Below is the market for funnel cakes at a small community fair.

a) what is the equilibrium price and quantity of the funnel cakes?

b) What is the total consumer spending on funnel cakes at the equilibrium point?

c) Calculate the producer surplus and consumer surplus at equilibrium. Show your work.

d) What would be the result if the suppliers charged $6? Explain.

e) Cheese pretzels are substitute good for funnel cakes at the same fair. Draw a correctly labeled graph of the market for cheese pretzels. Shade the area of consumer surplus.

f) A large number of new guests enter the fair. Illustrate the effect of this change on the same graph from part E.

g) does the consumer surplus increase, decrease, or stay the same as a result of the change from part F? Explain.

h) A new cheese pretzel stand opens at the same fair. On a new graph, illustrate the market for cheese pretzels at this fair before and after the new stand opened.

i) if the large number of new guests entering the fair happened at the same time that the new cheese pretzel stand open how would the equilibrium price and quantity for cheese pretzels change? Explain.

Answer:

A speaker is a term used to describe the user who is giving vocal commands to a software program. ... A computer speaker is an output hardware device that connects to a computer to generate sound. The signal used to produce the sound that comes from a computer speaker is created by the computer's sound card

Step-by-step explanation:

rate nyoooo plssss

Answer:

y = 1/2x^2 - 2x - 1

Step-by-step explanation:

Vertex(2, - 3)

Equation of Parabola (In vertex form): y = a(x - h)^2 + k,

                                                               y = a(x - 2)^2 - 3

Substitute given point (0, -1) and solve for a:

y = a(x - 2)^2 - 3,

-1 = a(0 - 2)^2 - 3,

a = 1/2

Equation: y = 1/2(x - 2)^2 - 3 = 1/2(x^2 - 4x + 4) - 3 = 1/2x^2 - 2x + 2 - 3 = 1/2x^2 - 2x - 1,

y = 1/2x^2 - 2x - 1: Option C

The sampling distribution is normal if the sampled populations are normal, and approximately normal if the populations are nonnormal and the sample sizes n1 and n2 are large: (A) TRUE

The central limit theorem states that as sample sizes increase, the distribution of the sample means approaches a normal distribution regardless of the shape of the population distribution, as long as the samples are randomly selected and independent.

Therefore, if the populations from which the samples are drawn are normal, the sampling distribution of the means will also be normal.

However, even if the populations are nonnormal, the sampling distribution will still be approximately normal if the sample sizes are large enough.

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Answer:The missing dimensions are now

width =7inches

length = 11 inches

Height = 3 inches

Step-by-step explanation:

Volume of a box is given as =width x length x height 231 in^3

Given

width = 7 inches

height =represented as h

l = 8 inches more than the height= 8+h

V = w x l x h

231 = 7(8+h)(h)

231=( h² + 8h)7

231/ 7= h²+8h

33= h²+8h

Giving us the quadratic equation

h² + 8h - 33 = 0

=(h-3)(h+11) = 0

h-3= 0

h= 3  also h+11=0, h=-11

h= 3 or -11

Since the value of  height cannot have a negative value,

h = 3inch

l = 8+h  = 8+3 = 11 in

The missing dimensions are now

width =7inches

length = 11 inches

Height = 3 inches

a. The region of integration is the region between the curves[tex]y = x^4[/tex]and [tex]y = x^2[/tex], for 0 ≤ y ≤ 1.

b. The value of the integral is -0.6875.

To sketch the region of integration, we need to find the boundaries of the integral.

We are integrating with respect to x first, so we need to express the limits of integration for x in terms of y.

From the inner integral, we have:

y ≤ [tex]x^2[/tex] ≤ √y

Taking the square root of both sides of the right inequality, we get:

[tex]y^{1/4}[/tex] ≤ x ≤ √y

Thus, the region of integration is the region between the curves[tex]y = x^4[/tex]and [tex]y = x^2[/tex], for 0 ≤ y ≤ 1.

To sketch the region, we can first draw the curves [tex]y = x^4[/tex] and [tex]y = x^2,[/tex]as shown in graph (A) below:

  |          .

1  |       .  

  |    .  

  | .        

  *------------>

    0  1  2  3

The region of integration is the shaded region between the curves, as shown in graph (B) below:

  |          +

1  |       +  

  |    +++  

  | +++        

  *------------>

    0  1  2  3

To evaluate the integral, we can use the boundaries we found and evaluate the integral using the following steps:

[tex]\int 1_0 \int y_(\sqrt{y } ) 110x^2y^3dxdy[/tex]

[tex]= \int 0^1 \int x^{1/2}^x^2 110x^2y^3 dy dx[/tex] (using the limits we found earlier)

[tex]= \int 0^1 110x^2 [(1/4)y^4]_(x^{1/2})^{x^2} dx[/tex]  (integrating with respect to y)

[tex]= \int 0^1 110x^2 [(1/4)x^8 - (1/4)x^4] dx[/tex] (substituting the limits of integration)

[tex]= \int 0^1 (27.5x^10 - 27.5x^6) dx[/tex].

