northwoods and 15 seconds what is the acceleration of the car
Answer:
3m/s^2
Explanation:
Acceleration is change in velocity / time = 45/15 = 3m/s^2
What two types of motion are the same in which they both are under the influence of gravity?
Answer:
Orbit and Gravity
Explanation:
May I have brainliest please I would appreciate it! Have a great day!
Protons, electrons, and neutrons make up atoms and atoms make up A: Substances B: Matter C: Molecules D: Solids
Answer:
I think it's matter
Explanation:
Because everything is made of matter
What is the best description of temperature?
Answer
An object's temperature is the best approximation of the kinetic energy of the particles. When we measure an object's temperature, we measure the average kinetic energy of the particles in the object. The higher the temperature, the faster the molecules of the substance move, on the average
The measure of the warmth or coldness of a substance or an object with reference to some standard value is termed as temperature.
TemperatureIt is a measure of the coldness or hotness expressed in terms of any of the many arbitrary scales and suggesting the direction in which the heat energy will flow spontaneously, that is, from a hotter body to a colder body.
Similar to pressure or density, temperature is an intensive property, which is independent of the quantity of matter being considered.
Thus, temperature refers to a physical quantity, which expresses the extent of coldness or hotness of a substance.
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If I travel at a velocity of 2m/s to the right for 4 seconds, what is my displacement?
Elements are arranged in the periodic table based on various patterns. For example, elements found in the rows near the top
A
have higher atomic numbers than the elements in the rows near the bottom
В.
all have the same atomic number.
C.
have lower atomic numbers than the elements in the rows near the bottom.
D. have the same atomic numbers as the elements in the rows near the bottom.
how many seconds are there in 3 days and 36 hours
The answer is 388 800 sec
Answer:
388800 secs
Explanation:
1 day = 24 hrs
so 24 times 3 = 72
and 1 hour is equal to 60 min
108 x 60 = 6480
and 60 secs in a minute
6480 x 60= 388800
Which of the following is NOT a likely result of regular physical activity?
a. increased energy
b. decreased attention span
c. improved school attendance
d. improved self-image
Answer:
B.) decreased attention span
Explanation:
took the test and got 100%
One particle has a charge of 4.2 x 10-°C, while another particle has a charge
of 1.10 10-9 C. If the two particles are separated by 0.005 m, what is the
electromagnetic force between them? The equation for Coulomb's law is
F = kongs, and the constant, k, equals 9.00 x 10°Nm2/C2
Answer:
1.66*10^-3N
Explanation:
a tennis ball is thrown straight up with an initial velocity of 22.5 m/s how much total time is the ball in the air
Answer:
4.6s
Explanation:
v=u+at
0=22.5+(-9.8)t
-22.5=-9.8t
t=-22.5/-9.8
t=2.295 s
The total time will double
2.295×2=4.59s
=4.6s
A person of 45 kg can accelerate at 1.5 m/s on a straight road. What is the force created?
Answer:
The answer is 67.5 NExplanation:
The force acting on an object can be found by using the formula
Force = mass × accelerationFrom the question
mass = 45 kg
acceleration = 1.5 m/s²
We have
Force = 45 × 1.5
We have the final answer as
67.5 NHope this helps you
A projectile is launched with an initial velocity of 1.414 m/s at 45° above the horizontal. What is the vertical component of the projectile's velocity when it strikes a wall 0.50 m away?
Answer:
As the projectile starts it’s motion from a vertical height at y=10m, it’s vertical motion may be described as under-
y= 10+ut-0.5gt^2
Where “u” is initial vertical velocity
= 45 sin60,
“g” is acceleration due to the gravity (10m/sec^2)
and “t” is time.
When the projectile touches the ground the vertical height “y”=0
Therefore the time “t” taken for the flight of the projectile till it touches the ground may be calculated from the above equation when y=0 as under -
0= 10+45sin60 x t- 0.5x10 t^2
0= 10+45x (√3/2)x t-5 t^2
t^2-9x (√3/2)x t-2 =0
t= [4.5√3 + √(243/4+4)]/2
t=[7.794+ 8.047]/2
t= 7.92 sec.
The horizontal distance travelled during this time=
vt
Where “v” is horizontal velocity = 45 cos60.
Therefore,
vt =45cos60 x 7.92
= 45x0.5x7.92
= 178.2 m
A gold puck has a mass of 12 kg and a velocity of 5i – 4j m/s prior to a collision with a stationary blue puck whose mass is 18 kg. After an elastic collision, the blue puck has a velocity of 2i – 2j m/s. What is the velocity of the gold puck after the collision?
A. 2i –j m/s
B. 3i –j m/s
C. 2i – 2j m/s
D. 3i – 2j m/s
Answer:
Explanation:D
The velocity of the gold puck after the collision is equal to (2i - j) m/s. Therefore, option (A) is correct.
What is velocity?The rate at which a displacement of the body changes in relation to time is called its velocity. Velocity is a vector parameter with both magnitude and direction. S.I. unit of velocity can be represented as meter/second.