[tex]= [2.75x^11 - 3.4375x^7]_0^1[/tex](integrating and substituting limits)

= 2.75 - 3.4375.

= -0.6875.

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Answer:

9 days

Step-by-step explanation:

32-2-2-2-2-2-2-2-2-2 = 14

The equation that represents the day, d, when there are 14 cookies in the jar will be 14 = 32 - 2d, and that day will be on the 9th day.

There are many different ways to define an equation. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.

As per the given,

Initial cookie = 32

Since each day 2 cookies are eaten so after "d" days the total eaten cookies will be 2d.

Remaining cookies = initial cookies - eaten cookies

Remaining cookies  = 32 - 2d

The day when 14 cookies remain will be,

14 = 32 - 2d

2d = 32 - 14

d = 9

Hence "The equation that represents the day, d, when there are 14 cookies in the jar will be 14 = 32 - 2d, and that day will be on the 9th day".

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Answer:

4 ...................

Step-by-step explanation:

hope the answer was helpful ......

Answer:

1024÷256=4

Step-by-step explanation:

hope u get that

Answer:

-9

Step-by-step explanation:

Parentheses first:16-35+4 = -35+16+4 = -35+20 = -15

3(-15) = -45/5

-45 divided by 5 = -9

The probability that the mean height of 64 dogs is between 27 and 28.5 inches is approximately 0.8531.

We can use the central limit theorem to approximate the distribution of the sample mean. The central limit theorem states that if we take a large enough sample from a population, the sample mean will be approximately normally distributed with mean equal to the population mean and standard deviation equal to the population standard deviation divided by the square root of the sample size. In this case, we have:

Population mean (μ) = 28 inches

Population standard deviation (σ) = 4 inches

Sample size (n) = 64

a) To find the probability that the mean height of 64 dogs is less than 27 inches, we need to standardize the sample mean and find the corresponding area under the standard normal distribution. We have:

z = (sample mean - population mean) / (population standard deviation / sqrt(sample size))

z = (27 - 28) / (4 / sqrt(64))

z = -2

Using a standard normal distribution table or calculator, we find that the probability of z being less than -2 is approximately 0.0228. Therefore, the probability that the mean height of 64 dogs is less than 27 inches is approximately 0.0228.

b) To find the probability that the mean height of 64 dogs is greater than 28.5 inches, we standardize the sample mean and find the area to the right of the standardized value. We have:

z = (sample mean - population mean) / (population standard deviation / sqrt(sample size))

z = (28.5 - 28) / (4 / sqrt(64))

z = 1

Using a standard normal distribution table or calculator, we find that the probability of z being greater than 1 is approximately 0.1587. Therefore, the probability that the mean height of 64 dogs is greater than 28.5 inches is approximately 0.1587.

c) To find the probability that the mean height of 64 dogs is between 27 and 28.5 inches, we need to find the area under the standard normal distribution between the two standardized values. We have:

z1 = (27 - 28) / (4 / sqrt(64))

z1 = -2

z2 = (28.5 - 28) / (4 / sqrt(64))

z2 = 1

Using a standard normal distribution table or calculator, we find that the probability of z being between -2 and 1 is approximately 0.8531. Therefore, the probability that the mean height of 64 dogs is between 27 and 28.5 inches is approximately 0.8531.

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The expression is evaluated to 1/9. Option D

We need to know that index forms are described as mathematical forms used in the representation of number or variables that are too large or too small in more convenient forms.

Also, other names for these index forms are scientific notation and standard forms.

From the information given, we have that;

[tex]3^-^\sqrt[3]{8}[/tex]

Now, find the cube root of the exponent with value of 8, we have;

∛8 = 2

Substitute the value, we have;

3⁻²

Express as a fraction, we get;

1/3²

Find the square of the denominator

1/9

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Answer:

146

Step-by-step explanation:

180=4+30+x

180=34+x

180-34=x

146=x

The number of errors in a textbook follows a Poisson distribution with a mean of 0.04 errors per page. To find the expected number of errors in a textbook with 204 pages, we need to multiply the mean by the number of pages.

Expected number of errors = mean * number of pages = 0.04 * 204 = 8.16

Therefore, we can expect to find approximately 8 errors in a textbook that has 204 pages, based on the given Poisson distribution with a mean of 0.04 errors per page. It is important to note that this is only an expected value and the actual number of errors could vary.

Additionally, Poisson distribution assumes that the errors occur independently and at a constant rate, which may not always be the case in reality. Nonetheless, the Poisson distribution provides a useful approximation for the expected number of rare events occurring in a given interval.

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Answer: 0.098

Step-by-step explanation: First you’ll need to find the sample distribution mean and standard deviation (which is 78 and 1.55). Then you plug it into calculator using normal approximation cause n is large: normalcdf(80,100,78,1.55)

As, 0.098 proportion of these samples would, we expect to have a mean greater than 80. Thus, option (C) is correct.

As the population is defined, as  a group of groupings with a common characteristic. In data point, a population is the pool of individuals from which a statistical sample is drawn for a study. As we see, different countries have different populations.

As here the μ = 78, σ = 1.5492 and x = 80

We need to compute P(X >= 80). The corresponding z-value is calculated using Central Limit Theorem

z = (x - μ)/σ

z = (80 - 78)/1.5492 = 1.29

Therefore,

P(X >= 80) = P(z <= (80 - 78)/1.5492)

= P(z >= 1.29)

= 1 - 0.902 = 0.098

Therefore, The right option (B) is correct

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Answer:

Step-by-step explanation:

Suppose an upward force of 15 N is added to the box. What will be the net vertical force on the box?

THIS IS THE COMPLETE QUESTION BELOW;

1. Explain how you calculate the net force in any direction on the box.

2. Suppose an upward force of 15 N is added to the box. What will be the net vertical force on the box?

3. What force could be applied to the box to make the net force in the horizontal direction zero? Explain.

4. Suppose a force of 25 N to the right is added to the box. What will be the net force to the right?

CHECK THE ATTACHMENT FOR THE FIQURE.

1)since the given horizontal forces are acting on the box at opposite direction then

NET FORCE= (100- 50)N

= 50N( this is because the 100N and 50N acting Horizontally will cancel each other, then the remaining force is 50N.

✓Since, the  two vertical forces also acted on the box in opposite direction, then

NET FORCE= (25 25)N

= 0N

Note: horizontal forces are one acting from right to left and vice versa, while vertical forces are ones acting from up to down and vice versa.

HENCE, NET FORCE = 50N + 0N= 50N

2) since the net vertical force was 0N, if

15N force is added then we still have NET FORCE OF 15N

3) if  force of 50N is applied to horizontal forces moving from left to right then NET HORIZONTAL FORCES= 0N

4) since, the net force for the box is 50N, if  Horizontal force of 25N is added  moving left to right then NET FORCE = 25N for whole box.

An n x n matrix a with an eigenvalue of multiplicity n is diagonalizable if and only if a = i, where i is the identity matrix.

Suppose a is diagonalizable. Then there exists an invertible matrix P such that a = PDP^(-1), where D is a diagonal matrix. Since a has an eigenvalue of multiplicity n, the diagonal entries of D are all equal to that eigenvalue. Therefore, a = PDP^(-1) = P(lambda I)P^(-1) for some scalar lambda. But since the eigenvalue has multiplicity n, lambda must equal the eigenvalue, which implies that D = lambda I. Therefore, a = [tex]P(lambda I)P^(-1) = PDP^(-1)[/tex] = P(lambda I)P^(-1) = lambda PPP^(-1) = lambda I. Thus, a = lambda I, and since the eigenvalue has multiplicity n, we have lambda = 1. Therefore, a = i.

Conversely, suppose a = i. Then a is trivially diagonalizable, since any matrix is diagonalizable if and only if it is already diagonal. Therefore, a is diagonalizable, and the proof is complete.

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Answer:

A) Triangle PQR

Step-by-step explanation:

This is the correct triangle because it has the exact same measurements as Triangle ABC. Angles A and P are the same angle on the triangles and they have the same measure (70). Angles C and R are the same angle on the triangles and they have the same measure (75). To solve for Angle C in Triangle ABC though, add angles 70 + 35 together to get 105. A triangle has a total measure of 180, so subtract 180 - 105 to get 75.

Hope it helps!

Answer:

Step-by-step explanation:

a) Frequency table:

Category       Frequency

Dog                     4

Cat                       3

Fish                      2

Hamster               1

b) Relative frequencies of each animal type

Dog: 4/10 = 0.4

Cat: 3/10 = 0.3

Fish: 2/10 = 0.2

Hamster: 1/10 = 0.1

c) Popularity

Dog is the most popular because it has the highest relative frequency.

Hamster is the least popular because it has the lowest relative frequency.

Answer:

Step-by-step explanation:

To find the area of a rectangle, we multiply its length by its width.

The length of the rectangle is 2 2/3 inches, which can be expressed as an improper fraction: (3 * 2 + 2)/3 = 8/3 inches.

The width of the rectangle is 2 1/3 inches, which can also be expressed as an improper fraction: (3 * 2 + 1)/3 = 7/3 inches.