Given, the mass of the gold puck, m = 12 kg
The velocity of the gold puck before the collision, u = 5i – 4j m/s.
The mass of the stationary blue puck, M = 18 kg.
The velocity of it after the collision, V = 2i – 2j m/s.
We have to determine the velocity of the gold puck after the collision:
The total momentum of the system before the collision is equal to the total momentum of the system after the collision.
mu + M ×0 = mv + MV
v = u - MV/m
v = (5i – 4j) m/s - (2i – 2j)m/s × 18/12
v = (5i – 4j) m/s - (3i - 3j)
v = (2i - j) m/s.
Therefore, the velocity of the gold puck is (2i - j) m/s after the collision.
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What is the acceleration of a car moving in a straight line that increases from 0m/s to 50 m/s in 5 seconds?
Answer:
10m/s^2
Explanation:
a=change in velocity/change in time
50/5=10m/s^2
Alguien ayudeme con estos problemas de fisica porfa 1. Una persona recorre 4200 m en 25 minutos, luego 4.54 Km en un hora y finalmente 9000 m en 55 minutos. Halle, el tiempo total empleado en minutos, su velocidad y rapidez. 2. Una partícula en una circunferencia de 40 cm de diámetro da 30 vueltas completas en dos minutos. Halle la velocidad y rapidez de la partícula. 3. Una persona da 500 pasos de 40 cm al oeste, luego 400 pasos de 35 cm al norte y finalmente 300 pasos de 30 cm al este utilizando en total 2 min y 120 segundos. Halle la distancia recorrida, desplazamiento, velocidad y rapidez. 4. Una persona recorre una pista circular de 250 metros de radio, ¿Cuál es su distancia, desplazamiento, velocidad y rapidez en dar media vuelta a la pista si el tiempo empleado es de 90 segundos
Answer:
1) t_total = 140 min , v = 126.7 m / min , 2) v = 0.628 m / s ,
3) v = 0.592 m / s , θ = -39.3 º
Explanation:
Here we have some short kinematics problems
1) d₁ = 4200 m at T1 = 25 min
d₂ = 4.54 km at t2 = 1 h
d₃ = 9000 m at t3 = 55 min
of the statement the direction of each route is the same
Let's reduce the distances to the SI system
d₂ = 4.54 km (1000 m / 1 km) = 4540 m
t₂ = 1 h (60 min / 1 h) = 60 min
Total time is
t_total = t1 + t2 + t3
t_total = 25 + 60 +55
t_total = 140 min
the distance is
d_total = 4200 + 4540 +9000
d_total = 17740 m
with movement it is in one dimension and all displacement is in the same direction, distance equals displacement.
Speed is
v = 17740/140
v = 126.7 m / min
in the direction of travel
Speed is the modulus of speed
| v | = 126.7 m / min
2) the angular velocity is
w = θ / t
In this exercise
t = 2 min (60 s / 1min) = 120 s
θ = 30 rev (2π rad / 1 rev) = 60π rad
w = 60π / 120
w = 1.57 rad / s
linear velocity is
v = w r
v = 1.57 0.40
v = 0.628 m / s
velocity is the speed tangential to the trajectory
3) the data for this exercise are
distance = (number of steps) (distance of one step)
d₁ = 500 0.40 m = 200 m West
d₂ = 400 0.35 m = 140 m North
d₃ = 300 0.30 m = 90 m East
in a total time of t = 2 min and 120 s
t = 2 60 + 120 = 240 s
the distance traveled is
x axis we assume the direction towards + x (East) positive
x_total = d₃ -d₁
x_total = 90-200 = -110 m
y axis
y_total = d₂
y_total = 140 m
we use the Pythagorean theorem to find the distance0
D = √ (x_total² + y_total²)
D = √ (110² + 90²)
D = 142.13 m
The speed is
v = D / t
v = 142.13 / 240
v = 0.592 m / s
speed is
v = 0592 m / s
tan θ = Y / X
θ = tan -1 y / x
θ = tan -1 (90 / (- 110))
θ = -39.3 º
4) This angle is measured on the positive side of the x axis in a clockwise direction
θ = 1.5 rev (2π rad / 1 rev) = 3π rad
t = 90 s
the angular velocity is
w = θ / t
w = 3πi / 90
w = 0.1047 rad / s
the speed is
v = w R
v = 0.14047 250
v = 26.17 m / s
velocity is tangent to path
In the qualifying round of the 50-yd freestyle in the sectional swimming championship, Dugan got an early lead by finishing the first 25.00 yd in 10.01 seconds. Dugan finished the return leg (25.00 yd distance) in 10.22 seconds. Determine Dugan's average velocity for the entire race. Number only, round to the nearest hundredth.
Answer:
v = 0
Explanation:
Given that,
Total distance is 50 yards
Dugan got an early lead by finishing the first 25.00 yd in 10.01 seconds
Dugan finished the return leg (25.00 yd distance) in 10.22 seconds.