Now, we can calculate the area by multiplying the length and width:

Area = (8/3) * (7/3)

= (8 * 7)/(3 * 3)

= 56/9

Therefore, the area of the rectangle is 56/9 square inches, which can be simplified, if needed.

Answer:

-1, y = 2

0, y = 3

2, y = 5

Step-by-step explanation:

-1, y = -1 + 3

0, y = 0 + 3

2, y = 2 + 3

Answer:

B.) 20 degrees

Step-by-step explanation:

We know that the sum of angles in a triangle is equal to 180, so we can say that 80 + 4x + x is equal to 180. This means that 5x is 100 degrees, meaning that x = 20 degrees. The option with this answer is B.).

Answer:

The answer is B.

Step-by-step explanation:

4 × 20 = 80

80 + 80 = 160

A triangle is 180°

Find the missing x.

180 - 160 = 20

Plug 20 in for both x's to check your work.

Hope this helps :)

-ilovejiminssi♡

Answer:

694

Step-by-step explanation:

Answer:

[tex] \frac{a}{b} = \frac{3}{2} [/tex]

Step-by-step explanation:

Since both the triangles are similar, so their corresponding sides would be in proportion.

Therefore,

[tex] \frac{a}{b} = \frac{2.1}{1.4} \\ \\ \frac{a}{b} = \frac{3}{2} [/tex]

Answer:

B, C, and D

Step-by-step explanation:

They all have lower values than 2.1

Answer:

33 tiles

Step-by-step explanation:

Given

[tex]1\ tile = \frac{1}{3}\ points[/tex]

Required

Determine the number of tiles in 11 points

Represent this with x. So, we have:

[tex]1\ tile = \frac{1}{3}\ points[/tex]

[tex]x = 11\ points[/tex]

Cross Multiply

[tex]x * \frac{1}{3} = 11 * 1[/tex]

Multiply through by 3

[tex]3*x * \frac{1}{3} = 11 * 1*3[/tex]

[tex]x = 33[/tex]

Eeither A is singular or det(A) = 1.

Let A be a square matrix such that A^2 = A.

If A is singular, then det(A) = 0, and we are done.

Otherwise, let B = A(I - A). Then we have:

B^2 = A(I - A)A(I - A) = A^2(I - A)^2 = A(I - A) = B

Multiplying both sides by B^-1 (which exists since B is invertible), we get:

B^-1 B^2 = B^-1 B

I = B^-1

Now we have:

det(A) = det(B)/det(I - A)

Since B = A(I - A), we have:

det(B) = det(A)det(I - A) = det(A)(1 - det(A))

Substituting into our expression for det(A), we get:

det(A) = det(A)(1 - det(A))/(1 - det(A))

Simplifying, we get:

1 = det(A)

Therefore, either A is singular or det(A) = 1.

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Answer:

The triangles are similar

Step-by-step explanation:

Since EF ║ UT, m∠FUT = m∠EFU because alternate interior angles are congruent when lines are parallel.

m∠UDT = m∠EDF because vertical angles are congruetnt

Therefore ΔUDF is similar to ΔFDE because if two angles of a triangle are congruent to two angles of another triangle, then the triangles are similar.

The statement is false because the general least-squares problem attempts to find an x that minimizes ||b - Ax||.

The general least-squares problem aims to find a solution for the equation Ax = b when there is no exact solution. In other words, it seeks to find an x that minimizes the residual vector ||b - Ax||.

The residual vector represents the error between the actual values of b and the values predicted by the matrix equation Ax. The objective is to minimize this error by finding the values of x that provide the best approximation to the equation.

The least-squares solution is obtained by minimizing the sum of the squared residuals, which is equivalent to minimizing the norm (magnitude) of the residual vector. Therefore, the goal is to find an x that minimizes the expression ||b - Ax||.

The statement (a) suggests that the general least-squares problem aims to find an x such that Ax = b, which is not correct. If Ax = b has an exact solution, then there is no need for the least-squares approach. The least-squares problem is specifically designed for cases where there is no exact solution.

Option A is incorrect because it contradicts the purpose of the least-squares problem. Option B is incorrect because it suggests maximizing the norm of the residual vector, which is not the objective. Option C is incorrect because it claims that the statement is true, but the statement is actually false. The correct answer is Option D, which correctly states that the general least-squares problem attempts to find an x that minimizes ||b - Ax||.

By minimizing the residual error, the least-squares solution provides the best approximation to the equation Ax = b in situations where an exact solution is not possible. This has important applications in various fields, including statistics, data fitting, signal processing, and regression analysis.

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Answer:

C

Step-by-step explanation:

The solution to the systems of linear equations through graphing is simply the coordinates of the intersection point of the two lines.

The coordinates of the intersection line is written like this: (x, y)

Since the point is 0 on the x-axis and 3 on the y-axis, the Solution = (0, 3)