We need to find Dugan's average velocity for the entire race. As he returns at the initial position. As a result, the net displacement is equal to 0. So,
Average velocity = net displacement/time
v = 0
Hence, his average velocity for the entire race is 0.
Four identical satellites are in orbit around the Earth, as shown in the diagram. For which satellite is the gravitational pull of Earth the strongest?
Explanation:
satellite A, because of its closest orbit.
Which one of the following is not a fundamental physical quantity??! A. Temperature b. Current c. Area d. Mass
Answer:
Out of this, Area is not a fundamental physical quantity.
Emma has a large piece of taffy (1.5 kg) that she wants to share with her friend Camila. However, Emma is having a hard time breaking the piece by herself. So, Emma grabs one end of the taffy while Camila grabs the other end. They both pull on the taffy in opposite directions: Emma pulls with 20 N and Camila with 23 N. Calculate the acceleration and give the direction of the acceleration.
Answer:
The acceleration is 2 m/s² in Camila's direction.
Explanation:
The acceleration can be found using the following equation:
[tex] \Sigma F = ma [/tex]
Where
F is the force
m is the mass of the taffy = 1.5 kg
a is the acceleration =?
Since Emma pulls one end of the taffy with 20 N and Camila pulls the other end with 23 N we have:
[tex] F_{C} - F_{E} = ma [/tex]
[tex]23 N - 20 N = 1.5 kg*a [/tex]
[tex] a = 2 m/s^{2} [/tex]
Hence, the acceleration is 2 m/s² in Camila's direction.
I hope it helps you!
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Which of the following statements is true about the force of gravity:
(A)The Force of gravity between two objects is directly related to the mass of the largest object.
(B)The force of gravity between two objects is directly related to the product of the object’s masses.
(C) The force of gravity between two objects is inversely related to the mass of the largest object.
(D) The force of gravity between two objects is inversely related to the product of the object’s masses.
Answer:
I believe it qould be A) The Force of gravity between two objects is directly related to the mass of the largest object.
Explanation:
Which is a physical property of matter that is always the same regardless of size or amount
Answer:
ntensive properties: A physical property that will be the same regardless of the amount of matter.
Explanation:
A long jumper leaves the ground at an angle of 25 degrees with respect to the horizontal with a resultant velocity of 30 ft/s. What was the horizontal velocity of the jumper at takeoff? What was the vertical velocity at takeoff? How high did the COM rise above the point of takeoff?
Answer:
The horizontal component of the velocity is 27.19 ft/s
The vertical component of the velocity at takeoff is 12.68 ft/s
The vertical distance traveled by the jumper is 8.2 ft
Explanation:
Given;
angle of projection or takeoff, θ = 25°
the resultant velocity, v = 30 ft/s
The horizontal component of the velocity is given by;
[tex]v_x = vcos \theta\\\\v_x = 30 * cos(25)\\\\v_x = 27.19 \ ft/s[/tex]
The vertical component of the velocity at takeoff is given by;
[tex]v_y = vsin \theta\\\\v_y = 30 * sin(25)\\\\v_y = 12.68 \ ft/s[/tex]
The vertical distance traveled by the jumper is given by;
[tex]v_y_f^2 = v_y_o^2 +2(-g)h\\\\v_y_f^2 = v_y_o^2 -2gh\\\\0 = 12.68^2 - (2*9.8)h\\\\0 = 160.78 - 19.6h\\\\19.6h = 160.78\\\\h = \frac{160.78}{19.6}\\\\ h = 8.2 \ ft[/tex]
Which of the following solar oven design materials would serve to conduct heat to maximize thermal energy in the s'more?
1. metal platform
2. foil on the exterior flap
3. layers of cotton lining the interior
4. white paper lining the interior
Answer:
The correct option is;
3. layers of cotton lining the interior
Explanation:
In the procedure for making a solar oven it is essential place the inside portion of the carboard flap be made that the air made hot by the heat of the Sun does is not removed from the oven as convection current, and to provide insulation that limits heat loss by thermal radiation as well as conduction to cooler surfaces.
Answer:
^
Explanation:
If a truck has a mass of 100 kg and
a velocity of 35 m/s, what is its
momentum?
A Parachutist with a camera, with descending at a speed of 12.5m/s, releases, the camera at an altitude of 64.3m. What is the magnitude of the velocity of the camera just before it hits the ground ? The acceleration of gravity is 9.8 m/s and air friction is negligible. How long does it take the camera to reach the ground
Given :
Initial velocity, u = 12.5 m/s.
Height of camera, h = 64.3 m.
Acceleration due to gravity, g = 9.8 m/s².
To Find :
How long does it take the camera to reach the ground.
Solution :
By equation of motion :
[tex]h = ut+\dfrac{gt^2}{2}[/tex]
Putting all given values, we get :
[tex]12.5t+\dfrac{9.8t^2}{2}=64.3\\\\4.9t^2+12.5t=64.3[/tex]
t = 2.56 and t = −5.116.
Since, time cannot be negative.
t = 2.56 s.
Therefore, time taken is 2.56 s.
Hence, this is the required solution.